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Operators•A function is something that turns numbers into numbers•An operator is something that turns functions into functions
•Example: The derivative operator
sinf x kxd
dxO =
( ) ( )df x f x
dxO =
•In quantum mechanics, x cannot be the position of a particle•Particles don’t have a definite position
•Instead, think of x as something you multiply a wave function by to get a new wave function
•x is an operator, sometimes written as xop or X•There are lots of other operators as well, like momentum
( ) ( )opx x x xy y=
p ki x
oppi x
( ) ( )sin cosd
kx k kxdx
= =
Expectation Values•Suppose we know the wave function (x) and we measure x. What answer will we get?
•We only know probability of getting different values•Let’s find the average value you get
•Recall |(x)|2 tells you the probability density that it is at x•We want an expectation value
•It is denoted by x
x
x P x x 2
x x xdx
* x x x dx
•For any operator, we can similarly get an average measurement
* x x dxO O
op*p x p x dx
*x
x dxi x
Sample ProblemA particle is in the ground state of a harmonic oscillator.
What is the expectation value of the operators x, x2, and p?
2140 2exp
Ax Ax
*x x dx
122
12 if is even
0 if is odd
nn
n Ax A nx e dx
n
2 2*x x dx
2 1 2x A
0x
*p dxi x
0p
Note: x2 x2More on this later
Note: Always use normalized wave functions for expectation values!
mA
31 12 2 2,
2 22 2Ax AxAe Ax e dx
i
2 2AxA e x dx
2AxA e xdx
The Hamiltonian Operator•In classical mechanics, the Hamiltonian is the formula for energy in terms of the position x and momentum p•In quantum, the formula is the same, but x and p are reinterpreted as operators
2
2
pH V x
m
2op
op
2 2
op2
2
2
pH V x
m
V xm x
•Schrodinger’s equations rewritten with the Hamiltonian: E H
i Ht
Advanced Physics:•The Hamiltonian becomes much more complicated
•More dimensions, Multiple particles, Special Relativity•But Schrodinger’s Equations in terms of H remain the same
•The expectation value of the Hamiltonian is the average value you would get if you measure the energy
E H
Sample ProblemA particle is trapped in a 1D infinite
square well 0 < x < L with wave function given at right. If we measure the energy, what is the average value we would get?
25
30x Lx x
L
E H 2
*2
oppV x dx
m
2 2
20
*2
L ddx
m dx
2 2
2 25 2
0
30
2
L dLx x Lx x dx
mL dx
2
25
0
152
L
Lx x dxmL
2
2 31 12 35 0
30 L
Lx xmL
23 31 1
2 35
30L L
mL
2
2
5
mL
•Compare to ground state:•Often gives excellent approximations
2 2 2
2 2
4.935
2E
mL mL
Tricks for Finding Expectation Values•We often want expectation values of x or x2 or p or p2
•If our wave function is real, p is trivial
*d
p dxi dx
d
dxi dx
2
2
ddx
i dx
2
2i
0p •To find p2, we will use integration by parts2 2
22
*d
p dxi dx
2 **
d d ddx
dx dx dx
22 2 d
p dxdx
•Recall: x2 x2. Why?•The difference between these is a measure of how spread out the wave function is•Define the uncertainty in x:
Uncertainty
22 24 6 4 626 25
2 2
22 2x x x
•We can similarly define the uncertainty in any operator:
22 2p p p 22 2O O O
Heisenberg Uncertainty Principle
12x p
Sample ProblemA particle is in the ground state of a harmonic
oscillator. Find the uncertainty in x and p, and check that it obeys uncertainty principle
2 1 2x A0x 0p •Much of the work was done five slides ago•We even found p, but since is real, it is trivial anyway•Now work out p2:
2 212p A
•Now get the uncertainties
22x x x 1
2A
22p p p 2A
12x p
2140 2exp
Ax Ax
mA
22 2 d
p dxdx
2
2 212exp
AAx Ax dx
22 2 2 AxA A x e dx