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General Info 5.1 The Construction of Stochastic Integrals
Math 562 Fall 2020
Renming Song
University of Illinois at Urbana-Champaign
October 07, 2020
General Info 5.1 The Construction of Stochastic Integrals
Outline
General Info 5.1 The Construction of Stochastic Integrals
Outline
1 General Info
2 5.1 The Construction of Stochastic Integrals
General Info 5.1 The Construction of Stochastic Integrals
I posted HW4 in my homepage. HW4 is due 10/16 at noon. I also setup HW4 in the course Moodle page.
HW3 is graded now.
General Info 5.1 The Construction of Stochastic Integrals
I posted HW4 in my homepage. HW4 is due 10/16 at noon. I also setup HW4 in the course Moodle page.
HW3 is graded now.
General Info 5.1 The Construction of Stochastic Integrals
Outline
1 General Info
2 5.1 The Construction of Stochastic Integrals
General Info 5.1 The Construction of Stochastic Integrals
Recall that P is the progressive σ-field on Ω× R+. If M ∈ H2, we useL2(M) to denote the collection of all progressive processes H suchthat
E[∫ ∞
0H2
s d〈M,M〉s]<∞
with the convention that two progressive processes H and H ′
satisfying this integrability condition are identified if Hs = H ′s,d〈M,M〉s a.e. a.s.
We can view L2(M) as an ordinary L2 space, namely
L2(M) = L2(Ω× R+,P,dPd〈M,M〉s),
where dPd〈M,M〉s refers to the finite measure on (Ω× R+,P) thatassigns the mass
E[∫ ∞
01A(ω, s)d〈M,M〉s
]to a set A ∈ P.
General Info 5.1 The Construction of Stochastic Integrals
Recall that P is the progressive σ-field on Ω× R+. If M ∈ H2, we useL2(M) to denote the collection of all progressive processes H suchthat
E[∫ ∞
0H2
s d〈M,M〉s]<∞
with the convention that two progressive processes H and H ′
satisfying this integrability condition are identified if Hs = H ′s,d〈M,M〉s a.e. a.s.
We can view L2(M) as an ordinary L2 space, namely
L2(M) = L2(Ω× R+,P,dPd〈M,M〉s),
where dPd〈M,M〉s refers to the finite measure on (Ω× R+,P) thatassigns the mass
E[∫ ∞
01A(ω, s)d〈M,M〉s
]to a set A ∈ P.
General Info 5.1 The Construction of Stochastic Integrals
Just like any L2 space, the space L2(M) is a Hilbert space for thescalar product
(H,K )L2(M) = E[∫ ∞
0HsKsd〈M,M〉s
]and the associated norm is
‖H‖L2(M) =
(E[∫ ∞
0H2
s d〈M,M〉s])
.
Definition 5.2An elementary process is a progressive process of the form
Hs(ω) =
p−1∑j=0
H(j)(ω)1(tj ,tj+1](s)
where 0 = t0 < t1 < · · · < tp = t and for every j = 0, . . . ,p − 1, H(j) isa bounded Ftj -measurable random variable.
General Info 5.1 The Construction of Stochastic Integrals
Just like any L2 space, the space L2(M) is a Hilbert space for thescalar product
(H,K )L2(M) = E[∫ ∞
0HsKsd〈M,M〉s
]and the associated norm is
‖H‖L2(M) =
(E[∫ ∞
0H2
s d〈M,M〉s])
.
Definition 5.2An elementary process is a progressive process of the form
Hs(ω) =
p−1∑j=0
H(j)(ω)1(tj ,tj+1](s)
where 0 = t0 < t1 < · · · < tp = t and for every j = 0, . . . ,p − 1, H(j) isa bounded Ftj -measurable random variable.
General Info 5.1 The Construction of Stochastic Integrals
The family E of all elementary processes forms a linear subspace ofL2(M).
Proposition 5.3
For every M ∈ H2, E is dense in L2(M).
Proof of Proposition 5.3
It suffices to show that, if K ∈ L2(M) is orthogonal to E , then K = 0.Assume that K ∈ L2(M) is orthogonal to E , and define, for everyt ≥ 0,
Xt =
∫ t
0Kud〈M,M〉u.
General Info 5.1 The Construction of Stochastic Integrals
The family E of all elementary processes forms a linear subspace ofL2(M).
Proposition 5.3
For every M ∈ H2, E is dense in L2(M).
Proof of Proposition 5.3
It suffices to show that, if K ∈ L2(M) is orthogonal to E , then K = 0.Assume that K ∈ L2(M) is orthogonal to E , and define, for everyt ≥ 0,
Xt =
∫ t
0Kud〈M,M〉u.
General Info 5.1 The Construction of Stochastic Integrals
The family E of all elementary processes forms a linear subspace ofL2(M).
Proposition 5.3
For every M ∈ H2, E is dense in L2(M).
Proof of Proposition 5.3
It suffices to show that, if K ∈ L2(M) is orthogonal to E , then K = 0.Assume that K ∈ L2(M) is orthogonal to E , and define, for everyt ≥ 0,
Xt =
∫ t
0Kud〈M,M〉u.
General Info 5.1 The Construction of Stochastic Integrals
Proof of Proposition 5.3 (cont)
To see that the integral in the right-hand side makes sense, anddefines a finite variation process (Xt )t≥0, we use the Cauchy-Schwarzinequality to get that
E
[∫ t
0|Ku|d〈M,M〉u
]≤
(E
[∫ t
0K 2
u d〈M,M〉u
])1/2
· (E[〈M,M〉∞])1/2.
The right-hand side is finite since M ∈ H2 and K ∈ L2(M), and thuswe have in particular
a.s. ∀t ≥ 0,∫ t
0|Ku|d〈M,M〉u <∞.
Thus (Xt )t≥0 is well defined as a finite variation process. Thepreceding bound also shows that Xt ∈ L1 for every t ≥ 0.
General Info 5.1 The Construction of Stochastic Integrals
Proof of Proposition 5.3 (cont)
Let 0 ≤ s < t , let F be a bounded Fs-measurable random-variable,and let H ∈ E be the elementary process defined byHr (ω) = F (ω)1(s,t](r). Since (H,K )L2(M) = 0, we have
E
[F∫ t
sKud〈M,M〉u
]= 0.
It follows that E[F (Xt − Xs)] = 0 for every s < t and every boundedFs-measurable random-variable F . Since the process X is adaptedand we know that Xt ∈ L1 for every t ≥ 0, this implies that X is a(continuous) martingale. On the other hand, X is also a finitevariation process and, by Theorem 4.8, this is only possible if X = 0.
General Info 5.1 The Construction of Stochastic Integrals
Proof of Proposition 5.3 (cont)
We have thus proved that∫ t
0Kud〈M,M〉u = 0, ∀t ≥ 0,a.s.
which implies that, a.s., the signed measure having density Ku withrespect to d〈M,M〉u is the zero measure, which is only possible if
Ku = 0, d〈M,M〉u − a.e. a.s.
or, equivalently K = 0 in L2(M).
Recall that, for stopping time T , X T stands for the stopped processX T
t = Xt∧T . If M ∈ H2, the fact that 〈MT ,MT 〉∞ = 〈M,M〉Timmediately implies that MT ∈ H2. Furthermore, if H ∈ L2(M), theprocess 1[0,T ]H defined by (1[0,T ]H)s(ω) = 10≤s≤T (ω)Hs(ω) alsobelongs to L2(M).
General Info 5.1 The Construction of Stochastic Integrals
Proof of Proposition 5.3 (cont)
We have thus proved that∫ t
0Kud〈M,M〉u = 0, ∀t ≥ 0,a.s.
which implies that, a.s., the signed measure having density Ku withrespect to d〈M,M〉u is the zero measure, which is only possible if
Ku = 0, d〈M,M〉u − a.e. a.s.
or, equivalently K = 0 in L2(M).
Recall that, for stopping time T , X T stands for the stopped processX T
t = Xt∧T . If M ∈ H2, the fact that 〈MT ,MT 〉∞ = 〈M,M〉Timmediately implies that MT ∈ H2. Furthermore, if H ∈ L2(M), theprocess 1[0,T ]H defined by (1[0,T ]H)s(ω) = 10≤s≤T (ω)Hs(ω) alsobelongs to L2(M).
General Info 5.1 The Construction of Stochastic Integrals
Theorem 5.4
Let M ∈ H2. For every H ∈ E of the form
Hs(ω) =
p−1∑j=0
H(j)(ω)1(tj ,tj+1](s).
the formula
(H ·M)t =
p−1∑j=0
H(j)(Mtj+1∧t −Mtj∧t )
defines a process H ·M ∈ H2. The mapping H 7→ H ·M extends to anisometry from L2(M) to H2. Furthermore, H ·M is the uniquemartingale of H2 with the property
〈H ·M,N〉 = H · 〈M,N〉, ∀N ∈ H2. (1)
If T is a stopping time, we have
(1[0,T ]H) ·M = (H ·M)T = H ·MT . (2)
General Info 5.1 The Construction of Stochastic Integrals
We often use the notation
(H ·M)t =
∫ t
0HsdMs
and call H ·M the stochastic integral of H with respect to M.
The quantity H · 〈M,N〉 in the right-hand side of (1) is an integral withrespect to a finite variation process. The fact that we use a similarnotation H · A and H ·M for the integrals with respect to a finitevariation process A and with respect to a martingale M creates noambiguity since these two classes of processes are essentiallydisjoint.
General Info 5.1 The Construction of Stochastic Integrals
We often use the notation
(H ·M)t =
∫ t
0HsdMs
and call H ·M the stochastic integral of H with respect to M.
The quantity H · 〈M,N〉 in the right-hand side of (1) is an integral withrespect to a finite variation process. The fact that we use a similarnotation H · A and H ·M for the integrals with respect to a finitevariation process A and with respect to a martingale M creates noambiguity since these two classes of processes are essentiallydisjoint.
General Info 5.1 The Construction of Stochastic Integrals
Proof of Theorem 5.4First note that the definition of H ·M does not depend on the
decomposition chosen for H in the first display of the theorem. Usingthis remark, one then checks that the mapping H 7→ H ·M is linear.
Now we verify that this mapping is an isometry from E (viewed as asubspace of L2(M)) into H2.
Fix H ∈ E of the form given in the theorem, and for everyj ∈ 0,1, . . . ,p − 1, define
M jt = H(j)(Mtj+1∧t −Mtj∧t ),
for every t ≥ 0. It is easy to check that M j is a martingale and thismartingale belongs to H2. It follows that H ·M =
∑p−1j=0 M j is also a
martingale in H2. Note that the continuous martingales M j areorthogonal, and their respective quadratic variations are given by
〈M j ,M j〉t = H2(j)(〈M,M〉tj+1∧t − 〈M,M〉tj∧t ).
General Info 5.1 The Construction of Stochastic Integrals
Proof of Theorem 5.4 (cont)
Thus
〈H ·M,H ·M〉t =
p−1∑j=0
H2(j)(〈M,M〉tj+1∧t − 〈M,M〉tj∧t ) =
∫ t
0H2
s d〈M,M〉s.
Consequently,
‖H ·M‖2H2 = E[〈H ·M,H ·M〉∞] = E [
∫ ∞0
H2s d〈M,M〉s] = ‖H‖2
L2(M).
By linearity, this implies that H ·M = H ′ ·M if H ′ is another elementaryprocess that is identified with H in L2(M). Therefore the mappingH 7→ H ·M makes sense from E (viewed as a subspace of L2(M)) intoH2. This latter mapping is linear, and, since it preserves the norm, itis an isometry from E (viewed as a subspace of L2(M)) into H2. SinceE is dense in L2(M) and H2 is a Hilbert space, this mapping can beextended in a unique way to an isometry from L2(M) into H2.
General Info 5.1 The Construction of Stochastic Integrals
Proof of Theorem 5.4 (cont)
Let us now prove (1). Fix N ∈ H2. We first note that, if H ∈ L2(M), theKunita-Watanabe inequality shows that
E[∫ ∞
0|Hs||d〈M,N〉s|
]≤ ‖H‖L2(M)‖N‖H2 <∞
and thus the variable∫∞
0 Hsd〈M,N〉s = (H · 〈M,N〉)∞ is well definedand in L1. Consider first the case where H is an elementary processof the form given in the theorem, and define the continuousmartingales M j , j = 0, . . .p − 1, as before. Then,
〈H ·M,N〉 =
p−1∑j=0
〈M j ,N〉
and for every j = 0, . . .p − 1,
〈M j ,N〉t = H(j)(〈M,N〉tj+1∧t − 〈M,N〉tj∧t ).
General Info 5.1 The Construction of Stochastic Integrals
Proof of Theorem 5.4 (cont)
It follows that
〈H ·M,N〉t =
p−1∑j=0
H(j)(〈M,N〉tj+1∧t − 〈M,N〉tj∧t ) =
∫ t
0Hsd〈M,N〉s.
which gives (1) when H ∈ E . We then observe that the linear mappingX 7→ 〈X ,N〉∞ is continuous from H2 into L1. Indeed, by theKunita-Watanabe inequality,
E[〈X ,N〉∞] ≤ E[〈X ,X 〉∞]1/2E[〈N,N〉∞]1/2 = ‖X‖H2‖N‖H2 .
If (Hn)n≥1 is a sequence in E such that Hn → H in L2(M), we havetherefore
〈H ·M,N〉∞ = limn→∞〈Hn ·M,N〉∞ = lim
n→∞(Hn ·〈M,N〉)∞ = (H ·〈M,N〉)∞.
where the convergences hold in L1, and the last equality again followsfrom the Kunita-Watanabe inequality by writing
General Info 5.1 The Construction of Stochastic Integrals
Proof of Theorem 5.4 (cont)
E[∫ ∞
0(Hn
s − Hs)d〈M,N〉s]≤ E[〈N,N〉∞]1/2‖Hn − H‖L2(M).
We have thus obtained the identity 〈H ·M,N〉∞ = 〈H ·M,N〉∞, butreplacing N by the stopped martingale N t in this identity also gives〈H ·M,N〉t = 〈H ·M,N〉t , which completes the proof of (1).
It is easy to see that (1) characterizes H ·M among the martingalesof H2. Indeed, if X is another martingale of H2 hat satisfies the sameidentity, we get, for every N ∈ H2
〈H ·M − X ,N〉 = 0.
Taking N = H ·M − X and using Proposition 4.12 we obtain thatX = H ·M.
General Info 5.1 The Construction of Stochastic Integrals
Proof of Theorem 5.4 (cont)
It remains to verify (2). Using the properties of the bracket of twocontinuous local martingales, we observe that, if N ∈ H2,
〈H ·MT ,N〉t = 〈H ·M,N〉t∧T = (H · 〈M,N〉)t∧T = (1[0,T ]H · 〈M,N〉)t
which shows that the stopped martingale (H ·M)T satisfies thecharacteristic property of the stochastic integral (1[0,T ]H) ·M. The firstequality in (2) follows. The second one is proved analogously, writing
〈H ·MT ,N〉 = H · 〈MT ,N〉 = H · 〈M,N〉T = 1[0,T ]H · 〈M,N〉.
This completes the proof of the theorem.
General Info 5.1 The Construction of Stochastic Integrals
RemarkWe could have used (1) to define the stochastic integral H ·M,observing that the mapping N 7→ E[(H · 〈M,N〉)∞] yields a continuouslinear map on H2, and thus there exists a unique martingale H ·M inH2 such that
E[(H · 〈M,N〉)∞] = (H ·M,N)H2 = E[(〈H ·M,N〉)∞].
Using the notation introduced after Theorem 5.4, we can rewrite (1) inthe form
〈∫ ·
0HsdMs,N〉t =
∫ t
0Hsd〈M,N〉s
We interpret this by saying that the stochastic integral “commutes”with the bracket. Let us immediately mention a very importantconsequence.
General Info 5.1 The Construction of Stochastic Integrals
RemarkWe could have used (1) to define the stochastic integral H ·M,observing that the mapping N 7→ E[(H · 〈M,N〉)∞] yields a continuouslinear map on H2, and thus there exists a unique martingale H ·M inH2 such that
E[(H · 〈M,N〉)∞] = (H ·M,N)H2 = E[(〈H ·M,N〉)∞].
Using the notation introduced after Theorem 5.4, we can rewrite (1) inthe form
〈∫ ·
0HsdMs,N〉t =
∫ t
0Hsd〈M,N〉s
We interpret this by saying that the stochastic integral “commutes”with the bracket. Let us immediately mention a very importantconsequence.
General Info 5.1 The Construction of Stochastic Integrals
If M ∈ H2 and H ∈ L2(M), two successive applications of (1) give
〈H ·M,H ·M〉 = H · (H · 〈M,M〉) = H2 · 〈M,M〉
using the “associativity property” integrals with respect to finitevariation processes. Put differently, the quadratic variation of thecontinuous martingale H ·M is
〈∫ ·
0HsdMs,
∫ ·0
HsdMs〉t =
∫ t
0H2
s d〈M,M〉s.
More generally, if N is another martingale of H2 and K ∈ L2(N), thesame argument gives
〈∫ ·
0HsdMs,
∫ ·0
KsdNs〉t =
∫ t
0HsKsd〈M,N〉s.