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2
Warm Up 13.5
1. Solve triangle ABC.
2. Solve triangle ABC with B = 41°, C = 90°, and c = 22.
b = 13A
B
C
ac
33°
4
The Law of Sines
Law of Sines
In any triangle ABC, with sides a, b, and c,
.sinsinsin Cc
Bb
Aa
.sinsinsincC
bB
aA
C
BA
ab
c
5
Use of Law of Sines
Use Law of Sines when we know:
One side and two angles SAA or ASA
Two sides and an angle opposite SSA This may lead to more than one solution.
Recall from geometry – SAA and ASA prove triangle congruence, but SSA doesn’t.
7
The Ambiguous Case - SSA
In the ambiguous (SSA) case, there are three possibilities:
1. There is no triangle with the given information.
2. There is exactly one triangle with the given information.
3. There are two triangles, one acute and one obtuse, with the given information.
8
The Ambiguous Case - SSA
Given two sides and an angle opposite one of them, several possibilities exist:
No solution - side too shortto make a triangle
One solution - side equals altitude 20°
10 3.42
20°
10 1
9
The Ambiguous Case - SSA
Two possible triangles could result.
One unique solution - the opposite sideis longer thanadjacent side.
Solving for A could give either an acute
or obtuse angle!
Solving for A could give either an acute
or obtuse angle! 20°
105 5
AA'
20°
10 13.42
12
Checkpoints 1, 2, & 3 Solve triangle ABC.
1. C = 14°, B = 117°, b = 21
2. A = 56°, a = 24, b = 16
3. B = 122°, b = 5, a = 8
14
Area of a Triangle
In any triangle ABC, with sides a, b, and c, the area is given by:
A = ½ ab sin C
A = ½ ac sin B
A = ½ bc sin A
C
BA
ab
c
15
Example 5 A piece of land is bordered by three roads as
shown. Find the area of the land.B
A
C
1.4 mi
2.3 mi
78.1°
16
Checkpoints 4 & 5
4. Solve triangle ABC with A = 35°, a = 11, and b = 14.
5. Suppose the side lengths in Example 5 are 4.6 miles and 2.8 miles. Find the area.