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MPM 2D Course Review Unit 1: Linear Systems

MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

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Page 1: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

MPM 2D Course ReviewUnit 1: Linear Systems

Page 2: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can graph a line• 3 ways:• Table of values• x- and y-intercepts• y-intercept and slope• Ex. 1) y=-3x+2

Page 3: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can graph a line• 3 ways:• Table of values• x- and y-intercepts• y-intercept and slope• Ex. 2) 4x-3y=12

Page 4: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can graph a line• 3 ways:• Table of values• x- and y-intercepts• y-intercept and slope• Ex. 3) y=(2/3)x-5

Page 5: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can translate a word problem into algebra• What important, defining information are you missing? THIS

WILL HELP YOU DEFINE YOUR VARIABLES• Hint: The question at the end will direct you to at least one of

the variables• EXAMPLE: Karl owns a small airplane. He pays $50/h for flying

time and $300/month for hangar fees at the local airport. If Karl rented the same type of airplane at a flying club, it would cost him $100/h. When will the monthly cost of owning and renting be the same?

Page 6: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve a linear system by graphing• Karl’s situation:

• y1=50x+300

• y2=100x

Page 7: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can determine if a point is the solution to the system• …using substitution!• We found the POI for Karl was (6, 600) on the graph. • How do we test our answer?• Plug it into both equations!• y1=50x+300

• y2=100x

Page 8: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can determine the number of solutions by looking at the equations in the system• 1 solution• Different slope

• No solutions• Same slope,• different y-intercepts

• Infinite solutions• Same slope, • same y-intercept

Page 9: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve a linear system by substitution• and

• CHECK YOUR ANSWER!

Page 10: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve a linear system by elimination• and

• CHECK YOUR ANSWER!

Page 11: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve problems using linear systems• A weekend at a lodge costs $360 and includes 2 nights’

accommodation and 2 meals a day. A week costs $1200 and includes 7 nights’ accommodation and 10 meals. What is the cost of one night and one meal? How much would it cost for five nights and 4 meals?

• CHECK YOUR ANSWER!

Page 12: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

MPM 2D Course ReviewUnit 2: Analytic Geometry

Page 13: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can calculate the length of a line segment, given its endpoints• Distance formula:

• Find the distance between (-7, 1) and (5, -2)

Page 14: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can find the midpoint of a line segment• Midpoint formula:

• Ex 1. Find the midpoint between (-4, 6) and (8, -2)

Page 15: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can find the midpoint of a line segment• Midpoint formula:

• Ex 2. Find the other endpoint of a line segment if one endpoint is (-4, -2) and the midpoint of the line segment is (2, 6).

Page 16: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve problems involving midpoints, medians, and perpendicular bisectors

• Median: a line that joins a vertex of a triangle to the midpoint of the opposite side.

• Perpendicular Bisector: of a line segment is the line that is perpendicular to the line segment and passes through the midpoint of the line segment.

Page 17: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

• STEPS TO FIND EQN OF MEDIAN:• Calculate the midpoint of the line opposite the vertex of interest• Calculate the slope of the line connecting the vertex of interest to

that midpoint (ie. The median)• Sub the slope into the eqn for a line: y=mx+b• Plug in (x, y) (either the midpoint or the vertex of interest)• Solve for b• State equation with slope (m) and y-intercept (b)

• Find the equation of the median line from vertex C in triangle ABC if the coordinates of the vertices are A(-3, 3), B(2, -5), and C(5, 2)

I can solve problems involving midpoints, medians, and perpendicular bisectors CONT’D

Page 18: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

• STEPS TO FIND EQN OF PERPENDICULAR BISECTOR:• Calculate the midpoint of the line segment• Calculate the slope of the line segment• The slope of the perpendicular bisector is the negative reciprocal

of the slope of the line segment it is bisecting• Plug the slope and the midpoint into y=mx+b• Solve for b• State equation with slope (m) and y-intercept (b)

• Find the equation of the perpendicular bisector of the line segment from A(1, 1) to B(5, 3)

I can solve problems involving midpoints, medians, and perpendicular bisectors CONT’D

Page 19: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can classify triangles given the coordinates of the vertices• The vertices of triangle ABC are A(5, 5), B(-3, -1), and C(1, -3).

Determine what kind of triangle it is.

Page 20: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can classify triangles given the coordinates of the vertices• The vertices of

triangle ABC are A(5, 5), B(-3, -1), and C(1, -3).

Determine what kind of triangle it is.

Page 21: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can verify properties of geometric figures algebraically• The vertices of triangle ABC are A(5, 5), B(-3, -1), and C(1, -3).

Show that the median from vertex C is half as long as the hypotenuse.

Page 22: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can verify properties of geometric figures algebraically CONT’D• Classify the shape with vertices at A(-4, 2), B(2, -5), C(7, -3)

and D(1, 5)

Page 23: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can verify properties of geometric figures algebraically CONT’D• PQRS is a rhombus with vertices at P(3, 3), Q(0, 1), R(3, -1),

and S(6, 1).• Verify that its diagonals bisect each other at right angles.

Page 24: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can determine the shortest distance from a point to a line• …the shortest distance from a point to a line is always the

PERPENDICULAR PATH from the point to the line.

Page 25: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can determine the equation of a circle centered at the origin, given the circle’s radius

• Equation of a circle:

• State the equation of the circle:• (a) centre origin, radius of 8

• (b) centre origin, radius of

Page 26: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can determine the radius of a circle centered at the origin, given the circle’s equation

• Length of a circle’s radius:

• A circle has the equation . Where is its centre? What is its radius?

Page 27: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can sketch a circle, given its equation

• A circle has the equation . Sketch its graph.

Page 28: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can determine the equation of a circle, given a point through which it passes • Find the equation of the circle passing through (-5, 12)

Page 29: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

STUDY• Shapes and their names and properties• Important terms (midpoint, median, perpendicular bisector)• Formulas

Page 30: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

MPM 2D Course ReviewUnit 3: Quadratics (Standard & Factored Form)

Page 31: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can simplify expressions involving exponents

( 48𝑥3 𝑦4−8 𝑥5 𝑦 )3

Page 32: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can expand & simplify polynomials• Distributive property •

• FOIL (first, outside, inside, last) •

Ex.

Page 33: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can factor using GCF

Page 34: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can factor differences of squares

Page 35: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can factor

Page 36: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can factor • 20

Page 37: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve a quadratic equation by factoring

Page 38: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can identify the key features of a graph of a parabola

Page 39: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can graph a parabola (determine the zeros and vertex ) from

𝑦=−𝑥2+6 𝑥−9

Page 40: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can find the equation of a quadratic given its zeros and another point on the parabola

• A parabola has zeros at (-2, 0) and (4, 0), and passes through (2, 16). Find its equation.

Page 41: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve problems involving quadratics• When Kermit the Frog makes a giant leap from one lily pad to

another, he follows a parabolic path. Kermit is in the air for 6 seconds before he makes a safe landing. Kermit knows that after 2 seconds, he is 72 cm high. How high is Kermit at his greatest height?

Page 42: MPM 2D Course Review Unit 1: Linear Systems. I can graph a line 3 ways: Table of values x- and y-intercepts y-intercept and slope Ex. 1) y=-3x+2

I can solve problems involving quadratics• A design engineer uses the equation to model an archway for

the entrance to a fair, where h is the height in metres above the ground, and d is the horizontal distance from the centre of the arch.• How wide and tall is the arch?• For what values of d is the relation valid? Why?• If a width of 2.5 m is needed per line-up at the entrance, how

many line-ups can there be?