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Dr. Zhenhe (Song) Song [email protected] GHD Pty Ltd Civil Engineering Analysis and Modelling (CIVL3140) 1

Lecture 01 Introduction Lecture Handout

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Page 1: Lecture 01 Introduction Lecture Handout

Dr. Zhenhe (Song) [email protected]

GHD Pty Ltd

Civil Engineering Analysis and Modelling (CIVL3140)

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Page 2: Lecture 01 Introduction Lecture Handout

Part 1 Geomechanics (Plaxis) Dr. Zhenhe Song

[email protected]

Part 2 Hydraulics (Fluent) A/Prof. Tongming Zhou (Unit coordinator)

[email protected]

Part 3 Structures (Multiframe) Mr. Philip Christensen [email protected]

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Page 3: Lecture 01 Introduction Lecture Handout

Yusuke Suzuki [email protected]

Wensu Chen [email protected]

Wen Gao [email protected]

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Page 4: Lecture 01 Introduction Lecture Handout

All the students to set up PLAXIS Version 9 software before tutorial.If you get your laptop this year, you may have PLAXIS 2010, you need to reinstall Plaxis V9Please try to run PLAXIS in your laptop and make sure it works well.Please ask help from the IT support if you have any problems to open PLAXIS. IT Support: Keith Russell [email protected]

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Page 5: Lecture 01 Introduction Lecture Handout

2x2hrs sessions per week

First 2hrs: Lecture (Theory)Second 2hrs: Tutorials (Practice)

4 weeks in total

6% Weekly Practice; 14% Assignment

40% Exam (combined)

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Page 6: Lecture 01 Introduction Lecture Handout

This note has incorporated the note from previous teaching by Prof. Yuxia Hu

The development of tutorial questions by Dr. Long Yu

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Finite element analysis in geotechnical engineering: theory, David M. Potts, Lidija ZdravkoviFinite element analysis in geotechnical engineering: application, David M. Potts, Lidija ZdravkoviGuidelines for the use of advanced numerical analysis, David Potts, Kennet Axelsson, Lars Grande, Helmut Schweiger and Michael Long

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Modelling and FEM in Geotechnical Engineering

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StabilityLoading on StructureMovement

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Footing;Retaining Wall and Deep Excavation;Piles and Bridge Abutment;Embankment, Dams and Seawalls;Tunnel;Stockpile;Dynamic (Seismic Analysis)

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Soils are neither elastic, nor homogeneous.

Soils around the world vary.

Same soil with different saturations and consolidations behaves differently.

Soil properties are difficult to measure.

In situ vs laboratory testing …

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13New civil engineer: 14/04/2005

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Geotechnical engineering is complex. It is not because you’re using the FEM that it becomes simpler;The quality of a tool is important, yet the quality of a result (mainly) depends on the user’s understanding of both the problem and the tool;The design process involves considerably more than analysis.

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Page 15: Lecture 01 Introduction Lecture Handout

Traditional methods of analysis often use techniques that based on assumptions that over simplify the problem at hand.

These methods lack the ability to account for all of the factors and variables the design engineer faces and may severely limit the accuracy of the solution.

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Equilibrium (stress)

Compatibility (strain)

Constitutive Relationship (stress-strain)

Boundary Condition

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Solution of GeotechnicalProblems

Numerical“Exact” or Closed Form

Empirical, Based on Experience

LimitAnalysis

DiscreteElement

FiniteElement

FiniteDifference

BoundaryElement

Finite/BoundaryElement

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LimitEquilibrium

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Method of Analysis Solution Requirements Design Information

Stress Equilibrium

Compatibility Constitutive behaviour

Stability Displacements

Limit equilibrium (P) XRigid plastic

X

Slip-line method (P) XRigid plastic

X

Limit Analysis-Lower Bound-Upper Bound X

XPerfectly plastic

XX

Displacement finite element Any

P– partially satisfied

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Receive Design Prescriptions(from a client)

Obtain Soil Properties(Site investigations and lab testing)

Model Geotechnical Problem

Detailed Design Report

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Verification

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http://www.cofs.uwa.edu.au/Researh/centrifugeprojects.html

http://www.pbase.com/image/41209293

Geotechnical modelNumerical modelling

Physical modellingSilo

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Plain strain or axisymmetric

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Footing (B/2)

CL

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Discretisation (mesh):Divide the model field (soil and/or structure) into parts (nodes and elements)

Displacement Approximation: Over each part (element), displacement is expressed as function of nodal values

Element Equation: Use an approximate variational principle (e.g. minimum potential energy) to derive an element equation KUE=PE

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Global Equation: Then assemble the parts of element equation to form a global equation KU=P

Boundary Condition: Formulate boundary conditions and modify global equations. Loads affect P, displacement affect U

Solutions: Solve displacement values at nodes and then stress and strain can be evaluated

Page 24: Lecture 01 Introduction Lecture Handout

Footing (B/2)

Elementx

xx

Node

Gauss point (integration point)x

CL

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Element Type Degree of Freedom

per Element

Plane Strain Axisymmetric

Integration rule

Gauss point

Constraints per

Element

Ratio Degrees of Freedom Constraints

Suitable Integration rule

Gauss point

Constraints per

Element

Ratio of Degrees of Freedom Constraints

Suitable

3-noded constant Strain

triangle

1 1-point 1 1 Y 3-point 3 1/3 N

6-noded linearStrain

triangle

4 3-point 3 4/3 Y 6-point 6 2/3 N

10-noded quadraticStrain

triangle

9 6-point 6 3/2 Y 12-point 10 9/10 N

15-noded cubicStrain

triangle

16 12-point 10 8/5 Y 16-point 15 16/15 Y

4-nodedquadrilateral

2 2x2 3 2/3 N 3x3 5 2/5 N

8-noded quadrilateral

6 3x3 6 1 Y 3x3 9 2/3 N

12-nodedquadrilateral

10 4x4 10 1 Y 4x4 13 10/13 N

17-nodedquadrilateral

16 5x5 14 8/7 Y 5x5 19 16/19 N

Sloan, S. W. and Randolph, M. F. (1982) “Numerical prediction of collapse loads using finite element analysis”, Int. J. Num. Ana. Meth. Geo.

Page 26: Lecture 01 Introduction Lecture Handout

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xy

u

v

1 2

3Function:u(x,y) = a1 + a2x + a3yv(x,y) = b1 + b2x + b3y

(x1, y1)u1, v1

(x3, y3)u3, v3

(x2, y2)u2, v2

u1 = u(x1, y1) = a1 + a2x1 + a3y1

u2 = u(x2, y2) = a1 + a2x2 + a3y2

u3 = u(x3, y3) = a1 + a2x3 + a3y3

3

2

1

33

22

11

3

2

1

111

aaa

yxyxyx

uuu

u = ?

Solve for a1, a2, a3

Page 27: Lecture 01 Introduction Lecture Handout

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2A)xy(x)yx(y)yxy(x

2A)xy(x)yx(y)yxy(x

2A)xy(x)yx(y)yxy(x

NNN

N

12211221

31133113

23322332

3

2

1

3

3

2

2

1

1

321

321

N0N0N00N0N0N

vu

U

vuvuvu

Function of (x,y)

Function of (x,y)

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6

6

5

5

4

4

3

3

2

2

1

1

654321

654321

N 0 N 0 N 0 N0N0N00 N 0 N 0 N 0N0N0N

vu

U

vuvuvuvuvuvu

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xy

u

v

1 2

3

(x1, y1)u1, v1

(x3, y3)u3, v3

(x2, y2)u2, v2

u = ?

6 5

4

(x6, y6)u6, v6

(x5, y5)u5, v5

(x4, y4)u4, v4

Function:u(x,y) = a1 + a2x + a3y + a4x2 + a5xy + a6y2

v(x,y) = b1 + b2x + b3y + b4x2 + b5xy + b6y2

6

5

4

3

2

1

2666

2666

2555

2555

2444

2444

2333

2333

2222

2222

2111

2111

6

5

4

3

2

1

111111

aaaaaa

yyxxyxyyxxyxyyxxyxyyxxyxyyxxyxyyxxyx

uuuuuu

Page 29: Lecture 01 Introduction Lecture Handout

Strain within an element:Displacement:u(x,y) = a1 + a2x + a3y + a4x2 + a5xy + a6y2

v(x,y) = b1 + b2x + b3y + b4x2 + b5xy + b6y2

Strain:

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u

v

1 2

3

6 5

4yaxaa

xu

542xx 2

ybxbyv

653yy 2b

ybaxbaabxy

yu )2()2()( 564532xy

eUBe

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Constitutive RelationStress and strain can be written in vector form and then expressed as

DLinear isotropic elasticity

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1 2

3

6 5

4P1x

P1Y

Body forces and surface tractions applied to the element may be generalized into a set of forces acting at the nodes

Based on an appropriate variationalprinciple (e.g. minimum potential energy) to derive element equations:

ee PUeKwhere

vDBdBK TeIn order to get [Ke], integration (gaussianintegration) must be performed for each element. Basically, the integral of the function is replaced by weighted sum of the function at a number of integration points

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The stiffness for the complete mesh is evaluated by combining the individual element stiffness matrixes assembly)

This produces a square matrix K of dimension equal to the number of degree-of-freedom in the mesh

The global vector of nodal forces P is obtained in a similar way by assembling the element nodal force vectors

The assembled stiffness matrix and force vector are related by:

PUK

Page 33: Lecture 01 Introduction Lecture Handout

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144

134

133

124

123

122

114

113

112

111

133

143

144

124

123

122

114

113

112

111

KKKKKKKKKK

KKKKKKKKKK

266

256

255

246

245

244

144

236

235

234

134

233

133

124

123

122

114

113

112

111

255

265

266

245

246

244

235

236

234

233

KKKKKKKKKKKKK

KKKKKKK

KKKKKKKKKK

Page 34: Lecture 01 Introduction Lecture Handout

Find symmetrical features, central line can be a roller boundary. (CL) (1)Soil domain needs to be large enough to avoid boundary effect. (10x(B/2), 10x(B/2))The bottom boundary can be fixed boundary. (2)The side boundary can be roller boundary. (3)Top boundary is normally a free boundary. (4)

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CL

Footing (B/2)

10x(B/2)

10x(B/2)1

2

3

4

Page 35: Lecture 01 Introduction Lecture Handout

Element size: the smaller, the more accurate

Element type: the higher order, the more accurate

Boundary conditions: domain size, realistic

Constitutive model: complexity economy

Soil parameters: realistic, measurable

Understanding of the real problem numerical

model

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Less elements to reduce computation timeSmaller elements to increase accuracy

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Optimum MeshCombination of coarse and fine mesh

How ?

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Footing (B/2)

Page 38: Lecture 01 Introduction Lecture Handout

Displacement control (prescribed displacement) or

load control (prescribed load) ?

2-dimensional or 3-dimensional analysis ?

Plain strain or axisymmetric ?

Drained, undrained or consolidation analysis?

Construction Stages

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Page 39: Lecture 01 Introduction Lecture Handout

Pre-processingDefine problem(2D or 3D? Plain strain or Axisymmetric? Soil model? Drained or undrained?); define domain (size?); define boundary condition; generate mesh (element type? mesh density?); input soil/foundation parameters (worked out soil parameter from site investigation).

2) CalculationFEM Calculation Steps

3) Post-processingProcess calculation results, such as soil stress/strain distribution; soil deformations, et al.

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