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1
Hydrocarbons: Alkanes, Alkenes and Arenes
1 By the use of a suitable example of each mechanism, compare and contrast
those reactions classified as electrophilic substitutions and those classified as
electrophilic additions. You should include in your answer:
(a) the reagents used and their function;
(b) the reaction conditions used;
(c) the products formed;
(d) the mechanism of each reaction;
(e) how the structure of a molecule determines the mechanism. [10]
2 (a) Suggest the identities of the intermediates and the final products obtained
when but-2-ene reacts with:
(i) steam, using a phosphoric acid catalyst at 300°C, 60 atm;
(ii) bromine in an inert organic solvent, followed by hot ethanolic
potassium hydroxide. [4]
(b) When an alkene reacts with an excess of hot aqueous potassium
manganate(VII), the carbon-to-carbon double bond is broken and the
terminal carbon atoms are oxidised to the maximum extent possible
without breaking a carbon-to-carbon single bond. Thus propene
undergoes the following reaction.
CH3CH=CH2CCH3
O
OH
+ CO2
KMnO4(aq)
heat
Predict the carbon-containing products obtained by subjecting each of the
following alkenes to the above conditions:
(i) CH3CH2CH=CH2;
(ii) (CH3)2C=CH2. [3]
(c) When each of the above two alkenes is treated with cold dilute potassium
manganate(VII), milder oxidation takes place. Draw the structure of the
organic product formed in each case and identify on your formulae any
chiral carbon atoms. [3]
2
3 Methylbenzene is required on a large scale both as an industrially important
organic compound and also because it is added to high grade unleaded
petrol/gasoline.
CH3
methylbenzene
(a) Write an equation for the combustion of methylbenzene. [1]
Methylbenzene is manufactured by passing n-heptane, CH3(CH2)5CH3, vapour
over a catalyst. In the process, there is one gaseous product.
(b) Construct a balanced equation for this process, showing the structural
formulae of the organic molecules. [2]
(c) The reaction is endothermic. Explain what conditions of temperature
would favour a high equilibrium yield. [2]
(d) Use the equation in (b) to explain what conditions of pressure would
favour a high equilibrium yield. [2]
(e) 1,4-dimethylbenzene can be produced by a similar process. Suggest the
structural formula of a C8 alkane to produce 1,4-dimethylbenzene. [1]
4 (a) Linoleic acid is an essential fatty acid in human diet.
CH3(CH2)4CH=CHCH2CH=CH(CH2)7CO2H
linoleic acid
In linoleic acid, both double bonds are in the cis configuration.
Representing the formula by the abbreviated structure
A-CH=CH-CH2-CH=CH-B, draw the displayed formulae of linoleic acid and
the other possible cis-trans isomers with this structure. [4]
3
(b) Geraniol is an alcohol used in perfumery.
(CH3)2C=CHCH2CH2C(CH3)=CHCH2OH
geraniol
On oxidation of geraniol with hot acidified aqueous potassium
manganate(VII), three products are initially obtained: P, C3H6O,
Q, C5H8O3, and R, C2H2O4.
(i) Geraniol has two double bonds. How many cis-trans isomers are
possible for geraniol?
(ii) Draw the structural formulae of P, Q and R.
(iii) Name the two functional groups in Q.
(iv) Continued heating with acidified potassium manganate(VII) causes
R to be further oxidised according to the following equation.
C2H2O4 2CO2 + 2H+ + 2e–
Make use of the Data Booklet to construct a balanced equation for
the reaction between R and acidified KMnO4(aq). [8]
5 Hex-3-ene occurs in two isomeric forms but cyclohexene occurs in only one form.
(a) Draw the displayed formulae of the two isomers of hex-3-ene and explain
why such isomerism is not possible in cyclohexene. [3]
(b) Describe the mechanism of the reaction between hex-3-ene and bromine.
Your account should
name the type of reaction undergone,
state the conditions of the reaction,
show the movement of electrons during the reaction,
include the formulae of the product and any intermediates. [4]
(c) Explain why the reaction of either isomer of hex-3-ene with hydrogen
bromide gives the same equimolar (1:1) mixture of two isomers of the
product. [2]
4
(d) The compound hex-3-en-1-ol, A, has a strong „leafy‟ smell of newly cut
grass and is used in perfumery.
A: CH3CH2CH=CHCH2CH2OH
Suggest the structural formulae of the compounds produced when A is
treated with an excess of hot concentrated KMnO4 in acid solution. [3]
Halogen Derivatives
6 (a) Describe the mechanism of the hydrolysis of bromoethane by aqueous
sodium hydroxide. [3]
(b) Suggest reagents, and describe the reaction conditions necessary, to
convert bromoethane into (i) CH3CH2NH2, (ii) CH3CH2CH2NH2. [5]
(c) A by-product in the formation of CH3CH2NH2 in (b) above has the formula
C8H20NBr and it gives an immediate precipitate with aqueous silver nitrate.
Suggest a structure for this compound. [2]
7 When the compound F, C6H5CH2Cl, reacts with hot ethanolic KOH, two products
are formed: compound G, C7H8O, and compound H, C6H5CH2OCH2CH3.
(a) (i) The hydroxide ion and ethanol can take part in an acid-base reaction.
Write an equation to represent it.
(ii) Suggest an identity for compound G and state the type of reaction
undergone by compound F, explaining how G and H are formed. [4]
(b) Suggest how the behaviour of compound F with hot ethanolic KOH differs
from that of C6H5Cl and from that of C6H5CH2CH2Cl. In each case, state
the type of reaction undergone (if any) and draw the structural formula of
the product. [3]
(c) Draw the structures of the products and intermediates derived from
compound F by reaction with:
(i) concentrated aqueous ammonia,
(ii) ethanolic potassium cyanide, followed by heating under reflux with
dilute hydrochloric acid. [3]
5
8 (a) 2-bromobutane can react with hydroxide ions under two different sets of
reaction conditions to give two different product mixtures C and D.
CH3CHBrCH2CH3
C4H10O
C4H8
(i) Describe the conditions necessary for each of the reactions I and II.
(ii) Product D is a mixture of three isomers, all of which decolourise
bromine water. Draw displayed formulae of these isomers and
explain the reaction with Br2(aq). [6]
(b) Explain the following observations as fully as you can.
compound observations after adding ethanolic AgNO3
CH3CHICH2CH3 precipitate forms almost immediately
CH3CHBrCH2CH3 precipitate forms after 2 minutes
CH3CHClCH2CH3 precipitate slowly forms after 10 minutes
CH3CHFCH2CH3 no precipitate forms
CH3CH=CClCH3 no precipitate forms
C6H5Cl no precipitate forms
[4]
9 An organic compound A has the following composition by mass: C, 35.1%; H,
6.6%; Br, 58.3%.
(a) Calculate the empirical formula of A. [1]
(b) When A is treated with aqueous alkali, 2-methylpropan-1-ol is formed.
Write an equation for this reaction, including displayed formulae of the
organic compounds. [2]
(c) (i) When A is refluxed with ethanolic potassium hydroxide, an alkene B
is formed. Give the displayed formula of B.
(ii) When B reacts with hydrogen bromide, a compound C is formed,
which is an isomer of A. Give the displayed formula of C. [2]
(d) C reacts with aqueous alkali to form an alcohol. How can this alcohol be
distinguished by a simple test from its isomer 2-methylpropan-1-ol? [2]
I
II
C
D
6
10 The volatile liquid Fluothane, CF3CHBrCl, is commonly used as an anaesthetic in
hospitals. It has the advantage that it does not readily react with sodalime (which
contains NaOH), used in closed anaesthetic systems to remove the CO2
breathed out by patients.
(a) Write an equation for the absorption of CO2 by NaOH. [1]
When Fluothane was being developed, it was tested to ensure it did not react
with NaOH. If it had reacted, bromide ions would have been produced.
(b) (i) Write an equation for a bromoalkane, e.g. RBr, reacting with aqueous
NaOH.
(ii) What type of reaction is this? [2]
(c) In an attempt to hydrolyse Fluothane, a mixture of Fluothane and sodalime
was stirred for an hour. It was then acidified and tested with the following
reagents.
Describe what you would expect to observe if bromide ions had been
produced, and write an equation in each case.
(i) aqueous silver nitrate
(ii) aqueous chlorine
(d) The attempted hydrolysis failed to break the C–Br bond in Fluothane. It
may be confidently assumed, therefore, that the other two types of C–Hal
bond in Fluothane also remain intact when hydrolysis is attempted.
Give a reason for the confidence of this assumption. [1]
Alcohols and Phenols
11 Alcohols A, CH3CH(OH)CH2CH3, and B, (CH3)3COH, are isomers.
(a) Draw the structural formula of one other alcohol isomeric with A and B. [1]
(b) What reagent and conditions would you use to dehydrate A and B to
alkenes? Draw the structural formulae of the three alkenes that are
obtained by dehydrating A. [3]
7
(c) Describe a reaction (reagent, conditions and observation) by which A
could be distinguished from B. [2]
(d) Draw diagrams to illustrate how A gives rise to optical isomerism. [2]
12 Archaeologists working on the preservation of the wreck of the English King
Henry VIII‟s warship, the “Mary Rose”, knew that wooden artefacts dry out
quickly.
(a) Why is it important that a wooden artefact in a museum should not dry
out? [1]
To prevent drying out, the object is impregnated with ethane-1,2-diol. Wood
consists of carbohydrate material containing many hydroxy groups.
(b) Suggest three reasons why ethane-1,2-diol is preferred to solvents such
as water, ethanol or hexane. [3]
(c) (i) Construct an equation for the synthesis of ethane-1,2-diol from
ethene.
(ii) What reagent is normally used in the laboratory to make ethane-1,2-
diol from ethene? [2]
13 Under suitable conditions, benzene and phenol both undergo substitution
reactions with chlorine.
(a) Describe the steps in the mechanism of the reaction between chlorine and
benzene. [2]
(b) How and why does the presence of the hydroxy group in phenol affect (i)
the conditions used for the reaction, (ii) the number of chlorine atoms
entering the ring? [3]
A mixture of trichlorophenols is used in aqueous solution as an antiseptic.
(c) Draw the structural formulae of 4 position isomers of trichlorophenol. [3]
(d) Predict, with reasons, whether trichlorophenol is a stronger or weaker acid
than phenol. [2]
8
14 Alkenes such as propene can be readily prepared from alcohols in a school or
college laboratory by using the apparatus below.
(a) (i) Give the full structural formula of an alcohol that can be used in this
apparatus to prepare propene. [1]
(ii) What type of reaction occurs in this case? [1]
(b) (i) Suggest why X needs to be heated strongly. [1]
(ii) During the reaction, the material X becomes black in colour. Suggest
the identity of the black substance and suggest how it is produced
during the reaction. [2]
(iii) At the end of the experiment, when no more propene is being
produced, the delivery tube is removed from water before the
apparatus is allowed to cool. Suggest why this is done. [1]
(iv) The material labelled X can be broken crockery, broken brick or
pumice. Give the chemical formula of a compound that is present in
one of these materials. [1]
(v) State another reagent that could be used to produce propene from an
alcohol. [1]
(c) Give the full structural formula of the organic product formed when
propene reacts separately with each of the following substances.
(i) Br2(l) (ii) cold, dilute KMnO4 (iii) hot, concentrated KMnO4 [3]
9
15 Ethylbenzene, C6H5CH2CH3, is an important intermediate in the manufacture of
poly(phenylethene), commonly known as polystyrene.
When ethylbenzene is treated with chlorine under different conditions, two
isomeric chlorides, C and D, are formed.
C reacts with hot concentrated alcoholic potassium hydroxide to give
phenylethene but, with aqueous sodium hydroxide, it forms E, C8H10O. E gives a
yellow precipitate with alkaline aqueous iodine.
D is inert towards aqueous sodium hydroxide but is oxidised by aqueous
potassium manganate(VII) to F, C7H5ClO2.
(a) (i) Deduce identities for C and D. [2]
(ii) Suggest the conditions needed to obtain each one from ethylbenzene
and, in each case, state the type of reaction undergone. [3]
(b) Deduce identities for E and F, giving your reasoning in full. [5]
16 (a) Explain how primary, secondary and tertiary alcohols can be distinguished
on the basis of their oxidation products. [3]
(b) The ester formed between 3-methylbutan-1-ol and ethanoic acid
contributes to the flavour of ripe pears.
(i) Draw the structural formula of the ester.
(ii) What conditions and reagents would you use in the laboratory to
make the ester from the acid and the alcohol named above?
(iii) Draw the structural formulae of three primary alcohols that are
isomers of 3-methylbutan-1-ol, labelling with an asterisk any chiral
carbon atom they contain. [6]
(c) Explain why ethanol is the only primary alcohol that undergoes the tri-
iodomethane (iodoform) reaction. [3]
10
Carbonyl Compounds: Aldehydes and Ketones
17 Some alcohols and ketones can be distinguished from their isomers by the tri-
iodomethane test (iodoform reaction).
(a) State the reagents used for this test and the observation made for a
positive result. [2]
(b) For each of the following molecular formulae, draw the structural formula
of an isomer that gives tri-iodomethane and of an isomer that does not.
Make sure you indicate which is which.
(i) C5H10O (ketones) (ii) C4H10O (alcohols) [4]
(c) Suggest a structure for each of the isomers B, C and D of the compound
C3H6O2, based on the following reactions. Explain which functional groups
in each molecule are taking part in each reaction.
B gives tri-iodomethane and reduces Fehling‟s solution,
C gives tri-iodomethane but does not reduce Fehling‟s solution,
D does not give tri-iodomethane but does reduce Fehling‟s solution. [4]
18 (a) In each case, name an organic functional group which gives
(i) an orange precipitate with 2,4-dinitrophenylhydrazine reagent;
(ii) a red precipitate with Fehling‟s solution;
(iii) fumes of hydrogen chloride with phosphorus pentachloride. [3]
(b) The molecule Q below is the substance chiefly responsible for the smell of
ripe raspberries.
OH C4H7O
It gives an orange precipitate with 2,4-dinitrophenylhydrazine reagent, no
precipitate with Fehling‟s solution and no reaction with phosphorus
pentachloride. It contains a chiral carbon atom.
(i) Draw the displayed formula of Q.
(ii) On your formula, draw a circle around the chiral carbon atom. [3]
11
(c) (i) What would you expect to see when Q is treated with aqueous
bromine?
(ii) Draw the displayed formula of the resulting organic product.
(iii) What type of reaction mechanism occurs when Q reacts with
aqueous bromine? [3]
19 The main component of cinnamon oil is cinnamaldehyde:
CH=CHCHO
(a) Using this compound as the starting material, suggest suitable reagents
and conditions to carry out the following types of reaction.
(i) nucleophilic addition,
(ii) reduction,
(iii) oxidation of the aldehyde group,
(iv) oxidation of the alkene group.
For each reaction, draw the structural formula of the organic product. [8]
(b) Suggest simple test-tube reactions (one in each case) you could use to
distinguish cinnamaldehyde from compounds A and B below.
CH2CH2CHO
CH=CHCH2OH
A B
For each test, give reagents and describe what you would see. [4]
12
20 (a) Three compounds E, F and G all have the molecular formula C3H6O. E is
an alcohol, F is a ketone, and G is an aldehyde.
(i) Draw possible structural formulae for E, F and G.
(ii) Describe tests (reagents, conditions and observations with each
compound) that would allow you to show that:
1. E is an alcohol, whereas F and G are not.
2. F and G are carbonyl compounds, whereas E is not.
3. G is an aldehyde, whereas E and F are not.
Write balanced equations for all reactions that occur. [9]
(b) One compound responsible for the flavour of butter is butane-2,3-dione:
CH3
CH3
O
O
Give the structural formulae of the organic products formed when butane-
2,3-dione reacts completely with (i) H2/Ni, (ii) I2/OH–(aq). [3]
21 2-oxopropanal, B, is one of a number of compounds responsible for the
characteristic smell of burnt sugar.
CH3
CC
O
O
H
(a) Describe what you might observe when this compound is
(i) heated gently with acidified potassium dichromate(VI),
(ii) added to alkaline aqueous iodine,
(iii) warmed gently with Fehling‟s solution.
In each case, suggest the structural formula of each organic product. [6]
13
(b) Treating B with NaBH4 in methanol produces compound C, C3H8O2. C
consists of 50:50 mixture of two isomers, both of which give the same
compound D, C3H6O, on passing their vapours over hot Al2O3. D gives no
reaction with 2,4-dinitrophenylhydrazine reagent, but decolourises
aqueous bromine.
Identify C and D, and explain the chemistry of the above reactions. [6]
22 Carbonyl compounds react with hydrogen cyanide to form cyanohydrins.
(a) Name and outline the mechanism of this reaction, indicating clearly why a
trace of sodium cyanide is needed for the reaction to take place, and how
it acts as a catalyst. [4]
(b) Draw the structural formula of each of the cyanohydrins formed from the
following compounds, indicating clearly any chiral carbon atom in each
product.
(i) CH3CH2CHO (ii) CH3CH2COCH2CH3 [2]
(c) Starting from a suitable carbonyl compound of your choice, and using a
cyanohydrin as an intermediate, devise a 3-stage synthetic route to form
compound A.
C
CH3
CH3 CO2CH2CH3
OH
A
Suggest reagents and conditions for each step, and draw the structural
formula of every intermediate compound. [6]
23 (a) Describe the mechanism of the reaction between ethanal and hydrogen
cyanide. Name the type of reaction undergone, state any other reagents
needed, and include the structural formula of any intermediate, as well as
of the product. [4]
14
(b) The above reaction produces two isomeric products in equal amounts.
Name the type of isomerism involved, draw displayed formulae to illustrate
it, and explain why two isomeric products are formed in equal amounts. [4]
(c) As a consequence of starvation or diabetes, the blood plasma and urine of
patients can contain large amounts of „ketone bodies‟. These include
propanone, 3-oxobutanoic acid, and 3-hydroxybutanoic acid.
CH3COCH3 CH3COCH2CO2H CH3CH(OH)CH2CO2H
propanone 3-oxobutanoic acid 3-hydroxybutanoic acid
Describe a separate simple chemical test in each case to distinguish 3-
oxobutanoic acid from (i) propanone, (ii) 3-hydroxybutanoic acid.
For each test, give reagents and conditions, and state what would be seen
with each compound. [5]
24 The limescale that collects in kettles in hard water areas is mostly calcium
carbonate. It can be removed fairly harmlessly by a warm solution of vinegar,
which contains ethanoic acid. The limescale dissolves with fizzing and a solution
of calcium ethanoate remains.
(a) Write a balanced equation for the reaction between ethanoic acid and
calcium carbonate. [1]
When the solution produced in (a) is evaporated, and the resulting solid calcium
ethanoate heated strongly in a test-tube, an organic compound G is formed
which condenses to a colourless liquid. The residue in the tube consists of
calcium carbonate.
(b) When 0.10 g of G was injected into a gas syringe at a temperature of
383 K and a pressure of 1.0 × 105 Pa, 55 cm3 of vapour was produced.
Calculate the relative molecular mass of G. [2]
(c) Compound G is neutral and water-soluble. G does not react with sodium
metal nor with Fehling‟s solution but it does react with alkaline aqueous
iodine. Suggest a structural formula for G. Justify your answer by
reference to these properties of G. [5]
15
(d) Construct a balanced equation for the formation of G by the action of heat
on calcium ethanoate. [1]
(e) Suggest a simple one-step test you could carry out to confirm the identity
of the functional group present in G. You should give the reagent and the
observation you would make. [2]
(f) Suggest the structural formula of the organic product you might expect
when calcium propanoate, (CH3CH2CO2)2Ca, is heated strongly. [1]
25 (a) Draw the structures of a secondary alcohol and a tertiary alcohol of your
choice. Describe a simple one-step reaction you could carry out to
distinguish between a secondary and a tertiary alcohol. You should state
reagents, conditions and observations with each alcohol. [3]
(b) Ester B (Mr, 116) is used in synthetic fruit flavours. When B is subjected to
hydrolysis, an acid C and an alcohol D are produced.
When 1.00 g of the monoprotic acid C is titrated with 0.500 mol dm–3
sodium hydroxide, 33.0 cm3 of alkali is needed for neutralisation. Alcohol
D reacts with alkaline aqueous iodine giving a precipitate E. D exists as a
pair of isomers, both of which are oxidised to ketone F. This ketone also
reacts with alkaline aqueous iodine, giving the same precipitate E and a
solution containing a sodium salt G.
(i) Suggest suitable reagents and conditions for the hydrolysis of B.
(ii) Calculate the Mr of acid C, and hence identify it.
(iii) Explain and illustrate the type of isomerism shown by D.
(iv) Describe and explain the reactions of D and F with alkaline aqueous
iodine, identifying E and G.
(v) Suggest the structural formulae of D and F.
(vi) Hence identify the original ester B and write a balanced equation for
its hydrolysis. [9]
16
Carboxylic Acids and Derivatives
26 (a) Explain why ethanoic acid is more acidic than ethanol and why
chloroethanoic acid is stronger than ethanoic acid.
How would you expect the acidity of 3-chloropropanoic acid and of
fluoroethanoic acid to compare with that of chloroethanoic acid? [6]
(b) One commercial use of chloroethanoic acid has been to make the
herbicide 2,4,5-T, which can be synthesised from 1,2,4,5-
tetrachlorobenzene by the following route:
Cl
Cl
Cl
Cl
Cl
OH
Cl
Cl
Cl
O-Na
+
Cl
Cl
Cl
O
Cl
Cl CH2CO2H
(i) What is unusual about reaction I?
(ii) What type of reaction is reaction II?
(iii) Draw the structural formulae of all other positional isomers of 1,2,4,5-
tetrachlorobenzene. [4]
27 Compound B, a dicarboxylic acid that occurs in apples and other fruits, has the
following composition by mass: C, 35.8%; H, 4.5%; O, 59.7%.
B reacts with ethanol in the presence of concentrated sulfuric acid under reflux to
give C, C8H14O5. Compound C evolves hydrogen gas when treated with sodium
metal and reacts with acidified potassium dichromate(VI) to give compound D.
Compound D produces an orange precipitate with 2,4-dinitrophenylhydrazine but
has no reaction with Fehling‟s or Tollens‟ reagent.
Suggest structures for compounds B, C and D and explain the reactions. [10]
excess NaOH
high temperature
NaOH
ClCH2CO2H
I
II
2,4,5-T
17
28 2-hydroxybenzoic acid, A, is a useful intermediate for making aspirin (an
analgesic) and “oil of wintergreen” (used in ointments).
CO2H
OH
CO2H
OCOCH3
CO2CH3
OH aspirin A oil of wintergreen
(a) Suggest suitable reagents and conditions for reactions I and II.
(b) Draw the structural formulae of the organic molecules produced when A
reacts with (i) Na2CO3(aq), (ii) NaOH(aq), (iii) HNO3(aq). [3]
(c) When an aspirin tablet was crushed in water and titrated with 0.1 mol dm–3
sodium hydroxide, 13.9 cm3 of alkali was required to neutralise its acidity.
What was the mass of aspirin in the tablet? [2]
(d) A “soluble aspirin” contains the calcium salt of aspirin.
(i) What reagent could you use to convert aspirin into its calcium salt?
(ii) Explain the difference in solubility between aspirin and its calcium
salt. [2]
29 Squaric acid is a most unusual organic compound with molecular formula,
C4H2O4, and its systematic name is 1,2-dihydroxycyclobutane-3,4-dione.
(a) The systematic name shows that certain groups are present in the
molecule. Draw the formulae of the groups indicated by the following parts
of the name:
(i) -one; (ii) -ene; (iii) cyclobut-. [3]
(b) Suggest a displayed formula for squaric acid. [1]
(c) Suggest what you would expect to see when squaric acid reacts with
(i) Br2(aq), (ii) PCl5, (iii) Brady‟s reagent. [3]
I II
18
(d) When 100 cm3 of aqueous squaric acid containing 0.017 mol dm–3 of the
acid was titrated against 0.100 mol dm–3 aqueous sodium hydroxide using
a pH meter, the following graph was obtained.
Volume of NaOH added / cm3
Is squaric acid a strong or weak acid?
Give two reasons to justify your answer. [2]
(e) How many acidic protons are there in one molecule of squaric acid? [1]
30 One of the products from the vigorous hydrolysis of oil of bitter almonds is
mandelic acid, H. It can be synthesised from benzaldehyde in two steps:
C6H5CHO J C6H5CH(OH)CO2H H
(a) Suggest reagents and conditions for the two steps, and draw the structural
formula of the intermediate J. [4]
(b) Suggest structural formulae for the products of the reaction of mandelic
acid with the following reagents.
(i) HBr (ii) PCl5 (iii) CH3COCl (iv) C2H5OH/H+ (v) NaOH(aq) [6]
(c) A sample of mandelic acid isolated from bitter almonds was contaminated
with a neutral impurity. A 0.100 g sample of the impure acid required
6.00 cm3 of 0.100 mol dm–3 NaOH to neutralise it. Calculate the
percentage purity of the mandelic acid. [2]
19
31 (a) 2-phenylethanol occurs naturally in rose oil and geranium oil; it is much
used in the perfume industry. It can be synthesised from
(chloromethyl)benzene by the following series of reactions:
C6H5CH2Cl C6H5CH2CN C6H5CH2CO2H C6H5CH2CH2OH
Suggest reagents and conditions for the above synthetic route and state
the type of reaction occurring in each step. [6]
(b) Suggest simple one-step test-tube reactions by which the isomers in the
following pairs can be distinguished from each other. You should state the
reagents and conditions for each test, and describe how each of the
isomers in the pair behaves.
(i) CH3CH(OH)CH3 and CH3CH2CH2OH
(ii) CH3COCH3 and CH2=CHCH2OH
(iii) CH3CH2COCH2CH3 and CH3CH2CH2CH2CHO
(iv) CH3CH2CO2H and CH3COCH2OH [8]
Nitrogen Compounds
32 The following structure represents part of the formula of a protein molecule:
NH CH CO NH CH CO NH CH CO
CH2
OH
CH2
CO2H
CH2
CH2
CH2
CH2
NH2
(a) What reagents and conditions could you use to hydrolyse this protein into
its constituent amino acids? [2]
(b) Draw the structural formula of one of the three amino acids that would be
produced by hydrolysing this segment of the protein. [1]
20
(c) Describe a test-tube reaction (including observations) you could carry out
on each amino acid that would enable you to distinguish it from the other
two. [4]
(d) Amino acids exist as zwitterions in aqueous solution.
Draw the structural formula of the zwitterion formed from one of these
three amino acids, and write equations to show how it can react as a
buffer. [2]
(e) Give one example of a buffer in a biological system. [1]
33 (a) Explain the differences in solubility and melting point of the following
substances as fully as you can.
substance formula solubility in water m.p. / °C
phenylamine
benzoic acid
phenylalanine
C6H5NH2
C6H5CO2H
C6H5CH(NH2)CO2H
insoluble
sparingly soluble
soluble
–6
121
>200
(b) Draw displayed formulae of the products of the reactions between
phenylalanine and (i) NaOH(aq); (ii) HCl(aq). [2]
(c) Two other amino acids are aspartic acid and serine:
NH2 CH CO2H
CH2
CO2H
NH2 CH CO2H
CH2
OH
aspartic acid serine
Draw the structural formula of a dipeptide formed from these two amino
acids, showing the ionic form in which it could exist at pH 12. [2]
21
34 Pethidine is a powerful painkilling drug:
CO2CH2CH3
N
CH3
CO2CH2CH3
N+
CH3
H Cl-
pethidine E
The pethidine molecule contains two functional groups, one of which reacts with
dilute hydrochloric acid to give compound E.
(a) What type of reaction is this and what type of functional group does it
show the pethidine molecule to contain? [2]
(b) Name the other functional group in the molecule. State the type of reaction
undergone, and give the structural formula of each of the products, when
pethidine reacts under reflux with aqueous sodium hydroxide. [3]
(c) A less powerful painkiller is paracetamol:
OH NH COCH3
Suggest how it might react with
(i) aqueous bromine,
(ii) cold aqueous sodium hydroxide,
(iii) hot aqueous sodium hydroxide.
In each case, suggest the type of reaction that takes place and draw the
structural formula of each organic product. [5]
22
35 A sodium salt of glutamic acid, monosodium glutamate (MSG), is a flavour
enhancer that occurs naturally in tomatoes, mushrooms and some other
vegetables.
NH2 CH CO2H
CH2
CH2
CO2
-Na
+
NH2 CH CO2H
CH2
CH2
CO2H
MSG glutamic acid
(a) What type of isomerism can be shown by MSG, and what part of the
molecule is responsible for it? [2]
(b) MSG can act as a buffer by reacting with either acids or bases. Write
balanced equations for its reactions with
(i) an excess of dilute hydrochloric acid,
(ii) an excess of aqueous sodium hydroxide. [3]
(c) The concentration at which MSG has its optimum flavour-enhancing effect
is 1.0 g dm–3. Calculate the number of moles of MSG in 300 cm3 of soup
with this concentration. [3]
(d) Suggest a likely pH for an aqueous solution of glutamic acid. [1]
(e) Glutamic acid is a component of many proteins and peptides. Draw the
structural formula of a dipeptide formed between glutamic acid and glycine,
NH2CH2CO2H. [2]
(f) What reagents and conditions are needed to hydrolyse peptides to amino
acids in the laboratory? [1]
23
36 (a) Amino acids exist as zwitterions.
(i) Draw the structural formula of the zwitterionic form of glycine
(aminoethanoic acid).
(ii) How would you expect the melting point and the solubility in water, of
an unionised covalent form of glycine to compare with the actual
properties of the zwitterionic form? [3]
(b) The following scheme of reactions illustrates the synthesis of a dipeptide E:
(C6H5)3C–Cl + H2N–CH(CH3)–CO2H
(C6H5)3C–NHCH(CH3)–CO2H
(C6H5)3C–NHCH(CH3)–COCl
(C6H5)3C–NHCH(CH3)–CO–NHCH2CO2H
(C6H5)3C–H + NH2–CH(CH3)–CO–NHCH2CO2H
E
(i) What type of reaction is step I?
(ii) Suggest a reagent for step II.
(iii) During which step is the peptide bond formed?
(iv) What are the products of hydrolysis of E, and how may the reaction
be carried out?
(v) Suggest the type of reaction in step IV. [7]
I
II
III
IV
+ NH2CH2CO2H
24
37 (a) A pH indicator is a chemical that is added in small amounts to a solution to
determine the pH of the solution visually. pH indicators are usually weak
acids or weak bases. One such pH indicator is the compound neutral red.
N
N
N
CH3
CH3
NH2
CH3 Neutral red
In order to understand the relative basicity of the various nitrogen groups
on neutral red, a comparison is done with similar nitrogenous bases.
The pKb values of these relevant bases are given below.
methylamine trimethylamine pyridine phenylamine
NCH3
H
H
NCH3
CH3
CH3
N
NH2
3.34 4.19 8.75 9.37
(i) Explain the relative basicity of
methylamine and trimethylamine
pyridine and phenylamine [3]
(ii) Hence rank the four nitrogen groups on neutral red in order of
increasing basicity. [1]
(b) In an aqueous solution of ethylamine, CH3CH2NH2, neutral red changes
colour from red to yellow; whereas in an aqueous solution of ethanoic acid,
CH3CO2H, neutral red remains red in colour.
(i) Write equations to explain the chemical behaviour shown in these
reactions. [2]
25
(ii) Ethylamine and ethanoic acid react together at room temperature to
produce compound A (C4H11O2N). Suggest a structure for A, and
describe the type of reaction undergone. [2]
(iii) Suggest the structural formulae for compounds B and C in the
following scheme:
CH3CO2H B C
[2]
(iv) Suggest reagents and conditions needed to re-form ethylamine and
ethanoic acid from C. [1]
38 (a) Suggest reagents and conditions for each step in the following synthesis
of the amino acid alanine, and identify the intermediate E. Explain why
unlike its naturally occurring counterpart, laboratory-synthesised alanine
does not have any effect on plane polarised light.
CH3CHClCN E CH3CH(NH2)CO2H
alanine [5]
(b) Draw the structural formulae of the compounds formed when glycine,
NH2CH2CO2H, reacts with (i) aqueous NaOH, (ii) aqueous HCl. [2]
(c) Proteins are polymers formed by joining together many amino acids.
(i) Describe, with the aid of a sketch, the structure of the -helix form of
protein. Indicate how the structure is stabilised, by drawing the
formula of the stabilising bonds. [3]
(ii) Hence suggest a reason why proline residues are rarely found in -
helix regions of proteins. [1]
C
CO2H
H
CH2
CH2
CH2
NH
proline (pro)
PCl5 or
SOCl2
C2H5NH2
I II
26
(d) Partial hydrolysis of a tetrapeptide (containing four amino acid residues)
produces the following three dipeptides, as well as individual amino acids.
NH2CH2CONHCH(CH3)CO2H
NH2CH2CONHCH2CO2H
NH2CH(CH3)CONHCH(CH3)CO2H
Deduce the order in which the amino acids are bonded together in the
tetrapeptide, explaining your reasoning. [3]
(e) The enzyme chymotrypsin digests proteins or polypeptides at the
carboxylic acid end of the phenylalanine residue, phe. A sample of the
polypeptide P was digested by chymotrypsin, and the following peptides
were identified:
asp-lys-gly-phe lys-val-arg val-phe
Another enzyme, trypsin, digests at the carboxylic acid end of lysine, lys.
The following peptides were identified after digestion of another sample of
the same polypeptide P with trypsin.
gly-phe-lys val-arg val-phe-asp-lys
Elucidate the primary structure of P. [3]
39 The general structure of amino acids includes an amino group and a carboxyl
group, both of which are bonded to the -carbon (the one next to the carboxyl
group). The -carbon is also bonded to a hydrogen atom and to the side chain
group, which is represented by the letter R.
(a) Some amino acids have carboxyl groups in their side chains, in addition to
the one present in all amino acids. One such amino acid is glutamic acid,
which has the following structure in its fully protonated form:
HO2C CO2H
NH3
+
glutamic acid
There are three pKa values associated with glutamic acid: 2.1, 4.1 and 9.5.
27
(i) Assign the three pKa values to the respective hydrogens, giving your
justifications in full. (Hint: consider the relative position of any
electron-donating or electron-withdrawing group and how it affects
the relative acidity of the three hydrogens.) [3]
(ii) Make use of these pKa values to suggest the major species present
in aqueous solutions of glutamic acid with the following pH values.
pH 1
pH 3
pH 7
pH 11 [4]
(b) On the other hand, there are also some amino acids with amino groups in
their side chains, in addition to the one present in all amino acids. One
such amino acid is lysine, which has the following structure in its fully
protonated form:
CO2H
NH3
+
NH3
+
lysine
There are three pKa values associated with lysine: 2.2, 9.2 and 10.7.
(i) Assign the three pKa values to the respective hydrogens, giving your
justifications in full. (Hint: consider the relative position of any
electron-donating or electron-withdrawing group and how it affects
the relative acidity of the three hydrogens.) [3]
(ii) Make use of these pKa values to suggest the major species present
in aqueous solutions of lysine with the following pH values.
pH 1
pH 7
pH 10
pH 11 [4]
28
(c) From (a) and (b) above, it can be generalised that in a typical amino acid,
(1) the -carboxyl group is more acidic than the R-carboxyl group; (2) the
-amino group is less basic than the R-amino group.
However, in histidine, the -amino group is more basic the R-amino group.
CO2H
NH3
+NH
NH
+
Explain this apparent contradiction. (Hint: consider the hybridisation of the
nitrogen atom in the unprotonated form of each amino group and its effect
on the availability of lone pair for protonation.) [2]
40 This question is about compound K, C6H7ON, which is formed when
phenylhydroxylamine, C6H5NHOH, is warmed with dilute sulfuric acid.
Compound K is not very soluble in water, but dissolves in dilute hydrochloric acid.
It also dissolves in aqueous sodium hydroxide, but not in aqueous potassium
carbonate. On reaction with one mole of ethanoyl chloride, CH3COCl, K forms
compound L, C8H9O2N.
L is no longer soluble in dilute hydrochloric acid, but is still soluble in aqueous
sodium hydroxide. On reaction with aqueous bromine, L produces compound M,
C8H7O2NBr2. When K is reacted with 2 moles of ethanoyl chloride, it produces
compound N, C10H11O3N, which is not soluble in either dilute acid or dilute alkali.
Compound K can be synthesised by treating phenol with dilute nitric acid,
followed by reaction with zinc metal and hydrochloric acid.
Deduce the structures of compounds K, L, M and N. Explain the chemistry of the
reactions described, writing equations where appropriate. (There is no need to
comment on the chemistry of the formation of K from phenylhydroxylamine.) [10]
pKa = 6.0
pKa = 9.1
pKa = 1.7