Lect_4CBB 30902- Mass Balance

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    The accounting of all mass in a

    chemical/pharmaceutical process is referred to

    as a mass (or material) balance.

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    • ‘day to day’ operation of process for

    monitoring operating efficiency

    • Making calculations for design anddevelopment of a process i.e. quantities

    required, sizing equipment, number of items

    of equipment

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    200 kg of a 40% w/w methanol/water solution ismixed with 100 kg of a 70% w/w

    methanol/water solution in a batch mixer unit.

    What is the final quantity and composition?

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    MIXER200 kg

    40% CH3OH/H2O

    100 kg

    70% CH3

    OH/H2

    O

    OUTPUT?

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    MIXER200 kg

    40% CH3OH/H2O

    100 kg

    70% CH3OH/H2O

    Total Mass in = Total Mass Out200 kg + 100 kg = 300 kg CH3OH/H2O

    300 kg

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    MIXER200 kg

    40% CH3OH/H2O

    100 kg

    70% CH3OH/H2O

    CH3OH Mass in = CH3OH Mass Out(40/100) x 200 kg + (70/100) x 100 kg = 150 kg

    300 kg

    150 kg CH3OH

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    MIXER200 kg

    40% CH3OH/H2O

    100 kg

    70% CH3OH/H2O

    Final composition of CH3OH= (150 kg / 300 kg) x 100

    = 50% CH3OH/H2O (w/w)

    300 kg

    50% CH3OH/H2O

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    Batch processes operate to a batch cycle and are

    non-steady state. Materials are added to a vessel

    in one operation and then process is carried out

    and batch cycle repeated. Integral balances arecarried out on batch processes where balances

    are carried out on the initial and final states of

    the system.

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    These processes are continuous in nature and

    operate in steady state and balances are carried

    out over a fixed period of time. Materials enter

    and leave process continuously.

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    When there is no net accumulation or depletion

    of mass in a system (steady state) then:

    Total massentering

    system

    Total massleaving

    system

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    Notes:

    Generation and consumption terms refer only togeneration of products and consumption of

    reactants as a result of chemical reaction.

    In Gen Out Con Acc

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    • Streams

    • Operations/equipment sequence

    • Standard symbols

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    Fresh feed

    - Reactants

    - Solvents

    - Reagents

    - Catalysts

    Product

    Recycle of unreacted material

    By-products/co-productsWaste

    Separation &purificationReactor

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    It is often useful to calculate a mass balance

    using molar quantities of materials and to

    express composition as mole fractions or mole %.

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    • A mole is the molecular weight of a substanceexpressed in grams

    • To get the molecular weight of a substance you need itsmolecular formula and you can then add up the atomic

    weights of all the atoms in the molecule• To convert from moles of a substance to grams multiply

    by the molecular weight

    • To convert from grams to moles divide by the molecularweight.

    • Mole fraction is moles divided by total moles

    • Mole % is mole fraction multiplied by 100

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    Example

    Benzene is C6H6. The molecular weight is:

    (6x12) + (6x1) = 78

    So 1 mole of benzene is 78 grams.

    1 kmol is 78 kg.

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    A crystalliser contains 1000 kg of a saturated

    solution of potassium chloride at 80 deg cent. It

    is required to crystallise 100 kg KCl from this

    solution. To what temperature must the solutionbe cooled?

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    T deg cent Solubility g KCl/100 g

    water

    80 51.1

    70 48.3

    60 45.5

    50 42.6

    40 40

    30 37

    20 34

    10 31

    0 27.6

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    At 80 deg cent, saturated solution contains:(51.1/151.1) x 100 KCl i.e. 33.8% by wt.

    So in 1,000 kg there is 338 kg KCl & 662 kgwater.

    Crystallising 100 kg out of solution leaves a

    saturated solution containing 238 kg KCl and662kg water i.e. 238/662 g KCl/100g water

    which is 36 g KCl/100g. So temperature required

    is approx 27 deg cent from table.

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    feed suspension

    wash water/solvent

    solid

    waste water filtrate

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    F1

    5000 kg water

    Impurity 55 kg

    Water 2600 kg

    API 450 kgWater 7300 kg

    Impurity 50 kg

    API 2kg

    Water 300 kg

    API 448 kg

    Impurity 5 kg

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     A + B

    S

     A + B

    S + B

    A – feed solvent; B – solute; S – extracting solvent

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    E1

    feed

    solvent

    raffinate

    extract

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    feed gas stream

    feed solvent

    waste solvent stream

    exit gas stream

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    • Overall balance

    • Unit balances

    • Component balances

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    E – evaporator; C – crystalliser; F – filter unit

    F1 – fresh feed; W2 – evaporated water; P3 – solid product;

    R4 – recycle of saturated solution from filter unit

    R4

    E C FF1

    W2

    P3

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    • Process description

    • Flowsheet

    • Label

    • Assign algebraic symbols to unknowns(compositions, concentrations, quantities)

    • Select basis

    • Write mass balance equations (overall, total,

    component, unit)• Solve equations for unknowns

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    • Stoichiometric quantities

    • Limiting reactant

    • Excess reactant

    • Conversion

    • Yield

    • Selectivity

    • Extent of reaction

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    Refers to quantities of reactants and products

    in a balanced chemical reaction.

    aA + bB cC + dD

    i.e. a moles of A react with b moles of B to give

    c moles of C and d moles of D. a,b,c,d are

    stoichiometric quantities

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    • In practice a reactant may be used in excess

    of the stoichiometric quantity for various

    reasons. In this case the other reactant is

    limiting i.e. it will limit the yield of product(s)

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    A reactant is in excess if it is present in a

    quantity greater than its stoichiometric

    proportion.

    % excess = [(moles supplied – stoichiometric

    moles)/stoichiometric moles] x 100

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    • Fractional conversion = amount reactant

    consumed/amount reactant supplied

    • % conversion = fractional conversion x 100

    Note: conversion may apply to single pass

    reactor conversion or overall process

    conversion

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    Yield = (moles product/moles limiting reactant

    supplied) x s.f. x 100

    Where s.f. is the stoichiometric factor =stoichiometric moles reactant required per

    mole product

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    Selectivity = (moles product/moles reactant

    converted) x s.f. x100

    OR

    Selectivity = moles desired product/moles

    byproduct

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    Extent of reaction = (moles of componentleaving reactor – moles of component enteringreactor)/stoichiometric coefficient ofcomponent

    Note: the stoichiometric coefficient of acomponent in a chemical reaction is the no. ofmoles in the balanced chemical equation (-vefor reactants and +ve for products)

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    A Bi.e. stoichiometric coefficients a = 1; b = 1

    100 kmol fresh feed A; 90 % single pass conversion in

    reactor; unreacted A is separated and recycled and

    therefore overall process conversion is 100%

    reactor separationF

    R

    P

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