Upload
tausiq
View
44
Download
2
Embed Size (px)
DESCRIPTION
Lecture 18 Eigenvalue Problems II. Shang-Hua Teng. Diagonalizing A Matrix. Suppose the n by n matrix A has n linearly independent eigenvectors x 1 , x 2 ,…, x n . Eigenvector matrix S: x 1 , x 2 ,…, x n are columns of S. Then. L is the eigenvalue matrix. Matrix Power A k. - PowerPoint PPT Presentation
Citation preview
Lecture 18Eigenvalue Problems II
Shang-Hua Teng
Diagonalizing A Matrix• Suppose the n by n matrix A has n linearly independent
eigenvectors x1, x2,…, xn.
• Eigenvector matrix S: x1, x2,…, xn are columns of S.• Then
n
ASS
11
is the eigenvalue matrix
Matrix Power Ak
• S-1AS = implies A = S S-1
• implies A2 = S S-1 S S-1 = S S-1
• implies Ak = S kS-1
Random walks
How long does it take to get completely lost?
000001
Random walks Transition Matrix1
2
345
6
000001
021
4100
21
310
41000
31
210
21
310
00410
310
0041
210
21
31000
310
100
P
Matrix Powers
• If A is diagonalizable as A = S S-1 then for any vector u, we can compute Aku efficiently
– Solve S c = u– Aku = S kS-1 S c = S k c
• As if A is a diagonal matrix!!!!
Independent Eigenvectors from Different Eigenvalues
• Eigenvectors x1, x2,…, xk that correspond to distinct (all different) eigenvalues are linear independent.
• An n by n matrix that has n different eigenvalues (no repeated ’s) must be diagonalizable
Proof: Show that
implies all ci = 0
011 kk xcxc
Addition, Multiplication, and Eigenvalues
• If is an eigenvalue of A and is an eigenvalue of B, then in general is not an eigenvalue of AB
• If is an eigenvalue of A and is an eigenvalue of B, then in general is not an eigenvalue of A+B
Example
0110
0001
0100
,0010
BA
AB
BA
Spectral Analysis of Symmetric Matrices A = AT (what are special about them?)
Spectral Theorem: Every symmetric matrix has the factorization
A = QQT
with real eigenvalues in and orthonormal eigenvectors in :
A =QQ-1 = QQT with Q-1= QT.
Simply in English
• Symmetric matrix can always be diagonalized
• Their eigenvalues are always real• One can choose n eigenvectors so that they
are orthonormal.
• “Principal axis theorem” in geometry and physics
2 by 2 Case
Real Eigenvalues
222det baccabcacb
ba
cbba
A
2 by 2 Case
so
bc
xxcb
baxIA
ab
xxcb
baxIA
cbba
A
222
2
222
111
1
111
21 xx
The eigenvalues of a real symmetric matrix are real
• Complex conjugate of a + i b is a - i b• Law of complex conjugate :
(a-i b) (c-i d) = (ac-bd) – i(bc+ad)• which is the complex conjugate of
(a+i b) (c+i d) = (ac-bd) + i(bc+ad)
• Claim:
• What can be?
TTTTT xAxxAxxxAxAxAx
AxxT
Eigenvectors of a real symmetric matrix when they correspond to different ’s are
always perpendicular
AyxyAx AA yAyxAx TTTT and and 21
What can the quantity be?
In general, so eigenvalues might be repeated
• Choose an orthogonal basis for each eigenvalue
• Normalize these vector to unit length
Every symmetric matrix has the factorization A = QQT
with real eigenvalues in and orthonormal eigenvectors in :
A =QQ-1 = QQT with Q-1= QT.
Spectral Theorem
Every symmetric matrix has the factorization A = QQT
with real eigenvalues in and orthonormal eigenvectors in :
A =QQ-1 = QQT with Q-1= QT.
Spectral Theorem and Spectral Decomposition
Tnnn
T
Tn
T
n
n xxxxx
xxxA
111
11
1
xi xiT is the projection matrix on to xi !!!!!