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Magnetic Force

Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

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Page 1: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Magnetic Force

Page 3: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

F = qvB sin q

Strength of Magnetic Force

A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s velocity and to the magnetic field itself.

Lorentz Force Law:

The magnitude of the magnetic force on a moving, charged particle is

(q is the angle between the charge’s velocity and the magnetic field)

Page 4: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

F = qvB sin q

Sin 0, 180 = 0 If a charge has velocity in the same (or opposite) direction of the magnetic field, it experiences no force!

Sin 90 = 1 A charge that has velocity perpendicular to the magnetic field experiences the greatest force!

Page 5: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Question?

The three charges below have equal charge and speed, but are traveling in different directions in a uniform magnetic field.

Which particle experiences the greatest magnetic force?

1 2 3 Same B

1

2

3F = q v B sin q

Page 6: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

charge q moving with velocity v in the mag. field B

v

B

q

The direction of the magnetic force is given by the Right-Hand Rule

► Point fingers in v (or current I) direction

Fpositive charge

F negative charge

► Curl fingers as if rotating vector v (current I) into B.

► Thumb is in the direction of the force.

● For negative charge force is in the opposite direction

F is perpendicular to the plane of v and B

Page 7: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

A proton enters a magnetic field, as shown. Which way will the electron turn?

1. Up2. Down3. Out of page4. Into page

Page 8: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

A proton enters a magnetic field, as shown. Which way will the electron turn?

1. Up2. Down3. Out of page4. Into page

Put your fingers in the direction of the velocity and curl out of the page … your thumb points up

Page 9: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

An electron enters a magnetic field, as shown. Which way will the electron turn?

1. Up2. Down3. Out of page4. Into page

Page 10: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

An electron enters a magnetic field, as shown. Which way will the electron turn?

1. Up2. Down3. Out of page4. Into page

Remember to flip the direction of the force for negative charges

Page 11: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

In which direction will wire segment B be pushed?

1. Up2. Down3. Out of page4. Into page5. No force exists

Page 12: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

In which direction will wire segment B be pushed?

1. Up2. Down3. Out of page4. Into page5. No force exists

Page 13: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

In which direction will wire segment C be pushed?

1. Up2. Down3. Out of page4. Into page5. No force exists

Page 14: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Convention for magnetic field direction:

x x x x x x x INTO Page

••••••••••••• OUT of Page

Right Hand Rule Practice

In which direction will wire segment C be pushed?

1. Up2. Down3. Out of page4. Into page5. No force exists

V and B are in the same direction; no force exists.

Page 15: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

We define the magnitude of the magnetic field by measuring the force on a moving charge:

v

Bq

sinqv

FB

The SI unit of magnetic field is the Tesla (T), named after Nikola Tesla, a Croatian physicist.

mC

sN

sm

C

N

1 T = 1 N·s/(C·m)

Magnitude of the magnetic field

Page 16: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Magnetic Field & Magnetic Force Problems

We do:What is the minimum magnetic field necessary to exert a 5.4 X 10-15 N force on an electron moving at 2.1 X 107 m/s?

Page 17: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Magnetic Field & Magnetic Force Problems

We do:What is the minimum magnetic field necessary to exert a 5.4 X 10-15 N force on an electron moving at 2.1 X 107 m/s?

B = F / qvsinθB will be at a minimum when sin θ = 1

B = F / qv = 5.4X10-15N / (1.6 X 10-19 C X 2.1 X 107 m/s)B = 1.61 X 10-3 T

Page 18: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Magnetic Field & Magnetic Force Problems

You do:What is the magnetic field necessary to exert a 5.4 X 10-15 N force on an electron moving at 2.1 X 107 m/s if the magnetic field is at 45 degrees from the electron’s velocity?

Page 19: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Magnetic Field & Magnetic Force Problems

You do:What is the magnetic field necessary to exert a 5.4 X 10-15 N force on an electron moving at 2.1 X 107 m/s if the magnetic field is at 45 degrees from the electron’s velocity?

B = F / qvsinθ = 5.4X10-15N / (1.6 X 10-19 C X 2.1 X 107 m/s X sin 45)B = 2.3 X 10-3 T.

Page 20: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Magnetic Field & Magnetic Force Problems

We do and You doWhat is the magnitude of the magnetic force on a proton moving at 2.5 X 105 m/s in a magnetic field of 0.5 T …

(a) …if the velocity and magnetic field are at right angles? (b) … if the velocity and magnetic field are at 30°?(c) … if the velocity is parallel to a magnetic field?

Page 21: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Magnetic Field & Magnetic Force Problems

We do and You doWhat is the magnitude of the magnetic force on a proton moving at 2.5 X 105 m/s in a magnetic field of 0.5 T …

(a) …if the velocity and magnetic field are at right angles? (b) … if the velocity and magnetic field are at 30°?(c) … if the velocity is parallel to a magnetic field?

F = qvBsinθ , so (a) when θ = 90°, F = (1.6 X 10-19 C)(2.5 X 105 m/s)(0.5 T) = 2.0 X 10-14 N,(b) F = (2.0 X 10-14 N) sin 30° = 1.0 X 10-14 N, and(c) F = qvB sin 0° = 0.

Page 22: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

Comparison of Electric and Magnetic Forces

Using your notes, and working in small groups (3 or less), compare the electric and magnetic forces in terms of:

• Magnitude• Direction• Work done• Effect on charged particles

Page 23: Magnetic Force. . Strength of Magnetic Force A charged particle moving in a magnetic field experiences a force that is perpendicular to BOTH the particle’s

The electric force: Felec = Eq

The magnetic force: Fmag = qvB sin q

Comparison of Electric and Magnetic Forces

is always parallel to the direction of the electric field. acts on a charged particle independent of the particle’s velocity

does work when moving charge: The work, W = Fel d cosθ1, is converted into kinetic / thermal energy.

The electric field accelerates charged particles.

is always perpendicular to the direction of the magnetic field acts on a charged particle only when the particle is in motion (F=0 if v=0), and only if v and B do not point in the same or opposite direction (sin 00 = sin 1800 = 0). Force is perpendicular to motion so the work done by magnetic force is zero. W = Fmagd cosq1 = 0 (cos 900 = 0). Change in kinetic energy of the charge is 0

In the presence of magnetic field, the moving charged particle is deflected (dotted lines)