24
Simple machine 1. In a simple machine, whose velocity ratio is 30, a load of 2400 N is lifted by an effort of 150 N and a load of 3000 N is lifted by an effort of 180 N. Find the law of machine (a) P = 0.50W + 144 (b) P = 0.60W + 25 (c) P = 0.05 W + 144 (d) P = 0.05 W + 30 2. In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10,000 N by a distance of 0.8 m. Determine the velocity ratio and mechanical advantage. (a) 10 and 35 (b) 20 and 35 (c) 10 and 25 (d) 25 and 20 3. In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10,000 N by a distance of 0.8 m. Determine the effort lost in friction. (a) 100 N (b) 10 N (c) 278 N (d) 136 N 1

MCQ Questions From Simple Machine FINAL MODIFICATION

  • Upload
    fotick

  • View
    251

  • Download
    13

Embed Size (px)

Citation preview

Simple machine1. In a simple machine, whose velocity ratio is 30, a load of 2400 N is lifted by an effort of 150 N and a load of 3000 N is lifted by an effort of 180 N. Find the law of machine (a) P = 0.50W + 144(b) P = 0.60W + 25(c) P = 0.05 W + 144(d) P = 0.05 W + 302. In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10,000 N by a distance of 0.8 m. Determine the velocity ratio and mechanical advantage.(a) 10 and 35 (b) 20 and 35(c) 10 and 25(d) 25 and 203. In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10,000 N by a distance of 0.8 m. Determine the effort lost in friction.(a) 100 N(b) 10 N(c) 278 N(d) 136 N4. In a simple machine, whose velocity ratio is 30, a load of 2400 N is lifted by an effort of 150 N and a load of 3000 N is lifted by an effort of 180 N. calculate the load that could be lifted by a force of 200 N. (a) 4400 N(b) 1400 N(c) 2400 N(d) 3400 N5. In a simple machine, whose velocity ratio is 30, a load of 2400 N is lifted by an effort of 150 N and a load of 3000 N is lifted by an effort of 180 N. calculate the amount of effort wasted in overcoming the friction using a force of 200 N. (a) 86.67 N(b) 72.67 N(c) 96.67 N(d) 52.67 N6. In a lifting machine an effort of 150 N raised a load of 7700 N. What are the mechanical advantage and velocity ratio if the efficiency at this load is 60%.(a) 51.33 and 85.55(b) 33.51 and 55.85(c) 56.23 and 88.75(d) 23.56 and 75.887. A load of 13,200 N is raised by an effort of 250 N, what is the efficiency? If VR is 85.55(a) 61.72%(b) 48.27%(c) 86.67%(d) 54.33%8. in an ideal machine,(a) Velocity Ratio > Mechanical Advantage(b) Velocity Ratio =0.5 X Mechanical Advantage(c) Velocity Ratio < Mechanical Advantage(d) Velocity Ratio = Mechanical Advantage9. From the law of machine, for an ideal machine, the intercept is(a) 0(b) less than 0(c) always greater than 0(d) 110. From the relations below which one is correct, for an ideal machine?(a) W/P=2.VR(b) W/P= VR(c) W/P= 0.5VR(d) VR =1.5W/P11. Ideal Load can be expressed by(a) Wi = VR 2P(b) Wi = VR P(c) Wi = VR P2(d) Wi = VR 0.5P12. Ideal Effort can be expressed by(a) Pi =2W/VR(b) Pi =W/VR(c) Pi =W2/VR(d) Pi =0.5W/VR13. In an ideal machine,(a) Output of a machine > Input of a machine(b) Output of a machine =0.5 X Input of a machine(c) Output of a machine < Input of a machine(d) Output of a machine = Input of a machine14. In practice, why it is difficult to get an ideal machine?(a) Work done is utilised to overcome frictional resistance.(b) Useful work done in lifting the load is reduced.(c) It occurs the reduction of efficiency.(d) All these reasons are valid.15. The law of machine can be expressed mathematically in the form of(a) Parabola starts from origin(b) Parabola does not start from origin(c) Straight line(d) Any of these 16. In practice, maximum mechanical advantage equals to (a) 1/m2(b) 1/m X 1/VR(c) 1/m(d) 1/VR17. From the law of machine, C/W which is in denominator, (a) Increases and hence mechanical advantage increases.(b) Decreases and hence efficiency increases.(c) Decreases and hence mechanical advantage increases.(d) As the load increases remains same.18. The variation of mechanical advantage with respect to load(a) Parabola starts from origin(b) Parabola does not start from origin(c) Straight line(d) Any of these 19. The variation of the efficiency with load (a) Parabola starts from origin(b) Parabola does not start from origin(c) Straight line(d) Any of these 20. The velocity ratio (VR) for a machine is(a) Always constant(b) Varies with effort (P)(c) Varies with machine input(d) Varies with machine output21. Which one is correct below for a simple machine?(a) Variation of efficiency with load is similar to the variation of mechanical advantage with the load. (b) Variation of efficiency with load is similar to the variation of velocity ratio with the load.(c) Variation of efficiency with load is similar to the variation of machine output with the load.(d) Variation of efficiency with load is similar to the variation of machine input with the load.22. Effort wasted in overcoming the friction can be given as(a) Actual effort - Ideal effort(b) Actual effort - Ideal load(c) Ideal effort - Actual effort(d) Actual load - Ideal load23. The efforts required for lifting various loads by a lifting machine is shown by the plot below, Determine the law of machine, if the velocity ratio is 25. P and W are in KN.

(a) P = 0.06 W + 10(b) P = 0.60 W + 20(c) P = 0.09 W + 10(d) P = 0.90 W + 2024. In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10 KN by a distance of 0.8 m. Determine the velocity ratio, mechanical advantage and efficiency of the machine respectively.(a) 25, 20 and 80%(b) 25, 50 and 70%(c) 25, 50 and 80%(d) 25, 20 and 70%25. In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10 KN by a distance of 0.8 m. Determine effort lost in friction.(a) 100 N(b) 100 KN(c) 400 N(d) 400 KN26. In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10 KN by a distance of 0.8 m. Determine frictional resistance.(a) 2500 N(b) 12500 N(c) 1250 N(d) 25000 N27. Frictional resistance can be given as(a) Actual effort - Ideal effort(b) Actual effort - Ideal load(c) Ideal effort - Actual effort(d) Ideal load - Actual load28. In a simple machine, whose velocity ratio is 30, a load of 2400 N is lifted by an effort of 150 N and a load of 3000 N is lifted by an effort of 180 N. Calculate the load that could be lifted by a force of 200 N. (a) 3400 N(b) 2400 N(c) 4400 N(d) 1400 N29. In a simple machine, whose velocity ratio is 30, a load of 2400 N is lifted by an effort of 150 N and a load of 3000 N is lifted by an effort of 180 N. Calculate the amount of effort wasted in overcoming the friction.(a) 86.67 N(b) 66.67 N(c) 33.67 N(d) 56.67 N30. In a lifting machine an effort of 150 N raised a load of 7700 N. The efficiency at this load is 60%, by the same machine, a load of 13,200 N is raised by an effort of 250 N; calculate the maximum mechanical advantage and the maximum efficiency.(a) 55(b) 44(c) 66(d) 3331. In a lifting machine an effort of 150 N raised a load of 7700 N. The efficiency at this load is 60%, by the same machine, a load of 13,200 N is raised by an effort of 250 N; calculate the maximum efficiency.(a) 64.29%(b) 44.22%(c) 76.85%(d) 52.36%32. A simple lifting machine will be reversible or self-locking solely based on its (a) Efficiency(b) Input to the machine(c) Output to the machine(d) Distance moved by effort33. The law of machine can be expressed for an ideal machine as 34. A lifting machine is self-locking if its efficiency is (a) Greater than 50 per cent(b) Less than 50 per cent (c) Greater than 100 per cent(d) Less than 100 per cent35. In a lifting machine, the condition for the reversibility is (a) Output > Frictional resistant(b) Output < Frictional resistant(c) Effort wasted in overcoming the friction < output(d) Input > Frictional resistant36. In a lifting machine having velocity ratio is 30; a load of 5000 N is lifted with an effort of 360 N. Determine whether it is self-locking or reversible machine. How much is the frictional resistance? (a) Self-locking machine(b) Reversible machine(c) Ideal machine(d) None of these37. In a lifting machine having velocity ratio is 27.778; a load of 5000 N is lifted with an effort of 360 N. Determine whether it is (a) Self-locking machine(b) Reversible machine(c) Ideal machine(d) None of these38. In a lifting machine having velocity ratio is 30; a load of 5000 N is lifted with an effort of 360 N. How much is the frictional resistance? (a) 5.8 KN(b) 3.2 KN(c) 8.3 KN(d) 9.4 KN39. From the maximum M.A. and the maximum efficiency relations which of the following is not correct?(a) M.A. increases with load,(b) Efficiency decreases with load,(c) M.A. will be maximum at a very high value of load,(d) Efficiency will be maximum at a very high value of load.40. In a lifting machine a load of 100 N is moved through a distance of 5 cm, by an effort P moving through a distance of 80 cm. Calculate the value of P if the efficiency of the machine is 60%.(a) 10.42 N(b) 18.68 N(c) 43.26 N(d) 25.34 N41. A machine raised a load of 360 N through a distance of 200 mm. The effort, a force of 60 N moved 1.8 m during the process. Calculate Efficiency at this load.(a) 66.66%(b) 44.67%(c) 55.66%(d) 86.66%42. A machine raised a load of 360 N through a distance of 200 mm. The effort, a force of 60 N moved 1.8 m during the process. Calculate the effort lost in friction.(a) 20 N(b) 28 N(c) 10 N(d) 35 N43. A machine raised a load of 360 N through a distance of 200 mm. The effort, a force of 60 N moved 1.8 m during the process. Calculate the frictional resistance in terms of load.(a) 180 N(b) 850 N(c) 260 N(d) 440 N44. The law of a certain lifting machine is P =W/50+ 1.5. The velocity ratio of the machine is 100. Determine the effort required to overcome friction while lifting a load of 150 N.(a) 3N(b) 30 N(c) 6 N(d) 60 N45. The law of a certain lifting machine is P =W/50+ 1.5. The velocity ratio of the machine is 100. Find the maximum possible mechanical advantage and maximum possible efficiency of the machine.(a) 50 and 50%(b) 50 and 60%(c) 60 and 50%(d) 60 and 60%46. What load will be lifted by an effort of 12 N if the velocity ratio is 18 and the efficiency of the machine at this load is 60%.(a) 130N(b) 260 N(c) 65 N(d) 390 N47. A load will be lifted by an effort of 12 N, the velocity ratio is 18 and the efficiency of the machine at this load is 60%, if the machine has a constant frictional resistance, determine the law of machine.(a) P = W/18 + 4.8(b) P = W/8 + 6.4(c) P = W/14 + 8.2(d) P = W/10 + 7.648. In a lifting machine, the efforts required to lift loads of 20 N and 30 N were 5 N and 6 N respectively. If the velocity ratio of the machine is 20, determine the law of the machine.(a) P = W/10 + 3.0(b) P = W/20 + 6.0(c) P = W/10 + 4.5(d) P = W/20 + 1.549. In a lifting machine, the efforts required lifting loads of 20 N and 30 N were 5 N and 6 N respectively. If the velocity ratio of the machine is 20, determine efficiencies corresponding to loads of 20 N and 30 N,(a) 20 %and 25%(b) 35% and 55%(c) 30% and 50%(d) 60% and 65%50. In a lifting machine, the efforts required lifting loads of 20 N and 30 N were 5 N and 6 N respectively. If the velocity ratio of the machine is 20, determine effort lost in friction in both cases of 20 N and 30 N,(a) 4 N and 4.5 N(b) 4.5 N and 5 N(c) 5.5 N and 6 N(d) 6.5 N and 7 N51. In a lifting machine, the efforts required lifting loads of 20 N and 30 N were 5 N and 6 N respectively. If the velocity ratio of the machine is 20, determine Maximum possible efficiency of the machine,(a) 50 %(b) 46.2 %(c) 100 %(d) 66.67 %52. The law of a machine taken from the load (W) versus effort (P) graph, where W and P are in N is W = 3P 16, the effort required to operate the machine at no load, is(a) 5.33 N(b) 3.69 N(c) 6.67 N(d) 8.86 N53. In the P = mW + C of a lifting machine, C represents (a) Effort lost in friction(b) Frictional load(c) Effort required under no load condition(d) Effort required under maximum load conditionAns: (c)55. In a simple whose VR is 6, an effort of 20 N was able to lift a load of 100N, find effort lost in friction. (a) 3.33N(b) 4.44N(c) 5.57N(d) 6.67NAns: (a)56. In a simple whose VR is 6, an effort of 20 N was able to lift a load of 100N, find the frictional load. (a) 120 N(b) 240 N(c) 20 N(d) 40 NAns: (c)57. In a simple whose VR is 18, and at a particular load the efficiency is 60%, effort required is 12 KN. If the machine has a constant frictional resistance, determine the law of machine.(a) P = W/12 + 4.8 (b) P = W/18 + 3.6(c) P = W/18 + 4.8(d) P = W/12 + 3.6Ans: (c)58. What is the principle feature of a simple machine?(a) P > W (b) P < W(c) P = W(d) None of theseAns: (b)59. Efficiency of a simple machine can be given as(a) Output energy/ Input energy (b) Output power/ Input power(c) Output work/ Input work(d) May be all of theseAns: (d)60. When an effort of 280 N is applied to a machine, it is found that 25% of the effort is lost in friction, the VR is 12. Find the load which can be lifted and the efficiency at this load.(a) 8.24 KN and 85%(b) 4.82 KN and 65%(c) 6.36 KN and 55%(d) 2.52 KN and 75%Ans: (d)61. When an effort of 280 N is applied to a machine, it is found that 25% of the effort is lost in friction, the VR is 12. Find the load which can be lifted and the efficiency at this load.(a) 8.24 KN and 85%(b) 4.82 KN and 65%(c) 6.36 KN and 55%(d) 2.52 KN and 75%Ans: (d)

62. In a simple whose VR is 6, an effort of 20 N was able to lift a load of 100N, find the frictional load. (a) 120 N(b) 240 N(c) 20 N(d) 40 NAns: (c)63. In a simple machine an effort of 100 N is required to lift a load of 900 N. It is found that the effort has to move through a distance of 75 cm, while load moves through a height 3 cm, determine the work done in lifting the load through 30 cm.(a) 27 KN cm(b) 24 KN cm(c) 21 KN cm(d) 42 KN cmAns: (a)64. In a simple machine an effort of 100 N is required to lift a load of 900 N. It is found that the effort has to move through a distance of 75 cm, while load moves through a height 3 cm, determine the distance described by the effort while the load moves through 30 cm.(a) 750 cm(b) 370 cm(c) 240 cm(d) 420 cmAns: (a)65. In a simple machine an effort of 100 N is required to lift a load of 900 N. It is found that the effort has to move through a distance of 75 cm, while load moves through a height 3 cm, determine the effort required to lift the load of 900 N under frictionless condition.(a) 12 N(b) 24 N (c) 36 N(d) 48 NAns: (c)66. Which one below is an irreversible simple machine?(a) Pulley(b) Wheel and axel(c) Screw jack(d) Inclined planeAns: (c)67. In a simple machine an effort of 50 N is required to lift a load of 500 N. It is found that the effort has to move through a distance of 60 cm, while load moves through a height 6 cm, determine the type of this machine.(a) Actual machine(b) Ideal machine(c) Reversible machine(d) Self locking machineAns: (b)68. In a simple machine VR is 25, lifts a load of 20 N on application of an effort of 20 N, calculate frictional loss of the machine.(a) 300 N(b) 370 N(c) 240 N(d) 420 NAns: (a)69. The efficiency of a simple machine is the ratio of (a) Output to input (b) Work done by it to the work done on it.(c) Its mechanical advantage to its velocity ratio(d) All of these are trueAns: (d)70. The efficiency of a simple machine is kept constant, then its velocity ratio is directly proportional to its(a) Maximum efficiency(b) Work done by the effort.(c) Mechanical advantage (d) Effort lost in frictionAns: (c)71. In a simple lifting machine a weight of 1 KN is lifted by an effort of 25 N. While weight moves up by 100 mm, the point of application of the effort moves by 8 m. The machine has an efficiency of(a) 50 %(b) Less than 50 %(c) More than 50 %(d) 100 %Ans: (a)72. In a simple machine VR is 50, lifts a load of 4 KN on application of an effort of 100 N, What effort should be applied, so that the machine is at the point of reversing?(a) 80 N(b) 160 N(c) 240 N(d) 320 NAns: (b)73. In a simple machine VR is 14, lifts a load of 315 N on application of an effort of 25 N, Find the difference between frictional load to effort lost in friction(a) 1N(b) 2.5 N(c) 1.5 N(d) 3.5 NAns: (a)

19