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STALL SPEED

(W S )V s

= 12

ρ V s2 C Lmax

= 12

(1.1116 ) (82) (1.8 )= 64.03 Kg

m3

MAX SPEED

( W ρSL)V max

=η p

12

ρ V max2 C Do

1

(W S )

+ 2 K ρσ V max

(W S )

K = 1π×e×AR

= 1π × 0.85 × 8

= 0.0468

σ = ρ ρo

= 1.11161.225

= 0.907

( W ρSL)V max

= 0.7 × 9.8

0.5 × 1.225 × (15 )3 × 0.015 1

(W S )

+ 2 × 0.04681.1116 × 0.907 × 15 (W

S )

¿ 6.86

31.01 ( 1W S )+ 0.00618 (W

S ) Kg /W

TAKE-OFF MAX

(W ρ )S¿

=

1 − exp

(0.6 ρgC D G

S ¿

( 1W S )) μ− ( μ+

C DG

C L R)[0.6 ρgC D G

S¿( 1W S )]

η p

V ¿

μ= 0.05

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∆ CL Flap ¿= 0.6

C Do HLD= 0.005

V ¿ = 1.1 × V s= 1.1 × 8 = 8.8

C L¿

= C LC + ∆ CL Flap ¿

= 0.3 + 0.6 = 0.9

oHLD.C D ¿

= C D o

+ C D ¿¿ = 0.015 + 0.005 = 0.02

C DoTO= C D¿

+ K C L¿

2 = 0.02 + 0.037 (0.9 )2= 0.05

C L R

= C Lmax

(1.1 )2= 1.8

1.21= 1.488

C DG

= (C D ¿

− μ C L¿)= 0.05 − 0.05 (0.9 )= 0.005

(W

ρ )S

¿

=

1− exp(0.6 × 1.137 × 9.81 × 0.005 × 2( 1W S ))

0.05 − (0.05 + 0.0051.488 )[exp(0.6 × 1.137 × 9.81 × 0.005 × 2( 1

W S ))] (

0.7

8.8 )× 9.8

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¿

1− exp(0.06691W S )

0.05 − (0.0534 )

[exp(0.0669

1W S )]

(0.779 ) Kg

W

RATE OF CLIMB

(W ρ ) ROC

= 1

ROC η p

+

√ 2

ρ√3 C Do

K (W S )(

1.155

( L D)maxη p )

¿ 1 × 9.8

1

0.7+√ 2

1.37 √ 3 (0.015 )0.0468

(W

S )( (1.155 )20 × 0.7 )

¿ 1× 9.8

1.428 +(√1.794 (W S ))(0.0825 )

KgW

SERVICE CEILLING

ROC pada keadaan sea level = 0.5ms

( W ρSL)=

σ

ROC

η p

+√ 2

ρ √3 C Do

K

(W S )( 1.155

( L D)maxη p)

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¿ 0.898 × 9.8

0.5

0.7+√ 2

1.10076 √3 × 0.015

0.0468

(W

S )( 1.155

20 × 0.7 )

¿ 8.8

0.714 + √0.401 (W S )(0.0825 )

KgW