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TOPICS COVERED:

PHYSICS : Complete SyllabusCHEMISTRY : Complete SyllabusBotany : Complete SyllabusZoology : Complete Syllabus

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PHYSICS & CHEMISTRY

Choose the correct answers :1. Unit of Stefan’s constant is

(1) watt-m2-K4 (2) watt/m2-K4

(3) watt/m2-K (4) watt-m2/K4

2. From the top of a tower, a particle is thrown verticallydownwards with a velocity of 10 m/s. The ratio ofthe distance covered by it in the 3rd and 2nd secondsof the motion, is (Take g = 10 m/s2)(1) 5 : 7 (2) 7 : 5(3) 3 : 2 (4) 2 : 3

3. A force ˆˆ ˆ( ) (3 2 ) F i cj k N ; acting on a particle

causes a displacement; ˆˆ ˆ( ) ( 4 2 3 ) S i j k m in its

own direction. If the work done is 6J, then the valueof ‘c’ is(1) 0 (2) 1(3) 6 (4) 12

4. A particle (A) is dropped from a height and anotherparticle (B) is thrown in horizontal direction withspeed of 5m/sec from the same height. The correctstatement is(1) both particles will reach at ground with same

period(2) both particles will reach at ground first with

respect to particle (B)(3) Particle (A) will reach at ground first with

respect to particel (B)(4) Particle (B) will reach at ground first with

respect to particle (A)5. The period of revolution of a certain planet in an

orbit of radius R is T. Its period of revolution in anorbit of radius 4R will be(1) 2T (2) T(3) 4T (4) 8T

6. A block of mass 10 kg is placed on a rough horizontalsurface having coefficient of friction = 0.5. If ahorizontal force of 100 N is acting on it, thenacceleration of the block will be(1) 0.5m/s2 (2) 5m/s2

(3) 10m/s2 (4) 15m/s2

7. A lift of mass 1000 kg is moving with an accelerationof 1 m/s2 in upward direction. Tension developed inthe string, which is connected to the lift, is(1) 9,800N (2) 10,000N(3) 10,800N (4) 11,000N

8. A disc is rotating with an angular speed of . If achild sits on it, which of the following is conserved?(1) Kinetic energy (2) Potential energy(3) Linear momentum (4) Angular momentum

9. A body of mass m is placed on the earth’s surface.It is taken from the earth’s surface to a heighth = 3R. The change in gravitational potential energyof the body is

(1)23

mgR (2)34

mgR

(3)2

mgR(4)

4mgR

10. Consider two rods of same length and differentspecific heats (S1 and S2), conductivities (K1 andK2) and areas of cross-sections (A1 and A2) and bothgiving temperature 1 and 2 at their ends. If therate of heat loss due to conduction is equal, then(1) K1A1 = K2A2 (2) K2A1 = K1A2

(3)1 1 2 1

1 2

K A K A

S S (4)2 1 1 1

2 1

K A K A

S S

11. A mass m is suspended separately by two differentsprings of spring constant k1 and k2 gives the time-period t1 and t2 respectively. If same mass m isconnected by both springs as shown in figure thentime-period t is given by the relation

m

k1 k2

(1) t = t1 + t2 (2)1 2

1 2

t ttt t

(3) 2 2 21 2

t t t (4) 2 2 21 2

t t t

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12. A wave travelling in positive X-direction withA = 0.2 m has a velocity at 360 m/sec. if = 60 m,then correct expression for the wave is

(1) 0.2sin 2 660

xy t

(2) 0.2sin 660

xy t

(3) 0.2sin 2 660

xy t

(4) 0.2sin 660

xy t

13. Tube A has both ends open while tube B has oneend closed, otherwise they are identical. The ratioof fundamental frequency of tube A and B is(1) 1 : 2 (2) 1 : 4(3) 2 : 1 (4) 4 : 1

14. A tuning fork arrangement (pair) produces 4 beats/sec with one fork of frequency 288 cps. A little waxis placed on the unknown fork and it then produces2 beats/sec. The frequency of the unknown fork is(1) 286 cps (2) 292 cps(3) 294 cps (4) 288 cps

15. A wave y = a sin(t – kx) on a string meets withanother wave producing a node at x = 0. Then theequation of the unknown wave is(1) y = a sin(t + kx) (2) y = –a sin(t + kx)(3) y = a sin(t – kx) (4) y = –a sin(t – kx)

16. Initial angular velocity of a circular disc of mass Mis 1. Then two small spheres of mass m areattached gently to two diametrically opposite pointson the edge of the disc. What is the final angularvelocity of the disc ?

(1) 1

M mM (2) 1

M mm

(3) 14

MM m (4) 12

M

M m

17. A cylinder of height 20 m is completely filled withwater. The velocity of efflux of water (in ms–1)through a small hole on the side wall of the cylindernear its bottom is(1) 10 (2) 20(3) 25.5 (4) 5

18. When forces F1, F2 F3 are acting on a particle ofmass m such that F2 and F3 are mutuallyperpendicular, then the particle remains stationary.if the force F1 is now removed then the accelerationof the particle is(1) F1/m (2) F3F3/mF1

(3) (F2 – F3)/m (4) F2/m19. Two forces are such that the sum of their magnitudes

is 18 N and their resultant is 12 N perpendicular tothe smaller force. Then the magnitudes of the forcesare(1) 12 N, 6 N (2) 13 N, 5 N(3) 10 N, 8 N (4) 16 N, 2 N

20. 1 mole of a gas with = 7/5 is mixed with 1 mole ofa gas with = 5/3, then the value of for the resultingmixture is(1) 7/5 (2) 2/5(3) 3/2 (4) 12/7

21. Two spheres of the same material have radii 1 mand 4 m and temperature 4000 K and 2000 Krespectively. The ratio of the energy radiated persecond by the first sphere to that by the second is(1) 1 : 1 (2) 16 : 1(3) 4 : 1 (4) 1 : 9

22. Three identical blocks of masses m = 2 kg aredrawn by a force F = 24 N on a frictionless surface.What is the tension (in N) in the string between theblocks B and C ?

FC B A

(1) 9.2 (2) 8(3) 4 (4) 9.8

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23. A particle starts from rest and has an accelerationof 2 m/s2 for 10 sec. After that, it travels for 30 secwith constant speed and then undergoes a retardationof 4 m/s2 and comes back to rest. The total distancecovered by the particle is(1) 650 m (2) 700 m(3) 750 m (4) 800 m

24. The latent heat of vapourisation of water is 2240 J.If the work done in the process of vapourisation of1 g is 168 J, then increase in internal energy is(1) 2408 J (2) 2240 J(3) 2072 J (4) 1904 J

25. According to Wein’s displacement law

(1) T = constant (2)1

T

(3)T

= constant (4) Both (1) and (2)

26. A siren emitting sound of frequency 800 Hz is goingaway from a static listener with a speed of 30 m/s.Frequency of the sound to be heard by the listeneris (Take velocity of sound as 330 m/s)(1) 733.3 Hz (2) 644.8 Hz(3) 481.2 Hz (4) 286.5 Hz

27. In a uniform circular motion(1) Velocity and acceleration remain constant(2) Kinetic energy remains constant(3) Speed and acceleration change(4) Only velocity changes, acceleration remains

constant28. The First Law of thermodynamics confirms the law

of(1) Conservation of momentum of molecules(2) Conservation of energy(3) Flow of heat in a particular direction(4) Conservation of heat energy and mechanical

energy29. An ideal gas undergoing adiabatic change has the

following pressure temperature relationship(1) P–1/T = constant (2) PT1– = constant(3) PT–1 = constant (4) P1–T = constant

30. A transverse wave is represented by the equation

02sin ( )

Y Y Vt X . For what value of is the

maximum particle velocity equal to two times thewave velocity.

(1) 0

Y

(2) 0 Y

(3) 02 Y (4) 022

Y

31. A particle’s position as a function of time is describedas y (t) = 2t2 + 3t + 4. What is the average velocityof the particle from t = 0 to t = 3 s ?(1) 3 m/s (2) 6 m/s(3) 9 m/s (4) 12 m/s

32. Water flows through a vertical tube of variable cross-section. the area of cross-section at A and B are 6and 3 mm2 respectively. If 12 c.c. of water entersper second through A, find the pressure differencePA – PB (g = 10 m/s2). The separation between thecross sections at A and B is 100 cm

B

A

100cm

(1) 1.6 × 105 dyner/cm2

(2) 2.29 × 105 dyne/cm2

(3) 5.9 × 104 dyne/cm2

(4) 3.9 × 105 dyne/cm2

33. Which of the following statements is correct ?(1) Kinetic energy and momentum both are

conserved in all types of collisions(2) Total kinetic energy is not conserved but

momentum is conserved in inelastic collisions(3) Momentum is conserved in elastic collisions but

not in inelastic collisions(4) Total kinetic energy is conserved in inelastic

collisions but momentum is not conserved inelastic collisions

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34. The equation of SHM is given asX = 3 sin 20t + 4cos20twhere X is a cms and t is in seconds. The amplitudeis(1) 7 cm (2) 4 cm(3) 5 cm (4) 3 cm

35. A wheel having rotational inertia of 0.20 kgm2 rotatesat 360 rpm about a vertical axis. What is the angularspeed of the wheel when a torque of –1 Nm is appliedabout the same axis for 3.0 s ?(1) 12.68 rad/s (2) 22.68 rad/s(3) 32.68 rad/s (4) 42.68 rad/s

36. Two mass m1 and m2 are attached to a string whichpasses over a frictionless smooth pulley. Whenm1 = 10 kg, m2 = 6 kg the acceleration of masses is

10 kg

6 kg

m1

m2

(1) 20 m/s2 (2) 5 m/s2

(3) 2.5 m/s2 (4) 10 m/s2

37. An object is moving through the liquid. The viscousdamping force acting on it is proportional to thevelocity. Then dimension of constant ofproportionality is(1) ML–1T–1 (2) MLT–1

(3) M0LT–1 (4) ML0T–1

38. A simple pendulum oscillates in a certical plane.Whne it passes through the mean position, the tensionin the string is 3 times the weight of the pendulumbob. What is the maximum displacement of thependulum of the string with respect to the vertical ?(1) 30° (2) 45°(3) 60° (4) 90°

39. A body of mass 8 kg is moved by a force F = 3x N,where x is the distance covered. Intial position isx = 2 m and the final position is x = 10 m. The initialspeed is 0.0 m/s. The final speed is(1) 6 m/s (2) 12 m/s(3) 18 m/s (4) 14 m/s

40. An inclined plane makes an angle 30° with horizontal.A solid sphere rolling down this inclined plane has alinear acceleration of(1) 5g/14 (2) 2g/3(3) g/3 (4) 5g/7

41. When a spring is stretched by 2 cm, it stores 100 Jof energy. If it is stretched further by 2 cm, the storedenergy will be in creased by(1) 100 J (2) 200 J(3) 300 J (4) 400 J

42. Two wires A and B are of same materials. Theirlengths are in the ratio 1 : 2 and diameters are in theratio 2 : 1. When stretched by force FA and FBrespectively they get equal increase in their lengths.Then the ratio FA/FB should be(1) 1 : 2 (2) 1 : 1(3) 2 : 1 (4) 8 : 1

43. A thermodynamic system is taken through the cyclePQRSP process. The net work done by the systemis

200Kp100Kp

100 cc 300 ccP Q

RSP

V

(1) 20 J (2) –20 J(3) 400 J (4) –374 J

44. A particle is moving in a vertical circle. The tensionsin the string when passing through two positions atangle 30° and 60° from vertical (lowest positions)are T1 and T2 respectively. Then(1) T1 = T2

(2) T2 > T1

(3) T1 > T2

(4) Tension in the string always remains the same45. The escape velocity on the surface of earth is

11.2 km/s. What would be the escape velocity onthe surface of another planet of the same mass but1/4 times the radius of the earth ?(1) 22.4 km/s (2) 67.2 km/s(3) 44.8 km/s (4) 89.6 km/s

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46. A uniform chain of length L and msss M lying on asmooth table and one-third of its length is hangingvertically down over the edge of the table. If g isthe acceleration due to gravity, the work required topull the hanging part on to the table is(1) MgL (2) MgL/9(3) MgL/3 (4) MgL/18

47. In a simple harmonic motion, what fraction of thetotal energy is kinetic energy at mid way betweenmean position and extreme position(1) 1/8 (2) 1/2(3) 1/4 (4) 3/4

48. In stationary waves(1) Energy is uniformly distributed(2) Energy is minimum at nodes and maximum at

antinodes(3) Energy is maximum at nodes and minimum at

antinodes(4) Alternating maximum and minimum energy

produced at nodes and antinodes49. A body of mass 5 kg kept on a rough inclined

plane of angle 30° starts sliding with a constantvelocity. Then the coefficient of friction is (assumeg = 10 m/s2)

(1) 1/ 3 (2) 2 / 3

(3) 3 (4) 2 3

50. A body of mass 3 kg is at rest. If a force of2 ˆ ˆ6 4F t i t j

is applied on the body then the

velocity of body at t = 3 s is

(1) ˆ ˆ18 3i j (2) ˆ ˆ18 6i j

(3) ˆ ˆ3 18i j (4) ˆ ˆ18 4i j

51. An alkaloid contains 17.28% of nitrogen and itsmolecular mass is 162. The number of nitrogenatoms present in one molecule of the alkaloid is(1) Five (2) Four(3) Three (4) Two

52. The wave number of first line of Balmer series ofhydrogen is 15200 cm–1. The wave number of firstBalmer line of Li2+ ion is(1) 15,200 cm–1 (2) 60,800 cm–1

(3) 76,000 cm–1 (4) 1,36,800 cm–1

53. The hybridization of the central atom in ICl2+ is

(1) dsp2 (2) sp(3) sp2 (4) sp3

54. When a gas is compressed at constant temperature(1) the speeds of the molecules increase(2) the collisions between the molecules increase(3) the speeds of the molecules decrease(4) the collisions between the molecules decrease

55. 1 g ice absorbs 335 J of heat to melt at 0°C. Theentropy change will be(1) 1.2 JK–1 mol–1 (2) 335 JK–1 mol–1

(3) 22.1 JK–1 mol–1 (4) 0.8 JK–1 mol–1

56. 500 mL of NH3 gas contain 6.00 × 1023 moleculesat S.T.P. How many molecules are present in 100mL of CO2 at S.T.P. ?(1) 6 × 1023 (2) 1.5 × 1021

(3) 1.2 × 1023 (4) None of these57. The energy of the second Bohr orbit of H atom

is –3.41eV. the energy of the second Bohr orbit ofHe+ ion is(1) –0.85 eV (2) –1.70 eV(3) –6.82 eV (4) –13.64 eV

58. Light of wavelength shines on a metal surfacewith intensity x and the metal emits y electrons persecond of average energy, z. What will happen toy and z if x is doubled ?(1) y will be doubled and z will become half(2) y will remain same and z will be doubled(3) both y and z will be doubled(4) y will be doubled but z will remain same

59. In a change from PCl3 PCl5, the hybrid state of Pchanges from(1) sp2 to sp3 (2) sp3 to sp2

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(3) sp3 to sp3d (4) sp3 to dsp2

60. The correct increasing bond angle among BF3, PF3

and ClF3 follows the order

(1) BF3 < PF3 < ClF3 (2) PF3 < BF3 < C1F3

(3) ClF3 < PF3 < BF3 (4) BF3 = PF3 = ClF3

61. In which of the following set of molecules is theorder of boiling points incorrect ?

(1) Xe > Ar > He

(2) HF > HCl > HBr

(3) H2O > H2Se > H2S

(4) C3H8 > C2H6 > CH4

62. Helium atom is two times heavier than a hydrogenmolecule at 298 K, the average kinetic energy ofhelium is

(1) Two times that of a hydrogen molecule

(2) Same as that of a hydrogen molecule

(3) Four times that of a hydrogen molecule

(4) Half that of a hydrogen molecule

63. Give the bond energies of N N, H – H and N – Hbonds are 945, 436 and 391 kJ mol–1 respectively,the enthalpy of the reaction,

N2(g) + 3H2(g) 2NH3(g), is

(1) –93 kJ (2) 120 kJ

(3) 90 kJ (4) 105 kJ

64. Heat of dissociation of benzene to elements is 5535kJ mol–1. The bond enthalpies of C–C, C = C andC – H are 347.3, 615.0 and 416.2 kJ respectively.Resonance energy of benzene is

(1) 1.51 kJ (2) 15.1 kJ

(3) 151 kJ (4) 1511 kJ

65. The combustion of 5.0 g of coke raised thetemperature of 1 kg of water from 10°C to 47°C.Calculate the fuel value of coke in kcal/g.

(1) 7.4 kcal/g (2) 8.4 kcal/g

(3) 9.4 kcal/g (4) 6.4 kcal/g

66. The equilibrium constant, K for the reaction

2HI(g) H2(g) + I2(g) at room temperature is2.85 and that at 698 K is 1.4 × 10–2. This impliesthat the forward reaction is

(1) Exothermic (2) Endothermic

(3) Exergonic (4) Unpredictable

67. Which of the following reactions is favoured byincrease of temperature ?

(1) N2 + 3H2 2NH3 + 22.9 kcal

(2) N2(g) + O2(g) 2NO(g) – 42.8 kcal

(3) 2SO2(g) + O2(g) SO3(g) + 45.3 kcal

(4) H2(g) + Cl2(g) – 44.0 kcal 2HCl(g)68. 56 g of N2 and 6 g of H2 were kept at 400°C in

1 litre vessel. The equilibrium mixture contained27.54 g of NH3. The approximate value of Kc forthe above reaction (in mol–2 lit2) is(1) 11.9 (2) 20.9(3) 33.9 (4) 44.9

69. Which anion is the weakest base ?(1) C2H5O– (2) NO3

–

(3) F– (4) CH3COO–

70. Among the following, which is not a Lewis acid ?(1) SnCl2 (2) AlCl3

(3) CCl4 (4) SiCl471. pH of a 1000 cc solution is 2. It will not change if

added(1) 100 cc of water is added to it(2) 100 cc of 0.1 M HCl is added to it(3) 100 cc of N/100 HCl is added to it(4) 1 cc of 0.1 M HCl is added to it

72. Which of the following statements is wrong ?(1) At 25°C pH of water is 7(2) pH of aqueous solution of FeCl3 is less than 7(3) The value of pKw at 25°C is 7(4) pH of aqueous solution of KCN is greater than

773. The pH of the neutralisation point of 0.1 N ammonium

hydroxide with 0.1 N HCl is(1) 1 (2) 6(3) 7 (4) 9

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74. The solubility product of Al(OH)3 and Zn(OH)2 are8.5 × 10–23 and 1.8 × 10–14 respectively. If a solutioncontains equal concentrations of Al3+ and Zn2+, onadding NH4Cl + NH4OH(1) Al(OH)3 is precipitated first(2) Zn(OH)2 is precipitated first(3) Both are precipitated together(4) Neither of them is precipitated

75. 1 mL of N/100 HCl is added to 1 litre of Bufferhaving pH = 5. The pH of the solution will(1) Become 7(2) Become 3(3) Remain unaffected(4) Become 6

76. Given that Ka for acetic acid as 1.8 × 10–5 and Kb ofNH4OH as 1.8 × 10–5 at 25°C, predict the nature ofaqueous solution of ammonium acetate(1) Acidic(2) Basic(3) Slightly acidic or basic(4) Neutral

77. Which of the following sets contains a pair ofelements that do not belong to the same group butshow chemical resemblance(1) B, Al (2) Be, Al(3) Zr, Hr (4) K, Rb

78. Which one of the following is correct order ofincrease of size(1) Mg < Na+ < F– < Al(2) Na+ < Al < Mg < F–

(3) Na+ < F– < Al < Mg(4) Na+ < F– < Mg < Al

79. The coefficients of I–, IO3– and H+ respectively in

the redox reaction, I– + IO3– + H+ I2 + H2O

(1) 5, 1, 6 (2) 1, 5, 6(3) 6, 1, 5 (4) 5, 6, 1

80. A solution of 10 ml, M/10 FeSO4 was titrated withKMnO4 solution in acidic medium. The amount ofKMnO4 used will b e(1) 5 ml of 0.1 M (2) 10 ml of 0.1 M(3) 10 ml of 0.5 M (4) 10 ml of 0.02 M

81. Equivalent weight of I2 in the reactionI2 + 5Cl2 + 6H2O 2HIO3 + 10HCl is(1) M (2) M/2(3) M/5 (4) M/10

82. On an industrial scale, H2O2 is prepared by auto-oxidation of(1) 2-Ethylanthraquinol(2) 2-Ethylanthraquinone(3) 1-Ethylanthraquinol(4) 1-Ethylanthraquinone

83. In basic medium, H2O2 acts as an oxidising agent inits reactions with(1) Cr2(SO4)3 (2) Ag2O(3) K3[Fe(CN)6] (4) K2Cr2O7

84. When hydrogen peroxide is treated with a coldacidified K2Cr2O7 solution containing ether, a bluecolour is obtained. This is due to(1) Chromium sulphate(2) Potassium chromate(3) Chromium oxide pereoxide(4) Chromium trioxide

85. Which of the following alkali metal ions in aqueoussolution is the best conductor of electricity ?(1) Li+ (2) Na+

(3) Cs+ (4) K+

86. Point out the correct statement about lithium ?(1) It is softer than other alkali metals(2) It is least reactive(3) It possesses lower melting and boiling points(4) It form chloride which is insoluble in pyridine

87. The bonds present in borazole are(1) 9 , 6 (2) 12 , 3 (3) 6 , 9 (4) 15 only

88. Which of the following does not give borax beadtest ?(1) Al2(SO4)3 (2) Cu(NO3)2

(3) NiSO4 (4) (CH3COO)2Co89. The reducing character of hydrides of group 14

elements is(1) Maximum for CH4 and minimum for PbH4

(2) Maximum for CH4 and minimum for SnH4

(3) Maximum for PbH4 and minimum for SiH4

(4) Maximum for PbH4 and minimum for CH4

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90. The correct IUPAC name of the compoundO

OHC COOH is

(1) 5-Carboxy-3-oxocyclohexanecarboxaladehyde(2) 2-Carboxy-5-formylcyclohexane(3) 4-Formyl-2-oxocyclohexanecarboxylic acid(4) 4-Carboxy-3-oxocyclohexanal

91. Maximum enol content is observed in(1) CH3COCH2COOC2H5

(2) O(3) CH3COCH2COCH3

(4) CH3COCH3

92. Total number of isomers having the molecularformula C3H6O is(1) 9 (2) 7(3) 6 (4) 4

93. Which of the following carbocations is least stable ?

(1) 6 5 2C H CH

(2) p-NO2–C6H4–CH2+

(3) p-CH3O–C6H4 – CH2+

(4) p-Cl–C6H4–CH2+

94. For the following reactions,CH3–Cl CH3

+ + Cl–; H10

CH3CH2–Cl CH3CH2+ + Cl–; H2

0

(CH3)2CH–Cl (CH3)2CH+ + Cl–; H30

(CH3)3C–Cl (CH3)3C+ + Cl–; H40

The correct order of enthalpies of ionization is

(1) 0 0 0 01 2 3 4H H H H

(2) 0 0 0 01 2 3 4H H H H

(3) 0 0 0 01 2 3 4H H H H

(4) 0 0 0 01 2 3 4H H H H

95. Which of the following is the least stable carbanion?(1) HC C (2) (C6H5)3C–

(3) (CH3)3C– (4) CH3–

96. An alkene gives two moles of HCHO, one mole ofCO2 and one mole of CH3COCHO on ozonolysis.What is its structure ?

(1)3

2 2

CH|

H C CH CH CH CH

(2) 2 2 3CH C CH CH CH

(3) 2 3

3

CH C C CH|CH

(4)3

2 2

CH|

CH C C CH CH

97. Addition of HCl to 2-methyl-2-butene mainly gives(1) 1-Chloro-2-methylbutane(2) 2-Chloro-2-methylbutane(3) 2-Chlorobutane(4) 1-Chlorobutane

98. Two gases, P and Q decolourise aqueous brominebut only one of them gives a white precipitate withaqueous ammoniacal silver nitrate solution. P and Qare likely to be(1) Ethane and ethyne(2) But-1-yne and but-2-yne(3) Ethane and but-2-yne(4) Ethyne and propyne

99. Which of the following has the least heat ofhydrogenation ?(1) 1, 3-Cyclohexadiene(2) Benzene(3) 1, 4-Cyclohexadiene(4) 1, 3-Butadiene

100. 1-Butyne can be converted into 1-bromo-1-buteneby reacting it with which of the following reagent ?(1) HBr (2) HBr and (C6H5COO)2

(3) Br2 and H2O2 (4) Br2 and CCl4

[10]

101.Sir J.C. Bose proposed a theory of ascent of sapwhich is known as(1) Pulsation theory(2) Transpiration pull theory(3) Relay pump theory(4) Capillary force theory

102.Who wrote the book “The Families of FloweringPlants” ?(1) Bentham and Hooker(2) Engler and Prantl(3) Hutchinson(4) Takhtajan

103.A tribe is a group between(1) Class and order(2) Order and family(3) Family and genus(4) Genus and species

104.Litmus is obtained from(1) Puffball(2) Cetraria islandica(3) Roccella tinctoria(4) Cladonia rangiferina

105. In C4 plants, Calvin enzymes are absent in(1) Mesophyll chloroplasts(2) Bundle sheath chloroplasts(3) Guard cell chloroplast(4) Epidermal chloroplasts

106.Match the columns and find the correct answerColumn I Column II

(a) Streptomyces (p) Food poisoning(b) Rhizobium (q) Source of antibiotics(c) Nitrosomonas (r) Nitrogen fixation(d) Acetobacter (s) Nitrification

(t) Vinegar synthesis(1) (a) - (s), (b) - (t), (c) - (p), (d) - (r)(2) (a) - (t), (b) - (p), (c) - (r), (d) - (s)(3) (a) - (q), (b) - (r), (c) - (p), (d) - (t)(4) (a) - (q), (b) - (r), (c) - (s), (d) - (t)

107.Corona is(1) Nectar secreting glands of plants(2) Outgrowth of different floral organs(3) Outgrowth of petals(4) Alternative name of perianth

108.Hexose monphosphate shunt is(1) A set of reactions that bypasses the glycolytic

and Krebs cycle routes for glucose oxidation inthe cell

BOTANY & ZOOLOGY

(2) Conversion of glucose into pyruvic acid(3) The sum of all chemical transformations(4) A process by which new products are

synthesised109.The hormone which has negative effect on apical

dominance is(1) Auxin (2) Gibberellin(3) Cytokinin (4) Ethylene

110. Botulism caused by Clostridium botulinum affects(1) Spleen(2) Intestine(3) Neuromuscular junctions(4) Lymph glands

111. The major portion of the dry weight of plantscomprises of(1) Nitrogen, phosphorus and potassium(2) Calcium, magnesium and sulphur(3) Carbon, nitrogen and hydrogen(4) Carbon, hydrogen and oxygen

112. During cell enlargement phase of growth, moleculesof new cell wall material are inserted between theoriginal molecules of stretched wall. This process isknown as(1) Integration (2) Apposition(3) Intussusception (4) None of these

113. Which one of the following pairs of plants are notseed producers?(1) Fern and Funaria(2) Funaria and Ficus(3) Ficus and Chlamydomonas(4) Punica and Pinus

114. The substrate for photorespiration in C3 plants is(1) Phosphoglycerate(2) Glycolate(3) Glycerate(4) Glycine

115. The role of PS-II in photosynthesis is(1) To reduce NADP to NADPH(2) To cause photolysis of water(3) To release oxygen(4) Both (2) & (3)

116. The tip of an etiolated stem is subjected to unilaterallight, it will(1) Not respond to light(2) Bend towards light(3) Bend away from light(4) Stop growing further

[11]

117. Movement of auxin is(1) Centripetal(2) Basipetal(3) Acropetal(4) Both basipetal and acropetal

118. In 1943, the causal organism and host of Bengalfamine was(1) Blast of rice by Xanthomonas oryzae(2) Wheat rust by Puccinia graminis(3) Blast of rice by Piricularia oryzae(4) Brown leaf spot of rice by Helminthosporium

oryzae119. Decline in quantum yield was noticed by Emerson at

a wavelength of(1) 400–500 nm (2) 600 – 650 nm(3) 650 – 680 nm (4) More than 680 nm

120.The waxy material deposited in the casparian stripof the endodermis is(1) Pectin (2) Suberin(3) Cellulose (4) Lignin

121.Tyloses are formed by(1) Ray parenchyma and xylem parenchyma cells(2) Ray parenchyma only(3) Collechyma(4) Phloem cells

122.Versatile anthers are found in(1) Brassica (2) Ranunculus(3) Passiflora (4) Grasses

123.The length of different internodes in a culm ofsugarcane is variable because of

(1) Shoot apical meristem(2) Position of axillary buds(3) Size of leaf lamina at the node below(4) Intercalary meristem

124.When a plant cell is placed in a solution which ishypotonic to the cell sap, which of the followingconditions will not apply ?(1) The cell will become turgid(2) The water potential of the cell sap will rise(3) The suction pressure of the cell sap will fall(4) The wall pressure of the cell will fall

125.When unidirectional light is given to the shoot apexand the root apex they show positive and negativephototropic curvature. This is because(1) The shoot and the root tips respond differently

to the same concentration of auxin(2) The roots are underground whereas the shoots

are aerial(3) The concentration of auxin is more in the darker

half in the shoot tip but is more in the illuminatedhalf in the root tip

(4) Auxins are denatured in light126.Sexual reproduction in Spirogyra is an advanced

feature because it shows(1) Different sizes of motile sex organs(2) Same size of motile sex organs(3) Morphologically isogamy(4) Physiologically heterogamy

127.Hill reaction occurs in(1) High altitude plants(2) Total darkness(3) Absence of water(4) Presence of ferricyanide

128. In plants a common symptom caused by deficienciesof P, K, Ca and Mg is(1) Bending of leaf tip(2) Formation of anthocyanin(3) Poor development of vasculature(4) Appearance of dead necrotic areas

129.The transfer of electrons in the light phase ofphotosynthesis occurs from(1) Lower electronegative potential to more

electronegative potential(2) Higher electronegative potential to lower

electronegative potential(3) Lower electropositive potential to higher

electropositive potential(4) Electropositive potential to electronegative

potential130. In which of the following the R.Q. decreases first

and then increases?(1) Germinating wheat grains(2) Ripening banana fruits(3) Germinating peanuts(4) Germinating castor seeds

[12]

131.The importance of microelements was recognisedrather late because(1) They are toxic to plants(2) They were lost by plants through the root -

system(3) Physiologists could not find them in plants(4) They were available to plants as contaminants

of the salts132.Streaming of protoplasm is known as

(1) Nutation (2) Circum nutation(3) Nasty (4) Cyclosis

133.Early experiments on phytohormones wereperformed by Darwin in(1) Podophyllum (2) Phragmites(3) Phalaris (4) Poinsettia

134.Examples for lateral meristems are(1) Phellogen and procambium(2) Fascicular cambium and procambium(3) Procambium and dermatogen(4) Fascicular cambium and cork cambium

135.Which of the following co-factors are used duringthe formation of Acetyl –CoA ?(1) CoA, TPP, Mg++

(2) CoA, Mg++, NAD+

(3) CoA, TPP, NDA+, Mg++

(4) CoA, TPP, NAD+, Mg++, Lipoic acid136.The absorption of water and ascent of sap in plants

is(1) Symplastic in all cells(2) Largely apoplastic in nature(3) Apoplastic and symplastic respectively(4) Symplastic and apoplastic respectively

137. Independent sporophyte and small independentgametophyte is the characterictic feature of(1) Mosses and other bryophytes(2) Ferns and other seedless vascular plants(3) Gymnosperms(4) Angiosperms

138.Eyes of potato are(1) Apical buds (2) Extra-axillary buds(3) Axillary buds (4) Adventitious roots

139.Which is the odd type of vegetable in a basketcontaining the following ?(1) Carrots (2) Radishes(3) Beet roots (4) Potatoes

140.Thorns are called modified stem because(1) They arise from the axil of leaves(2) They arise from branches(3) They arise from tips of stem(4) They arise from plumule

141.Leaf apex is mofified into a tendril in(1) Gloriosa (2) Smilax(3) lathyrus aphaca (4) Pisum sativum

142.Origin of stem branches is(1) Exogenous(2) Endogenous(3) Superficial(4) Partly superficial and partly endogenous

143.Transpiration–Cohesion tension theory operates in(1) Passive absorption(2) Active absorption(3) Both active and passive absorption(4) None of these

144.All the following involves osmosis except(1) Water from the soil entering a root hair(2) Water passing from a root hair to adjacent cells(3) Water passing up a xylem vessel element to

xylem vessel element above it(4) Water entering a mesophyll cell from the xylem

vessel element145.A cell is plasmolysed after being kept in a hypertonic

solution. What will be present between cell wall andthe plasmalemma ?(1) Air or water(2) Hypertonic solution(3) Hypotonic solution(4) Isotonic solution

146.Cut flowers are dipped by their bases in dilute sodiumchloride solution to(1) Reduce bacterial growth(2) Reduce transpiration(3) Induce endosmosis(4) Increase solute inside flowers

147.When a molecule of pyruvic acid is subjected toanaerobic oxidation and forms lactic acid there is(1) Gain of 2 ATP molecules(2) Gain of 4 ATP molecules(3) Loss of 3 ATP molecules(4) Loss of 6 ATP molecules

[13]

148. In respiration pyruvic acid is(1) A result of protein break down(2) Formed only when oxygen is available(3) One of the produce of Krebs cycle(4) Broken down into a two carbon fragment and

carbon dioxide149.Which one of the following are the largest families in

dicots and monocots ?(1) Malvaceae and Leguminosae(2) Poaceae and Brassicaceae(3) Asteraceae and Orchidaceae(4) Solanaceae and Poaceae

150.Blakman demonstrated that increasing illumination,increased the photosynthetic rate up to point whenCO2 becomes limiting. If light was not limiting,temperature becomes limiting. Emerson found thatmaximum CO2 fixation could be achieved with briefflashes of light. Mark the correct statement in thefollowing(1) The trapping of light by chloroplast is temperature

dependent(2) The trapping of light by chloroplast can occur if

CO2 is present(3) Only one factor can be limiting in photosynthesis(4) Photosyntheis consists of a light and dark

reaction151.Which of the following is a least harmful fat for

heart?(1) Poly unsaturated fats(2) Mono-unsaturated fats(3) Saturated fats(4) Chylomicron

152.Glenoid cavity is found in(1) Pectoral girdle (2) Pelvic girdle(3) Femur (4) Lower jaw

153.Which of the following disease is caused is due tohypothyroidism ?(1) Mixoderma (2) Cretinism(3) Both of these (4) Expothalmic goitre

154.Pepsinogen is secreted by one of the following cells(1) Paneth cells (2) Pantal cell(3) Chief cell (4) Acener cells

155.Haematuria is(1) Presence of haemoglobin in urine(2) Presence of blood cells in urine(3) Presence of pus cells in urine(4) Increased amount of urea in urine

156. In free living protozoans the type of nutrition is(1) Saprozoic (2) Holozoic(3) Parasite (4) Autotrophic

157.Respiratory pigment remain dissolved in the blood in(1) Cockroach (2) Fish(3) Earthworm (4) Ascaris

158.The type of enzymes found in digestive juice are(1) Hydrolytic (2) Lyase(3) Oxido-reductase (4) Transferase

159.Which of the following diasaccharide exhibit differentlinkage ?(1) Cellulose (2) Glycogen(3) Amylose (4) Starch

160.Oxygen haemoglobin dissociation curve is(1) Sigmoid (2) Hyperbola(3) Parabola (4) Elipse

161.Eye lense consists of which type of protein(1) Crystalline protein(2) Cellulase(3) Collagen(4) None of these

162.Differentiated cell arrests at(1) G

1(2) G

2

(3) S (4) G0

163.Testosteron is secreted by(1) Lydig cells (2) Sertoli cells(3) Kuffer cells (4) Paneth cells

[14]

164., and cells in islets of langerhans secretes(1) Insulin, glucagon, somatostatin(2) Insulin, somatostatin, glucagon(3) Glucagon, insulin, somatostatin(4) Glucagon, somatostatin, insulin

165. If a part of cell is discharged along with secretion itis called(1) Apocrine (2) Merocrine(3) Endocrine (4) Exocrine

166.Effortless volume in breathing is(1) Residual volume (2) Inspiratory volume(3) Vital capacity (4) Tidal volume

167.Vital capacity is(1) TV + IRV - ERV + RV(2) TLC - RV(3) ERV + TV + RV(4) IC + FRV

168.Chloride shift is(1) Expulsion of HCO3– and Cl– from RBC(2) Expulsion of HCO3– from RBC and Cl–

into RBC(3) Passage of HCO3– and Cl– in the RBC(4) Passage of Cl– from RBC and HCO3– into

RBC169.Oil in the plant cell is stored in

(1) Alurinoplast (2) Amyloplast(3) Leucoplast (4) Elioplast

170.Reasoning, intelligence, insight, creativity etc. areassociated with(1) Frontal lobe (2) Parital lobe(3) Oxypetal lobe (4) Temporal lobe

171.Which one produces immunoglobulin ?(1) Lymphocytes (2) Monocytes(3) RBC (4) Macrophage

172.Receptor for peptide hormone is present on(1) Transmembrane protein(2) Intrinsic protein(3) Extrinsic protein(4) Integral protein

173.Which one of the following is responsible forbalancing ?(1) Choclea (2) Organ of Corti(3) Vestibule (4) All of these

174.The synaptic vesicles are present in(1) Presynaptic membrane(2) Postsynaptic membrane(3) All of these(4) Schwan cells

175.Match the bones with their originColumn A Column B(a) Malleus (i) Articular bone(b) Incus (ii) Quadrate bone(c) Stapes (iii) Hyomendibular bone(1) a-i, b-iii, c-ii(2) a-ii, b-iii, c-i(3) a-i, b-ii, c-iii(4) a-iii, b-i, c-ii

176.Lapto-meaninges refers to(1) Fused Duramater and Arachnoid(2) Fused Arachnoidmater, duramater and piamater(3) Fused Arachnoidmaterand piamater(4) Fused Duramater and piamater.

177.Study of life outside the earth is called(1) Ethology (2) Ethanology(3) Exobiology (4) None of these

178.Protein deficiency leads to(1) Kwasiorker (2) Marasmus(3) Scurvy (4) Pellegra

179.Vitamin responsible for blood coagulation(1) Vit. A (2) Vit. B(3) Vit. C (4) Vit. K

180.Microtubules consists of(1) 9 + 2 microfilaments(2) 9 + 0 microfilaments(3) 12 microfilaments(4) 13 microfilaments

[15]

181.Which one of the following is osmoregulatory inshark?(1) Urea (2) Uric acid(3) NH3 (4) All of these

182.Transverse binary fission occurs in(1) Euglena (2) Paramecium(3) Leishmania (4) None of these

183. cells of Dieter’s, Pillars, and Hensen’s are found in(1) Nasal epithelium (2) Corti’s organ(3) Taste buds (4) Retina

184.A polysome is formed by attachment of manyribosomes with(1) Single mRNA (2) DNA(3) Proteins (4) None of these

185.Steroidal hormones are synthesised in(1) RER (2) Cytoplasm(3) Golgi (4) SER

186.Disc shaped structures present on the sides ofcentromeres in a chromosome are(1) Ribosomes (2) Centrioles(3) Basal body (4) Kinetochores

187.Ribosomes are non-membrane bound organelles thatcould be found in(1) Cytoplasm only(2) Cytoplasm and chloroplast(3) Cytoplasm, chloroplast and mitochondria(4) None of these

188. Identify the type of intercellular junction betweenanimal cells(1) Plasmodesma (2) Desmosome(3) Glycocalyx (4) Middle lamella

189.Synaptonemal complex during meiosis occurs during(1) Prophase I – Leptotene(2) Prophase I – Zygotene(3) Prophase I – Diplotene(4) Metaphase I

190.Given below is a pair of mono and poly-unsaturatedfatty acids(1) Oleic and palmitic acid(2) Oleic and linolenic acid(3) Stearic and oleic acid(4) Linoleic and lino-lenic acid

191.One of the following is the simplest amino acid(1) Tryptophan (2) Lysine(3) Leucine (4) Glycine

192.A glycosidic bond between two monosaccharides isformed by(1) Dehydration (2) Deamination(3) Decarboxylation (4) None of these

193.Centromeres split and the chromatids separateduring(1) Interphase (2) Metaphase(3) Anaphase (4) Telophase

194.One of the following is a substituted methane ?(1) Glycerol (2) Glucose(3) Amino acid (4) Fatty acid

195.The property of an amino acid depends on its(1) Amino group (2) R group(3) Carboxyl group (4) All the above

196.Nissl’s granules are found in(1) Axon (2) Synapse(3) Cyton (4) Telodendrites

197.Glass like cartilage is(1) Hyaline cartilage(2) Fibro cartilage(3) Calcified cartilage(4) Elastic cartilage

198.Z - line divides(1) A - band into two

(2) I - band into two

(3) A and I bands into two

(4) None of these

199.Osteoclast cells are

(1) Bone forming cells(2) Bone dissolving cells(3) Bone joining cells(4) None of these

200.Deamination takes place in(1) Spleen (2) Liver(3) Kidney (4) Stomach

ANSWERS

Physics

1. (2) 2. (2) 3. (3) 4. (1) 5. (4)6. (2) 7. (3) 8. (4) 9. (2) 10. (1)

11. (4) 12. (3) 13. (3) 14. (2) 15. (2)16. (3) 17. (2) 18. (1) 19. (2) 20. (3)21. (1) 22. (2) 23. (3) 24. (3) 25. (4)26. (1) 27. (2) 28. (2) 29. (4) 30. (2)31. (3) 32. (1) 33. (2) 34. (3) 35. (2)36. (3) 37. (4) 38. (4) 39. (1) 40. (1)41. (3) 42. (4) 43. (2) 44. (3) 45. (1)46. (4) 47. (4) 48. (2) 49. (1) 50. (2)

Chemistry

51. (4) 52. (4) 53. (4) 54. (2) 55. (3)56. (3) 57. (4) 58. (4) 59. (3) 60. (3)61. (2) 62. (2) 63. (1) 64. (3) 65. (1)66. (1) 67. (2) 68. (1) 69. (2) 70. (3)71. (3) 72. (3) 73. (3) 74. (1) 75. (3)76. (4) 77. (2) 78. (2) 79. (1) 80. (4)81. (4) 82. (1) 83. (1) 84. (3) 85. (3)86. (2) 87. (2) 88. (1) 89. (4) 90. (3)91. (3) 92. (2) 93. (2) 94. (1) 95. (3)96. (4) 97. (2) 98. (2) 99. (2) 100. (2)

Botany

101. (1) 102. (3) 103. (3) 104. (3) 105. (1)106. (4) 107. (3) 108. (1) 109. (3) 110. (3)111. (4) 112. (3) 113. (1) 114. (2) 115. (4)116. (2) 117. (4) 118. (4) 119. (4) 120. (2)121. (1) 122. (4) 123. (4) 124. (4) 125. (1)126. (4) 127. (4) 128. (4) 129. (4) 130. (3)131. (4) 132. (4) 133. (3) 134. (4) 135. (4)136. (2) 137. (2) 138. (3) 139. (4) 140. (1)141. (1) 142. (1) 143. (1) 144. (3) 145. (2)146. (1) 147. (4) 148. (4) 149. (3) 150. (4)

Zoology

151 (1) 152 (1) 153 (3) 154 (3) 155 (2)156 (2) 157 (3) 158 (1) 159 (1) 160 (1)161 (1) 162 (4) 163 (1) 164 (3) 165 (1)166 (4) 167 (2) 168 (2) 169 (4) 170 (1)171 (1) 172 (1) 173 (3) 174 (1) 175 (3)176 (3) 177 (3) 178 (1) 179 (4) 180 (4)181 (1) 182 (2) 183 (2) 184 (1) 185 (4)186 (4) 187 (3) 188 (2) 189 (2) 190 (2)191 (4) 192 (1) 193 (3) 194 (3) 195 (2)196 (3) 197 (1) 198 (2) 199 (1) 200 (2)

1. (2) By Stefan’s law, 4 , E T is Stefan’s constnat

4 4

sec( )

E energy radiated per ond per unit area

T Temperature in kelvin

Unit of Stefan constant,

4

unit of energyis unit of area unit of timeunit of Temperature in K

= 2 42 4

1 / Joule Watt m Km S K

2. (2) (2 1),2

nthaS u n for a body falling under gravity a = g

(2 1)2

nthgS u n

First case : n = 3, 31010 (2 3 1) 352

rdS m

2nd case : 2102 10 (2 2 1) 252

ndn S m

S3rd : S2nd = 35 : 25 or S3rd/S2nd = 7/5

3. (3) We know that, work done, .

W F S

ˆ ˆˆ ˆ ˆ ˆ6 3 2 . 4 2 3 i cj k i j k

6 = –12 + 2 c + 6 2c = 12; c = 6

4. (1) Since velocity of both particles in vertically downward direction is zero and both are under the effect ofgravity and are accelerated with ‘g’ therefore, both the particles reach the grand simultaneously, since theycover same height under similar condition in vertical direction.

5. (4) Using Kepler’s 3rd law 2 3T r32 3

1 1 12 3

2 2 2

1 1;4 64 8

T R TRT R R T

2 18 8 T T T

6. (2) Resultant force = Force applied – Force of friction = 100 – mg = 100 – 0.5 × 10 × 10 = 50 N

a = 2Re tan 50 510

sul t force ms

mass

7. (3) ( ) 1000(9.8 1) 1000 10.8 10800 T M g a N

8. (4) According to principle of conservation of angular momentum, when the child sits on the rotating disc,moment of inertia changes, so angular velocity also must change so as to keep angular momentum unchanged,as there is no torque acting on the system.

SOLUTIONS

9. (2) Initial gravitational Potential Energy is 1

U eGM mR

=2

2( ) e

gR m mgR GM gRR

Final gravitational potential Energy = 2 (3 )

eGM mUR R

=2

4 4 4

eGM m gR m mgRR R

Change in Potential Energy = U2 – U1

=3( )

4 4

mgR mgRmg R

10. (1) Using conduction formula

1 2( )KA tQd

for first rod, 1 1 1 1 2( )dQ K Adt l

for 2nd rod, 2 2 1 1 2( )dQ K Adt l

As 1 2 1 1 1 2 2 2 1 2( ) ( ),dQ dQ K A K Adt dt l l

K1A1 = K2A2

11. (4) 11

2 mtk ...(i)

22

2 mtk ...(ii)

For springs in parallel k = k1 + k2

and 2 mtk

...(iii)

where k = k1 + k2 ...(iv)From (i), (ii) and (iii)

2 2 2

1 22 2 21 2

4 4 4;

m m mk and k kt t t

Puting in (iv)

2 2 2

2 2 21 2

4 4 4

m m mt t t or 2 2 2

1 2

1 1 1

t t t

or 2 2 21 2

t t t

12. (3) The standard equation of an equation travelling along positive direction of x-axis is

2sin ( )

y A vt x

here A = 0.2 m, v = 360 m/s = 60 m

20.2sin (360 )60

y t x

= 0.2sin 2 (6 )60

xt

13. (3) For tube A, open at both ends, fundamental frequency, 2

Avnl

For tube B, closed at one end, fundamental frequency, 4

Bvnl

4 22 1

A

B

n v ln l v

14. (2) Frequency of known tuning fork is 288 cpsNumber of beats/s = 4Therefore possible frequency of unknown tuning fork is 288 ± 4 = 292 or 284On putting little wax on unknown tuning fork, its prongs become heavier, time period increases frequencydecreases.The tuning fork will produce two beats only if the frequency unknown is 292.

15. (2) The equation y = a sin(t – kx) –(1) represents the equation of wave travelling along positive direction ofx-axis.The equation of wave travelling along negative x-axis is eithery = a sin(t + kx) and y = – a sin(t + kx)Since at x = 0 should give a nodeThis is possible if y2 = – a sin(t + kx) is superimposed on y1 = a sin(t – kx)

y1 + y2 = y = asin(t – kx) – a sin(t + kx) = 2a cos t sin kx. ( 0; 0 ) x y Node

16. (3) By conservation of angular momentum2

1MR

2 = (M/2 + 2m)R2 2

12 ( 4 )

M

M m

17. (2) 12 2 10 20 20 effluxv gh ms

18. (1) When the body is in equilibrium with F1, F2 and F3 acting on body. If F1 is removed F2 and F3 together havethe same effect as F1. Therefore a = F1/m

19. (2) Let F1 be smaller force, then F2 = 18 – F1 then from figure2 2 2

2 1 F F R

Or (18 – F1)2 = F12 + 12

2

328 + F12 – 36 F1 = F1

2 + 14436 F1 = 324 – 144 = 180, F1 = 5N

and F2 = 18 – 5 = 13 N

RF2

F2

F1

20. (3) 1 2 1 1 v vmix

n n C T n C T + n2(Cv)2 T

1 21 2

1 2

v v

v mix

n C n CC

n n

Now, 1

vRC

1 25 3( ) ; ( )2 2

v vR RC C

( ) 2v mixC R

31

( ) 2 mix

v mix

RC

21. (1) 4 41 1 1 2 2 2, E A T E A T

4 2 41 1 1

4 2 42 2 2

4 (1) (40000) 1 256 14 (4) (2000) 16 16 1

E A TE A T

22. (2) F = 24C B A2kg 2kg 2kg

Common acceleration = 224 46

ms

Tension between B and C is = 2a = 2 × 4 = 8N

23. (3) 21 2 3 1

1, 2 10 1002

S S S S S m

2 2 1 2( ) 2 10 30 600 S vt at t m

2 2 2 2

30 0 (2 10) 502( ´) 2( 4)

vS ma

S = S1 + S2 + S3 = (100 + 600 + 50) m = 750 m

24. (3) , Q U W mL

1 2240 168 U or 2072 U J25. (4) Since Wien’s displacement law states m T = b = constant

T = constant

26. (1)800 330´ 733.33330 30

cv v

c vHz

27. (2) In uniform circular motion only the magnitude of velocity (or speed remains unchanged, velocity vector andacceleration cector change KE alone remains constant in uniform circular motion

28. (2) First law of thermodynamics tells that heat and work are interconvertible according to the relation w = JQ,on the basis of law of conservation of energy.

29. (4) For an adiabatic change Pv = constant, Also PV = RT, to obtain relation between P and T, weeliminate V,

Putting RTVP

in PV = constant

we have

RTPP = constant

1 tan

cons tP TR

= constant

30. (2) Maximum particle velocity = 0 2 VY A

Now, 0 2 2VY V

0Y

31. (3) y(t) = 2t2 + 3t + 4y(0) = 4, y(3) = 2(32) + 3 × 3 + 4 = 31

=( ) ( (0) (3) (0) 31 4

0 3 0 3y t y y y

t

= 27 9 /3

m s

32. (1) By Bernoulli’s Theorem 21 1

12

AP v gh

=22 2

12

BP v gh

or 2 22 1 2 1

1( )2A BP P g h h v v

Volume of liquid flowing per second throughA = A1 v1 = 12 cm3

or 6 × 10–2 × v1 = 12, v1 = 200 ms–1

From equation of continuity A1v1 = A2v2

or11 1

2 122

12 4003 10

A vv cmsA

For water, = 1 gm/cc

2 211 1000(100) 1 [(400) (200) ]2A BP P

= 5 4 5 4110 12 10 10 6 102

= 1.6 × 105 dyne/cm2

33. (2) In an inelastic collision only momentum is conserved, K.E. is not conserved.34. (3) X = 3 sin20 t + 4 cos 20 t

Put 3 = A cos , 4 = A sin32 + 42 = A2 (cos2 + sin2); A = 5 x = 5 sin t cos + 5 cos 20 t sin

= 5[sin (20 t + )]. Amplitude is 5.

35. (2)1; 5

0.2l

l

rad/S2

03602 ( 5) 360

t

12 × 3.14 – 15 = 37.68 – 15 = 22.68 rad/s

36. (3)1 2

1 2

10 6 410 10 2.510 6 16

M Ma gM M

ms–2

37. (4) F v F kv

or1 1 2

1 0 11 1

[ ][ ][ ]F M LTk M L TV LT

38. (4)2

, 3mvT mg T mgr

2

23 ; 2mvmg mg v grr

, Also v2 = 2gh

h = r (1 – cos), Since h = r1 – cos = 1, cos = 0, = 90°

39. (1) 3dvF ma mv xdx

10

0 2

38 38

v xv dv x dx vdv dx

102 22 2 2

2

3 3; (10 2 ) 362 8 2 8v x v

v = 6 ms–1

40. (1) 2 2

sin sin 30 5 1 52 7 2 141 / 15

g ga g gk r

41. (3) 2 21

1100 (2 10 )2

W k

2 22 2

2221

1 14 10 2 102 2

1 2 102

k kWW k

22

16 4 3, 300100 4W W J

42. (4)1 2

2 2 21 1 2 1

4 44 ; ;A BF L F LFL FLY Y YAl D l D l D l

1 2

2 21 1 2 2

A BF L F LD l D l

or2 2

2 1 12 2

1 1 2

2 (2) 811 (1) 1

A

B

F L D lF L D l

43. (2) Network done by the system is area of closed curve = Pdv = 100 kP (200 CC)= 100 × 103 × 200 × 10–6 J = 20 JSince area of closed curve is anticlockwise, it is –ve W = –20 J

44. (3) N2

N1

v1

v2C

BA u

O60°30° An = h11

An = h2 2

2

cos mvT mgr

or 2cos 2mT mg u ghr

= 2 2 ( )(1 cos )m u g rr

or 2cos ( 2 2 cos )mT mg u gr grr

= 2 2 2 cosm u mg mgr

2

2 3 cosmuT mg mgr

2

1 2 3 cos30muT mg mgr

2

2 2 3 cos60muT mg mgr

1 2 3 (cos30 cos60 )T T mg

=3 13

2 2mg

= 3 mg (0.86 – 0.5) = 3 mg (0.36)= 1.08 mg T1 > T2

45. (1) Escape speed on a planet is ve = 2GM

R

on earth ve = 2GM

R, on planet, v e =

2/ 4

GMR

= 122 2 2 11.2 22.4eGM v KmsR

46. (4) Mass per unit length of the chain is M/L

Mass of small element of length dx at distance x from the edge of the table is M dxL

Work done in taking it on to the table is ( )Mdw dx gxL

Intergrating it from 0 ot 2L

, We have

/ 3

0 0

W LMgdw xdxL

x

dx

=/ 32 2

02 18 18

LMg x Mg L MgLL L

47. (4) K.E. of a particle executing as S.H.M is 12

mv2 where

2 24v a ; KE = 12

m 2 (a2 – y2)

when y = 2a

; KE = 12

m 2 2

2

4aa

= 2 21 32 4

m a

fraction of KE to total energy is 2 2

2 2

1 332 4

1 42

m a

m a

48. (2) In stationary waves energy is minimum at nodes and maximum at antinodes.49. (1) The body starts sliding with a constant velocity if the component of weight down the plane, mg sin equals

the force of friction, mg cos.

mg sin = mg cos or = tan = tan 30° = 13

50. (2)mdvF madt

2

2 6 4ˆ ˆ ˆ ˆ6 4 ;3 3

mdv dv t tt i t j i j

dt dt

or2ˆ6 4ˆ

3 3i t dt tdtdv j

2

0

4ˆ ˆ23

v tdv t dt i dt j

3 22 2ˆ ˆ3 3

t tv i j

at t = 3 sec

3 22 2ˆ ˆ ˆ ˆ3 3 18 63 3

v i j i j

51. (4)Suppose one molecule of the alkaloid contains x

N-atoms. Then % of 14 100 17.28162

xN (Given)

or x = 252. (4)

For 2 21 2

1 1,H v Rn n

For other atoms/ions, 2

2 21 2

1 1v R Zn n

For Li2+, v = 15200 × 32 = 136,800 cm–1

53. (4)

(2LP + 2 = 4) Cl

I Cl

+

Hybridization of I in ICl2+ is sp3.

54. (2)On compressing the gas, pressure increases and hence the collisions between the molecules increase.

55. (3)funS = fusH/Tf = (335 × 18)/273 = 22.1 JK–1 mol–1

56. (3)Equal volumes of different gases contain equal number of molecules at S.T.P. 500 ml of CO2 at S.T.P. will contain 6.00 × 1023 molecules 100 ml of CO2 at S.T.P. will contain

=236.00 10 100

500

= 1.2 × 1023 molecules.57. (4)

2

2nZE

n

E2 for He+ = –E2 for H × 22

= 3.41 × 4 = –13.64 eV58. (4)

When intensity is doubled, number of electrons emitted per second is also doubled but average energy ofphotoelectrons emitted remains the same.

59. (3)For PCl3,

1 [ ]2

X VE MA c a

=1[5 3 0 0] 42

Hybridization of P in PCl3 is sp3.For PCl5,

1[5 5 0 0] 52

X

Hybridization is sp3d.

60. (3)The bond angle is BF3 is 120° since is sp2 hybridized. In PF3, P is sp3 hybridized but the bond angle is little less than109°28 (but far greater than 90°) due to bond pair-lone pair repulsion. In ClF3, Cl is sp3d hybridized. It hasT-shape and hence the bond angle is around 90°. Therefore the correct order of increasing bond angle isClF3 < PF3 < BF3

61. (2)Amongst HF, HCl and HBr, boiling point of HF is the highest. Out of HCl and HBr, HBr has a higher boiling pointdue to increase in molecule size or molecular mas. Or Vanderwaal-force.

62. (2)Average kinetic energy depends only on temperature and does not depend upon the nature of the gas.

63. (1)

Energy releasedEnergy absorbed

H|

N N 3H H 2N H|945 3 436 H

2253 kJ 2 (3 391) 2346

Net energy released = 2253 – 2346 = – 93 kJi.e., DH = –93 kJ

64. (3)Calculated value heat of dissociation of

C

C C C

H

HH

H H

H

= 3(C – C) + 3 (C = C) + 6(C – H)= 3 × 347.3 + 3 × 615.0 + 6 × 416.2= 1041.9 + 1845 + 1497.2 = 5384.1 kJResonance energy = Experimental value– Claculated value= 5535.0 – 5384.1 = 150.9 = 151 kJ

65. (1)Heat produced from 5g coke = 1 × 37 = 37 kcal Heat produced from 1g coke = 37/5 = 7.4 kcal

66. (1)As K decrease with increase of temperature, the reaction is exothermic.

67. (2)Endothermic reaction is favoured by increase of temperature

68. (1)

56 656g N 2 moles, 6g H 3 moles2 228 2

327.5427.54 g NH 1.62 moles

17

2 2 3N 3 H 2NH

Initial moles 2 3 0At. eqm. 2–0.81 3–2.43 1.62

= 1.19 = 0.57

2

c 3

1.62K 11.9

1.19 0.57

69. (2)As HNO3 is the strongest acid, its conjugate baseNO3

– is the weakest base70. (3)

SnCl2 and SiCl4 have empty d-orbitals and AlCl3 has Al with incomplete octet. Hence, they are Lewis acid, inCCl4 absence of empty d-orbital. i.e., CCl4 do not act as a Lewis acid.

71. (3)

N HCl has also pH 2100

72. (3)At 25°C, pKw = 14

73. (2)NH4OH + HCl forms NH4Cl which gives acidic solution with pH < 7

74. (1)With lowerst Ksp value

75. (3)By definition of Buffer solution

76. (4)For salt of weak acid, weak like

3 4 a b1CH COONH , pH 7 [pK pK ] 72

a bK K

Hence, solution is neutral77. (2)

Because of diagonal relationship78. (2)

Na+ and F– ions are isoelectronic, therefore, F– has the largest and Na+ has the lowest size. Further, Al with highernuclear charge has lower size than Mg. Thus, the overall order isNa+ < Al < Mg < F–

79. (1)

03 2 2

1 5I IO H I H O

(i) 022I I 2 i.e. increase in O.N. = 2

(ii) 03 2

52IO I

10 i.e. decrease in O.N. = 10

To make increase in O.N. = decrease, multiply equation (i) by 5 and add. Hence

3 210I 2IO 6I

To balance O atoms, add. 6H2O on RHS. Hence

3 2 210I 2IO 6I 6H O

To balance H atoms, add 12H+ to LHS. Hence

3 2 210I 2IO 12H 6I 6H O

or 3 2 25I IO 6H 3I 3H O

80. (4)2KMnO4 + 3H2SO4

K2SO4 + 2MnSO4 + 3H2O + 5(O)

4 2 4 2 4 3 2

4 2 4 4

[2FeSO H SO (O) Fe (SO ) H O] 52KMnO 8H SO 10FeSO Products

1 1 2 2

1 2

M V M Vn n

(KMnO4) (FeSO4)

11 1 2 2

2

n 2 1 1M V M V 10n 10 10 5

1 11M V 0.02 105

81. (4)

For the given reaction 2 3

50I 2IO

change in oxidation number of I2 = 10

Eq. wt. = M/1082. (1)

2-Ethyl anthraquinol 2O 2-ethyl anthraqinone + 2H2O2

83. (1)Cr2(SO4)3 + 3H2O2 + 10 NaOH

2Na2Cro4 + 3Na2SO4 + 8H2Oor 2Cr3+ + 3H2O 10OH– 2CrO4

2– + 8H2O84. (3)

K2Cr2O7 + H2SO4 + 4H2O2 K2SO4 + 2CrO5 + 5H2OCrO5 is peroxide of Cr which dissolves in ether producing blue colour

CrOO

OO

O85. (3)

Cs+ is least hydrated and hence has the highest mobility86. (2)

Li is least reactive due to high ionization enthalpy87. (2)

There are six B–N, three B–H and three N–H sigma bonds and three B–N pi bonds in borazole88. (1)

Colourless salt (i.e, Al2(SO4)3) will not give borax bead test89. (4)

The thermal stabilities of the hydrides of carbon family decrease down the group as is evident from their thermaldissociation temperaturesCH4 SiH4 GeH4 SnH4 PbH4

1073K 723K 558K 423K 273KThus plumbane (PbH4) gives H2 even at 273 K and hence has the maximum reducing character while CH4

decomposes only at a very high temperature (1073K) and hence has the least reducing character90. (3)

O

OHC COOH

4-Formyl-2-oxocyclohexanecarboxylic acid91. (3)

The enol content is much higher (76%) in acetylacetone than in ethyl acetoacetate (8%)

92. (2)Total number of isomers = 7(i) Acyclic isomers are : CH3COCH3,CH3CH2CHO, CH2 = CHCH2OHCH2 = CH – OCH3

(ii) Cyclic isomers are :

O OCH3

OHH

93. (2)

p-NO2–C6H4 – 2CH

is the least stable carbocation since electron withdrawing – NO2 group destabilizes the

carbocation94. (1)

Smaller the value of 0H , more stable is the carbocation. Since the stabilities of carbocations follows the order

3 3 3 2 3 2 3(CH ) C (CH ) CH CH CH CH

therefore, enthalpies of ionization increase in the reverse order, i.e., 0 0 0 01 2 3 4H H H

95. (3)For the stronger acid, its carbanion are more stable and vice versa(Stability of carbanion also depends disperson of its charge)PKa – 6 5 3 4HC CH(25), (C H ) CH(31.5),CH (48)

3 3(CH ) CH( 51) . Thus, (CH3)3C– is the least stable carbanion96. (4)

CH = C = C – CH = CH2 2

(i) O3

(ii) Zn/H2O

CH3

2HCHO + CO2 + CH3COCHO97. (2)

Mark3 3 addn.

3

CH C CHCH HCl|CH

3 2 3

3

Cl|

CH C CH CH|CH

2–Methyl–2–butene 2–Chloro–2–methylbutane

98. (2)Since both gases P and Q decolourise aqueous Br2 solution, therefore, both are unsaturated. Since one of themgives a white ppt. with ammoniacal AgNO3 solution, while the other does not, therefore, one of them is a terminalalkyne (but-1-yne) while the other is a non-terminal alkyne (but-2-yne).

99. (2)More stable the compound, lower is the heat of hydrogenation. Thus, benzene has the lowest heat of hydrogenation(–208.36 kJ mol–1) as compared to others due to resonance stablization and aromaticity.

100. (2)6 5 2(C H COO)

3 2CH CH C CH HBr 3 2CH CH CH CHBr