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Grade 8 Module 2 Lesson Excerpts
Lesson 3, Exercises 1-Ββ4 Draw a line passing through point P that is parallel to line πΏ. Draw a second line passing through point π that is parallel to line πΏ, that is distinct (i.e., different) from the first one. What do you notice?
Translate line πΏ along the vector π΄π΅. What do you notice about πΏ and its image πΏβ²?
Line πΏ is parallel to vector π΄π΅. Translate line πΏ along vector π΄π΅. What do you notice about πΏ and its image, πΏβ²?
Translate line πΏ along the vector π΄π΅. What do you notice about πΏ and its image, πΏβ²?
Understanding that translations of lines produce an image that is either the line itself or a line parallel to the given line rely on the work completed at the end of Lesson 2 about the translation of a point.
Note that references to βA aboveβ and βB aboveβ should be replaced by βLesson 2β and that the exercise numbers referenced do not match. (Exercise 4 should be Exercise 2, Exercise 5 should be Exercise 3, and Exercise 6 should be Exercise 4.)
πΏ
Grade 8 Module 2 Lesson Excerpts
Lesson 4, Example 4
A simple consequence of (Reflection 2: Reflections preserve lengths of segments) is that it gives a more precise description of the position of the reflected image of a point.
Β§ Let there be a reflection across line πΏ, let π be a point not on line πΏ, and let πβ represent π ππππππ‘πππ π . Let the line ππβ intersect πΏ at π, and let π΄ be a point on πΏ distinct from π, as
shown.
Β§ Because π ππππππ‘πππ ππ = πβ²π, (Reflection 2) guarantees that segments ππ and πβπ have the same length.
Β§ In other words, π is the midpoint (i.e., the point equidistant from both endpoints) of ππβ. Β§ In general, the line passing through the midpoint of a segment is said to βbisectβ the segment.
Lesson 5, Problem Set 1
Let there be a rotation by β 90Λ around the center π.
During the lesson, be sure to show students how to use the transparency to rotate in multiples of 90Λ.
Grade 8 Module 2 Lesson Excerpts
Lesson 6, Exit Ticket 1
Let there be a rotation of 180 degrees about the origin. Point π΄ has coordinates β2,β4 , and point π΅ has coordinates (β3, 1), as shown below.
What are the coordinates of π ππ‘ππ‘πππ(π΄)? Mark that point on the graph so that π ππ‘ππ‘πππ(π΄) = π΄β².
What are the coordinates of π ππ‘ππ‘πππ(π΅)? Mark that point on the graph so that π ππ‘ππ‘πππ(π΅) = π΅β².
Lesson 7, Discussion
Β§ What need is there for sequencing transformations?
Β§ Imagine life without an undo button on your computer or smartphone. If we move something in the plane, it would be nice to know we can move it back to its original position.
Β§ Specifically, if a figure undergoes two transformations πΉ and πΊ, and ends up in the same place as it was originally, then the figure has been mapped onto itself.
Β§ Suppose we translate figure π· along vector π΄π΅.
Grade 8 Module 2 Lesson Excerpts
Β§ How do we undo this move? That is, what translation of figure π· along vector π΄π΅ that would bring π·β² back to its original position?
Lesson 8, Discussion
Β§ Does the order in which we sequence rigid motions really matter?
Β§ Consider a reflection followed by a translation. Would a figure be in the same final location if the translation was done first then followed by the reflection?
Β§ Let there be a reflection across line πΏ and let π be the translation along vector π΄π΅. Let πΈ represent the ellipse. The following picture shows the reflection of E followed by the translation of πΈ.
Β§ Before showing the picture, ask students which transformation happens first: the reflection or the translation?
ΓΊ Reflection
Β§ Ask students again if they think the image of the ellipse will be in the same place if we translate first and then reflect. The following picture shows a translation of πΈ followed by the reflection of E.
Β§ It must be clear now that the order in which the rigid motions are performed matters. In the above example, we saw that the reflection followed by the translation of πΈ is not the same as the translation followed by the reflection of πΈ; therefore a translation followed by a reflection and a reflection followed by a translation are not equal.
π ππππππ‘πππ(πΈ)
π ππππππ‘πππ, π‘βππ π‘ππππ πππ‘πππ ππ(πΈ)
πππππ πππ‘πππ, π‘βππ πππππππ‘πππ ππ (πΈ)
πππππ πππ‘πππ(πΈ)
Grade 8 Module 2 Lesson Excerpts
Lesson 9, Exploratory Challenge 2
a. Rotate β³ π΄π΅πΆ π degrees around center π· and then rotate again π degrees around center πΈ. Label the image as β³ π΄β²π΅β²πΆβ² after you have completed both rotations.
b. Can a single rotation around center π· map β³ π΄β²π΅β²πΆβ² onto β³ π΄π΅πΆ? c. Can a single rotation around center πΈ map β³ π΄!π΅!πΆ! onto β³ π΄π΅πΆ? d. Can you find a center that would map β³ π΄β²π΅β²πΆβ² onto β³ π΄π΅πΆ in one rotation? If so, label the
center πΉ.
Grade 8 Module 2 Lesson Excerpts
Lesson 10, Exercise 4
In the following picture, we have two pairs of triangles. In each pair, triangle π΄π΅πΆ can be traced onto a transparency and mapped onto triangle π΄!π΅!πΆ!. Which basic rigid motion, or sequence of, would map one triangle onto the other?
Scenario 1:
Scenario 2:
Lesson 11, Exercise 1
Describe the sequence of basic rigid motions that shows π! β π!. Describe the sequence of basic rigid motions that shows π! β π!. Describe the sequence of basic rigid motions that shows π! β π!.
Grade 8 Module 2 Lesson Excerpts
Congruence is transitive!
Lesson 12, Exploratory Challenge 2
In the figure below, πΏ! β₯ πΏ!, and π is a transversal. Use a protractor to measure angles 1β8. List the angles that are equal in measure.
What did you notice about the measures of β 1 and β 5? Why do you think this is so? (Use your transparency, if needed).
What did you notice about the measures of β 3 and β 7? Why do you think this is so? (Use your transparency, if needed.) Are there any other pairs of angles with this same relationship? If so, list them.
What did you notice about the measures of β 4 and β 6? Why do you think this is so? (Use your transparency, if needed). Is there another pair of angles with this same relationship?
Lesson 13, Exploratory Challenge 2
Grade 8 Module 2 Lesson Excerpts
The figure below shows parallel lines πΏ! and πΏ!. Let π and π be transversals that intersect πΏ! at points π΅ and πΆ, respectively, and πΏ! at point πΉ, as shown. Let π΄ be a point on πΏ! to the left of π΅, π· be a point on πΏ! to the right of πΆ, πΊ be a point on πΏ! to the left of πΉ, and πΈ be a point on πΏ! to the right of πΉ.
Name the triangle in the figure.
Name a straight angle that will be useful in proving that the sum of the interior angles of the triangle is 180Λ.
Write your proof below.
Lesson 14, Exercise 4
Grade 8 Module 2 Lesson Excerpts
Show that the measure of an exterior angle is equal to the sum of the related remote interior angles.
Lesson 15, Proof of Pythagorean theorem
Lesson 16, Exercise 3
Find the length of the segment π΄π΅.
Grade 8 Module 2 Lesson Excerpts