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PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

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Page 1: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

PERCENT COMPOSITION AND CHEMICAL FORMULAS

03/09 – 03/12

Page 2: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Percent Composition by Mass

% 𝑏𝑦𝑚𝑎𝑠𝑠=𝑚𝑎𝑠𝑠𝑜𝑓 𝑒𝑙𝑒𝑚𝑒𝑛𝑡𝑚𝑎𝑠𝑠𝑜𝑓 𝑐𝑜𝑚𝑝𝑜𝑢𝑛𝑑

×100

Page 3: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Ex: Percent Composition by Mass

Given: 100 g sample55 g Element X45 g Element Y Work:X:

Y:

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Example Cont

Check your work:The sum of the percentages should add up to 100:55% Element X + 45% Element Y = 100%

Page 5: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Pg 350, problem 62

49.98 g O10.47 g H60.45 g sampleWhat is the percent composition by mass of each element?

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Pg 350, problem 63

46.45% N53.32% O100 g sampleWhat are the masses of N and O?

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Pg 350, problem 65

65.4% C29.09% O5.45% H23.8 g sampleWhat are the masses of each element?

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Percent Composition from Chemical Formula

% 𝑐𝑜𝑚𝑝 𝑋=𝑚𝑜𝑙𝑎𝑟 𝑚𝑎𝑠𝑠𝑜𝑓 𝑋

𝑚𝑜𝑙𝑎𝑟𝑚𝑎𝑠𝑠 𝑜𝑓 𝑐𝑜𝑚𝑝𝑜𝑢𝑛𝑑×100

Page 9: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Example: pg 343 in Text book Given: NaHCO3

What is the percent composition of each element?

1. Find the molar mass of each element:

1. Na: 22.98 g/mole2. H: 1.01 g/mole3. C: 12.01 g/mole4. O: 15.99 g/mole

2. Find the molar mass of the compound:

1. 22.98 g/mole + 1.01 g/mole + 12.01 g/mole + 3(15.99 g/mole) = 83.97 g/mole

3. Find the percent composition for each element:

1. Na: 2. H: 3. C: 4. O:

4. Check your work: the sum of the percentages should be between 99 and 101:

27.37% + 1.20% + 14.30% + 57.13% = 100%

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Pg 344 #54

What is the percent composition of each element in H3PO4?

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Pg 344, #56

Calculate the percent by mass of each element in CaCl2.

Page 12: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Empirical Formulas

Formula for a compound with the smallest whole number mole ratio of elements

Method for determining the subscripts in a formula

Page 13: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Ex: Determining the Empirical Formula Given Percent Composition

You have a 100 g sample made up of S and O. 40.05% of this compound is S, while 59.95% is O. What is the empirical formula?1. Figure out how many grams of each

element you have:S:

O:

Page 14: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Clicker Question 1

If you have a 20 g sample that is 43% Oxygen, how many grams of Oxygen do you have?A. 8.75 gB. 86 gC. 215 gD. Not enough information

Page 15: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Clicker Question 2

A 15 g sample contains 8.32 g of S. What is its percent composition of S?A. 55.47%B. 62.71%C. 58.95%D. Not enough information

Page 16: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Clicker Question 3

A 48 g sample is made up of C, O, and H. Its percent composition of C is 23%. What is the mass of O in the compound?A. 11.04 gB. 47.92 gC. 38.72 gD. Not enough information

Page 17: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Ex: Determining the Empirical Formula Given Percent Composition cont.

2. Using the molar mass of each element, determine how many moles of each element you have:S: O:

Page 18: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Clicker Question 4

Which letter represents the molar mass of this element?AB

CD

Page 19: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Clicker Question 5

What are the appropriate units of molar mass?A. gB. MolesC. g/moleD. mole/g

Page 20: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Ex: Determining the Empirical Formula Given Percent Composition cont.

3. Figure out which element has the smallest number of moles: S, with 1.249 moles4. Divide the moles of each element by the smallest number of moles:S: O: 5. These numbers are now the subscripts for your empirical formula: SO3

*If dividing by the smallest mole value does not give you a whole #, then you must find the least common multiple of the mole values*

Page 21: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Clicker Question 6

In the previous example, we determined that the empirical formula for the compound was SO3. How many Oxygen atoms are there in one molecule?A. 1B. 2C. 3D. 4

Page 22: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Summary of Finding Empirical Formula Steps

1. Figure out how many grams of each element you have

2. Using the molar mass of each element, determine how many moles of each element you have

3. Figure out which element has the smallest number of moles

4. Divide the moles of each element by the smallest mole value (or multiply if dividing does not give you whole numbers)

5. Use the results of that division to assign subscripts.

Page 23: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Finding Empirical Formula: Example to Work Through as a Class

100 g sample made up of C, H, and O48.64% C8.16% H43.20% O

What is the empirical formula for this compound?

Page 24: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Pg 350, # 64

23.55 g of a compound is decomposed, resulting in 83.01% K and 16.99 O. What is the empirical formula for this compound?

Page 25: PERCENT COMPOSITION AND CHEMICAL FORMULAS 03/09 – 03/12

Pg 350, # 66

A 100 g sample of morphine is broken down and yields the data in the table. What is the empirical formula for morphine?

Element Mass (g)

C 17.900

H 1.680

O 4.225

N 1.228