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= 20 KN/m3 = 32 ° = 20 KN/m2 ru = 0.4 b= 2 Rebanada b (m) h (m) (°) l(m) W (KN) Wsen(a) Wcos(a) 1 2 1.3 -14 2.06 52 -12.6 50.5 2 2 2.5 -4 2.00 100 -7.0 99.8 3 2 3.6 8 2.02 144 20.0 142.6 4 2 4.6 18 2.10 184 56.9 175.0 5 2 4.4 36 2.47 176 103.5 142.4 6 2 2.2 58 3.77 88 74.6 46.6 14.43 235.4 FS = 2.039 α Σ α Σ φ + = Wsen ) ul cos W ´. !"n # ´. c $% "

Metodo de Fellenius(Ejercicios)

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METODO DE FELLENIUS.EJEMPLO =20KN/m3 =32c =20KN/m2ru =0.4b=2Rebanadab (m)h (m)()l (m)W (KN)Wsen(a)Wcos(a)u (KN/m2)Wcos(a)-u*l121.3-142.0652-12.650.510.429.0222.5-42.00100-7.099.82059.7323.682.0214420.0142.628.884.4424.6182.1018456.9175.036.897.6524.4362.47176103.5142.435.255.4622.2583.778874.646.617.6-19.814.43235.4306.3

FS =2.039

EJERCICIO PROPUESTO =16KN/m3 =35c =10KN/m2ru =0.4b=3.15REBANADAb (m)h (m)()l (m)W (KN)Wsen(a)Wcos(a)u (KN/m2)Wcos(a)-u*l13.1516.53.1750.45.750.16.429.823.153.0819.53.34155.23251.8146.319.71280.533.154343.80201.6112.7167.125.669.943.152.751.55.06136.08106.584.717.28-2.715.37276.8177.4FS =1.004