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Pair Production. Here a photon passes by a nucleus and converts to a particle anti particle pair. Virtual particles. A system particles that don’t have enough energy to exist are virtual. How can a particle exist without energy? - PowerPoint PPT Presentation
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Pair Production Pair Production
Here a photon passes by a nucleus and converts to a particle anti particle pair.
Virtual particlesVirtual particles A system particles that don’t have enough A system particles that don’t have enough
energy to exist are virtual. energy to exist are virtual. How can a particle exist without energy?How can a particle exist without energy? A system can be in a state of higher energy A system can be in a state of higher energy
without violating a law of physicswithout violating a law of physics As long as it “de-excites” to a lower state within As long as it “de-excites” to a lower state within
a very small time interval. a very small time interval. The same relationship is true for momentum and The same relationship is true for momentum and
space. space. These are known as “Heisenberg’s uncertainty These are known as “Heisenberg’s uncertainty
principles. principles.
So what if a particle “decayed into So what if a particle “decayed into two similar mass particles? two similar mass particles?
So what if a particle “decayed into So what if a particle “decayed into two similar mass particles? two similar mass particles?
Momentum must be conserved, Momentum must be conserved, So pSo pii = p = pff
Also EAlso Eii = E = Eff
But if the new particles have mass, there But if the new particles have mass, there could be a problem: could be a problem:
m1
m2
m3
EE22=(pc)=(pc)22 + (mc + (mc22))
If PIf P11 = (p = (p22 + p + p33) = p ) = p
EE11 = (E = (E22 + E + E33) ?) ?
EE1122
= = (pc)(pc)22 + (m + (m11cc22))22
(E(E22 + E + E33))22 = (pc) = (pc)22 + ((m + ((m2 2 +m+m33)c)c22))22
So ESo E11 = (E = (E22 + E + E33) if m) if m1 1 = m= m22 + m + m33
But in pair production m1 = 0 photon, and m2 and m3 have mass! But in pair production m1 = 0 photon, and m2 and m3 have mass!
m1
m2
m3
p1
p2
p3
EE22=(pc)=(pc)22 + (mc + (mc22))22
If PIf P11 = (p = (p22 + p + p33) = p ) = p
Let (ELet (E22 + E + E33)-E)-E11 = = E E
E E t t > > h/2h/2
So So E can be greater than zero as long as E can be greater than zero as long as
The particles exist for less time than The particles exist for less time than t t < < h/(2h/(2E)E)
m1
m2
m3
p1
p2
p3
The virtual particles must The virtual particles must recombine recombine
You would never know it happens
….unless another particle “interferes” by changing the momentum and energy of the system!