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• Work is required to remove a nucleon from
a stable nucleus because of the strong
nuclear force
• The binding energy of a nucleus is the
energy required to separate all of its
nucleons and move them infinitely far
apart
Mass Defect
• The mass of a nucleus is always less than
the mass of all the separate nucleons
(protons and neutrons)
• this difference in mass is called the mass
defect
Solution • alpha particle mass (2 protons, 2 neutrons) =
6.65 x 10-27 kg (data sheet)
• mass of 2 protons = 2 x 1.67 x 10-27 kg = 3.34 x 10-27 kg
• mass of 2 neutrons = 2 x 1.67 x 10-27 kg = 3.34 x 10-27 kg
• total mass of separate nucleons = 6.68 x 10-27
kg
• mass defect = separate nucleon mass -
mass = 0.03 x 10-27 kg
• E = mc2
• E = (0.03 x 10-27 kg)(3.00 x 108 m/s)2
• E = 2.70 x 10-12 J
• in nuclear reactions, mass is converted to
energy or energy is converted to mass
• Conservation of mass-energy
principle
Example
• Calculate the energy produced in the reaction
2H mass = 3.34341 x 10-27 kg 3H mass = 5.00661 x 10-27 kg
Solution
• Total mass of reactants = 8.35002 x 10-27 kg
• The total mass of the products = 8.3212x10-27 kg
• Mass defect
• =8.35002x10-27 kg – 8.3212x10-27 kg
• = 2.882 x 10-29 kg
• E = mc2
• E = (2.882 x 10-29 kg)(3.00 x 108 m/s)2
• E = 2.59 x 10-12 J
• in the form of kinetic energy of products
STS
• In a CANDU reactor, 1 kg of fuel (natural
uranium) produces 3.4 x 105 MJ of heat
that is converted to electricity
• in oil and coal power plants 1 kg of fuel
produces about 4 MJ of heat
Pair Production
• a very high energy photon may create
matter
• The process must produce 2 particles
whose total charge is zero, since charge &
momentum must be conserved.
• A particle and its antiparticle (antimatter) are
often produced (i.e. an electron and antielectron)
have the same mass and other properties, but
opposite signs
Example
• A 8.50 x 1020 Hz photon produces an
electron and an anti-electron. Determine
the total kinetic energy of the particles.
• Conservation of Mass-Energy!!!
Solution
• photon energy = energy to make particles + Ek
• Ephoton = Eelectron + Eantielectron + Ek
• hf = mc2 + mc2 + Ek
• Ek =(6.63x10-34Js)(8.50x1020) - 2(9.11x10-31kg)c2
• = 4.00 x 10-13 J