Math Gold Medal

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    Introduction

    a) The Olympic

    Games is aninternational

    event featuringsummer and

    winter sports,in which

    athletesparticip

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    ate in different

    competitions.

    In ancientGreece the

    Olympic Gameswere athletic

    competitionsheld in honor of

    Zeus. Since the

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    Olympic Games

    began they have

    been thecompetition

    grounds for

    greatestathletes. First

    place obtaining

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    gold; second

    silver and third

    bronze. TheOlympic

    medalsrepresent the hardship

    of what thecompetitors of

    the Olympics

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    have done in

    order to obtain

    the medal.Onone side the

    Olympic medalhas Nike the

    goddess ofvictory holding

    a palm and a

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    winners crown

    andon the other

    side the medalhas a different

    label for eachOlympiad

    reflecting thehost of the

    games.Olympic

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    medals could be

    used as a unit

    of measure ofathleticism.Top

    10 OlympicMedal- winning

    CountriesCountry Medals won1.

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    The

    UnitedStates24

    042.

    Soviet Union

    12043.

    Great Britain

    6894.

    France 6795.Germany 6486.

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    Italy 5957.Sweden 5888.East Germany5199.Hungary 45410.

    Finland 446This

    is a tableshowing the top

    10 Olympic

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    Medal- Winning

    Countries and

    definitelyshows how

    theOlympicscan be seen as a

    standardizedunit of

    athleticism

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    Dataa)Height (in

    centimeters)

    achieved by the

    gold medalist at

    various Olympicgames.Year

    1932 1936 1948

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    1952 1956 1960

    1964 1968 1972

    19761980Height(cm)

    197 203 198204 212 216

    218 224 223225 236

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    Variables andConstraintsa) Thedependent

    variable forthis data set is

    the OlympicGold Medalist

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    Heights. The

    independentvari

    able for thisdata set is the

    years in whichthe summer

    Olympic Gamesoccurred in. A

    constraint of

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    this data set is

    the limited

    amount of datathat is

    available. Thedata available is

    only between1932 and

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    19520020521021

    5220225230235

    2401 9 2

    0 1 9 3 0

    1 9 4 0 1

    9 5 0 1 96 0 1 9 7

    0 1 9 8 01 9 9 0 H

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    e i g h t ( c m )YearYear Of

    OlympicsVS. Gold

    Medal

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    H

    eightsInitial values1980. If there

    were more data

    and if there is a

    pattern the

    pattern would

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    become more

    apparent. Ontop

    of this there isa gap between

    1936 and 1948which is a 12

    year chunk ofdata missing.

    And since

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    theOlympics

    are held every

    4 years that is3 Olympic

    competitionsmissing from

    the data.b) In amath textbook

    the variables

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    and constraints

    could be seen

    as y= OlympicGold Medalist

    Heightsand x=years in which

    the summerOlympic games

    occurred in.c)

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    In the context

    of this problem

    is that the xaxis would be

    used to showthe Year of the

    OlympicGamesand y

    would be used

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    to show the

    height of the

    gold medalist.d)This data set is

    continuousbecause it is

    associated witha measurement

    and its possible

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    to have

    thesame y value

    for different xvalues. And

    since the datais measuring

    height adecimal answer

    is possible.A

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    function that

    would fit most

    of the datawould be a

    quadraticfunction. The

    constraint thatthere is a12

    year gap

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    between 1936

    and 1948 could

    skew the data.The data that

    we are missingcould of

    showedus amuch clearer

    model like a

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    linear or could

    of reassured us

    of a quadraticmodel.Graph ofInitialD

    ataa)

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    Analysis andModel

    ConstructionBased on thedata the typeof curve that

    might beexpected is

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    quadratic and

    maybe even a

    thirddegreefunction.

    The expectedshape would be

    quadratic if wedisregarded the

    1936 value and

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    itlooks like a

    third degreefunction would

    fit well.

    a)Some generalformulas that

    the data could

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    fit can be

    quadratic

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    f(x),linear

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    , or exponential

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    .Quadratic

    possible values

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    :X Y1932 197

    begin_of_the_s

    kype_highlighting 1932 197

    end_of_the_skype_highlightin

    g.991936199.041948

    204.331952

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    206.821956

    209.671960

    212.881964216.461968

    220.391972224.691976

    229.341980234.36Linear

    Possible values

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    X Y1932 194

    begin_of_the_s

    kype_highlighting 1932 194

    end_of_the_skype_highlightin

    g.141936197.161948

    206.221952

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    209.241956

    212.261960

    215.281964218.31968

    221.321972224.341976

    227.361980230.38Exponen

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    tial Possible

    Values

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    X Y1932 194

    begin_of_the_skype_highlighti

    ng 1932 194end_of_the_sk

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    ype_highlightin

    g.721936

    197.491948206.041952

    208.971956211.951960 214begin_of_the_s

    kype_highlighti

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    ng 1960 214

    end_of_the_sk

    ype_highlighting.961964

    218.021968221.121972

    224.271976227.461980

    230.69All of

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    the formulas

    used to fit the

    data areincreasing and

    all have a min (when x=0) for

    thequadraticfit the minimum

    is 41946.847 of

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    the linear fit

    the minimum is

    -1264.6484 andfor

    theexponentialfit the min is

    0.21211804. Allof the formulas

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    maximum.For

    the model to

    become muchmore realistic

    the logical fitwould be a

    sinusoidalcurve.

    Theconstraints

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    on a sinusoidal

    curve would be

    that the curvewould have to

    be half a cycle.The curve has

    tobe half acycle because it

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    curve would

    show that the

    heightsfluctuate from

    OlympicstoOlympics and

    this would notrepresent our

    data. But by

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    limiting the

    curve to half a

    cycle then thecurvewould fit

    the data.b)

    Linear Model

    QuadraticModel

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    General formfor a linear

    equation:

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    When using twopoints from thedata

    andsubstituting

    them into the

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    values for x

    andy the values

    for m and b canbe found.

    Thepoints thatare going to be

    used aregoingto be

    (1972,223) and

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    (1960,216).

    Thesepoints

    were chosenbecause they

    look likea niceline can be

    drawn betweenthemwithout

    too much

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    differentiation

    betweenthe

    other points.

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    To find the

    value of a, we

    can subtractthetwo

    equations. Thiswill

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    We can now

    find m by

    dividing bothsidesby 12 so

    we get:

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    The value for b

    can now be

    foundbysubstituting

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    to any of theequations

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    The general

    form for an

    quadraticequation is

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    . With 3pointson the graph anequation can

    beformulated in

    the form

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    . The points

    that are going

    to be usedaregoing to be

    (1936,203),(1972,233)

    and(1960,216)We can make

    three equations

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    using

    thesethree

    points and thegeneral formula

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    . bysubstitutingxand y values

    we get:

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    or

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    or

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    or

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    Then we cansubtract twoequationstogeth

    er to eliminate

    C. I chose to

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    subtractthe

    first and

    second equation

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    The equationwill now be:

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    Now I willsubtract thesecond and

    thirdequation

    to get two new

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    equations

    tosolve for a

    and b.

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    With the two

    equations now

    we mustisolatea variable to

    solve, I will bechosinga, so we

    need toeliminate b. we

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    can dothis by

    multiplying

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    Bysince

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    . By multiplyinby

    we get

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    . then weadd

    the equations:

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    Now we can

    solve for a and

    we get

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    . Now we can

    substitute ainto

    one of theequations with

    twovariables tosolve for

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    . I will be using

    theequation

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    .bysubstitutinga we get:

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    we can nowsubstitute botha and b intothe

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    original

    equations and

    solve for c. Iwillbe

    substituting ininto the

    secondequation.

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    Now we havefound allvariables and

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    wecan write our

    equation. And

    we get:

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    Linear FunctionQuadraticfunction

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    The reason whyI chose a linearmodel is

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    because despite

    some points the

    data in thegraph seemed

    tobe modeledwell by a linear

    model. I alsochose a

    quadratic model

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    because the

    data points

    seemed tobemodeled well

    by a quadraticmodel.b)Linear Equation:

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    1952002052102152202252302352401 9 2

    0 1 9 3 01 9 4 0 1

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    9 5 0 1 9

    6 0 1 9 7

    0 1 9 8 0

    1 9 9 0 He i g h t ( c m )

    Year

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    Year Of

    Olympics

    VS. GoldMedalH

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    eightsInitialvaluesLinearEquationYearsInitialvalues Linear

    Equation1932197 199.671936

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    203

    202.003333319

    48 198209.003333319

    52 204211.336666719

    56 212213.671960 216

    216.003333319

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    64 218

    218.336666719

    68 224220.671972

    223223.003333319

    76 225225.336666719

    80 236

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    227.67This

    linear function

    is not the bestfit for the

    model becauseas we can see

    from the graphthere are a

    lotof points left

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    out and that

    are not even

    close to thelinear equation.

    Also in the datatable there

    aresome yearswhere the

    linear equation

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    varies greatly

    from the actual

    seethat forsome years it is

    close like for1936 but for

    others it is

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    much farther

    away from the

    linearequationlike in 1948.0501001502002503001 9

    2 0 1 9

    3 0 1 9

    4 0 1 9

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    5 0 1 9

    6 0 1 9

    7 0 1 9

    8 0 1 9

    9 0 He i g h t ( c m )Year

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    Year Of

    Olympics

    VS. GoldMedalH

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    eightsQuadraticEquation:

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    Years Initialvalues

    Quadratic

    Equation1932

    197

    204.578947419

    36 203

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    2031948 198

    204.157894719

    52 204206.508771919

    56 212209.842105319

    60 216214.157894719

    64 218

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    219.456140419

    68 224

    225.73684211972 223

    2331976 225241.245614198

    0 236250.4736842T

    he quadratic

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    equation that I

    came up with is

    a reasonable fitbut still not the

    best fit. As wecan seefrom

    the graph thequadratic

    equation

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    increases

    quicker than

    the actualvalues. This

    causes the datato0501001502002501 9 2 0

    1 9 3 0 1

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    9 4 0 1 9

    5 0 1 9 6

    0 1 9 7 0

    1 9 8 0 1

    9 9 0 He i g h t ( c m )Year

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    Year Of

    Olympics

    VS. GoldMedalH

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    eightsInitialvaluesLinearRegressionbe way off forthe final two

    years in ourdata. We can

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    see this from

    the data table

    as 1976 and1980 arenot as

    close are theother actual

    values to thevalues from the

    quadratic

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    equation.Linear

    Regression

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    Years Initial

    values Linear

    Regression1932197

    194.13824261936 203

    197.15850481948 198

    206.219291419

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    52 204

    209.239553619

    56 212212.259815819

    60 216215.280078196

    4 218218.3003402

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    19520020521021

    5220225230235

    2401 9 2 0

    1 9 3 0 1

    9 4 0 1 9

    5 0 1 9 60 1 9 7 0

    1 9 8 0 19 9 0 H

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    e i g h t ( c m )YearYear Of

    OlympicsVS. Gold

    Medal

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    H

    eightsInitial

    valuesQuadratic

    Regression1968 224

    221.32060241972 223

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    224.340864619

    76 225

    227.36112681980 236

    230.381389This is a better

    linear model butit is still not

    the best.

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    Because it is

    linear it

    excludes somepoints like1948.

    In 1948 we cansee that

    differencebetween the

    actual values

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    and the linear

    regression

    models isquitesignificant.Qua

    draticRegression

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    Years Initial

    values

    QuadraticRegression1932

    197197.995296519

    36 203199.0379511194

    8 198

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    204.334820919

    52 204

    206.82341271956 212

    209.67348881960 216

    212.88504931964 218

    216.458094

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    19520020521021

    5220225230235

    2401 9 2 0

    1 9 3 0 1

    9 4 0 1 9

    5 0 1 9 60 1 9 7 0

    1 9 8 0 19 9 0 H

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    e i g h t ( c m )YearYear Of

    OlympicsVS. Gold

    Medal

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    H

    eightsInitial

    valuesQuadratic

    Regression1968 224

    220.3926231972 223

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    224.688636419

    76 225

    229.3461341980 236

    234.3651159This is the best

    fit because aswe can see

    from the graph

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    it fits most

    points without

    leaving othertoo faroff.

    From the datatable we can

    see that this isthe only

    function that

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    does not vary

    too wildly from

    theactual value.

    Proposed

    modelThe quadraticregressionmodel is a

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    reasonable fit

    for the data

    because theregression line

    does not varyallthat much from

    the actualvalues.As we

    can see the

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    quadratic

    regression

    model fits thegraph almost

    perfectly. Theonly year that

    thegraph doesnot fit all that

    well is 1948.

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    The data is

    increasing for

    the entiredomain but this

    doesnotnecessarily

    mean thatfuture years

    will be

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    accurate. This

    is because

    there arealmost

    asymptotes inall of the

    graphs. Therehas to be a limit

    of how low the

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    heights have to

    be to qualify

    and since theOlympiccompeti

    tors are humanthere is a limit.

    This makes allof the graphs

    not a best fit

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    for all of the

    futureyears

    that the eventwill be held and

    all of the pastyears but this

    quadratic modeldoes model the

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    datagiven

    accurately.Considerationof AccuracyLinear Equation:

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    Years Initial

    values Linear

    EquationPercent

    Error1932 197199.67

    1.351936 203202.0033333

    .491948 198

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    209.0033333

    5.551952 204

    211.33666673.61956 212

    213.67 .791960216

    216.0033333.00151964 218

    218.3366667

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    .1541968 224

    220.67

    1.481972 223223.0033333

    .00151976 225225.3366667

    .151980 236227.67

    3.53Average

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    1.55Quadratic

    Equation:

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  • 7/31/2019 Math Gold Medal

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  • 7/31/2019 Math Gold Medal

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    X-Values Initialvalues

    Quadratic

    Equation Error

    Percent1932

    197 204

    begin_of_the_s

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    kype_highlighti

    ng 1932 197

    204end_of_the_sk

    ype_highlighting.5789474

    3.851936 203203 01948 198

    204.1578947

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    3.111952 204

    206.5087719

    1.231956 212209.8421053

    1.021960 216214.1578947

    .851964 218219.4561404

    .671968 224

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    225.7368421

    .771972 223

    233 01976 225241.245614

    7.221980 236250.4736842

    6.13Average2.26Linear

    Regression:

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    X-Values Initialvalues LinearRegression

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    Error

    Percent1932

    197 194begin_of_the_s

    kype_highlighting 1932 197

    194end_of_the_sk

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    204/306

    ype_highlightin

    g.1382426 1.451936 203 197begin_of_the_s

    kype_highlighting 1936 203

    197end_of_the_sk

    ype_highlightin

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    g.1585048

    2.881948 198

    206.21929144.151952 204

    209.23955362.561956 212

    212.2598158.1221960 216

    215.280078

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    .3331964 218

    218.3003402

    .141968 224221.3206024

    1.21972 223224.3408646

    .601976 225227.3611268

    1.051980 236

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    230.381389

    2.38Averga

    1.53QuadraticRegression:

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    X-Values InitialvaluesQuadratic

    Regression

    Error

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    Percent1932

    197 197

    begin_of_the_skype_highlighti

    ng 1932 197197

    end_of_the_skype_highlightin

    g.9952965

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    .501936 203

    199.0379511

    1.951948 198204.3348209

    3.21952 204206.8234127

    1.381956 212209.6734888

    1.11960 216

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    212.8850493

    1.441964 218

    216.458094.711968 224

    220.3926231.611972 223

    224.6886364.761976 225

    229.346134

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    1.931980 236

    234.3651159

    .69Average1.36From the

    errorpercentages we

    can see thatthe most

    accurate is the

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    quadratic

    regression

    model.Thequadratic

    regressionmodel had an

    average errorpercent of

    about 1.36 while

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    the others had

    highererror.

    The only modelthat came close

    was the linearregression

    model with anerror

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    percentage of

    1.53.Predictions

    These

    predictions aregoing to be with

    the model thatI thought was

    the best.

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    Quadratic

    Regressionmode

    l. The equationis:

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  • 7/31/2019 Math Gold Medal

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    1984

    Predictions

    2016PredictionsFirst

    we mustsubstitute in

    the year for xand thenwe can

    find y which is

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    0 1 9 3 0 1 9 4

    0 1 9 5 0 1 9 6

    0 1 9 7 0 1 9 8

    0 1 9 9 0 2 0 0

    0 2 0 1 0 2 0 2

    0 2 0 3 0 He i g h t ( c m )Year

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    Year Of

    Olympics

    VS. GoldMedalH

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    eightsQuadraticRegression

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  • 7/31/2019 Math Gold Medal

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    Height in cm =

    239.75

    295.8Table:X-ValuesInitialval

    uesQuadraticRegression1932

    197197.995296519

    36 203

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    199.0379511194

    8 198

    204.33482091952 204

    206.82341271956 212

    209.67348881960 216

    212.885049319

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    64 218

    216.458094196

    8 224220.392623197

    2 223224.688636419

    76 225229.346134198

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    0 236

    234.36511591984239.752016

    295.8

    Graph:0501001502002503001 8 8

    0 1 9 0 0

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    1 9 2 0 1

    9 4 0 1 9

    6 0 1 9 8

    0 2 0 0 0

    2 0 2 0 He i g h t ( c m )Year

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    Year Of

    Olympics

    VS. GoldMedalH

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    eightsInitialvaluesQuadraticRegressionMy answers for1984 make

    sense becauseit is not too far

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    from the other

    values like that

    of 1980. Ontheother hand

    my value for2016 is high.

    The mainproblem with

    any of the

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    models is that

    they show

    thatthe heightis continuously

    rising. It is veryunlikely that

    the resultswould keep

    rising like the

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    models

    Isuggested.

    Since 2016 farfrom the years

    given we cansafely say that

    neither of themodels

    stated(linear or

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    quadratic) are a

    suitable

    regression touse.Additional

    Data

    a)Year 1896

    1904 1908 1912

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    1920 1928 1984

    1988 1992 1996

    2000 20042008Height(cm

    )190 180 191193 193 194

    235 238 234239 235 236

    236

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    0501001502002

    503001 8 8

    0 1 9 0 0

    1 9 2 0 1

    9 4 0 1 9

    6 0 1 9 80 2 0 0 0

    2 0 2 0 He i g h t ( c m )

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    YearYear Of

    Olympics

    VS. Gold

    MedalH

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    eightsInitialvaluesQuadraticRegressionb)As we can seethe model does

    fit the newdata for the

  • 7/31/2019 Math Gold Medal

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    most part. The

    only part that

    we see notfittingthe data

    is when thequadratic

    regressionstarts

    increasing from

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    1984 and

    beyond.Year

    1896 1904 19081912 1920 1928

    1932 1936 19481952

    1956Height(cm)190 180 191 193

    193 194 197

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    203 198 204

    212Year 1960

    1964 1968 19721976 1980 1984

    1988 1992 19962000Height(cm

    )216 218 224223 225 236

    235 238 234

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    239 235Year

    2004

    2008Height(cm)236 236As we

    can see fromthe graph the

    quadraticregression

    seems to follow

  • 7/31/2019 Math Gold Medal

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    the data

    closely. There

    are onlysomevalues at the

    beginning and atthe end where

    the quadraticregression is

    different. From

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    the tablebelow

    we can see that

    most of thevalues are

    reasonablyclose to the

    given actualvalue. A thing

    thatcould be

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    done to make

    the data more

    accurate ismake a new

    quadraticregression line

    for all ofthedata and not

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    just the initial

    data given.X-ValuesInitialval

    uesQuadraticRegression1896

    190204.878198190

    4 180

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    200.818274319

    08 191

    199.33053881912 193

    198.20428771920 193

    197.03623831928 194

    197.3141261193

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    2 197

    197.995296519

    36 203199.0379511194

    8 198204.334820919

    52 204206.823412719

    56 212

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    209.673488819

    60 216

    212.88504931964 218

    216.4580941968 224

    220.3926231972 223

    224.688636419

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    76 225

    229.346134198

    0 236234.365115919

    84 235239.745582119

    88 238245.487532719

    92 234

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    251.590967519

    96 239

    258.05588662000 235

    264.882292004 236

    272.07017772008 236

    279.6195497

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    Further testingand applicationThe patterns

    that showed up

    Jump also show

    up in other

    sports in the

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    Olympics.

    Forexample the

    Olympicrecords for

    free style

    shows this samepattern.Year

    1896 1904 1908

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    1912 1920 1928

    1932 1936 1948

    1952 1956Time(seconds)82.2

    62.8 65.6 63.461.4 58.6 58.2

    57.6 57.3 57.455.4Year 1960

    1964 1968 1972

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    1976 1980 1984

    1988 1992 1996

    2000Time(seconds)55.2

    53.4 52.2 51.249.9 50.4 49.8

    48.6 49.0 48.748.3Year 2004

  • 7/31/2019 Math Gold Medal

    266/306

    2008Height(cm

    )48.2 47.20102030405060

    7080901 8

    8 0 1 9 0

    0 1 9 2 0

    1 9 4 0 1

    9 6 0 1 98 0 2 0

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    0 0 2 0

    2 0 He i g h t ( c m )YearYear Of

    Olympics

  • 7/31/2019 Math Gold Medal

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    VS. Gold

    Medal

    HeightsInitial values

    When the data

    is graphed it

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    looks like

    this:The X

    valuesrepresent the

    years in whichthe Olympics

    were hostedinThe Y values

    represent the

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    time of the gold

    medalist

    resultsThegraph shows a

    decline in timesince the early

    1900s. The gold

    results were

  • 7/31/2019 Math Gold Medal

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    becomingshorte

    r and shorter

    over the yearuntil towards

    the start of the21stcentury. Like on

    the Gold

  • 7/31/2019 Math Gold Medal

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    medalistheights

    this suggests a

    type ofasymptote. If

    we do aquadratic

    regression forthis data we

    get theequation

  • 7/31/2019 Math Gold Medal

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    f(x) =

    .0017830124x^

    2-7.173749547x+

    7264.004005.When we graph

    this equation weget

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    thefollowing

    graph.0102030405060

    7080901 8

    8 0 1 9

    0 0 1 9

    2 0 1 9

    4 0 1 96 0 1 9

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    275/306

    8 0 2 0

    0 0 2 0

    2 0 He i g h t ( c m )Year

    Year Of

    Olympics

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    VS. Time

    of 100m

    FreeStyleInitial

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    X-Values Initial

    values

    QuadraticRegression1896

    82.272.1763676119

    04 62.868.9899481919

    08 65.6

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    67.4823230819

    12 63.4

    66.031754361920 61.4

    63.301786121928 58.6

    60.800043471932 58.2

    59.6347567319

  • 7/31/2019 Math Gold Medal

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    36 57.6

    58.5265264194

    8 57.355.5441737719

    52 57.454.6641690319

    56 55.453.8412206719

    60 55.2

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    53.0753287219

    64 53.4

    52.366493161968 52.2

    51.714714197251.2

    51.119991241976 49.9

    50.5823248719

  • 7/31/2019 Math Gold Medal

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    80 50.4

    50.10171491984

    49.849.6781613319

    88 48.649.31166415199

    2 4949.0022233719

  • 7/31/2019 Math Gold Medal

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    96 48.7

    48.749838990102030405060

    7080901 8

    8 0 1 9

    0 0 1 9

    2 0 1 9

    4 0 1 96 0 1 9

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    8 0 2 0

    0 0 2 0

    2 0 He i g h t ( c m )Year

    Year Of

    Olympics

  • 7/31/2019 Math Gold Medal

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    VS. Time

    of 100m

    Freestyle2000 48.348.5545112004

    48.2

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    48.4162394120

    08 47.2

    48.33502422Compare and

    contrast:

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    0501001502002

    503001 8

    8 0 1 9

    0 0 1 9

    2 0 1 9

    4 0 1 96 0 1 9

    8 0 2 0

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    288/306

    0 0 2 0

    2 0 He i g h t ( c m )YearYear Of

    Olympics

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    VS. Gold

    Medal

    HeightsFrom the twographs above

    we can see that

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    they are really

    opposites of

    each other. Thegold

    medalheightsare a concave

    up quadraticfunction while

    the time for

  • 7/31/2019 Math Gold Medal

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    freestyle is

    concavedown.The gold medal

    heights graph isincreasing

    throughout thedata and the

  • 7/31/2019 Math Gold Medal

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    freestyle

    isdecreasing

    throughout thedata. They are

    both similar inthe way that

    accurately

    model

  • 7/31/2019 Math Gold Medal

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    everysingle

    year that the

    Olympics will beheld because

    they will bothdecrease and

    increase beyondtheactual

    values. This is

  • 7/31/2019 Math Gold Medal

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    because humans

    are competing

    in these eventsand we all have

    limits. This isalsoapparent in

    the gold medalheights, as the

    years went on

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    the heights got

    more and more

    close toeachother

    withoutsignificant

    difference. The

    freestyle seems

  • 7/31/2019 Math Gold Medal

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    to fit the data

    better

    becausetowardsrecent years

    the times havebeen very close.

    Over all we cansee that the

  • 7/31/2019 Math Gold Medal

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    freestylequadra

    tic regression

    model fits itsdata better

    than the goldmedal heights.Conclusion

    a)

  • 7/31/2019 Math Gold Medal

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    jump results

    from 1896 to2008 Olympics

    showed thatthe gold

    medalistresultsfor high

    jump steadily

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    increased.

    Towards the

    end the heightsstarted to level

    off because ofhuman limits.

    The best modelthat was found

    to model the

  • 7/31/2019 Math Gold Medal

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    data was

    quadratic. This

    is becausefrom896 towards

    2008 the datawas steadily

    increasing at aparabola like

    shape. The

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    m

    Freestyle

    results from1896 to 2008

    showed thatthe results for

    the 100 mfreestyle

    weresteadily

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    decreasing, and

    towards the

    end the resultsleveled off.

    This is becauseof

    humanlimitations. A good type

    of model to

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    model the 100m

    freestyle data

    from 1896 to2008 was alsoa

    quadraticfunction. This

    modeled thedata almost

    perfectly

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    BibliographySwim-City.

    "Swim-City.com

    - Record

  • 7/31/2019 Math Gold Medal

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    History Olympic

    Records Men."Swim-City.com -SwimmingMetro

    polis. Swim-City,

    2011. Web. 20Jan. 2012.

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