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Magnetism Alternating- Current Circuits

Magnetism Alternating-Current Circuits

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Magnetism Alternating-Current Circuits. Alternating Current Generators. A coil of area A and N turns rotating with constant angular velocity in a uniform magnetic field produces a sinusoidal emf. Alternating current motor. - PowerPoint PPT Presentation

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Page 1: Magnetism                          Alternating-Current Circuits

Magnetism Alternating-Current Circuits

Page 2: Magnetism                          Alternating-Current Circuits

Alternating Current Generators

Alternating current motor

A coil of area A and N turns rotating with constant angular velocity in a uniform magnetic field produces a sinusoidal emf

Instead of mechanically rotating, we can apply an ac potential difference generated by other ac generator to the coil. This produces an ac current in the coil, and the magnetic field exerts forces on the wires producing a torque that rotates the coil.

Page 3: Magnetism                          Alternating-Current Circuits

The magnetic field.

Magnetic forces on moving charges.

Magnetic forces on a current element

Torques on current loops and magnets

Page 4: Magnetism                          Alternating-Current Circuits

The Magnetic FieldMagnets

The Earth is a natural magnet with magnetic poles near the north and south geographic poles.

Page 5: Magnetism                          Alternating-Current Circuits

The Magnetic Field

Magnets Does an isolated magnetic pole exist?

The SI units of magnetic field is the tesla [T]

Earth magnetic field is about 10-4 T

Powerful laboratories produce fields of 1 -2 T as a maximum

1 Gauss [G] = 10-4 Tesla [T]

Page 6: Magnetism                          Alternating-Current Circuits

The Magnetic Field

Page 7: Magnetism                          Alternating-Current Circuits

The Magnetic Field. Magnetic force on a moving charge

A proton is moving in a region of crossed fields E = 2x105 N/C and B = 3000 G, as shown in the figure. (a) What is the speed of the proton if it is not deflected. (b) If the electric field is disconnected, draw the path of the proton

Page 8: Magnetism                          Alternating-Current Circuits

The Magnetic Field. Magnetic force on a current element

In the case of a straight segment of length L

Page 9: Magnetism                          Alternating-Current Circuits

The Magnetic Field. Torques on Current loops and Magnets

A circular loop of radius 2 cm has 10 turns of wire and carries a current of 3 A. The axis of the loop makes an angle of 30º with a magnetic field of 8000 G. Find the magnitude of the torque on the loop.

BA current-carrying loop experiences no net force in a uniform magnetic field, but it does experience a torque that tends to twist the loop

Page 10: Magnetism                          Alternating-Current Circuits

Sources of Magnetic Field

The Magnetic Field of Moving Charges

The Magnetic Field of Currents. The Biot-Savart Law

The Magnetic Field Due to a Current loop

Page 11: Magnetism                          Alternating-Current Circuits

Sources of Magnetic Field

Moving Point Charges are the source of Magnetic Field

Page 12: Magnetism                          Alternating-Current Circuits

A solenoid is a wire tightly wounded into a helix of closely space turns . A solenoid is used to produce a strong, uniform magnetic field in the region surrounded by the loops

For a long solenoid Find the magnetic field at the center of a

solenoid of 600 turns, length 20 cm; radius 1.4 cm that carries a current of 4 A

Sources of Magnetic Field

A solenoid

In this figure, the length is ten times longer than the radius

n = N/L; N number of turns; L : length of solenoid

Page 13: Magnetism                          Alternating-Current Circuits

Sources of Magnetic Field: Solenoid and magnets

Left: Magnetic field lines of a solenoid; right Magnetic field lines of a bar magnet

Page 14: Magnetism                          Alternating-Current Circuits

Magnetic Induction

Magnetic Flux

Induced EMF and Faraday´s Law

Lenz´s Law

Page 15: Magnetism                          Alternating-Current Circuits

MAGNETIC INDUCTIONIn 1830, Michel Faraday in England and Joseph Henry in the USA independently discovered that in a changing magnetic field, a changing magnetic flux through a surface bounded by a stationary loop of wire induces a current in the wire: emf induced and induced current. This process is known as induction.

In a static magnetic field, a changing magnetic flux through a surface bounded by a moving loop of wire induces an emf in the wire: motional emf

Magnetic flux through a surface bounded by a loop of wire.

The SI unit for magnetic flux is weber [Wb] 1Wb= 1 T∙m2 Find the magnetic flux through a 40 cm long

solenoid with a 2.5 cm radius and 600 turns carrying a current of 7.5 A.

Page 16: Magnetism                          Alternating-Current Circuits

The induced emf is in such direction as to oppose, or tend to oppose, the change that produces it. Lenz´s Law

MAGNETIC INDUCTION

Page 17: Magnetism                          Alternating-Current Circuits

The coil with many turns of wire gives a large flux for a given current in the circuit. Thus, when the current changes, there is a large emf induced in the coil opposing the change. This self-induced emf is called a back emf

MAGNETIC INDUCTION

Page 18: Magnetism                          Alternating-Current Circuits

Eddy Currents

Heat produced by eddy currents constitute a power loss in a transformer. But eddy currents have some practical applications: damping mechanical oscillations, magnetic braking system

Page 19: Magnetism                          Alternating-Current Circuits

Inductance Self-inductance The SI unit of

inductance is the henry [H]

1 H = 1 Wb/A= 1 T.m2.A-1

Find the self-inductance of a solenoid of length 10 cm, area 5 cm2, and 100 turns

Page 20: Magnetism                          Alternating-Current Circuits
Page 21: Magnetism                          Alternating-Current Circuits

Magnetic Energy

Page 22: Magnetism                          Alternating-Current Circuits

Alternating Current Generators

Alternating current motor

A coil of area A and N turns rotating with constant angular velocity in a uniform magnetic field produces a sinusoidal emf

Instead of mechanically rotating, we can apply an ac potential difference generated by other ac generator to the coil. This produces an ac current in the coil, and the magnetic field exerts forces on the wires producing a torque that rotaes the coil.

Page 23: Magnetism                          Alternating-Current Circuits

Alternating Current Generators A coil of area A and N turns rotating with constant angular velocity in a uniform magnetic field produces a sinusoidal emf

fffrequency

t

tNBAdt

d

tNBA

tandNBA

peak

m

m

m

2;

)sin(

)sin(

)cos(

cos

Page 24: Magnetism                          Alternating-Current Circuits

Alternating Current Circuits: Alternating current in a Resistor

Inductors in Alternating Currents Capacitors in Alternating Currents

Page 25: Magnetism                          Alternating-Current Circuits

Potential drop across the resistor, VR

Current in the resistor I Power dissipated in the resistor, P Average power dissipated in the resistor Paverage

Alternating currents in a Resistor

R

VIt

R

VI

tVtV

peakRpeak

peakR

peakRR

,,

,max

cos

coscos

RtIRIP

RtIRIP

avpeakavav

peak

))(cos()(

)(cos222

222

Page 26: Magnetism                          Alternating-Current Circuits

Root-Mean-Square Values

Page 27: Magnetism                          Alternating-Current Circuits

Inductors in Alternating Current Circuits

The potential drop across the inductor led the current 90º (out of phase)

Instantaneous power delivered by the emf to the inductor is not zero

The average power delivered by the emf to the inductor is zero.

)2

cos(sincos

coscos

,,,

,max

tL

Vt

L

VIt

L

V

dt

dI

tVtdt

dILV

peakLpeakLpeakL

peakLL

INDUCTIVE REACTANCE L

VI

L

VI rmsL

rmspeakL

peak ,, ;

Page 28: Magnetism                          Alternating-Current Circuits

Inductors in Alternating Current Circuits

Instantaneous power delivered by the emf to the inductor is not zero

The average power delivered by the emf to the inductor is zero.

INDUCTIVE REACTANCE

L

VI

L

VI rmsL

rmspeakL

peak ,, ;

The potential drop across a 40-mH inductor is sinusoidal with a peak potential drop of 120 V. Find the inductive reactance and the peak current when the frequency is (a) 60 Hz, and (b) 2000 Hz

Page 29: Magnetism                          Alternating-Current Circuits

Capacitors in Alternating Current CircuitsThe potential drop lags the current by 90º

Power delivered by the emf in the capacitor: Instantaneous and average

CAPACITIVE REACTANCE

)2

cos(1

sin

cos

coscos

,,

,

,max

t

C

VItCV

dt

dQI

tCVQ

tVtC

QV

peakCpeakC

peakC

peakCC

C

VI

C

VI rmsC

rmspeakC

peak

1

;1

,,

Page 30: Magnetism                          Alternating-Current Circuits

Driven RLC Circuits

Series RLC circuit The Kirchhoff´s rules govern the behavior of potential drops and current across the circuit. (a)When any closed-loop is traversed, the algebraic sum of the changes of potential must equal zero (loops rule)(b)At any junction (branch point) in a circuit where the current can be divided, the sum of the currents into the junction must equal the sum of the currents out of the junction (junction rule)

Page 31: Magnetism                          Alternating-Current Circuits

)cos(

cos

;cos

,

2

,

tII

tVC

QR

dt

dQ

dt

QdL

dt

dQI

C

QIR

dt

dILtV

peak

peakapp

peakapp

Series RLC circuits

Page 32: Magnetism                          Alternating-Current Circuits

Power delivered to the series RLC circuit

coscos2

1

/cos/

coscos2

1

)2

cos(cos

,,

,

22

,2

2

rmsrmsapppeakpeakapp

peakapppeak

rmsapprmsav

rmsrmspeakpeakav

peakpeak

IVIVP

ZVIandZRasZ

RVRIP

resistortheindissipatedRIP

IIP

tItIP

Power factor: cosδ

Page 33: Magnetism                          Alternating-Current Circuits

Series RLC circuits

A series RLC circuit with L = 2 H, C =2 μF and R=20Ω is driven by an ideal generator with a peak emf of 100 V and a frequency of 60 Hz, find (a) the current peak (b) the phase (c) the power factor, (d) the average power delivered; (e) the peak potential drop across each element

Page 34: Magnetism                          Alternating-Current Circuits

Phasors Potential drop across a resistor can be represented by a vector VR, which is called a phasor. Then, the potential drop across the resistor IR, is the x component of vector VR,

Potential drop across a series RLC circuit

C

QIR

dt

dILtVapp cos

Page 35: Magnetism                          Alternating-Current Circuits

In the circuit shown in the figure, the ac generator produces an rms voltage of 115 V when operated at 60 Hz. (a) What is the rms current in the circuit (b) What is the power delivered by the ac generator (c) What is the rms voltage across: points AB; points BC; points CD; points AC; points BD?.

A certain electrical device draws 10 A rms and has an average power of 720 W when connected to a 120-V rms 60-Hz power line. (a ) What is the impedance of the device? (b) What series combination of resistance and reactance is this device equivalent to? (c) If the current leads the emf, is the reactance inductive or capacitive?

Page 36: Magnetism                          Alternating-Current Circuits

The Transformer

Because of the iron core, there is a large magnetic flux through each coil, even when the magnetizing current Im in the primary circuit is very small . The primary circuit consists of an ac generator and a pure inductance (we consider a negligible resistance for the coil). Then the average power dissipated in the primary coil is zero. Why?: The magnetizing current in the primary coil and the voltage drop across the primary coil are out of phase by 90º

11

2222

11

VN

NVNV

NV

dtd

dtd

turn

turn

Secondary coil open circuit The potential drop across the primary coil is

If there is no flux leakage out of the iron core, the flux through each turn is the same for both coils, and then

A transformer is a device to raise or lower the voltage in a circuit without an appreciable loss of power. Power losses arise from Joule heating in the small resistances in both coils, or in currents loops (eddy currents) within the iron core. An ideal transformer is that in which these losses do not occur, 100% efficiency. Actual transformers reach 90-95% efficiency

Page 37: Magnetism                          Alternating-Current Circuits

The Transformer

rmsrmsrmsrms IVIV

ININ

,2,2,1,1

2211

However, the potential drop in the primary is determined by the generator emf According to this, the total flux in the iron core must be the same as when there is no load in the secondary. The primary coil thus draws an additional current I1 to maintain the original flux Φturn. The flux through each turn produced by this additional current is proportional to N1I1. Since this flux equals – Φ´turn, the additional current I1 in the primary is related to the current I2 in the secondary by

These curents are 180 º out of phase and produce counteracting fluxes. Since I2 is in phase with V2, the additional current I1 is in phase with the potential drop across the primary. Then, if there are no losses

A resistance R, load resistance, in the secondary circuit

A current I2 will be in the secondary coil, which is in phase with the potential drop V2 across the resistance. This current sets up and additional flux Φ´turn through each turn, which is proportional to N2I2. This flux opposes the original flux sets up by the original magnetizing current Im in the primary.