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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
1
Vertex: (0,0)Line of symmetry: x = 0
2
Vertex: (-3,0)Line of symmetry: x = -3Maximum-minimum value: 0It has Minimum value.
Note: the boxes are there to insert the answers.
My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
3
Vertex: (-3,0)Line of symmetry: x = -3Maximum-minimum value: 0It has Minimum value.
Note: the boxes are there to insert the answers.
My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
4
Vertex: (-3,-4)Line of symmetry: x = -3Maximum-minimum value: -4It has Minimum value.
Note: the boxes are there to insert the answers.
My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
5
Vertex: (-3,1)Line of symmetry: x = -3Maximum-minimum value: 1It has Maximum value.
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Vertex: (-6,-3)Line of symmetry: x = -6Maximum-minimum value: -3It has Maximum value.
Note: the boxes are there to insert the answers.
My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
7
Vertex: (1,-3)Line of symmetry: x = 1Maximum-minimum value: -3It has Minimum value.
Note: the boxes are there to insert the answers.
My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
8
Vertex: (4,18)Line of symmetry: x = 4Maximum-minimum value: 18It has Maximum value.
Note: the boxes are there to insert the answers.
My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
9
Vertex: (2,0)Line of symmetry: x = 2Maximum-minimum value: 0It has Minimum value.
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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
10
x-coordinate of vertex: 1/2y- coordinate of vertex: 19/2Line of symmetry: x = 1/2Maximum-minimum value: 19/2It has Maximum value.
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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
11
Answer:
Vertex: (0, 10)Line of symmetry: x = 0Maximum-minimum value: 10It has Maximum value.
Use the points (0, 10) and (1, 9).
12
Answer:x-coordinates of intercepts are x = -3, 5
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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
y-coordinates of intercepts are y = 15
13
Answer:Length: 32Width: 32Maximum area = 1024
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Answer: 161
15
ANSWER: (B)
16
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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
Answer: (C)
Instructions/Show Work Answer Choices YourAnswer
Question 1: Suppose you are an event coordinator for a large performance theater. One of the hottest newBroadway musicals has started to tour, and your city is the first stop on the tour. You need to supply informationabout projected ticket sales to the box office manager. The box office manager uses this information to anticipatestaffing needs until the tickets sell out. You provide the manager with a quadratic equation that models the expectednumber of ticket sales for each day x. ( 1x is the day tickets go on sale).
11+12x+-0.2x 2Tickets
N
a. Does the graph of this equation open up or down? How did you determine this?
Show Your Work:
Since the coefficient of the x^2 term is negative so it opens down.
Answer: B) DOWN, because lead coefficient is a NEGATIVE
A) UP, because leadcoefficient is aNEGATIVE
B) DOWN, becauselead coefficient is aNEGATIVE
C) UP, because leadcoefficient is aPOSITIVE
D DOWN, becauselead coefficient is aPOSITIVE
b. Describe what happens to the tickets sales as time passes?
Show Your Work:
First, the ticket sales rises up then after reaching its highest value, it falls down to zero.A) INCREASE, THEN DECREASE
A) INCREASE,THEN DECREASE
B) DECREASE,THEN INCREASE
C) INCREASE,ONLY
D DECREASEONLY
c. Use the quadratic equation to determine the last day that tickets will be sold. (Note:A) 11 DAYS
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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
Write your answer in terms of the number of days after ticket sales begin.)
Show Your Work:
Equate the given equation to 0:0 = -0.2x^2+12x+11
Multiply by -5, we will get
x^2 - 60x - 55 = 0
By using quadratic formula:
903.0,903.602
)55(*1*460602
4 22
xa
acbbx
Discard the negative value
x = 60.903 ≈ 61 days
Answer: D 61 DAYS
B) ZERO DAYS
C) 60 DAYS
D 61 DAYS
d. Will tickets peak or be at a low during the middle of the sale? How do you know?
Show Your Work:
Since the graph opens downwards, the vertex will be the maximum point of the function. Thus ticketswill be at peak in the middle of the sale.
EXPLAIN YOURANSWER
Y
e. After how many days will the peak or low occur?
Show Your Work:
The sales will be at peak when x = -b/2a = -12/(2*(-0.2))
x = 30 days
Answer: C) 30 DAYS
A) 6 DAYS
B) 5 DAYS
C) 30 DAYS
D UNCLEAR
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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
f. How many tickets will be sold on the day when the peak or low occurs?
Show Your Work:
Plug in x = 30 in the given function
Number of tickets = -0.2*30^2 + 12*30 + 11 = 191 tickets
Answer: B) 191 TICKETS
A) 360 TICKETS
B) 191 TICKETS
C) 97 TICKETS
D UNCLEAR
g. What is the point of the vertex? How does this number relate to your answers in parts eand f?
Show Your Work:The vertex will be at (30,191).The x-coordinate represents the day when the sales was at peak. The y-coordinate is the maximumnumber of tickets sold.
Answer: D) (30, 191)
A) (6, 97)
B) (5, 97)
C) (6,191)
D (30, 191)
h. How many solutions are there to the equation 011122.0 2 xx ? How do youknow?
Show Your Work:
Discriminant = b^2 – 4ac = 12^2 - 4*(-0.2)*11 = 152.8
Since b^2 – 4ac > 0 so there are two solutions to the equation.
Answer: B) TWO SOLUTIONS
A) THREESOLUTIONS,explain
B) TWOSOLUTIONS,explain
C) ONESOLUTION, explain
D NO SOLUTION,explain
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My Math Lab Assignment (Math Problems) Due Sunday April 22, 2012 @ 11:59pm
i. What do the solutions represent? Is there a solution that does not make sense? If so, inwhat ways does the solution not make sense?
Show Your Work:
The solutions represents the days when sale was 0.
Negative solution doesn't make sense because number of days cannot be negative. Thus, the solution-0.903 does not make sense.
EXPLAIN YOURANSWER
Y