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Happenings Yesterday (Monday)
We completed the topic of capacitance Today
We begin to study electric current and the concept of resistance.
Tomorrow (Friday) Continue with electric current QUIZ on the material from this week. WebAssign on C is due
Monday WebAssign on Resistance and current is due
Conductors In the past we decided that in a
conductor The Electric Field is ZERO because we
postulated that no charges were to move. Static Situation Any electric field must be at the surface That field must be normal to the surface
Let’s look at another situation.
Consider a conductor
The mobile electrons can “move” under the influence of an electric field.
We then have a “current” (to be defined) flowing in the wire. But WAIT … how can we????? Only if …
V1 V 2
Electric Field
Walla ….. a CIRCUIT
A Different Situation
Charge will begin to flow through the short. Charge can flow back into the battery and discharge
it. Wire can get warm, emit light or even burn our (fuse). The FLOW of charge is defined as a current.
Vo
circuit
Franklin’s Impact on Physics!!!
Positive charge will leave the battery from the positive terminal and flow through an external circuit to the negative terminal.
Electrons will go the other way.
Current is defined as the flow of POSITIVE CHARGE.
+ charge does not normally flow in a wire.
ELECTRONS
CURRENT
Definition
Current is the total amount of charge that flows through a “wire” in one second.
Current is measured in Coulombs per second.
A current of one coulomb per second is defined as an AMPERE. (Amp.)
CONCISE DEFINITION: CURRENT
2
1
)(t
t
dttiq
idtdqdt
dqi
Current will flow throughout the cross-section of the wire (usually).
Current through aa’ is the same as the current through bb’ and cc’.
What is DIFFERENT between aa’ and bb’ with respect to current?
What’s Different??
CURRENT DENSITY
areaunit
currentj
i=5 amps
A=.1 m2 A=0.05 m2
J=5 amps/.05 m2 = 100 amps/m2J=5 amps / .1 m2 = 50 amps/m2
Question:A 5 Amp current is set up in a circuit for 6 minutes by a 6 Volt Battery. How much chemical energy is provided by the battery?
+
-
Vo
CIRCUIT OF SOME SORTWORK (Energy) per unitCharge = qV
KJVoltscoulqV
coulombscoul
coulamps
1061800
18006030min
sec60min6
sec5min65
Definition
i V
wire
SYMBOL
OHMAmpere
VoltUNIT
i
VR
11Current increases
with PotentialDifference (V)
Ohm’s Law
High Low
Observations Wires and Resistors are made from conducting
materials. These materials have some fundamental
properties associated with them. Electrons are attached to atoms.
Outer electrons weakly bound Small Force (Applied Electric Field) can easily push
them. They bump into things which retard their motion. The more things that retard their motion, the more
difficult it is to push a current via an applied potential difference.
Thus, the resistance goes up.
What kinds of things cause resistance?
Sudden Constrictions in the conductor including bends!
Underlying structure- Amorphous Crystalline
Defects Impurities Thermal Collisions
Temperature
Fundamental Property RESISTANCE vs. RESISTIVITY
Consider a wire made of some material.
Resistance is a property of the rire itself … the material and the shape.
New Quantity: RESISTIVITY is a property of the
material itself regardless of its shape/
Consider our wire:
V
A
L
What would happen to the current if we Increased the voltage? Increased the Area? Increased the length?
Resistivity – Ohm-Meters
Silver 1.62 x 10-8
Copper 1.69
Aluminum 2.65
Tungsten 5.25
Platinum 10.6
Silicon-Pure 2.5 x 103
Glass 1010 to 1014
Fused Quartz ~1016
WIRESAmerican Wire Gauge Diameter - mm
30 gauge 0.255
24 0.511
18 (typical household)
1.024
14 1.628
12 2.05
Question-For an 18 gauge wire of length L to have a resistance of 1 ohm what must L be if the material is copper?
2622
8
2
101
1069.1
4/
0.1
mmmd
dAL
RA
LR
(d for 18 gauge is about 1 mm)
A current of 6.5 Amps exists in a 9 Ohm resistor for 5 minutes. How many coulombs and how many electrons pass through the resistor in this time?
Coulombs: 6.5 COULOMBS per Second for 5 minutes6.5C x 5 min X 60 sec/min = 1950 coulombs
Number of electrons = # coulombs / electron charge =1950 / 1.6 x 10-19 = 1.22 x 10 +22
Micro-View “Resistivity”
m
eEa
m
eEa
d
a
depends on the material and is the mean time between collisions
ease of motion – mobilityresistance to motion - scattering
m
ne
EEEm
nenevJ d
2
2 1
Power
V i
+
-
ELECTRONs
Battery supplies energy to the resistor which, in turn, dissipates it in the form of heat.
Work done on charge Q = Q x V
RiiRiiVVt
Q
t
QVP
PPOWERtimeWork
2
/
REMEMBER: P=iV and P=i2R
When 105 volts are applied across a wire that is 12 meters long and has a 0.30 mm radius, the current density us 1.7 x 10 4 A/m2. What is the resistivity of the wire??
L
A
LR
RA
thatso
From the current density we can find the CURRENT.
i=JA = 1.7 x 104 amp/m2 X ( X 0.32) mm2 X (1m/1000mm)2
I = 4.8 ma
R= V/i = 105 volts / (4.8 x 10-3) amps = 2.18 x 104 ohms
= 2.18 x 104 ohms x 3 x 10-7 m2 / 12m = 0.005 ohm-meters
The figure below gives the electrical potential V(x) along a copper wire carrying a uniform current, from a point at higher potential (x=0m) to a point at a lower potential (x=3m). The wire has a radius of 2.45 mm. What is the current in the wire?
copper
12 volts 0 volts
What does the graph tell us??
*The length of the wire is 3 meters.*The potential difference across the
wire is 12 volts.*The wire is uniform.
Let’s get rid of the mm radius and convert it to area in square meters:A=r2 = 3.14159 x 2.452 x 10-6 m2
orA=1.9 x 10-5 m 2
Material is Copper so resistivity is (from table) = 1.69 x 10-8 ohm meters
We have all we need….
ma 49.41067.2
1012
R
Vi
:Law sOhm' From
67.2 109.1
0.3m-ohm 1069.1
3
6
5
8
ohms
volts
mx
mx
A
LR