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One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

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Page 1: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

One-phase Solidification Problem:

FEM approach via Parabolic Variational Inequalities

Ali Etaati

May 14th 2008

Page 2: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Content:

• One-phase Stefan problem-solidification example

• Derivation of a complementarity system

• Parabolic variational inequality

• Finite element method

Page 3: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

One-Phase Stefan problem

1

2

)(t )(t )(0 t

)(0),(

)(0),(

)(0),( 0

txtxu

txtxu

txtxu

},)(:{)(

},)(:{)(

},)(:{)(0

txlxt

txlxt

txlxt

)0(0,0)(

),0()0(,0)(0xlxl

xxl

Page 4: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Solidification:

1

2

)(t )(t )(0 t

)()(

0

21

21

tt

tt

),0( TT

(T: final time)

Page 5: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Heat conduction equation (in the solid)

Txut

u,

Freezing temperature

0))(,( xlxu

Llxlxu solidliquid .))](,([

Energy balance (Stefan condition) at )(t

(L is the latent heat)

Solidification (cont’d):

Page 6: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Solidification (cont’d):

Initial and Boundary conditions (temperature distribution):

2

1

00

,0

,0),(

)0(,0

)0(),()0,(

xu

xtxgu

x

xxuxu

Initial enthalpy:

)0(,

)0(),()(

00

0xL

xxuxH

Page 7: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Freezing index:

)0(,),(

)0(),(,0

)0(),(,),(

),(

0

0

0

)(

xdxu

xxlt

xxltdxu

txUt

t

xl

Then:

)(,0,0

,0

),(

0

0

txUU

xU

xxHUt

U

T

T

2

1

0

,0

,),(~

xU

xdxgUt

xxU ,0)0,(

Page 8: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Linear complementarity system:

,0))((

,0

,0)(

0

0

UxHUt

U

U

xHUt

U

a.e. in T

Page 9: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Parabolic Variational Inequalities:

Let

}..:))(,,0({

}..),(:)({)(10

2

10

ToneaGvHTLvK

oneatxGvHvtk

where

)()),(,,0( 222TL

t

GHTLG

and),0(..0 ToneaG

Suppose: )(2 TLf

Define: vdxwvwawvdxvw .),(,),(

Page 10: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Parabolic Variational Inequalities (cont’d)

Problem 1:

Find with

such that

and for almost all and is such that:

for all with a.e. in (0,T).

))(;,0( 10

2 HTLw ))(;,0(/ 22 LTLtw

)0()0,( 0 kwxw

)()(),,0( tktwTt

),(),(),( wvfwvwawvt

w

))(;,0( 10

2 HTLv )()( tktv

Page 11: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Parabolic Variational Inequalities (cont’d)

Problem 2:

Find with such that

and

for all .

Kw ))(;,0(/ 22 LTLtw

)0()()0,( 0 kxwxw

0)},(),(),({0

dtwvfwvwawvt

wT

Kv

Page 12: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Parabolic Variational Inequalities (cont’d)

Equivalence:

),(,~),(,

tKv

twv

then

Consider a solution of Problem 2, for any and 0 ),,0( T

0)}~,()~,()~,({

dtwvfwvwawvt

w

We obtain the solution for Problem 1.

• Clearly a solution of Problem 1 solves Problem 2.

Page 13: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Parabolic Variational Inequalities (cont’d)

.0))((

,

,0

Gwfwt

w

Gw

fwt

w

a.e. in T

Theorem

Solution to Problem 2 satisfies the linear complementarity system:

Page 14: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Parabolic Variational Inequalities (cont’d)

Proof

For any non-negative and so, from Problem 2:

KwvC T ),(0

0)},(),(),({])[(0

dtwvfwvwawvt

wdxdtfw

t

w T

T

Which implies that

,0

fwt

wa.e. in T

Page 15: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Parabolic Variational Inequalities (cont’d)

T

dxdtfwt

wdtwvfwvwawv

t

wT

.])[()},(),(),({00

Hence,0

fwt

wa.e. in T

Proof (cont’d)

Now let Then for any

for sufficiently small so that

)}.,(),(:),{( txGtxwtx TT

KwvC T ),(0

Conversely, by noting that if satisfies the complementarity system, then, for

KwKv

,..,0))(( Tineawvfwt

w

It is then clear that w solves Problem 2.

Page 16: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Finite Element approximation (FEM)

: Space of continuous functions which are linear on each element and which vanish on the boundaries.

hV

General Discretisation by FEM for Problem 1:

hnnnn

hnnn wvfwvwawvkww ),(),(),/)(( 1111

For all )})1(,(:)({1 knxGvVxbvvkv iih

Iiii

nh

(for all interior points)

: a piecewise linear basis function.)(xbi

]1,0[,)1(1 nnn www

find such that11 nh

n kw

Page 17: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Finite Element approximation (cont’d)

In nkff )}({If f is continuous:

kn

nk

hn dtvtf

kvf

)1(

)),((1

),( Otherwise: (for all )

hVv

),(),(

,)(,)(

00

200

0

vwavwa

Hwifww I

(for all )hVv

In any case:

)(,)()( 100

02, HinwwLinftf Tkh

Page 18: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Time marching of the discrete system

(*)0)()(,0,0 111111 nnTnnnn GwzGwz

where

),(ˆ,),(

,ˆ/)( 11

jiijhjiij

nnnnn

bbaAbbM

fwAkwwMz

},,{ nnn Gfw are nodal vectors.

: is a symmetric positive definite matrix which

causes the problem (*) to have unique solution.

AkM ˆ

Page 19: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

FEM; Stability

Let

kvvvvAvv

vvvvMuvuvvnnn

k

T

/)(,~ˆ~||||

,,||,~~,,~

122

2

and let’s assume:

)0(0)()( ** kandttfortktk

.0)0,(),(),( ** xGandttfortxGtxG

Or equivalently that

The complementarity problems are equivalent to

0)~~()~( 11 nTn wvZ for all 1~~ nGv (**)

We may take in (**), then nwv ~~

Page 20: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

FEM; Stability (cont’d)

Stability theorem:

Providing the stability condition

2)]([)21( 2 hSk

holds when , there is a constant C, independent of space- and time-steps such that:

2/1

}||||{|||||||| 2

0

20212

0

jn

j

njk

n

j

fkwCwwk

Page 21: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

FEM; Stability (cont’d)

Lemma:

is stable under the following conditions

}~~~){(

~~ 111 nnnnn GfkwkAIGw

The explicit method

0;,0;01 j

ijijii AjiAkA

0)(),(,0)(),( tGtxGxftxf

0)0()0,(0)(,0)( ''' GxwandtGtG

for which is bounded by}{ nw

0~~~~~ 11 nnnn wwGG

Page 22: One-phase Solidification Problem: FEM approach via Parabolic Variational Inequalities Ali Etaati May 14 th 2008

Reference

• Weak and variational methods for moving boundary problems, C M Elliott & J R Ockendon.