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8/19/2019 Lect_4CBB 30902- Mass Balance
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The accounting of all mass in a
chemical/pharmaceutical process is referred to
as a mass (or material) balance.
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• ‘day to day’ operation of process for
monitoring operating efficiency
• Making calculations for design anddevelopment of a process i.e. quantities
required, sizing equipment, number of items
of equipment
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200 kg of a 40% w/w methanol/water solution ismixed with 100 kg of a 70% w/w
methanol/water solution in a batch mixer unit.
What is the final quantity and composition?
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MIXER200 kg
40% CH3OH/H2O
100 kg
70% CH3
OH/H2
O
OUTPUT?
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MIXER200 kg
40% CH3OH/H2O
100 kg
70% CH3OH/H2O
Total Mass in = Total Mass Out200 kg + 100 kg = 300 kg CH3OH/H2O
300 kg
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MIXER200 kg
40% CH3OH/H2O
100 kg
70% CH3OH/H2O
CH3OH Mass in = CH3OH Mass Out(40/100) x 200 kg + (70/100) x 100 kg = 150 kg
300 kg
150 kg CH3OH
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MIXER200 kg
40% CH3OH/H2O
100 kg
70% CH3OH/H2O
Final composition of CH3OH= (150 kg / 300 kg) x 100
= 50% CH3OH/H2O (w/w)
300 kg
50% CH3OH/H2O
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Batch processes operate to a batch cycle and are
non-steady state. Materials are added to a vessel
in one operation and then process is carried out
and batch cycle repeated. Integral balances arecarried out on batch processes where balances
are carried out on the initial and final states of
the system.
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These processes are continuous in nature and
operate in steady state and balances are carried
out over a fixed period of time. Materials enter
and leave process continuously.
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When there is no net accumulation or depletion
of mass in a system (steady state) then:
Total massentering
system
Total massleaving
system
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Notes:
Generation and consumption terms refer only togeneration of products and consumption of
reactants as a result of chemical reaction.
In Gen Out Con Acc
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• Streams
• Operations/equipment sequence
• Standard symbols
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Fresh feed
- Reactants
- Solvents
- Reagents
- Catalysts
Product
Recycle of unreacted material
By-products/co-productsWaste
Separation &purificationReactor
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It is often useful to calculate a mass balance
using molar quantities of materials and to
express composition as mole fractions or mole %.
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• A mole is the molecular weight of a substanceexpressed in grams
• To get the molecular weight of a substance you need itsmolecular formula and you can then add up the atomic
weights of all the atoms in the molecule• To convert from moles of a substance to grams multiply
by the molecular weight
• To convert from grams to moles divide by the molecularweight.
• Mole fraction is moles divided by total moles
• Mole % is mole fraction multiplied by 100
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Example
Benzene is C6H6. The molecular weight is:
(6x12) + (6x1) = 78
So 1 mole of benzene is 78 grams.
1 kmol is 78 kg.
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A crystalliser contains 1000 kg of a saturated
solution of potassium chloride at 80 deg cent. It
is required to crystallise 100 kg KCl from this
solution. To what temperature must the solutionbe cooled?
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T deg cent Solubility g KCl/100 g
water
80 51.1
70 48.3
60 45.5
50 42.6
40 40
30 37
20 34
10 31
0 27.6
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At 80 deg cent, saturated solution contains:(51.1/151.1) x 100 KCl i.e. 33.8% by wt.
So in 1,000 kg there is 338 kg KCl & 662 kgwater.
Crystallising 100 kg out of solution leaves a
saturated solution containing 238 kg KCl and662kg water i.e. 238/662 g KCl/100g water
which is 36 g KCl/100g. So temperature required
is approx 27 deg cent from table.
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feed suspension
wash water/solvent
solid
waste water filtrate
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F1
5000 kg water
Impurity 55 kg
Water 2600 kg
API 450 kgWater 7300 kg
Impurity 50 kg
API 2kg
Water 300 kg
API 448 kg
Impurity 5 kg
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A + B
S
A + B
S + B
A – feed solvent; B – solute; S – extracting solvent
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E1
feed
solvent
raffinate
extract
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feed gas stream
feed solvent
waste solvent stream
exit gas stream
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• Overall balance
• Unit balances
• Component balances
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E – evaporator; C – crystalliser; F – filter unit
F1 – fresh feed; W2 – evaporated water; P3 – solid product;
R4 – recycle of saturated solution from filter unit
R4
E C FF1
W2
P3
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• Process description
• Flowsheet
• Label
• Assign algebraic symbols to unknowns(compositions, concentrations, quantities)
• Select basis
• Write mass balance equations (overall, total,
component, unit)• Solve equations for unknowns
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• Stoichiometric quantities
• Limiting reactant
• Excess reactant
• Conversion
• Yield
• Selectivity
• Extent of reaction
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Refers to quantities of reactants and products
in a balanced chemical reaction.
aA + bB cC + dD
i.e. a moles of A react with b moles of B to give
c moles of C and d moles of D. a,b,c,d are
stoichiometric quantities
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• In practice a reactant may be used in excess
of the stoichiometric quantity for various
reasons. In this case the other reactant is
limiting i.e. it will limit the yield of product(s)
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A reactant is in excess if it is present in a
quantity greater than its stoichiometric
proportion.
% excess = [(moles supplied – stoichiometric
moles)/stoichiometric moles] x 100
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• Fractional conversion = amount reactant
consumed/amount reactant supplied
• % conversion = fractional conversion x 100
Note: conversion may apply to single pass
reactor conversion or overall process
conversion
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Yield = (moles product/moles limiting reactant
supplied) x s.f. x 100
Where s.f. is the stoichiometric factor =stoichiometric moles reactant required per
mole product
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Selectivity = (moles product/moles reactant
converted) x s.f. x100
OR
Selectivity = moles desired product/moles
byproduct
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Extent of reaction = (moles of componentleaving reactor – moles of component enteringreactor)/stoichiometric coefficient ofcomponent
Note: the stoichiometric coefficient of acomponent in a chemical reaction is the no. ofmoles in the balanced chemical equation (-vefor reactants and +ve for products)
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A Bi.e. stoichiometric coefficients a = 1; b = 1
100 kmol fresh feed A; 90 % single pass conversion in
reactor; unreacted A is separated and recycled and
therefore overall process conversion is 100%
reactor separationF
R
P
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