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Name: Mohit N. Mulani Experiment Due Date: 2/20/14 Section instructor: Brian Kasper Section: 231 Luminol and Chemiluminescence 1) In 3nitrophthalic acid, the carboxylic which is more acidic is at the 2 position with pKa=2. In this conjugated ring system, the nitro group acts as a powerful electron withdrawing group (deactivating agent) which serves to remove/pull away electron density from the carboxylic acid groups and make them more electrophilic which stabilizes the conjugate base (anion) and makes it easier for it to lose the H + . This effect of the nitro group is felt much more strongly by the carboxylic group closer to it on the ortho position (w.r.t it) than the other one in the meta position making it more acidic. 2) To calculate the K eq , we need the pK a values of the acid and the conjugate acid. We have one of these (for 3nitrophthalic acid: 2) and to find the other, we can use the pK b value of Hydrazine which is 5.77. As the sum of the pK b and pK a values for a conjugate pair is 14, we can calculate it to be 8.23. Making dissociation equations for the acids and dividing them to get the original reaction, we see that pK eq is 28.23=6.23. K eq therefore is 10 6.23 or 1.7x10 6 . 3) The reaction of 3nitrophthalic acid and Hydrazine could go both ways but only the one which involves the replacement of the OH group with amine group (NH) and then the intramolecular replacement of the other OH group of 3nitrophthalic acid with the other amine group is favoured. This reaction is more likely to happen because as it is intramolecular, it is faster than the minor one which involves 2 molecules of hydrazine attacking the separate OH groups. We’ve also established that because of its position relative to the nitro group one of the carboxylic groups is more acidic which makes it more likely to be the one which is attacked first followed by an intramolecular reaction. 4) The pK b value for ethant 1,3 diamine is higher than that of hydrazine (it is a weaker base) which

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Luminol and Chemiluminescence

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  • Name:MohitN.Mulani ExperimentDueDate:2/20/14

    Sectioninstructor:BrianKasper Section:231

    LuminolandChemiluminescence

    1)In3nitrophthalicacid,thecarboxylicwhichismoreacidicisatthe2positionwithpKa=2.

    Inthisconjugatedringsystem,thenitrogroupactsasapowerfulelectronwithdrawinggroup

    (deactivatingagent)whichservestoremove/pullawayelectrondensityfromthecarboxylicacidgroups

    andmakethemmoreelectrophilicwhichstabilizestheconjugatebase(anion)andmakesiteasierforit

    tolosetheH+.Thiseffectofthenitrogroupisfeltmuchmorestronglybythecarboxylicgroupcloserto

    itontheorthoposition(w.r.tit)thantheotheroneinthemetapositionmakingitmoreacidic.

    2)TocalculatetheKeq,weneedthepKavaluesoftheacidandtheconjugateacid.Wehaveoneof

    these(for3nitrophthalicacid:2)andtofindtheother,wecanusethepKbvalueofHydrazinewhichis

    5.77.AsthesumofthepKbandpKavaluesforaconjugatepairis14,wecancalculateittobe8.23.

    Makingdissociationequationsfortheacidsanddividingthemtogettheoriginalreaction,weseethat

    pKeqis28.23=6.23.Keqthereforeis106.23or1.7x106.

    3)Thereactionof3nitrophthalicacidandHydrazinecouldgobothwaysbutonlytheonewhich

    involvesthereplacementoftheOHgroupwithaminegroup(NH)andthentheintramolecular

    replacementoftheotherOHgroupof3nitrophthalicacidwiththeotheraminegroupisfavoured.This

    reactionismorelikelytohappenbecauseasitisintramolecular,itisfasterthantheminoronewhich

    involves2moleculesofhydrazineattackingtheseparateOHgroups.Wevealsoestablishedthat

    becauseofitspositionrelativetothenitrogrouponeofthecarboxylicgroupsismoreacidicwhich

    makesitmorelikelytobetheonewhichisattackedfirstfollowedbyanintramolecularreaction.

    4)ThepKbvalueforethant1,3diamineishigherthanthatofhydrazine(itisaweakerbase)which

  • meansthesubsequentpKaoftheconjugateacidwillbesmallermakingitsKeqhigher.Thislowersthe

    Keqoftheoriginalreaction(whichiscalculatedastheratioofacidKeqandconjugateacidKeqimplying

    thattherateofforwardreactionhasbeenlowered.Theproductformedasaresultofreactingtheacid

    withethane1,3diaminewillbeamuchlargerringastheamidegroupnowattacksthecarboxylicacid

    forminganeightmemberedring.Eightmemberedringsascomparedtosixmemberedrings(nostrainin

    chairconformation)orfivememberedrings(onlytorsionalstrain)havebothtorsionalstrainandsteric

    strain.Thismakesitmoreunstable.

    5)Thisoccursbecauseamidesarelessbasicthanaminesonaccountofresonancestabilization.The

    resonanceoccursduetothepresenceofalonepaironNitrogenwhichisdelocalizedbetweenitandthe

    electronegativeoxygenofthecarbonylgroup.

    6)485nm.TheluminolontreatmentwithK3Fe(CN)6/H2O2emitslightwhichhasabrightblue(almost

    cyan)colourwhichcorrespondstothehighendofthebluewavelength(450500nm),edgingtowards

    greenratherthanviolet.Thislightwouldbeamixtureofseveralwavelengthsaroundthehigherendof

    thisrangesoIselected485nm.

    7)Itwouldbeaterriblelightsourcebecauseoftheshorttimeitsglowlasts(onlyafewseconds).This

    wouldmeanconstantreactionsofluminolwithoxidisingagentswhichiscostlyanddifficultifthesignis

    torun24hoursaday.

    8)A)Luminol:Exactmass177.05g

    Massoftwomostabundantisotopes:177.05g,178.06g.

    Luciferin:Exactmass280.00g

    Massoftwomostabundantisotopes:280.00g,281.00g.

    B)Luminolwouldhaveauniquesignalataround3000cm1associatedwiththeNHgroupand

  • Luciferinwouldalsohavearecognizablesignalduetothepresenceofsulphursinglebondedtocarbon

    initsheterocyclicsystem.

    C)Luminolhas7signals(with2uniquecarbonsatthecentreofthebicyclicsystemhavingthesame

    energywithashiftdifferenceofabout1ppm)andLuciferinhas11signalswithdifferentchemicalshifts.

    D)Luminolhas5signalsandLuciferinhas8signals.