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21 April 2023 F L1 MH
Objectives :
•To know what log means
•To learn the laws of logs
•To simplify logarithmic expressions
•To solve equations of the type ax=b
21 April 2023 F L1 MH
We WILL meet the graph of y=ax and will see that it represents growth or decay.
Say possibly growth of Bacteria if x>0
Say possibly decay of radioactivity if x<0 So we will need to be able to solve
equations of the type b = ax
e.g. How would you solve
Ans: If we notice that 3101000
3 x
31010 x
We can use the same method to solve
813 x or
2552 x
122 xx4 x
433 x 22 55 x
then, (1) becomes
- - - - (1)100010 x
We need to write 75 as a power ( or index ) of 10.
Suppose we want to solve
7510 x
This index is called a logarithm ( or log ) and 10 is the base.
Our calculators give us the value of the logarithm of 75 with a base of 10.
87511010 xThe value is ( 3 d.p.) so,
8751
8751 x
Tip: It’s useful to notice that, since 75 lies between 10 and 100 ( or ), x lies between 1 and 2.
21 1010 and
The button is markedLog 75
Logarithm
21 April 2023 F L1 MH
919683log3
logarithms
log264=6 because 26 = 64
log2(1/2)=-1 because 2-1 = ½
log21=0 because 20= 1
log2√2=1/2 because 21/2 = √2
21 April 2023 F L1 MH
Logarithms to base 10
Any positive number can be written as a power of 10. Logarithms to base 10 are used in such subjects as:
Chemistry pH value of a liquidPhysics power ratio – e.g. noise level –
decibel scale Earthquake measurement - Richter scale
(Logarithmic scales are also used for example to measure radioactive decay, pitch of musical notes, f-stops in photography, particle size in geology and population growth)
Log to base 10
Log10 10 = 1
Scientists only work with 2 specific bases (log, ln)We do not write the 10 as Log means to base 10
Log10=1 Log 0.1 = -1 Log1=0Log100=2 Log 0.01=-2Log1000=3 Log0.001=-3We can not take logs of negative numbers
21 April 2023 F L1 MH
Log is an Inverse
Log is the inverse to 10x (last lesson)
(can show this when we learn the laws of logarithms)
Ln is the inverse of ex, (we will see this later)
e is a very important irrational number in maths and science, it has some very special properties!!
21 April 2023 F L1 MH
So A logarithm is just an index
Solve the equation 10x = 4 giving the answer correct to 3 significant figures.
“x is the logarithm of 4 with a base of
10”
21 April 2023 F L1 MH
logindex
Log 4 = 0.602 (3 sig fig) – on calculator
Laws of Logarithms
These are like the laws of indices (surprised NO!)
log a xy = log a x + log a y
log a x/y = log a x – log a y
log a x n = n log a x
21 April 2023 F L1 MH
Some Important Rules
21 April 2023 F L1 MH
Loga1=0
1log aa
xn
xx an
an
a log1
loglog 1
xxx aaa loglog1
log 1
These are the
Laws of Logs
a0=1
a1=a
Using these Rules- Simplify
21 April 2023 F L1 MH
6log3log24log aaa
6log3log4log 2aaa
6log34log 2aa
6
34log
2
a
~ Loga6
21 April 2023 F L1 MH
Express in terms of logax, logay, logaz
Loga = loga x3 – logay2z
Loga = loga x3 – (logay2 + logaz)
zy
x2
3
zy
x2
3
zy
x2
3
Loga = 3loga x – 2logay - logaz) zy
x2
3
21 April 2023 F L1 MH
Do Ex 11A Page 325 q 1 - 5
We don’t actually take the logs anywhere: we put them in, but the process is always called taking logs!
Solving ba x
52 xe.g.1 Solve
Solution: 52 x
2log
5log
10
10x
) s.f. ( 3322
5log2log 1010 x
We “take” logs
( Notice that 2 < x < 3 since ) 8242 32 and
5log2log 1010 x
We used logs with base 10 because the values are on the calculator. However, any base could be used. You could check the result using the “ln” button ( which uses a base you will meet in A2 ).
Using the “power to the front” law, we can simplify the l.h.s.
x)3(1001000 e.g.2 Solve the equation
Solution: We must change the equation into the form before we take logs.xab
Using the “power to the front” law:
x3log
10log
) s.f. ( 3102 x
x3log10log x)3(1001000 x310
Divide by 100:
Take logs:
3log10log x
Solving ba x
SUMMARY
bxba ax log
The Definition of a Logarithm
Solving the equation bna x
• “Take” logs
The “Power to the Front” law of logs:
xkx ak
a loglog
• Use the power to the front law
• Rearrange to find x.
• Divide by n
Exercises
143 x
14log3log 1010 x
( 2 d.p. )
1. Solve the following equations giving the answers correct to 2 d.p.(a) (b) 15122 x
4023log
14log
10
10 x
(a) “Take” logs:14log3log 1010 x
0898112log
15log2
10
10 x
(b) 15log12log 102
10 x“Take” logs:
15log12log2 1010 x
( 2 d.p. )540 x
2. Solve the equation giving the answer correct to 2 d.p.
x)2(200500
Solution: Divide by 200:xx 252)2(200500
x2log52log Take logs:
Power to the front: 2log52log x
Rearrange: x
2log
52log
( 2 d.p. )321 x
Exercises
Do Ex 11A page 326 no 6 ff
21 April 2023 F L1 MH