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$Molecular Geometry
Molecular geometry as determined by the Valence Shell Electron Pair Repulsion Model (VSEPR model)
Molecular Geometry = three-dimensional arrangement of atoms in a molecule/ion, including bond angles, (bond angles in degrees)
Valence electrons = outer electrons, bonding electrons and lone pair electrons
VSEPR model/theory – molecular geometry is that which minimizes repulsion of valence electrons pairs by having electron pairs as far away from each other as geometrically possible. (Gillespie/Nyholm theory)
a. Double/triple bonds between 2 atoms treated as one location b. VSEPR structure for individual resonance structures
A. Central atom has only bonding pairs/ no lone pairs on central atom: AB2 – AB6 (AB7 has several structures)
Electron pairs arrangement Molecular Geometry
Examples
2 linearBeCl2, HgCl2
3
Trigonal planar
BF3
4
tetrahedral
CH4, NH4+, BF4
5
Trigonal bipyramid
PF5
Equatorial
axail
6SF6, PF6
Cis
trans
octahedralRelative strength of electron-pair repulsion:
Lone pair vs lone pair > lone pair vs bonding pair > bonding pair vs bonding pair. (Lone pair “need more space”; bonding pairs contained between atoms)
ABxEy, A = central atom, B = bonded atoms, E = lone pairs on A:Overall geometry of electron pairs = x + y positionsGeometry of molecule/ion = X positions only; only atoms are measurable.
B. Central atom with Bonding Pairs (B) and Lone pairs (E):
Class, ABxEy Number of elec. pairs
Bonding pairs
Lone pairs
Overall geometry
Molecular Geometry
AB2E
SO2, O2
3 2 1Trigonal planar
Bent molecule
AB3E
NH3
4 3 1Tetrahedral
Trigonal pyramidAB2E2
H2O4 2 2
Tetrahedral
Bent moleculeAB4ESF4, IF4
+, XeO2F2
5 4 1Trigonal bipyramidBond angles120o and 180o
See-saw moleculeAB3E2
ClF3
5 3 2Trigonal bipyramid
T-shaped moleculeAB2E3
XeF2, I3
5 2 3Trigonal bipyramid
Linear
AB5E
BrF5, XeOF4
6 5 1Octahedral
Square pyramidAB4E2
XeF4, ICl4 6 4 2Octahedral
Square planar
Examples:
NH3
AB3E, Overall = tetrahedral; Molecular = trigonal pyramidRepulsion i > ii, so the HNH angle shorter than that normally expected for a tetrahedral structure (HNH = 107.3o)
H2O AB2E2, overall geometry = tetrahedral; molecular
geometry = bent molecule Electron repulsion, I > ii > iiiActual bond angle HOH is 104.5o
SF4 AB4E, 5 pairs trigonal bipyramid FSF bond angle, expected is 120o, but actual one is 116
SO2 or both AB2E. Trigonal planar/bent molecule.
Actual bond angle OSO is 119.5o
Review Procedure
1. Write Lewis structure
2. Count bonding pairs (B) and lone pairs (E) around central atom (A), treating double/triple bonds as 1 bonding pair, to obtain ABxEy formula.
3. Predict overall geometry of electron pairs from x + y.
4. Predict geometry of molecule by B positions in ABxEy, remembering that one pair repulsion stronger than bonding pair repulsion.
ICl4 5 x 7 + 1 = 36 electrons/18 pairsAB4E2 overall = octahedral
Molecular = square planar
Polar (covalent) Bonds/ Dipole Moments
Polar covalent bonds result when electron-pairs are shared between atoms of different electeronegativities (A), and have a partial separation of charge (because of this unequal sharing)
dipole molecule align in an electrical field
Dipole moment, = Q x r|charge| in coulombs, distance in mDebye unit (D), 1D = 3.33 x 10-30 C.m
{electron-positron 100 pm separated = 4.80 D}
Covalent bond between atoms of same element is non polar, because of equally-shared electron pairs: H-H, F-F etc.Homo-nuclear diatomic molecules, = 0Hetero-nuclear diatomic molecules 0 (have dipole moment)
Polyatomic molecules have dipole moment, 0, if:1. has polar covalent bonds;
2. Individual bond moments do NOT cancel in vector addition
CO2, AB2, linear molecule, , , = 0
Non-polar molecule with polar bonds
SO2, AB2E bent molecule, , 0, has dipole moment, is polar molecule
NH3, AB3E, trigonal pyramid, , 0
NF3, , 0, has dipole moment.
ClHC=CHCl, 1, 2, dichloroehtylene (planar molecule)
, 0
= 0, no dipole moment
When all the B atoms the same, the following ABxEy formulas
= 0 for AB2, AB3, AB4, AB5, AB6, AB2E3, AB4E2
0 for AB2E, AB3E, AB2E2, AB4E, AB3E2, AB5E
BF3(AB3), = 0; NF3(AB3E) 0
Care should be taken when considering different B atoms; can have 0.
BF3, BBr3 = 0
But, BFBr2, 0,
Valence Bond Theory
Overlap of atomic orbitals illustrates covalent bonds; H-H
-bondH 1s-1s covalent bond
- bonds – end-on overlap of atomic orbitals along bond axis:
F-F, [He]2s2 2px2 2py2 2pz1 , 2pz-2pz, overlap of same sign
H-F 1s-2pz
Multiple bonds [He] 2s2 2px1 2py
1 2pz1
1 – bond2 - bonds
- bond – parallel or side-by-side overlap of orbitals producing an electron cloud above and below bonding axis but a nodal plane through the axis.
Single bond = – bond, H-H, F-F, H-F etcDouble bond = 1 -bond + 1 -bond, O=C=O etc
Triple bond = 1 -bond + 2 -bonds, -bonds usually slightly weaker than -bonds
Hybridization of Atomic Orbitals
Simple atomic orbitals often suggest wrong number and geometry of bondse.g C [He]2s2 2px1 2py1 – suggests 2 covalent bonds at 90o angle- but CH4, in general CX4, tetrahedral – is observed
Hybridization is a possible explanation
1. Promotion (excitation) of valence electron:[He]2s2 2p2 [He] 2s1 2px
1 2py1 2pz
1 – an allowed excited state that would give 4 covalent bonds, but wrong angles and unequal bonding
2. Hybridization (mixing or linear combination) of valence atomic orbitals [He] 2s1 2px
1 2py1 2pz
1 [He] four (sp3 hybrid orbitals)4
Shape of each sp3 hybrid orbital:
4 equivalent sp3 hybrid orbitals directed to vertices of tetrahedronCH4
Four (Csp3 – H1s) bondsHybridization of 4 atomic orbitals (S, px, py, pz) produces 4 hybrid orbitals (sp3) having correct geometry (tetrahedral) for covalent bonds on central atom with equivalent bonding.
n atomic orbitals n hybrid orbitals
NH3 – use 4 sp3 hybrid orbitals
N – [He] 4 (sp3)5 bond angle – 107.3o
H2O – use 4 sp3 hybrid orbitals: O – [He] 4 (sp3)6 – two covalent bonds + 2 lone pairs of electrons
Sp hybridizationBCl2(g) – linear molecule
Be – [He] 2s2 – promotion [He] 2s1 2pz1
sp linear combination
Two sp hybrid orbitals – orbitals at 180o angle
Sp 2 hybridization
BF3 – trigonal planar
B – [He] 2s2 2px1 [He] 2s1 2px1 2py1 [He] three sp2 hybrid orbitals
Three – bonds (B sp2 – F2pz)
Three sp2 hybrid orbitals directd to points of triangle (120o angles)
Sp3d hybridization
PF5 trigonal bipyramid
P – [Ne] 3s2 3p3 [Ne] 3s1 3px1 3py1 3pz1 3d1 – [Ne] five (sp3d)5
Five sp3d hybrid orbitals directed to vertices of a trigonal bipyramid ; 5 s bonds (Psp3d – F2pz)
Expanded octet/expanded valence shell by atoms having available d orbitals (3rd, 4th period): P, As, Sb, (NOT N), Cl, Br, I (not F)
Sp3d2 hybridization – SF6 octahedral
S: [Ne] 3s2 3p4 [Ne] 3s1 3px1 3py1 3pz1 3x2-y2d1 3dz21
Six covalent bonds (Ssp3d2 – F2pz)
Summary of Hybridization schemes:
Number of Overall geometry Hybridization Valence electrons valence electron pair scheme
2 lnear sp3 trigonal planar sp2
4 tetrahedral sp3
5 trigonal bipyramid sp3d6 octahedral sp3d2
Hybridization procedure
Draw Lewis structures /determine geometry by ABxEy classMatch geometry to hybridization schemeHybridize atomic orbitals on central atom in molecules, never isolated atomsN atomic orbitals used – n hybrid orbitals formed
Energy needed for promotion recovered in bond formationCovalent bonds explained as overlap of orbitals