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PENRITH HIGH SCHOOL 2015 HSC TRIAL EXAMINATION
Mathematics Extension 1
General Instructions: โข Reading time โ 5 minutes โข Working time โ 2 hours โข Write using black or blue pen
Black pen is preferred โข Board-approved calculators may
be used โข A table of standard integrals is
provided at the back of this paper โข In questions 11 โ 14, show
relevant mathematical reasoning and/or calculations
โข Answer each question on a new sheet of paper
Total marksโ70
Pages 3โ5
10 marks โข Attempt Questions 1โ10 โข Allow about 15 minutes for this section Pages 6โ9 60 marks โข Attempt Questions 11โ14 โข Allow about 1 hours 45 minutes for this section
Student Number: Teacher Name:
This paper MUST NOT be removed from the examination room
Assessor: T Bales
SECTION II
SECTION I
1
Section I 10 marks Attempt Questions 1โ10 Allow about 15 minutes for this section Use the provided multipleโchoice answer sheet for Questions 1โ10 1 For ๐ฅ๐ฅ > 1, ๐๐๐ฅ๐ฅ โ ln๐ฅ๐ฅ is:
(A) = 0
(B) > 0
(C) < 0
(D) = ๐๐
2 Consider the function ๐๐(๐ฅ๐ฅ) given in the graph below: f(x) โ๐๐ 0 ๐๐ ๐ฅ๐ฅ Which domain of the function f(x) above is valid for the inverse function to exist?: (A) ๐ฅ๐ฅ > 0
(B) โ๐๐ < ๐ฅ๐ฅ < ๐๐
(C) 0 < ๐ฅ๐ฅ < ๐๐
(D) ๐ฅ๐ฅ < 0
3 What is the acute angle between the lines 2๐ฅ๐ฅ โ ๐ฆ๐ฆ โ 7 = 0 and 3๐ฅ๐ฅ โ 5๐ฆ๐ฆ โ 2 = 0 ?
(A) 4โ24โฒ
(B) 32โ28โฒ
(C) 57โ32โฒ
(D) 85โ36โฒ
3
4 A particle is moving in a straight line with velocity ๐ฃ๐ฃ ๐๐/๐ ๐ and acceleration ๐๐ ๐๐/๐ ๐ 2. Initially the particle started moving to the left of a fixed point ๐๐. The particle is noticed to be slowing down during the course of the motion from 0 to ๐ด๐ด. It turns around at ๐ด๐ด, keeps speeding up for the rest of the course of motion, passing ๐๐and ๐ต๐ต and continues. The particle never comes back. Take left to be the negative direction.
A ๐๐ B ๐ฅ๐ฅ
During the course of the particleโs motion from ๐๐ to ๐ด๐ด, which statement of the following is correct?
(A) ๐ฃ๐ฃ > 0 and ๐๐ > 0
(B) ๐ฃ๐ฃ > 0 and ๐๐ < 0
(C) ๐ฃ๐ฃ < 0 and ๐๐ > 0
(D) ๐ฃ๐ฃ < 0 and ๐๐ < 0
5 A particle is moving in a straight line with velocity, ๐ฃ๐ฃ = 11+๐ฅ๐ฅ
๐๐/๐ ๐ where ๐ฅ๐ฅ is the displacement of the particle from a fixed point ๐๐. If the particle was observed to have reached the position ๐ฅ๐ฅ = โ2 ๐๐ at a certain moment of time, then this particle:
(A) will definitely reach the position ๐ฅ๐ฅ = 1๐๐ (B) may reach the position ๐ฅ๐ฅ = 1๐๐ (C) will never reach the position ๐ฅ๐ฅ = 1๐๐ (D) will come to rest before reaching ๐ฅ๐ฅ = 1๐๐
6 If the rate of change of a function ๐ฆ๐ฆ = ๐๐(๐ฅ๐ฅ) at any point is proportional to the value of the function at that point then the function ๐ฆ๐ฆ = ๐๐(๐ฅ๐ฅ) is a:
(A) Polynomial function (B) Trigonometric function (C) Exponential function (D) Quadratic function
4
7 Let ๐ผ๐ผ and ๐ฝ๐ฝ be any two acute angles such that ๐ผ๐ผ < ๐ฝ๐ฝ. Which of the following statements is correct ?
(A) ๐ ๐ ๐ ๐ ๐ ๐ ๐ผ๐ผ < ๐ ๐ ๐ ๐ ๐ ๐ ๐ฝ๐ฝ (B) ๐๐๐๐๐ ๐ ๐ผ๐ผ < ๐๐๐๐๐ ๐ ๐ฝ๐ฝ (C) ๐๐๐๐๐ ๐ ๐๐๐๐๐ผ๐ผ < ๐๐๐๐๐ ๐ ๐๐๐๐๐ฝ๐ฝ (D) ๐๐๐๐๐๐๐ผ๐ผ < ๐๐๐๐๐๐๐ฝ๐ฝ
8 Which of the following is a primitive function of ๐ ๐ ๐ ๐ ๐ ๐ 2๐ฅ๐ฅ + ๐ฅ๐ฅ2? (A) ๐ฅ๐ฅ โ 1
2๐ ๐ ๐ ๐ ๐ ๐ 2๐ฅ๐ฅ + ๐ฅ๐ฅ3
3+ ๐๐
(B) 1
2๐ฅ๐ฅ โ 1
4๐ ๐ ๐ ๐ ๐ ๐ 2๐ฅ๐ฅ + ๐ฅ๐ฅ3
3+ ๐๐
(C) ๐ฅ๐ฅ โ 1
2๐ ๐ ๐ ๐ ๐ ๐ 2๐ฅ๐ฅ + 2๐ฅ๐ฅ + ๐๐
(D) 1
2๐ฅ๐ฅ โ 1
4๐ ๐ ๐ ๐ ๐ ๐ 2๐ฅ๐ฅ + 2๐ฅ๐ฅ + ๐๐
9 Consider the binomial expansion (1 + ๐ฅ๐ฅ)๐๐ = 1 + ๐ ๐ ๐ถ๐ถ1๐ฅ๐ฅ+๐ ๐ ๐ถ๐ถ2๐ฅ๐ฅ2 + โฏ+ ๐ ๐ ๐ถ๐ถ๐๐๐ฅ๐ฅ
๐๐. Which of the following expressions is correct? (A) ๐๐1๐๐ + 2 ๐๐2๐๐ + โฏ+ ๐ ๐ ๐๐๐๐๐๐ = ๐ ๐ 2๐๐โ1 (B) ๐๐1๐๐ + 2 ๐๐2๐๐ + โฏ+ ๐ ๐ ๐๐๐๐๐๐ = ๐ ๐ 2๐๐+1 (C) ๐๐1๐๐ + ๐๐2๐๐ + โฏ+ ๐๐๐๐๐๐ = 2๐๐โ1 (D) ๐๐1๐๐ + ๐๐2๐๐ + โฏ+ ๐๐๐๐๐๐ = 2๐๐+1
10 Using the substitution, ๐ข๐ข = 1 + โ๐ฅ๐ฅ, find the value of โซ 1
๏ฟฝ1+โ๐ฅ๐ฅ๏ฟฝ21โ๐ฅ๐ฅ๐๐๐ฅ๐ฅ4
1 is:
(A) 65
(B) 1
3
(C) 2
3
(D) 3
2
5
Section II 60 marks Attempt Questions 11โ14 Allow about 1 hour and 45 minutes for this section Begin each question on a new sheet of paper. Extra sheets of paper are available. In questions 11โ14, your responses should include relevant mathematical reasoning and/or calculations Question 11 (15 marks) Start a new sheet of paper. (a) (๐ฅ๐ฅ + 1) and (๐ฅ๐ฅ โ 2) are factors of ๐ด๐ด(๐ฅ๐ฅ) = ๐ฅ๐ฅ3 โ 4๐ฅ๐ฅ2 + ๐ฅ๐ฅ + 6. Find the third factor. 2 (b) Find the coordinates of the point ๐๐ which divides the interval ๐ด๐ด๐ต๐ต internally in the ratio 2: 3 3 with ๐ด๐ด(โ3, 7) and ๐ต๐ต(15,โ6)
(c) Solve the inequality 1
4๐ฅ๐ฅโ1< 2, graphing your solution on a number line. 3
(d) Use the method of mathematical induction to prove that, for all positive integers ๐ ๐ : 3 12 + 32 + 52 + 72 + โฏ+ (2๐ ๐ โ 1)2 = ๐๐
3(2๐ ๐ โ 1)(2๐ ๐ + 1)
(e) T P โขB โขQ A PT is the common tangent to the two circles which touch at T. PA is the tangent to the smaller circle at Q, intersecting the larger circle at points ๐ต๐ต and ๐ด๐ด as shown. i) State the property which would be used to explain why ๐๐๐๐2 = ๐๐๐ด๐ด ร ๐๐๐ต๐ต 1
ii) If ๐๐๐๐ = ๐๐,๐๐๐ด๐ด = ๐ ๐ ๐๐๐ ๐ ๐๐ ๐๐๐ต๐ต = ๐๐, prove that nrm
n r=
โ 3
Proceed to next page for question (12)
6
Question 12 (15 marks) Start a new sheet of paper. (a) The equation ๐ ๐ ๐ ๐ ๐ ๐ ๐ฅ๐ฅ = 1 โ 2๐ฅ๐ฅ has a root near ๐ฅ๐ฅ = 0.3. Use one application of Newtonโs 3 methods to find a better approximation, giving your answer correct to 2 decimal places. (b) Five couples sit at a round table. How many different seating arrangements are possible if: i) there are no restrictions? 1 ii) each person sits next to their partner? 2
(c) In the expansion of (4 + 2๐ฅ๐ฅ โ 3๐ฅ๐ฅ2) ๏ฟฝ2 โ ๐ฅ๐ฅ5๏ฟฝ6, find the coefficient of ๐ฅ๐ฅ5 3
(d) i) Write the binomial expansion for (1 + ๐ฅ๐ฅ)๐๐ 2
ii) Using part (i), show that ( )3 10 0
11 31
nn n kk
kx dx C
k+
=+ =
+โโซ 2
iii) Hence show that 1 1
0
1 13 4 11 1
nn k n
kk
Ck n
+ +
=
= โ+ +โ 2
Proceed to next page for question (13) 7
Question 13 (15 marks) Start a new sheet of paper. (a) Use the substitution ๐ข๐ข = ๐ฅ๐ฅ
๏ฟฝ1โ๐ฅ๐ฅ2 to show that ๐๐
๐๐๐ฅ๐ฅ๏ฟฝ๐๐๐๐๐ ๐ โ1 ๏ฟฝ ๐ฅ๐ฅ
โ1โ๐ฅ๐ฅ2๏ฟฝ๏ฟฝ = 1
โ1โ๐ฅ๐ฅ2 3
(You can use the result that โซ 1
๐๐2+๐ฅ๐ฅ2๐๐๐ฅ๐ฅ = 1
๐๐๐๐๐๐๐ ๐ โ1 ๐ฅ๐ฅ
๐๐+ ๐๐. You do not need to prove this).
(b) Give the exact value for 3
23 3
dxxโ +โซ 3
(c) The distinct points P, Q have parameters ๐๐ = ๐๐1 and ๐๐ = ๐๐2 respectively on the parabola ๐ฅ๐ฅ = 2๐๐,๐ฆ๐ฆ = ๐๐2. The equations of the tangents to the parabola at P and Q respectively are given by: ๐ฆ๐ฆ โ ๐๐1๐ฅ๐ฅ + ๐๐12 = 0 and ๐ฆ๐ฆ โ ๐๐2๐ฅ๐ฅ + ๐๐22 = 0 (You do not need to prove these) i) Show that the equation of the chord ๐๐๐๐ ๐ ๐ ๐ ๐ 2๐ฆ๐ฆ โ (๐๐1 + ๐๐2)๐ฅ๐ฅ + 2๐๐1๐๐2 = 0 2 ii) Show that M, the point of intersection of the tangents to the parabola at P and Q, 2 has coordinates ๏ฟฝ๐๐1 + ๐๐2 , ๐๐1๐๐2๏ฟฝ.
iii) โ) Prove that for any value of ๐๐1, except ๐๐1 = 0, there are exactly two values 3 of ๐๐2 for which M lies on the parabola ๐ฅ๐ฅ2 = โ4๐ฆ๐ฆ. ๐ฝ๐ฝ) Find these two values of ๐๐2 in terms of ๐๐1. 2
Proceed to next page for question (14)
8
Question 14 (15 marks) Start a new sheet of paper. (a) A particle ๐๐ is moving in simple harmonic motion on the ๐ฅ๐ฅ axis, according to the law ๐ฅ๐ฅ = 4๐ ๐ ๐ ๐ ๐ ๐ 3๐๐ where ๐ฅ๐ฅ is the displacement of ๐๐ in centimetres from ๐๐ at time ๐๐ seconds. i) State the period and amplitude of the motion. 2 ii) Find the first time when the particle is 2cm to the positive side of the origin and 2 itโs velocity at this time. iii) Find the greatest speed and greatest acceleration of ๐๐ 3 (b) ๐ฆ๐ฆ ๐๐ ๐๐ ๐๐ ๐๐ ๐ฅ๐ฅ Q A projectile is fired from ๐๐, with speed ๐๐๐๐๐ ๐ โ1, at an angle of elevation of ๐๐ to the horizontal. After ๐๐ seconds, its horizontal and vertical displacements from ๐๐ (as shown) are ๐ฅ๐ฅ metres and ๐ฆ๐ฆ metres,
repectively. i) Prove that ๐ฅ๐ฅ = ๐๐๐๐๐๐๐๐๐ ๐ ๐๐ and ๐ฆ๐ฆ = โ1
2๐๐๐๐2 + ๐๐๐๐๐ ๐ ๐ ๐ ๐ ๐ ๐๐ 3
ii) Show that the time taken to reach ๐๐ is given by ๐๐ = 2๐๐๐๐๐๐๐๐๐๐๐๐
2
iii) The projectile falls to ๐๐, where its angle of depression from ๐๐ is ๐๐. 3 Prove that, in its flight from ๐๐ to ๐๐, ๐๐ is the half-way point in terms of time.
End of paper
9
STANDARD INTEGRALS
0nif,0x;1n,x1n
1dxx 1nn <โ โโ +
=โซ +
โซ >= 0x,xlndxx1
โซ โ = 0a,ea1dxe axax
โซ โ = 0a,axsina1dxaxcos
โซ โ โ= 0a,axcosa1dxaxsin
โซ โ = 0a,axtana1dxaxsec2
โซ โ = 0a,axseca1dxaxtanaxsec
โซ โ =+
โ 0a,axtan
a1dx
xa1 1
22
โซ <<โโ =โ
โ axa,0a,axsindx
xa
1 122
โซ >>โ+=โ
0ax),axxln(dxax
1 2222
โซ ++=+
)axxln(dxax
1 2222
NOTE: ln x = loge x, x > 0
10