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11 Measurement and geometry Geometry The word ‘geometry’ comes from the Greek word geometria, which means ‘land measuring’. The principles and ideas of geometry are evident in many aspects of our lives. For example, geometry can be seen in the design of buildings, bridges, roads and transport networks.

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Page 1: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

11Measurement and geometry

GeometryThe word ‘geometry’ comes from the Greek wordgeometria, which means ‘land measuring’. The principlesand ideas of geometry are evident in many aspects of ourlives. For example, geometry can be seen in the design ofbuildings, bridges, roads and transport networks.

Page 2: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

n Chapter outlineProficiency strands

11-01 Angle sum of a polygon* U F R C11-02 Exterior angle sum of a

polygon* U F R C11-03 Congruent triangle

proofs* U F PS R C11-04 Proving properties

of triangles andquadrilaterals* U F PS R C

11-05 Similar figures U F R C11-06 Finding unknown sides

in similar figures U F R C11-07 Tests for similar

triangles* U F PS R C

*STAGE 5.2

nWordbankcongruence test One of four tests for proving thattriangles are congruent: SSS, SAS, AAS and RHS

congruent Identical, exactly the same (symbol: ” )

enlargement An increase in the size of a shape

included angle The angle between two given sides of ashape

convex polygon A polygon whose vertices all pointoutwards

regular polygon A polygon with all angles equal and allsides equal, such as an equilateral triangle or a square

scale factor The amount by which a shape has been

enlarged or reduced, equal toimage length

original length

similar To have the same shape but not necessarily thesame size, an enlargement or reduction (symbol: |||)

Shut

ters

tock

.com

/Ser

gey

Kel

in

NEW CENTURY MATHSfor the A u s t r a l i a n C u r r i c u l u m 10

9780170194655

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n In this chapter you will:• (STAGE 5.2) formulate proofs involving congruent triangles and angle properties• solve problems using ratio and scale factors in similar figures• (STAGE 5.2) solve problems involving the angle sum of a polygon and the exterior angle sum

of a convex polygon• (STAGE 5.2) write formal proofs for congruent triangles• (STAGE 5.2) prove properties of triangles and quadrilaterals using congruent triangles• explain similarity and investigate the properties of similar figures• (STAGE 5.2) identify and use the four tests for similar triangles

SkillCheck

1 Find the value of each pronumeral.

117°

a

d e f

b c

25°

w° 74°

62°r°

38°

27°

x°44°

60°

3a°

2a°

2 Find the value of p in each diagram.

101°

114°

a b c

d e f

81°

p° 26°58°

35°

76°80°

68°

37° p° 58°p° 83°21°

Worksheet

StartUp assignment 11

MAT10MGWK10077

Puzzle sheet

Finding angles

MAT10MGPS00026

Video tutorial

Geometry

MAT10MGVT00008

Skillsheet

Starting Geometer’sSketchPad

MAT10MGSS10013

368 9780170194655

Chapter 1 2 3 4 5 6 7 8 9 10 11 12 13 14

Geometry

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3 Match shapes that are congruent.

a b c

g h

d

fe

i j k l

4 Triangles MNP and WXY are similar.

X

Y

WM

NPa List all pairs of matching angles.

b List all pairs of matching sides.

Technology Angle sum of a polygonIn this activity, you will use GeoGebra to find a rule for the angle sum of a polygon.

1 Before you start, remove Axes and click Grid on. Also, click Options Rounding 0 decimalplaces.

2 Click polygon and construct any pentagon.Click Angle and in a clockwise direction,measure the size of each of the five anglesin the pentagon (these are called the interiorangles). Find the total sum of the five interiorangles. Write your answer in your book.

3699780170194655

NEW CENTURY MATHSfor the A u s t r a l i a n C u r r i c u l u m 10

Page 5: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

3 Click Interval between Two Points andfrom only one vertex, draw as manytriangles as possible in your pentagon(as shown below).

4 Copy and complete this table for the above pentagon.

No. of sidesin polygon

Angle sum ofeach triangle

Angle sum of alltriangles in polygon

Angle sum of polygonAngle sum of triangle

5 Repeat Steps 1 and 2 for the following shapes:• regular hexagon (use Regular Polygon to construct it)• regular pentagon• octagon (use Polygon to construct it)• nonagon (9 sides)

6 Continue the table from Step 4 for each shape. Can you see the relationship between thenumber of sides in a polygon (n) and the angle sum of a triangle?

7 Complete the rule for the angle sum of any polygon.

Angle sum of a polygon with n sides ¼ 180 3 (n � ____)

11-01 Angle sum of a polygonStage 5.2

NSW

Technology

GeoGebra: Namingpolygons

MAT10MGTC00008

Ala

my/

Ray

mon

dW

arre

n

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Chapter 1 2 3 4 5 6 7 8 9 10 11 12 13 14

Geometry

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A polygon is any shape with straight sides. A polygon may be either convex or non-convex(concave).

Convex polygon Non-convex polygon

In a convex polygon, all vertices point outwards, all diagonals lie within the shape and all anglesare less than 180�. In a non-convex polygon, some vertices point inwards, some diagonals lieoutside the shape and some angles are more than 180� (reflex angles).A polygon’s name is determined by the number of sides that it has.

Name Number of sidesPentagon 5Hexagon 6Heptagon 7Octagon 8Nonagon 9Decagon 10Hendecagon 11Dodecagon 12

octagon

dodecagonheptagon

Summary

The angle sum of a polygon with n sides is given by the formula A ¼ 180(n � 2)�.This formula applies to both convex and non-convex polygons.

Example 1

Find the angle sum of a 15-sided polygon.

SolutionAngle sum ¼ 180ð15� 2Þ�

¼ ð180 3 13Þ�

¼ 2340�

n ¼ 15

Stage 5.2

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Example 2

Find the number of sides in a polygon that has an angle sum of 1080�.

Solution180ðn� 2Þ ¼ 1080

180n� 360 ¼ 1080

180n ¼ 1440

n ¼ 1440180

¼ 8

[ The polygon has 8 sides (octagon).

Regular polygonsA regular polygon has all its angles and sides equal.For example, a regular hexagon has 6 equal angles and 6 equal sides.A square is a regular polygon but a rhombus is not.

Summary

The size of each angle in a regular polygon with n sides ¼ Angle sumNumber of sides

¼ 180ðn� 2Þ�n

Example 3

Find the size of one angle in a regular pentagon.

SolutionA pentagon has 5 sides (n ¼ 5).

Size of one angle ¼ 180ð5� 2Þ�

5

¼ ð180 3 3Þ�

5¼ 108�

Each angle in a regular pentagon is 108�.

Stage 5.2

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Geometry

Page 8: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

Exercise 11-01 Angle sum of a polygon1 Name each polygon.

a b c

d e f

2 Which polygons from question 1 are:

a convex? b regular?

3 What is the more common name for a regular triangle? Select the correct answer A, B, C or D.

A isosceles B scalene C equilateral D acute

4 Find the angle sum of a polygon with:

a 12 sides b 10 sides c 9 sides d 20 sides e 15 sides.

5 Find the value of each pronumeral.

148°

84°

a

123°

156°

97°

79°76°

68°

81°

135°153°

117° 131°

140°4a°

3a°

97°

137°

128°

114°

w°w°

w° w°

x° y°b c

d e f

6 Find the number of sides in a polygon that has an angle sum of:

a 720� b 3420� c 1980� d 5040� e 1260�.

7 The angle sum of a regular polygon is 2520�.a How many sides does the polygon have?

b Find the size of each angle.

8 Find the size of one angle in a regular

a decagon b octagon c hexagon d dodecagon.

9 How many sides does a regular polygon have if each of its angles is:

a 168�? b 156�? c 172�? d 165.6�?

Stage 5.2

See Example 1

See Example 2

See Example 3

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Page 9: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

Technology Exterior angle sum of a polygonIn this activity, you will use GeoGebra find a rule for the exterior angle sum of a polygon.

1 Before you start, remove Axes and click Grid on. Also, click Options Rounding 0 decimalplaces.

2 Click Polygon and construct any pentagon.

3 Click

To produce the side AE, click a point on AE and then point E.

Investigation: Exterior angle sum of a convex polygon

1 Draw any convex polygon and extend the sidesas shown. Label the vertices A, B, C, etc.

A

BD

E

C

2 Use a protractor to measure all of the exterior angles of the polygon.3 What is the sum of the exterior angles of the polygon?4 Start at A and move around the polygon, turning in the direction indicated at each vertex,

until you return to A, facing the same direction that you started from.5 What must be the sum of the turns in any round trip of a convex polygon?6 Test whether this rule works for a non-convex polygon.

Stage 5.2

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Geometry

Page 10: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

4 Insert New Point on the produced side AE (in diagram shown as point G). Click Angleand in a clockwise direction, measure the size of each of the angles outside the pentagon(these are called the exterior angles). This is shown below as \GED ¼ 60�.

5 Repeat step 3 to produce the remaining 4 sides of the pentagon. Use Angle to find the sizeof each exterior angle. When completed, your diagram should look like the one shownbelow, with 5 exterior angles.

6 Calculate the total sum of the five exterior angles. Write the answer in your book.

7 Copy and complete this table for the above pentagon.

No. of sides in polygon Angle sum of all exterior angles of polygon

Stage 5.2

3759780170194655

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Page 11: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

8 Repeat steps 1 to 6 for the following shapes.• octagon (use Polygon to construct it)• regular hexagon (use Regular Polygon to construct it)• regular heptagon (use Regular Polygon to construct it)

9 Continue the table from step 7 for each shape. What is the exterior angle sum of anypolygon?

10 Complete the rule for the exterior angle sum of any polygon:

Exterior angle sum of a polygon ¼ _______

11 Using the results of the regular polygons from step 8, complete the rule for the exteriorangle of any regular polygon:

Exterior angle of a regular polygon with n sides ¼ _______

11-02Exterior angle sum of a convexpolygon

Summary

The sum of the exterior angles of a convex polygon is 360�.

Example 4

For a regular octagon, find the size of:

Exterior angle

Interior angle

a each exterior angleb each (interior) angle.

Solutiona Sum of exterior angles ¼ 360�

One exterior angle ¼ 360�4 8

¼ 45�

b Each angle ¼ 180� � 45�

¼ 135�(angles on a straight line)

OR : Each angle ¼ 180ð8� 2Þ�

8¼ 135�

Stage 5.2

NSW

Worksheet

Angles in polygons

MAT10MGWK10078

376 9780170194655

Chapter 1 2 3 4 5 6 7 8 9 10 11 12 13 14

Geometry

Page 12: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

Example 5

Find the number of sides in a regular polygon if:

a each exterior angle is 24� b each (interior) angle is 140�.

Solutiona Number of exterior angles ¼ 360 4 24

¼ 15

[ The regular polygon has 15 sides.

b Exterior angle ¼ 180� � 140�

¼ 40�(angles on a straight line)

Sum of exterior angles ¼ 360�Number of exterior angles ¼ 360 4 40

¼ 9[ The regular polygon has 9 sides.

OR:180ðn� 2Þ

n¼ 140

180ðn� 2Þ ¼ 140n

180n� 360 ¼ 140n

40n� 360 ¼ 0

40n ¼ 360

n ¼ 36040

¼ 9[ The regular polygon has 9 sides.

Exercise 11-02 Exterior angle sum of a polygon1 Find the size of each exterior angle in a regular:

a pentagon b dodecagon c 18-sided polygon d hexagon.

2 Find the size of each angle in a regular:

a nonagon b 20-sided polygon c decagon d 30-sided polygon.

3 Find the number of sides in a regular polygon if each exterior angle is:

a 15� b 72� c 20� d 40� e 5� f 12�.

4 Find the number of sides in a regular polygon if each angle is:

a 135� b 144� c 156� d 178� e 165� f 150�.

Stage 5.2

See Example 4

See Example 5

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NEW CENTURY MATHSfor the A u s t r a l i a n C u r r i c u l u m 10

Page 13: Measurement and geometryGeometryweb2.hunterspt-h.schools.nsw.edu.au/studentshared... · 2015. 8. 27. · Dodecagon 12 octagon heptagon dodecagon Summary The angle sum of a polygon

Just for the record The geometry of CanberraCanberra is located 300 km south-west of Sydney and was designed by the American architectWalter Burley Griffin. Construction of Australia’s capital city began in 1913. The ‘centre’ ofCanberra is based on an equilateral triangle, bounded by the ‘sides’ Commonwealth Avenue,Kings Avenue and Constitution Avenue. The smaller ‘Parliamentary triangle’ is bounded byCommonwealth Avenue, Kings Avenue and King Edward Terrace. The axis of symmetry ofthe triangle runs from Parliament House, across Lake Burley Griffin, directly along AnzacParade to the Australian War Memorial.What other geometrical features can you see in Canberra’s design?

11-03 Congruent triangle proofsTwo figures are congruent if they are identical in shape and size. For congruent figures:

• matching sides are equal• matching angles are equal

There are four sets of conditions that can be used to determine if two triangles are congruent.These are called the tests for congruent triangles or congruence tests.

Stage 5.2

Worksheet

Congruent trianglesproofs

MAT10MGWK10079

Worksheet

Congruent triangles

MAT10MGWK00022

Video tutorial

Congruent trianglesproofs

MAT10MGVT10019

Worksheet

Congruent and similartriangle proofs

MAT10MGWK10083

378 9780170194655

Chapter 1 2 3 4 5 6 7 8 9 10 11 12 13 14

Geometry

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Summary

There are four tests for congruent triangles: SSS, SAS, AAS or RHS.Two triangles are congruent if:

• the three sides of one triangleare respectively equal to thethree sides of the other triangle(SSS rule)

• two sides and the includedangle of one triangle arerespectively equal to two sidesand the included angle of theother triangle (SAS rule)

• two angles and one side of onetriangle are respectively equal totwo angles and the matching sideof the other triangle (AAS rule)

• they are right-angled and thehypotenuse and another side ofone triangle are respectivelyequal to the hypotenuse andanother side of the othertriangle (RHS rule).

The congruence symbol ”The symbol for ‘is congruent to’ is a special equals sign, written as ‘”’ (which also means ‘isidentical to’). The two triangles below are congruent, so we can write nABC ” nXYZ, which isread as ‘triangle ABC is congruent to triangle XYZ’.

C

B

A X

Z

Y

When using this notation, we must make sure that the vertices (angles) of the congruent figuresare written in matching order: nABC ” nXYZ means \A ¼ \X, \B ¼ \Y, \C ¼ \Z.To formally prove that two triangles are congruent, we need to use one of the four tests forcongruence SSS, SAS, AAS or RHS.

Stage 5.2

3799780170194655

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Example 6

In the diagram, PQ || LM, QR || MN and QR ¼ MN.Prove that nPQR ” nLMN.

P Q

N

M

R

L

SolutionIn nPQR and nLMN: Identifying the triangles in matching

order of vertices.

QR ¼ MN (given) Stating each part of the congruencetest, giving reasons.

\P ¼ \L (alternate angles, PQ || LM)

\QRP ¼ \MNL (alternate angles, QR || MN)[ nPQR ” nLMN (AAS) Concluding the congruence proof,

stating the test used.

Exercise 11-03 Congruent triangle proofs1 For each set of triangles:

i decide which two are congruent and state the congruence test used

ii use the correct notation to write a congruency statement relating those two triangles.

5 cm

11 cm

a

b

8 cm5 cm

24 mm19 mm

16 mm24 mm

24 mm

16 mm16 mm

86°86°

19 mm

11 cm 11 cm

T

T

X

E

L

P

M

V

R

CE

P S

C

Y

G

A

A

Stage 5.2

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Geometry

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Stage 5.2

d 15 cm

33 cm

15 cm

33 cm15 cm25°20°

20°25°

25°

R

C Q

N

H

T

E

D

C

c 8 cm

6 cm8 cm

8 cm

41°

41°

41° B

AT

E

B

P

X

S

V

2 Prove that nWXY ” nWZY.

Z

X

W

Y

3 In the diagram, EG ¼ EH and DH || FG.Show that nDEH ” nFEG. D

G

F

E

H

4 For this kite ABCD, prove that nABC ” nADC.B

C

D

A

5 If PQ ¼ LQ and NQ ¼ MQ, prove that nPQN ” nLQM.

P

N

Q

L M

6 Prove that nWXY ” nYVW. W

Y

X

V

See Example 6

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Stage 5.2 7 O is the centre of the circle and AB ¼ CD.Prove that nAOB ” nCOD.

AD

B

C

O

8 Prove that nFNM ” nTMN. F

M

N

T

9 If \ABC ¼ \DCB and AB ¼ DC in the diagram,prove that nABC ” nDCB.

A

X

B C

D

10 TS || PL and K is the midpoint of TL. Prove that nTSK ” nLPK. T S

K

P L

11 In the diagram, PW || QT, RW || QV and PQ ¼ QR.Prove that nPVQ ” nQTR.

RP

V

W

T

Q

12 If \DEG ¼ \EDF and GE ¼ FD,prove that nDEG ” nEDF.

G

D

HF

E

13 In nABC, AB ¼ AC and AD?BC. Prove thatnABD ” nACD and hence AD bisects \BAC.

A

CDB

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Geometry

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14 If CX ’ AB, BY ’ AC and XC ¼ YB,prove that nBCX ” nCBY.

CB

YX

A

15 XW ¼ XZ in the isosceles triangle and Y is themidpoint of WZ. Prove that nWYX ” nZYX.

X

ZYW

11-04Proving properties of triangles andquadrilaterals

Properties of triangles and quadrilaterals can be proved using the congruence tests.

Example 7

nABC is an isosceles triangle with AB ¼ AC. D is the midpoint of BC.

a Which congruence test can be used to prove that nABD ” nACD? A

D CB

b Explain why \B ¼ \C.c What geometrical result about isosceles triangles does this prove?

Solutiona For nABD and nACD:

AB ¼ AC (given)AD is common.BD ¼ CD (D is the midpoint of BC)[ The congruence test is SSS.

b \B ¼ \C because they are matching angles of congruenttriangles.

c The angles opposite the equal sides of an isoscelestriangle are equal.

Stage 5.2

Worksheet

Quadrilaterals: True orfalse?

MAT10MGWK00020

Technology

GeoGebra: Makingquadrilaterals

MAT10MGTC00012

Worksheet

Proving properties ofquadrilaterals

MAT10MGWK10080

Animated example

Geometric problemsand proofs

MAT10MGAE00008

Puzzle sheet

Geometrical proofsorder activity

MAT10MGPS10081

Worksheet

Congruent and similartriangle proofs

MAT10MGWK10083

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Example 8

a If LMNP is a rectangle, prove that nPNT ” nMLT. P N

ML

T

b Prove that the diagonals of a rectangle bisect each other.

Solutiona In nPNT and nMLT:

PN ¼ ML (opposite sides of a rectangle)\PNT ¼ \MLT (alternate angles, PN || ML)\PTN ¼ \MTL (vertically opposite angles)[ nPNT ¼ nMLT (AAS)

b [ PT ¼ MT and NT ¼ LT (matching sides ofcongruent triangles)[ T is the midpoint of the diagonals LN and MP.[ The diagonals of a rectangle bisect each other.

Exercise 11-04 Proving properties of triangles andquadrilaterals

1 nABC is an isosceles triangle, with AB ¼ AC. D is the midpoint of BC.a Which congruence test can be used to prove that nABD ” nACD?

b Explain why \ADB ¼ \ADC.

c Hence prove that AD ’ BC. A

D CB

2 In the diagram, \S ¼ \T and WP ’ ST.

S P T

W

a Which congruence test can be used to prove that nSPW ” nTPW?

b Explain why WS ¼ WT.

c What geometrical result about triangles does this prove?

Stage 5.2

See Example 7

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Geometry

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3 nABC is an equilateral triangle (AB ¼ BC ¼ AC). X is the midpoint of BC.

CXB

A

CB

A

Y

a Which congruence test can be used to prove that nABX ” nACX?

b Explain why \B ¼ \C.

c In the second diagram, nABC is redrawn so that Y is themidpoint of AC. Which congruence test can be used toprove that nBAY ” nBCY?

d Is \A ¼ \C? Why?

e Calculate the sizes of the three angles of nABC.

f What geometrical result about equilateral trianglesdoes this prove?

4 In nPMN, \M ¼ \N and YP bisects \MPN.a Explain why \MPY ¼ \NPY.

NYM

P

b Which congruence test can be used to prove thatnPMY ” nPNY?

c Explain why MY ¼ NY.

d Is \PYM ¼ \PYN? Why?

e Prove that PY ’ MN.

5 ABCD is a quadrilateral whose opposite sides are equal.a Prove that nABC ” nCDA.

b Explain why \BAC ¼ \DCA and \BCA ¼ \DAC.

BA

D C

c Hence state why AB || CD and AD || CB.

d What type of quadrilateral is ABCD?

6 WXYZ is a parallelogram whose opposite sides are parallel.

XW

Z Y

a Copy the diagram into your book.

b On your diagram, show two pairs of equalalternate angles.

c Prove that nWXZ ” nYZX.

d Explain why \W ¼ \Y.

e Draw the other diagonal WY and prove thatnWXY ” nYZW.

f Explain why \WXY ¼ \YZW.

g What angle property of a parallelogram does this prove?

Stage 5.2

See Example 8

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7 STUV is a rhombus, so all sides are equal.

S

V U

T

a Prove that nVUS ” nTUS.

b Prove that the diagonal US bisects \VUT and \VST.

8 ABCD is a parallelogram with opposite sides parallel.a Prove that nABD ” nCDB. D C

BA

b Explain why AB ¼ CD and AD ¼ CB.

c What property of a parallelogram does this prove?

9 BEGH is a rhombus (a parallelogram with equal sides) whose diagonals BG and EH

intersect at L.a Prove that nBEL ¼ nGHL.

B

H G

E

L

b Prove that the diagonals of a rhombus bisect each other.

c nBEH is isosceles, so which two angles are equal?

d Hence prove that nBEL ” nBHL.

e Hence prove that the diagonals of a rhombus crossat right angles.

10 ABCD is a kite, so adjacent sides are equal.a Prove that nABD ” nCBD.

A

B

C

D

b Prove that \A ¼ \C.

c Prove that diagonal DB bisects \ADC and \ABC.

d Copy the diagram and draw the other diagonal AC,intersecting DB at point X.

e Prove that nDAX ” nDCX.

f Prove that diagonal DB bisects diagonal AC.

g Prove that DB ’ AC.

Mental skills 11 Maths without calculators

Dividing a quantity in a given ratio1 Study this example.

Divide $5600 between Alice and Peter in the ratio 5 : 3.Total number of parts ¼ 5 þ 3 ¼ 8.1 part ¼ $5600 4 8 ¼ $700Alice’s share ¼ 5 3 $700 ¼ $3500Peter’s share ¼ 3 3 $700 ¼ $2100Check: $3500 þ $2100 ¼ $5600 (original amount)

Stage 5.2

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Technology Properties of similar figuresWe will use GeoGebra to look at the properties of similar figures.

1 Go to Graphics and hide the axes and grid.

2 Construct a 5-sided polygon as shown.

3 To label the sides of the polygon, select Segment a, then select Show Label. Label the othersides of the polygon.

2 Now divide each of these quantities in the given ratio.a Divide $150 between Mark and Jenni in the ratio 2 : 1.b Divide $2100 between Simon and Sunil in the ratio 4 : 3.c Divide $720 between Lisa and Bree in the ratio 2 : 7.d Divide $2000 between William and Adriana in the ratio 1 : 3.e Divide $4500 between Ed and Pete in the ratio 3 : 2.f Divide $3000 between Sharanya and Asam in the ratio 3 : 7.g Divide $3600 between Cindy and Carmen in the ratio 5 : 1.h Divide $1600 between Nancy and John in the ratio 3 : 5.i Divide $990 between Carol and Louis in the ratio 5 : 4.j Divide $4000 between Yvette and Andre in the ratio 1 : 4.k Divide $4900 between Arden and Ivan in the ratio 3 : 4.l Divide $3200 between Tan and Mai in the ratio 5 : 3.

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4 The lengths of the sides of the polygon are shown in the Algebra View, where segment a,with length 4.54, is the side AB.

5 Enlarge the polygon by a scale factor of 2 to obtain the image A0B0C0D0E0 as shown.

The lengths of the sides of the image are shown in the Algebra View. Is the ratio ofmatching sides the same for all sides?

6 Measure the angles of the polygon and its image. (It may be necessary to delete the labelson the sides of the polygon.)

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The angles of the polygon and its image are shown on the diagrams and in the Algebra view.Are the matching angles equal?

7 Repeat the above process for:

a a triangle b a quadrilateral.

8 For figures that are similar:

a are matching angles equal? b are matching sides in the same ratio?

11-05 Similar figuresSimilar figures have the same shape but are not necessarily the same size.When a figure is enlarged or reduced, a similar figure is created. The original figure is called theoriginal, while the enlarged or reduced figure is called the image.The scale factor describes by how much a figure has been enlarged or reduced.

Summary

Scale factor ¼ image lengthoriginal length

• If the scale factor is greater than 1, then the image is an enlargement.• If the scale factor is between 0 and 1, then the image is a reduction.

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Example 9

Find the scale factor for each pair of similar figures.

20 mm 15 mm

a b

20 mm

45 mm27 mm

12 mm

Solutiona Scale factor ¼ 15

20

¼ 34

Image lengthOriginal length

b Scale factor ¼ 4527ðor

2012Þ

¼ 53

Image lengthOriginal length

The similarity symbol |||The symbol for ‘is similar to’ is ‘|||’. As with congruence notation, we must make sure that thevertices (angles) of similar figures are written in matching order.

Summary

If two figures are similar, then:

• the matching angles are equal• the matching sides are in the same ratio

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Example 10

The two quadrilaterals KLMN and PQRT are similar.

K

LM

P

Q

R

TN

a List all pairs of matching sides and matching angles.b Use the correct notation to write a similarity statement relating these two quadrilaterals.

Solutiona By rotating the figure KLMN, its shape can be matched with PQRT.

The pairs of matching sides are: The pairs of matching angles are:

KN and QR

MN and PQ

ML and PT

LK and TR.

\K and \R

\N and \Q

\M and \P

\L and \T.

b \K matches with \R, \L matches with \T, \M matches with \P, \N matches with \Q.

[ KLMN ||| RTPQ Matching order of vertices.

Example 11

Test whether each pair of figures are similar.

30 mm

15 mm

a b

24 mm

20 mm 12 mm

25 mm16 mm

20 mm

107˚ 107˚97˚

97˚

65˚ 65˚26 mm

14 mm

20 mm

10 mm

Solutiona For the two quadrilaterals, matching angles

are equal and the ratios of matching sidesare equal.[ The quadrilaterals are similar.

2016¼ 25

20¼ 30

24¼ 15

12¼ 5

4

b For the two rectangles, matching angles areequal (90�) but the ratios of matching sidesare not equal.[ The rectangles are not similar.

1020¼ 1

2but 14

26¼ 7

13

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Exercise 11-05 Similar figures1 By measurement, find the scale factor for each pair of similar figures.

ba

dc

2 Copy each figure onto graph paper and draw its image using the given scale factor.

a Scale factor ¼ 2 b Scale factor ¼ 2.5

c Scale factor ¼ 12

d Scale factor ¼ 23

See Example 9

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3 For each pair of similar figures:i list all pairs of matching angles

ii list all pairs of matching sides

iii use the correct notation to write a similarity statement relating them.

A

B

T R

W

F K

S

V

Q

B

K

C

N

GP

MJ

C

K

L

MZ

YD

E

G

H

X

W

a b

c d

4 Test whether each pair of figures are similar.

12 mm

b

d

a

c

e f

20 mm

8 mm

15

94

10

6

45 mm

35 mm

20 mm 27 mm

21 mm

6

6

10

30 mm 12 mm

23

× ×

See Example 10

See Example 11

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11-06Finding unknown lengths in similarfigures

Example 12

The two triangles are similar.Find the values of d and k.

42 mm

27 mm

28 mm

44 mmd mm

k mm

SolutionSince the triangles are similar, the ratios of matching sides are equal.

d

44¼ 42

28

d ¼ 4228

3 44

¼ 66

k

27¼ 28

42

k ¼ 2842

3 27

¼ 18

OR

Scale factor ¼ 2842¼ 2

3

d ¼ 44 423

¼ 66

k ¼ 27 323

¼ 18

Example 13

nKLN ||| nPMN. Find the value of y.

K P

LM

Ny

9

18

15

SolutionMPLK¼ PN

KNRatios of matching sides are equal.

y

18¼ 15

24

y ¼ 1524

3 18

¼ 1114

KN ¼ 9 þ 15 ¼ 24

Skillsheet

Finding sides in similartriangles

MAT10MGSS10014

Worksheet

Finding sides in similarfigures

MAT10MGWK10082

Puzzle sheet

Similar triangles

MAT10MGPS00025

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Exercise 11-06 Finding unknown lengths in similarfigures

1 Find the value of every pronumeral in each pair of similar figures.

16 mm

a b

c d

e f

g h

20 mm 15 cm

27 cm 18 cm

45 cm

8 cm

6 cm 16 cm

5 cm8 cm 8 cm11 cm20 mm 16 mm

16 mm

12 mm

10 cm 27 cm

20 cm

15 cm

10 cm

30 mm

12 mm

15 mm

12 mm

35 mm

25 mm

28 mm

w mmm cm

p mm

h mm

q cm

g cm

w cm

y mmb mm t cm u cm

a cm

x mm

×

×

×

×

2 nABC ||| nADE. Find the value of h.

58

7

D

BC

E

A

h

3 nMNP ||| nMWY. Find the value of x.

15

M

P

N W

x

Y12

16

See Example 12

See Example 13

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4 This photograph of theSydney Harbour Bridge hasbeen enlarged so that itslength is 24 cm. If thedimensions of the originalphoto were 15 cm 3 10 cm,what is the width of theenlargement?

15 cm

10 cm

5 A building that is 40 m high castsa shadow 15 m long. At the sametime, the shadow of a tree is 4.5 mlong. What is the height of the tree?

40m

15m 4.5m

6 nWXY ||| nWDE. What is the value of x?Select the correct answer A, B, C or D.

24

1510

W

E

Yx

D

X

A 4 B 6C 8 D 10

7 Katrina is 1.72 m tall and casts a shadowthat is 2.5 m long. At the same time,a flagpole casts a shadow that is3.5 m long. How long is the flagpole?

1.72 m

3.5 m 2.5 m

8 Which two rectangles are similar? Select the correct answer A, B, C or D.

K M N P

A M and N B K and P C M and P D K and N

9 A 2 m high fence casts a shadow of 1.4 m. How long is the shadow cast by a pole that is 3.2 mhigh at the same time?

Shut

ters

tock

.com

/cle

arvi

ewst

ock

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11-07 Tests for similar trianglesThere are four sets of conditions that can be used to determine if two triangles are similar. Theseare called the tests for similar triangles or similarity tests.

Summary

There are four tests for similar triangles.Two triangles are similar if:

• the three sides of one triangle are proportional to the three sides of the other triangle(‘SSS’)

5

4

42

10

8

C

A B

F

D E

• two sides of one triangle are proportional to two sides of the other triangle, and theincluded angles are equal (‘SAS’)

5

3

50

30

C

AB E

F

D

• two angles of one triangle are equal to two angles of the other triangle (‘AA’ or‘equiangular’)

C

AB D

F

E

• they are right-angled and the hypotenuse and a second side of one triangleare proportional to the hypotenuse and a second side of the other triangle (‘RHS’).

615

5

2

Stage 5.2

Worksheet

Congruent and similartriangle proofs

MAT10SPWK10083

equiangular means ‘equalangles’

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Example 14

Which test can be used to prove that each pair of triangles are similar?

1511.25

8

8

15

24

5

187.5

5

12

a

c

b

d

9

6

12

105°

61°

61° 44°44°

105°

Solutiona Two pairs of angles are equal, or equiangular (‘AA’).

b Two pairs of matching sides are in the same ratio and theincluded angles in both triangles are equal (‘SAS’).

155¼ 24

8¼ 3

c Both have right angles, and the pairs of hypotenuses and secondsides are in the same ratio (‘RHS’).

7:55¼ 18

12¼ 3

2

d All three pairs of matching sides are in the same ratio (‘SSS’). 11:2515¼ 9

12¼ 6

8¼ 3

4

Exercise 11-07 Tests for similar triangles1 Which test can be used to prove that each pair of triangles are similar?

72°

a b

c d

72°

34°

34°

59°

12

6

168

59°

15.5

119 18

22

3156°

56°

e f

12

1912

9

9

14.2526

1512

20.8

Stage 5.2

See Example 14

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g h

i j

67° 67°27.514.4

22

20

18

16

81°

81°

18.2

21

30

268

10 23

13

10

6

813

2 For each set of triangles, find the pair of similar triangles.

a

b

c

47°

47°47°

47°

18

2436

32

1620

1410

1714

10.5

7.58.57

5

24

20

12

16

129 14

10 8

11.5

31.5

28

18D

CBA

AB C D

DCBA

3 Use the correct notation to write a similarity statement relating each pair of similar triangles.

a b

c d

52°

128°

128°

25°25°

52°

1013 10.4 15

1112.5

20 14

21

17.515.4

10.5

8

U

C

AB

15

H K D

M

T

P

Q

L

A

T

WS

VNG

H

PE

WY

Stage 5.2

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Power plus

1 a Explain why \KMN ¼ \KRP. K

RPNM

b Prove that nKMN ” nKRP.c Hence prove that KN ¼ KP and that nKNP

is an isosceles triangle.

2 nJDC ||| nJLP. Find the value of x.

8

x

L

D

J

C

P24

12

3 G and H are the midpoints of CD and CE

respectively. Prove that:

a nCGH ||| nCDE

b GH || DE

c GH ¼ 12

DE E

H

C

G

D

4 a Which similarity test proves that nSTY ||| nSVW?b Find the value of y.

S T y V

Y

W

7

12

10

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Chapter 11 review

n Language of maths

AAS angle sum congruence test congruent (”)

convex polygon enlargement equiangular exterior angle

hypotenuse image included angle matching

original polygon proof proportional

reduction regular polygon RHS SAS

scale factor similar (|||) similarity test SSS

1 What is a convex polygon?

2 Explain the difference between the interior and exterior angles of a polygon.

3 What is the symbol and meaning of ‘is similar to’?

4 What happens to a figure that is changed by a scale factor of 12?

5 What are the four tests for similar triangles?

6 What is the meaning of the ‘A’ in the SAS test for congruent triangles?

7 What does equiangular mean in the similarity tests?

n Topic overview

Copy and complete this mind map of the topic, adding detail to its branches and using pictures,symbols and colour where needed. Ask you teacher to check your work.

Exterior angle sumof a polygon Congruent triangle

proofs

Angle sum of apolygon

Tests for similartriangles

Finding unknownsides in similar

figures

Similar figures

Proving properties oftriangles andquadrilaterals

GEOMETRY

Puzzle sheet

Geometry crossword

MAT10MGPS10084

Quiz

Geometry

MAT10MGQZ00008

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1 Find the angle sum of a polygon with:

a 15 sides b 24 sides c 12 sides d 48 sides

2 Find the size of one angle in a regular 15-sided polygon.

3 The angle sum of a polygon is 6120�. How many sides does the polygon have?

4 Find the number of sides in a regular polygon if each exterior angle is:

a 10� b 24� c 45� d 15�

5 Each angle of a regular polygon is 162�. How many sides does the polygon have? Select thecorrect answer A, B, C or D.

A 18 B 20 C 22 D 24

6 Which congruence test (SSS, SAS, AAS or RHS) can be used to prove that each pair oftriangles are congruent?

cba

5

58

878°

78°

60°

60°

8 cm 8 cm

7 In nWXY, \W ¼ \X and YZ ’ WX. Prove that nWZY ” nXZY.

WZ

X

Y

8 PNML is a rectangle.

M

NP

L

T

a Which congruence test can be used to prove thatnPML ” nNLM?

b Hence explain why PM ¼ NL.c What geometrical result about rectangles does this prove?

9 Calculate the scale factor between each pair of similar figures.

ba

50 mm 40 mm3 cm

5 cm

Stage 5.2

See Exercise 11-01

See Exercise 11-01

See Exercise 11-01

See Exercise 11-02

See Exercise 11-02

See Exercise 11-03

See Exercise 11-03

See Exercise 11-04

See Exercise 11-05

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10 Test whether each pair of figures are similar.

15

27 18

10 1622

9 12

15

27.5

11.25

20

a b

11 Find the value of the pronumeral in each pair of similar figures.

ba

dc

7 cm

10 cm k cm

9 cm

6 mm

9 mm

d mm

4 mm

y m

10 m

6 m

7 m

x cm

11 cm

6 cm

3 cm

12 If nABE ||| nACD, find the value of d.

d cm

7 cm 9 cm

5 cm

A

B

C

DE

13 Which test can be used to prove that each pair of triangles are similar?

13.5

1518

2047°

47°

10

30

18

16 23 22°

121°

22°

121°

a b c

See Exercise 11-05

See Exercise 11-06

Stage 5.2

See Exercise 11-06

See Exercise 11-07

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