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8•4 Lesson 8 Lesson 8: Linear Equations in Disguise Lesson 8: Linear Equations in Disguise Classwork Example 3 Can this equation be solved? 6+ 7 + 2 3 = 3 8 Example 4 Can this equation be solved? 7 3 +9 = 1 8 A STORY OF RATIOS This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org G8-M4-SE-1.3.0-07.2015 S.26

Lesson 8: Linear Equations in DisguiseLesson 8 8•4 Lesson 8 : Linear Equations in Disguise Example 5 In the diagram below, # $ % ~ #′ $ %′.Using what we know about similar triangles,

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Page 1: Lesson 8: Linear Equations in DisguiseLesson 8 8•4 Lesson 8 : Linear Equations in Disguise Example 5 In the diagram below, # $ % ~ #′ $ %′.Using what we know about similar triangles,

8•4 Lesson 8

Lesson 8: Linear Equations in Disguise

Lesson 8: Linear Equations in Disguise

Classwork

Example 3

Can this equation be solved?

6 + 𝑥𝑥

7𝑥𝑥 + 23=38

Example 4

Can this equation be solved?

73𝑥𝑥 + 9 =

18

A STORY OF RATIOS

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka- math.orgG8-M4-SE-1.3.0-07.2015

S.26

Page 2: Lesson 8: Linear Equations in DisguiseLesson 8 8•4 Lesson 8 : Linear Equations in Disguise Example 5 In the diagram below, # $ % ~ #′ $ %′.Using what we know about similar triangles,

8•4 Lesson 8

Lesson 8: Linear Equations in Disguise

Example 5

In the diagram below, △ 𝐴𝐴𝐴𝐴𝐴𝐴 ~ △ 𝐴𝐴′𝐴𝐴′𝐴𝐴′. Using what we know about similar triangles, we can determine the value of 𝑥𝑥.

Exercises

Solve the following equations of rational expressions, if possible.

1. 2𝑥𝑥 + 19

=1 − 𝑥𝑥6

A STORY OF RATIOS

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka- math.orgG8-M4-SE-1.3.0-07.2015

S.27

Page 3: Lesson 8: Linear Equations in DisguiseLesson 8 8•4 Lesson 8 : Linear Equations in Disguise Example 5 In the diagram below, # $ % ~ #′ $ %′.Using what we know about similar triangles,

8•4 Lesson 8

Lesson 8: Linear Equations in Disguise

2. 5 + 2𝑥𝑥3𝑥𝑥 − 1

=67

3. 𝑥𝑥 + 912

=−2𝑥𝑥 − 12

3

4. 8

3 − 4𝑥𝑥=

5

2𝑥𝑥 + 14

A STORY OF RATIOS

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka- math.orgG8-M4-SE-1.3.0-07.2015

S.28

Page 4: Lesson 8: Linear Equations in DisguiseLesson 8 8•4 Lesson 8 : Linear Equations in Disguise Example 5 In the diagram below, # $ % ~ #′ $ %′.Using what we know about similar triangles,

8•4 Lesson 8

Lesson 8: Linear Equations in Disguise

Problem Set Solve the following equations of rational expressions, if possible. If an equation cannot be solved, explain why.

1. 5

6𝑥𝑥 − 2=

−1𝑥𝑥 + 1

6. 2𝑥𝑥 + 52

=3𝑥𝑥 − 26

2. 4 − 𝑥𝑥8

=7𝑥𝑥 − 13

7. 6𝑥𝑥 + 13

=9 − 𝑥𝑥7

3. 3𝑥𝑥𝑥𝑥 + 2

=59

8. 13𝑥𝑥 − 8

12=−2 − 𝑥𝑥15

4. 12𝑥𝑥 + 6

3=𝑥𝑥 − 32

9. 3 − 𝑥𝑥1 − 𝑥𝑥

=32

5. 7 − 2𝑥𝑥6

=𝑥𝑥 − 51

10. In the diagram below, △ 𝐴𝐴𝐴𝐴𝐴𝐴 ~ △ 𝐴𝐴′𝐴𝐴′𝐴𝐴′. Determine the lengths of 𝐴𝐴𝐴𝐴���� and 𝐴𝐴𝐴𝐴����.

Lesson Summary

Some proportions are linear equations in disguise and are solved the same way we normally solve proportions.

When multiplying a fraction with more than one term in the numerator and/or denominator by a number, put the expressions with more than one term in parentheses so that you remember to use the distributive property when transforming the equation. For example:

𝑥𝑥 + 42𝑥𝑥 − 5 =

35

5(𝑥𝑥 + 4) = 3(2𝑥𝑥 − 5).

The equation 5(𝑥𝑥 + 4) = 3(2𝑥𝑥 − 5) is now clearly a linear equation and can be solved using the properties of equality.

A STORY OF RATIOS

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka- math.orgG8-M4-SE-1.3.0-07.2015

S.29