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ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected])
ME 012 Engineering Dynamics
Lecture 19
Rigid Body Motion, Translation, and Rotation About a Fixed Axis
(Chapter 16, Sections 1, 2, and 3)
Tuesday,
Apr. 02, 2013
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 2
REMAINING COURSE MATERIAL
Chapter 16: Planar Kinematics of a Rigid Body
• 16.1 Rigid-Body Motion
• 16.2 Translation
• 16.3 Rotation About a Fixed Axis
• 16.4 Absolute Motion Analysis
• 16.5 Relative Motion Analysis: Velocity
• 16.6 Instantaneous Center of Zero Velocity
• 16.7 Relative Motion Analysis: Acceleration
Chapter 17: Planar Kinematics of a Rigid Body: Force and Acceleration
• 17.1 Moment of Inertia
• 17.2 Planar Kinetic Equations of Motion
• 17.3 Equations of Motion: Translation
• 17.4 Equations of Motion: Rotation About a Fixed Axis
• 17.5 Equations of Motion: General Plane Motion
Today’s
Lecture
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 3
Analyze the kinematics of a rigid body undergoing planar translation or rotation about a
fixed axis.
In-Class Activities :
• Applications
• Types of Rigid-Body Motion
• Planar Translation
• Rotation About a Fixed Axis
• Problem Solving
TODAY’S OBJECTIVE
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 4
Passengers on this amusement ride are
subjected to curvilinear translation since
the vehicle moves in a circular path but
always remains upright.
If the angular motion of the rotating arms
is known, we can then determine the
velocity and acceleration experienced by
the passengers.
Gears, pulleys and cams, which rotate
about fixed axes, are often used in
machinery to generate motion and
transmit forces. The angular motion of
these components must be understood to
properly design the system.
APPLICATIONS
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 5
16.1 Rigid Body Motion
We will now start to study rigid body motion. The analysis will be limited to planar motion.
For example, in the design of gears, cams, and links in machinery or mechanisms, rotation of
the body is an important aspect in the analysis of motion.
• There are cases where an object cannot be treated as a particle.
• In these cases the size or shape of the body must be considered.
• Also, rotation of the body about its center of mass requires a different approach.
A body is said to undergo planar motion when all parts of the body move along paths
equidistant from a fixed plane.
Why rigid body motion analysis?
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 6
There are three types of planar rigid body motion:
16.1 Rigid Body Motion
1) Translation (Rectilinear and Curvilinear)
2) Rotation about a fixed axis 3) General plane motion
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 7
Translation: Translation occurs if every line segment on the body remains parallel to its
original direction during the motion. When all points move along straight lines, the
motion is called rectilinear translation. When the paths of motion are curved lines, the
motion is called curvilinear translation.
16.1 Rigid Body Motion
TRANSLATION
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 8
General plane motion: In this case, the body
undergoes both translation and rotation.
Translation occurs within a plane and rotation
occurs about an axis perpendicular to this plane.
Rotation about a fixed axis: In this case, all the particles of the
body, except those on the axis of rotation, move along circular
paths in planes perpendicular to the axis of rotation.
16.1 Rigid Body Motion
ROTATION ABOUT A FIXED AXIS
GENERAL PLANE MOTION
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 9
• The wheel and crank undergo rotation about a fixed axis. In this case, both axes of
rotation are at the location of the pins and perpendicular to the plane of the
figure.
• The piston undergoes rectilinear translation since it is constrained to slide in a
straight line.
• The right connecting rod undergoes curvilinear translation, since it will remain
horizontal as it moves along a circular path.
• The left connecting rod undergoes general plane motion, as it will both translate
and rotate.
An example mechanism of bodies undergoing the three types of motion:
16.1 Rigid Body Motion
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 10
16.2 Rigid-Body Motion: Translation
The positions of two points � and � on a translating
body can be related by:
Note, all points in a rigid body subjected to translation move with the
same velocity and acceleration.
The velocity at B is:
POSITION
VELOCITY
ACCELERATION
�� = ��+ ��/�
where �� & �� are the absolute position vectors
defined from the fixed x-y coordinate system, and
��/� is the relative-position vector between � and �.
�� = �� +��/�
�
Now drB/A/dt = 0 since rB/A is constant, ergo, vB = vA
By following similar logic, aB = aA.
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 11
16.3 Rigid-Body Motion: Rotation About a Fixed Axis
When a body rotates about a fixed axis, any point P in the body
travels along a circular path. Three basic quantities describe angular
motion.
• Angular velocity ( ): obtained by taking the time derivative of
angular displacement:
ANGULAR MOTION
• Angular acceleration (�): if positive, accelerating, if negative,
decelerating:
• Angular position (�): angular position of radial line �. The change
in angular position, �, is called the angular displacement, with
units of either radians or revolutions. They are related by:
1 revolution = 2π radians
=�
�[rad/s] + (normally)
� =
�=��
��
• Useful relation between the three quantities:
�� =
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 12
If the angular acceleration of the body is constant, � = ��, the
equations for angular velocity and acceleration can be integrated to
yield the set of algebraic equations below:
where �� and � are the initial values of the body’s angular
position and angular velocity.
16.3 Rigid-Body Motion: Rotation About a Fixed Axis
= � + ���
� = �� + �� +1
2���
�
� = �� + 2�� � − ��
Note these equations are very similar to the constant acceleration
relations developed for the rectilinear motion of a particle.
CONSTANT ANGULAR ACCELERATION
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 13
The magnitude of the velocity of P is equal to r (the text
provides the derivation). The velocity’s direction is tangent to
the circular path of P.
In the vector formulation, the magnitude and direction of vcan be determined from the cross product of � and rrrr�. Hererrrr� is a vector from any point on the axis of rotation to P.
vvvv = � × rrrr� = � × rrrr
The direction of v is determined by the right-hand rule.
16.3 Rigid-Body Motion: Rotation About a Fixed Axis
MOTION OF POINT P: POSITION
MOTION OF POINT P: VELOCITY
Scalar form:
Vector form:
v = �
The position of P is defined by the position vector r which
extends from O to P.
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 14
The acceleration of P is expressed in terms of its normal (aaaa�) and tangential (aaaa�) components.
The tangential component, at, represents the time rate of
change in the velocity's magnitude. It is directed tangent to
the path of motion.
The normal component, aaaa� , represents the time rate of
change in the velocity’s direction. It is directed toward the
center of the circular path.
MOTION OF POINT P: ACCELERATION
16.3 Rigid-Body Motion: Rotation About a Fixed Axis
Scalar form:
Vector form: aaaa� = × �� = × �
aaaa� = �× � × �� = − ��
a� = �r
Scalar form:
Vector form:
a� = �r
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 15
Using the vector formulation, the acceleration of P can also be
defined by differentiating the velocity.
It can be shown that this equation reduces to the following
vector form:
The magnitude of the acceleration vector is:
16.3 Rigid-Body Motion: Rotation About a Fixed Axis
MOTION OF POINT P: ACCELERATION (cont.)
a = a�� + a�
�
! =�
�=�
�× �� +� ×
��
�
! = × �� +� × �× ��
! = × �� − ��� = aaaa� + aaaa�
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 16
ROTATION ABOUT A FIXED AXIS: PROCEDURE
• Establish a sign convention along the axis of rotation.
• Alternatively, the vector form of the equations can be used (with i, j, kcomponents).
• If � is constant, use the equations for constant angular acceleration.
• If a relationship is known between any two of the variables (�, , �,or �), the other
variables can be determined from the equations:
• To determine the motion of a point, the scalar equations can be used:
=�
�� =
��� =
! = × �� − ��� = aaaa� + aaaa�
vvvv = � × rrrr� = � × rrrr
v = � a� = �r a� = �r a = a�� + a�
�
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 17
Example 1
The motor M begins rotating at an angular rate
= 4 1 − %&� . If the pulleys and fan have the radii of �' = 1
in, �� = 4 in, and �( = 16 in, determine the magnitudes of the
velocity and acceleration of point P on the fan blade when
� = 0.5 s. Also, what is the maximum speed of this point?
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 18
Example 1: Solution
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 19
Example 2
The engine shaft S on the lawnmower rotates at a constant
angular rate � = 40 rad/s. Determine the magnitudes of
the velocity and acceleration of point P on the blade and
the distance P travels in time � = 3 s. The shaft S is
connected to the driver pulley A, and the motion is
transmitted to the belt that passes over the idler pulleys at
B and C and to the pulley at D. This pulley is connected to
the blade and to another belt that drives the other blade.
Let �� = 200 mm, �� = 75mm, and �. = 50 mm.
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 20
Example 2: Solution
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 21
Example 3
For a short time a motor of the random-orbit sander drives the
gear � (�� = 10 mm) with an angular velocity � = 40 �( + 6� .
This gear is connected to gear � (�� = 40 mm), which is fixed
connected to the shaft 01. The end of this shaft is connected to
the eccentric spindle 23 and pad 4, which causes the pad to orbit
around shaft 01 at a radius �5 = 15mm. Determine the
magnitudes of the velocity and the tangential and normal
components of acceleration of the spindle 23 at time � = 2 s
after starting from rest.
ME 012 Engineering Dynamics: Lecture 19
J. M. Meyers, Ph.D. ([email protected]) 22
Example 3: Solution