Lecture 4.3 Integral as Net Change

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    Theimage cannotbe displayed.Your computer may nothaveenough memory toopen theimage, or theimagemay havebeen corrupted.Restartyour computer, and then open thefileagain.I fthe red x stillappears, you may havetodelete theimage and then insertit again.

    ft

    min

    minutes

    A honey bee makes several trips from the hive to a flower

    garden. The velocity graph is shown below.

    What is the total distance traveled by the bee?

    200ft

    200ft

    200ft

    100ft

    200 200 200 100 700 ! 700 feet

    p

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    Theimage cannotbe displayed.Your computer may nothaveenough memory toopen theimage, or theimagemay havebeen corrupted.Restartyour computer, and then open thefileagain.I fthe red x stillappears, you may havetodelete theimage and then insertit again.

    ft

    min

    minutes

    What is the displacement of the bee?

    200ft

    -200ft

    200ft

    -100ft

    200 200 200 100 100 !

    100 feet towards the hive

    p

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    To find the displacement (position shift) from the velocity

    function, we just integrate the function. The negative

    areas below the x-axis subtract from the totaldisplacement.

    Displacementb

    a

    V t dt !

    Distance Traveledb

    a

    t dt! To find distance traveled we have to use absolute value.

    Find the roots of the velocity equation and integrate in

    pieces, just like when we found the area between a curveand the x-axis. (Take the absolute value of each integral.)

    Or you can use your calculator to integrate the absolute

    value of the velocity function. p

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    Theimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.Theimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.Theimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.Theimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.

    Theimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.Theimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.Theimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.

    velocity graphTheimage cannotbed isplayed.Your computer may nothaveenough memory toopen theimage,or theimage may havebeen corrupted.Restart your computer,and then open thefile again.If thered x stillappears,you may havetodeletethe imageand then insertit again.

    position graph

    1

    2

    1

    2

    1

    2

    Displacement:

    1 11 2 1

    2 2 !

    Distance Traveled:

    1 11 2 4

    2 2 !

    Every AP exam I have seenhas had at least one

    problem requiring students

    to interpret velocity and

    position graphs.

    p

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    In the linear motion equation:

    dS V tdt

    ! V(t) is a function of time.

    For a very small change in time, V(t) can be

    considered a constant. dS V t dt!

    S V t t ( ! ( We add up all the small changes in S to getthe total distance.

    1 2 3S V t V t V t ! ( ( (

    1 2 3S V V V t! (

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    S V t t( ! ( We add up all the small changes in S to getthe total distance.

    1 2 3S V t V t V t ! ( ( (

    1 2 3

    S V V V t! (

    1

    k

    n

    n

    S V t

    !

    ! (

    1

    n

    n

    S V t

    g

    !

    ! (

    S V t dt!

    As the number of subintervals becomes

    infinitely large (and the width becomes

    infinitely small), we have integration.

    p

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    This same technique is used in many different real-life

    problems.

    p

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    Example 5: National Potato Consumption

    The rate of potato consumption

    for a particular country was:

    2.2 1.1tC t !

    where t is the number of years

    since 1970 and is in millions

    of bushels per year.

    For a small , the rate of consumption is constant.t(

    The amount consumed during that short time is . C t t (

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    Example 5: National Potato Consumption

    2.2 1.1

    tC t !

    The amount consumed during that short time is . C t t (

    We add up all these small

    amounts to get the totalconsumption:

    total consumption C t dt!

    4

    2

    2.2 1.1tdt

    4

    2

    12.2 1.1

    ln1.1

    tt!

    From the beginning of 1972 to

    the end of 1973:

    7.066}million

    bushels

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    Hookes law for springs: F kx!

    x = distance that

    the spring is

    extended beyond

    its natural length

    k= spring

    constant

    p

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    Hookes law for springs: F kx!

    Example 7:

    It takes 10 Newtons to stretch a

    spring 2 meters beyond its natural

    length.

    F=10 N

    x=2 M

    10 2k!

    5 k! 5F x!

    How much work is done stretching

    the spring to 4 meters beyond its

    natural length?

    p

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    F(x)

    x=4 M

    How much work is done stretching

    the spring to 4 meters beyond its

    natural length?

    For a very small change in x, the

    force is constant.

    dw F x dx!

    5 dw x dx!

    5 dw x dx!

    4

    0

    5 W x dx!

    4

    2

    0

    5

    2W x!

    40W ! newton-meters

    40W ! joules

    5F x x!

    T