PAPER - 2 - · PDF filePAPER - 2 CODE 0 INSTRUCTIONS A ... Iron (II) thus produced is estimated by titration with a standard permangnate solution. The reaction is MnO4Œ + +5 Fe+

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  • Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.

    Date : 29-08-2010 Duration : 3 Hours Max. Marks : 252

    PAPER - 2

    CODE

    0

    INSTRUCTIONSA. General :

    1. This Question Paper contains 72 questions.

    2. The question paper CODE is printed on the right hand top corner on this sheet of this booklet.

    3. No additional sheets will be provided for rough work.

    4. Blank paper, clipboard, log tables, slide rules, calculators, cellular phones, pagers and electronic gadgets

    in any form are not allowed.

    5. The answer sheet, a machine-gradable Objective Response Sheet (ORS), is provided separately.

    6. Do not Tamper / mutilate the ORS or this booklet.

    7. Do not break the seals of the question-paper booklet before instructed to do so by the invigilators.

    8. Write your Name, Roll No. and Sign in the space provide on the back page of this booklet.

    B. Filling the bottom-half of the ORS :

    9. The ORS has CODE printed on its lower and upper Parts.

    10. Make sure the CODE on the ORS is the same as that on this booklet. If the Codes do not match, ask for a

    change of the Booklet.

    11. Write your Registration No., Name and Name of centre and sig with pen in appropriate boxes. Do not write

    these anywhere else.

    12. Darken the appropriate bubbles below your registration number with HB Pencil.

    C. Question paper format and Marking scheme :

    13. The question paper consists of 3 parts (Chemistry, Mathematics & Physics). Each part consists of four Sections.

    14. For each question in SectionI , you will be awarded 4 marks if you darken the bubble corresponding to the

    correct answer and zero marks if no bubble is darkened. In case of bubbling of incorrect answer, minus

    one (1) mark will be awarded.

    15. For each question in SectionII , you will be awarded 4 marks if you darken the bubble(s) corresponding

    to the correct choice(s) for the answer and zero mark if no bubbled is darkened. There is no negative

    marking for incorrect answer(s) for this this section.

    16. For each question in SectionIII, you will be awarded 3 marks if you darken the bubble corresponding to

    the correct answer, and zero mark if no bubble is darkened. In case of bubbling of incorrect answer, minus

    one (1) mark will be awarded.

    17. For each question in SectionIV, you will be awarded 3 marks if you darken the bubble corresponding to

    the correct answer, and zero mark if no bubble is darkened. There is no negative marking for incorrect

    answer(s) for this this section.

    DO

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    BE

    ING

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    D T

    O D

    O S

    O B

    Y T

    HE

    INV

    IGIL

    AT

    OR

    COURSE : VIJAY (R)

    PART TEST-2 (PT-2)TARGET : IIT-JEE 2011

  • RESONANCE P2R290810C0-1

    (SPACE FOR ROUGH WORK)

    PART-I

    Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24, Al = 27, Si = 28,P = 31, S = 32, Cl = 35.5, K = 39, Ca = 40, Cr = 52, Mn = 55, Fe = 56, Cu = 63.5, Zn = 65, As = 75, Br =80, Ag = 108, I = 127, Ba = 137, Hg = 200, Pb = 207]

    SECTION - IStraight Objective Type

    This section contains 8 multiple choice questions. Each question has choices (A), (B), (C) and (D), outof which ONLY ONE is correct.

    1. Which of the following statement is correct for the 1 : 1 complex of trimethyl amine and boron tri fluoride ?(A) The B - F bond length in the complex is longer than that of in BF3.(B) The N is pyramidal with sp3 hybridisation and B is planar with sp2 hybridisation.(C) The coordination geometry of N and B both are tetrahedral with sp3 hybridisation each.(D) (A) and (C) both.

    2. Which of the following statements is INCORRECT ?(A) As difference in electronegativity of the bonded atoms increases, bond length of single covalent bondgenerally decreases.(B) HI is a stronger acid than HF.(C) Ionic hydrides contain Hydrogen in 1 oxidation state.(D) Removal of an electron from Be+ requires higher energy than from B+.

    3. Which of the following statement is INCORRECT ?(A) XeO2F2 and XeOF4 have same number of lone pair(s) of electrons but different structures.(B) XeO2F2 and XeO3F2 have same structures and different number of lone pair(s) of electrons.(C) XeOF4 and XeF5

    + have same structure and same number of lone pair(s) of electrons.(D) In XeO3F2 and XeF5

    + the hybridisation of central atoms are sp3d and sp3d2 respectively.

  • RESONANCE P2R290810C0-2

    (SPACE FOR ROUGH WORK)

    4. In - SO3 (solid) which exists as (SO3)3, (select the correct one)(A) all S O bond lengths are shorter and identical due to p - d interaction between sulphur and oxygen.(B) all sulphur atoms are tetrahedrally surrounded by three oxygen and one sulphur atoms.(C) there are six p - d bonds.(D) there are S-S linkages.

    5. Lanthanoid contraction is caused due to :(A) the appreciable shielding on outer electrons by 4f electrons from the nuclear charge(B) the same effective nuclear charge from Ce to Lu(C) the imperfect shielding on outer electrons by 4f electrons from the nuclear charge(D) the appreaciable shielding on outer electrons by 5d electrons from the nuclear charge

    6. Indicator used in the titration reaction of Fe2+ and MnO4 is :(A) Starch (B) Methyl orange(C) KMnO4 is self indicator (D) Diphenylamine

    7. and

    the above pair represents.(A) Enantiomers (B) diastereomers(C) Identical compounds (D) Conformers

  • RESONANCE P2R290810C0-3

    (SPACE FOR ROUGH WORK)

    8. Following stereoisomers are :

    (A) Enatiomers (B) Diastereomers (C) Identical (D) Conformers

    SECTION - IIMultiple Correct Answers Type

    This section contains 4 multiple correct answer(s) type questions. Each question has 4 choices (A),(B), (C) and (D), out of which ONE OR MORE is/are correct.

    9. Which of the following is correct :(A) CO bond length in CH3OH is longer than CO bond length in CO3

    2

    (B) Bond order are fractional for N N and N O bonds in N2O molecule.(C) Symmetric NON skeleton is found as compare to NNO skeleton in N2O molecule.(D) CO and Al2O3 both are soluble in aqueous conc. HCl and aqueous conc. NaOH solution :

    10. A bottle of an aqueous H2O2 solution is labelled as '28V' H2O2 and the density of the solution in g/ml is 1.25.Choose the correct option:(A) % w/v = 8.5 % (B) Strength (g/litre) = 85(C) Molality of H2O2 solution is 2.15 (approx) (D) % w/w = 10%

  • RESONANCE P2R290810C0-4

    (SPACE FOR ROUGH WORK)

    11. Which of the following statements is/are correct for an electron of quantum numbers n = 3 and m = 2 ?(A) The value of may be 2. (B) The value of may be 3.(C) Two angular nodes are present (D) number or radial nodes are zero.

    12. Consider the ozonolysis of trans-4, 5-dimethyl cyclohexene having the configuration given below.

    Which product(s) possible is/are formed in the above reaction ?

    (A) (B) (C) (D)

    SECTION - IIIComprehension Type

    This section contains 2 paragraphs. Based upon each paragraph, 3 multiple choice questions have tobe answered. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

  • RESONANCE P2R290810C0-5

    (SPACE FOR ROUGH WORK)

    Paragraph for Question Nos. 13 to 15

    Hydroxylamine reduces iron (III) according to the equation

    2NH2OH + 4Fe+3

    N2O (g) + H2O + 4Fe+2 + 4H+

    Iron (II) thus produced is estimated by titration with a standard permangnate solution. The reaction is

    MnO4 + 5 Fe+2 + 8H+ Mn

    +2 + 5Fe+3 + 4H2O

    A 10 ml sample of hydroxyl amine solution was diluted to 1 litre. 50 ml of this diluted solution was boiled with

    excess of iron (III)solution. The resulting solution required 12 ml of 0.02 M KMnO4 solution for complete

    oxidation of iron (II) in acidic medium.

    Answer the following questions

    13. Amount of MnO4 consumed in the oxidation of iron (II) will be :

    (A) 12 0.02 mol (B) 10

    02.012 mol (C)

    10002.012

    mol (D) 1000

    02.012 mol

    14. Amount of Fe+2 can form by the reduction of Fe+3 by NH2OH in 10 ml sample will be :

    (A) 5 12 0.02 mol (B) 10

    02.0125 mol (C)

    10002.0125

    mol (D) 1000

    02.012205 mol

    15. Amount of NH2OH present in 50 ml of its diluted solution will be :(A) 0.6 mili mol (B) 0.12 mili mol (C) 1.2 mili mol (D) 6.0 mili mol

  • RESONANCE P2R290810C0-6

    (SPACE FOR ROUGH WORK)

    Paragraph for Question Nos. 16 to 18

    An aromatic compound (P), which gives dicarbonyl compound (Q) on ozonolysis. (Q) gives positive iodoformtest and also give red precipitate with fehling solution. Hydrogenetion of (P) results (S). Compound (S) givesthree monochloro products (only structural) on monochlorination.

    P Q R + CHI3

    S16. The structure of the aromatic compound P is :

    (A) (B) (C) (D)

    17. The structure of the product Q is :

    (A) (B) (C) (D)

  • RESONANCE P2R290810C0-7

    (SPACE FOR ROUGH WORK)

    18. The structure of the product R is :

    (A) (B)

    (C) (D)

    SECTION - IVInteger Answer Type

    This section contains 6 questions. The answer to each of the questions isa single digit integer, ranging from 0 to 9. The appropriate bubble below therespective question number in the ORS have to be darkened.

    19. If the possible value of spin quantum number are

    21

    ,0,21

    then how many maximum number of electron

    are possible in 2p subshell. Consider that Pauli rule is applicable.

  • RESONANCE P2R290810