LEADER TEST SERIES / JOINT PACKAGE COURSE · PDF file-4/35 LATS 0999DM610216003 Target : Pre-Medical 2017/AIIMS-MAJOR/09-04-2017 14. 10 m

LEADER TEST SERIES / JOINT PACKAGE COURSETARGET : PRE-MEDICAL 2017

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DISTANCE LEARNING PROGRAMME(Academic Session : 2016 - 2017)

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5. Each correct answer carries 1 marks, while one third mark will be deducted from the total of individual subject for each

incorrect answer.

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Paper Code : 0999DM610216003

Test Type : MAJOR Test Pattern : AIIMS

TEST DATE : 09 - 04 - 2017

TEST SYLLABUS : FULL SYLLABUS

LATS-1/350999DM610216003

Leader Test Series/Joint Package Course/09-04-2017

1. 8 = ____ :-(1) 16 (2) 1 (3) 4 (4) 64

2. ˆ ˆ ˆA 2i j k

ˆ ˆ ˆB i j k

:-

(1) A

ˆ ˆj k

2

(2) A

ˆ ˆj k

2

(3) B

ˆ ˆk j

2

(4) B

ˆ ˆk j

2

3. +x :-

(1) 2ˆ10i m / s (2) 2ˆ10 j m / s

(3) 2ˆ ˆ10i 5j m /s (4) 2ˆ ˆ2i 8j m / s

4. m (cabin) a :-

(1) gsin– a (2) gsin + a

(3) (g – a)sin (4) (g + a)sin

5. W F h :-

(1)2 2F h

W Fh

(2)

2 2h

W Fh

(3) 2 2

W Fh

F h

(4) 2 2

W Fh

h

BEWARE OF NEGATIVE MARKING

HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE 100% SUCCESS

1. In a particular system of unit, if the unit of mass

becomes twice and that of time becomes half, then

8 joules will be written as _____ units of work :-

(1) 16 (2) 1 (3) 4 (4) 64

2. If ˆ ˆ ˆA 2i j k

and ˆ ˆ ˆB i j k

are two

vectors then the unit vector:-

(1) Perpendicular to A

is ˆ ˆj k

2

(2) Parallel to A

is ˆ ˆj k

2

(3) Perpendicular to B

is ˆ ˆk j

2

(4) Parallel to B

is ˆ ˆk j

2

3. An object is moving initial ly in the +x

direction. Which of the following acceleration,

all acting for the same time interval, will cause

the greatest change in its direction :-

(1) 2ˆ10i m / s (2) 2ˆ10 j m / s

(3) 2ˆ ˆ10i 5j m /s (4) 2ˆ ˆ2i 8j m / s

4. A block of mass m is placed on a smooth inclined

plane of inclination . The inclined plane itself is

placed in a cabin, which is accelerating upwards

at the rate a in a direction making angle with the

horizontal. What will be the acceleration of the

block down the inclined plane :-

(1) gsin– a (2) gsin + a

(3) (g – a)sin (4) (g + a)sin

5. A log of weight W is pulled at a constant velocity

and with a force F by means of a rope of length .

The distance between the free end of the rope and

ground is h. Neglecting the thickness of the log, the

coefficient of friction between log and ground is :-

(1)2 2F h

W Fh

(2)

2 2h

W Fh

(3) 2 2

W Fh

F h

(4) 2 2

W Fh

h

0999DM610216003LATS-2/35

Target : Pre-Medical 2017/AIIMS-MAJOR/09-04-2017

6. R 45o v0 :-

(1)2

0

Re

v

(2) 2

0

R1 e

v

(3) 0

Rv (4)

0

2Rv

7. 5m 1 kg 2 kg

8 (g = 10 m/s2) :-

(1) 550 J (2) 525 J

(3) 125 J (4) 500 J

8. e1 e

2

3 : 1 :-(1) 1 : 2

(2) 2 : 3

(3) 3 : 2

(4) 6 : 1

9. m, 2m, 3m, ........ nm , 2, 3, ....n :-

(1)(2n 1)

3

(2)

n 1

(3) 2n(n 1)

2

(4) 2

2

n(n 1)

10.

P:-

(1) 3

kp

x

P

p

x

xx

p

p

(2) 3

4kp

x

(3)

(4) 3

2kp

x

6. A particle is moving in circle of radius R in such

a way that at any instant the total acceleration

makes an angle of 45o with radius. Initial speed

of particle is v0. The time taken to complete the

first revolution is :-

(1)2

0

Re

v

(2) 2

0

R1 e

v

(3) 0

Rv (4)

0

2Rv

7. A person draws water from a 5m deep well in

a bucket of mass 2 kg of capacity 8 litre by a

rope of mass 1 kg. What is the total work done

by the person (g = 10 m/s2) :-

(1) 550 J (2) 525 J (3) 125 J (4) 500 J

8. In two separate collisions, the coefficient of

restitutions e1 and e

2 are in the ratio 3 : 1. In

the first collision the relative velocity of

approach is twice the relative velocity of

separation. Then the ratio between the relative

velocity of approach and relative velocity of

separation in the second collision is :-

(1) 1 : 2 (2) 2 : 3

(3) 3 : 2 (4) 6 : 1

9. Particles of masses m, 2m, 3m, ........ nm are

placed on the same line at distances , 2, 3,

....n from a fixed point. The distance of centre

of mass of the particles from the fixed point is

:-

(1)(2n 1)

3

(2)

n 1

(3) 2n(n 1)

2

(4) 2

2

n(n 1)

10. Three identical dipoles are arranged as shown

below. What will be the net electric field at P:-

(1) 3

kp

x

P

p

x

xx

p

p

(2) 3

4kp

x

(3) Zero

(4) 3

2kp

x

LATS-3/350999DM610216003


11.

(i)

Y5q

2q -3qXO

(ii)

Y–3q

2q –qXO

(iii)

Y

4q –2qXO (iv)

Y

3q –qXO

(1) (i) > (ii) > (iii) > (iv)

(2) (ii) > (i) > (iii) = (iv)

(3) (i) > (iii) = (iv) > (ii)

(4) (iv) > (iii) > (ii) > (i)

12.

++

++

++

++

++

a

+++++++++

a

(1) 1

2(2)

2

3(3)

3

2 (4)

1

1

13. 5F 4F

:- (@ t )

(1) 0.6 (2) 0.7 (3) 0.8 (4) 0.9

11. In the following four situations charged

particles are at equal distance from the origin.

Arrange them in the order of magnitude of the

net electric potential at origin greatest first

(i)

Y5q

2q -3qXO

(ii)

Y–3q

2q –qXO

(iii)

Y

4q –2qXO (iv)

Y

3q –qXO

(1) (i) > (ii) > (iii) > (iv)

(2) (ii) > (i) > (iii) = (iv)

(3) (i) > (iii) = (iv) > (ii)

(4) (iv) > (iii) > (ii) > (i)

12. A linear charge having linear charge density

, penetrates a cube diagonally so as to have

maximum flux and then it penetrate a sphere

diametrically as shown. What will be the ratio

of flux coming out of cube and sphere ?

++

++

++

++

++

a

+++++++++

a

(1) 1

2(2)

2

3(3)

3

2 (4)

1

1

13. Find the ratio of energy stored in 5F and 4F

capacitor in the given circuit in steady state :-

(1) 0.6 (2) 0.7 (3) 0.8 (4) 0.9

0999DM610216003LATS-4/35


14. 10 m

4 /m e.m.f. 2 V

0.1 V/m

(1) 80 (2) 120 (3) 40 (4) 4

15. R A B

A

5

43

2

1

B

(1) 11R

12(2)

13R

12

(3) R

5(4)

15R

12

16. 60° 0.8 J 30° (1) 4 J (2) 0.4 J (3) 8 J (4) 0.8 J

17. B B

0

(1) OQ OR (2) OQ OR (3) OQ OR (4) OQ OR

18.

(1)

(2)

(3)

(4)

14. A potentiometer wire has a length of 10 m and

resistance 4 /m. An accumulator of e.m.f. 2 V

and a resistance box are connected in series with

it. Calculate the resistance to be introduced in the

box so as to get a potenitial gradient of 0.1 V/m.

(1) 80 (2) 120 (3) 40 (4) 4

15. The circuit shown has resistors of equal

resistance R. Find the equivalent resistance

between A and B, when the key is closed :

A

5

43

2

1

B

(1) 11R

12(2)

13R

12

(3)R

5(4)

15R

12

16. A magnet is parallel to a uniform magnetic field.

If it is rotated by 60°, the work done is 0.8 J.

How much work is done in moving it 30° further

(1) 4 J (2) 0.4 J (3) 8 J (4) 0.8 J

17. The figure illustrate how B, the flux density

inside a sample of unmagnetised ferromagnetic

material varies with B0, the magnetic flux

density in which the sample is kept. For the

sample to be suitable for making a permanent

magnet

(1) OQ should be large, OR should be small

(2) OQ and OR should both be large

(3) OQ should be small and OR should be large

(4) OQ and OR should both be small

18. Curie temperature is the temperature above

which

(1) A paramagnetic material becomes ferromagnetic

(2) A ferromagnetic material becomes paramagnetic

(3) A paramagnetic material becomes diamagnetic

(4) A ferromagnetic material becomes diamagnetic

LATS-5/350999DM610216003


19. 10H

(1) 3.5 sec

(2) 2.5 sec

(3) 5.5 sec

(4) 7.5 sec

20.

(1) /4

(2) /2

(3)

(4) 2

21. (0, 2, 0)(3m, 0, 0) x-20N :-

(1) 20

(2) 60

(3) 40

(4) 30

22. m

:

OXX'

Y

Y'

(1) m2

(2) Zero

(3) 2

2

m

(4) 2

2

m

2

19. A solenoid of 10 henry inductance and 2 ohm

resistance, is connected to a 10 volt battery. In

how much time the magnetic energy will be

reaches to 1/4 th of the maximum value?

(1) 3.5 sec

(2) 2.5 sec

(3) 5.5 sec

(4) 7.5 sec

20. An alternating emf of angular frequency is

applied across an inductance. The

instantaneous power developed in the circuit

has an angular frequency :

(1) /4

(2) /2

(3)

(4) 2

21. Moment of a force of magnitude 20 N acting

along positive x direction at point (3m, 0, 0)

about the point (0, 2, 0) (in N-m) is :-

(1) 20

(2) 60

(3) 40

(4) 30

22. A thin wire of length and mass m is bent in

the form a semicircle as shown. Its moment of

inertia about an axis joining its free ends will

be :

OXX'

Y

Y'

(1) m2

(2) Zero

(3) 2

2

m

(4) 2

2

m

2

Key Filling

0999DM610216003LATS-6/35


23. Re)

(1) e

16R

15(2) eR

15

(3) e

4R

15(4)

24. 8000 6.0

(1) 6 (2) 4.8 × 107

(3) 8 × 105 (4) 4.8 × 102

25. 120g 80g

60g

:

(1) 3, 2 (2) 3, 3/2 (3) 3/2, 2 (4) 4, 3

26. 'PT2 ='

:-

(1) 1

T(2)

2

T(3)

3

T(4)

4

T

27. 0°C 10 gm 50°C 100g

:-

(1) 31.2°C (2) 32.8°C

(3) 36.7°C (4) 38.2°C

28.

V 3V :-(1) R/(–1) (2) pV

(3) 2pV/(–1) (4) pV/(–1)

29. A

60° 60°

(1) 2A (2) 3A

2

(3) A (4) 5A

2

23. A particle is projected vertically upwards the

surface of the earth (radius Re) with a speed equal

to one fourth of escape velocity. What is the

maximum height attained by it from the surface

of the earth ?

(1) e

16R

15(2)

eR

15

(3) e

4R

15(4) None

24. The intensity of gravitational field at a point

situated at a distance 8000 km from the centre

of Earth is 6.0 newton /kg. The gravitational

potential at that point in newton – meter/kg will be

(1) 6 (2) 4.8 × 107

(3) 8 × 105 (4) 4.8 × 102

25. A piece of solid weighs 120g in open air, 80g

in water and 60g in a liquid. The relative density

of the solid and that of the liquid are respectively:

(1) 3, 2 (2) 3, 3/2 (3) 3/2, 2 (4) 4, 3

26. An ideal gas is expanding such that

PT2 =constant. The coefficient of volume

expansion of the gas is:-

(1) 1

T(2)

2

T(3)

3

T(4)

4

T

27. 10 g of ice at 0°C is mixed with 100g of water

at 50°C. What is the resultant temperature of

mixture:-

(1) 31.2°C (2) 32.8°C

(3) 36.7°C (4) 38.2°C

28. If the ratio of specific heat of a gas at constant

pressure to that at constant volume is , the

change in internal energy of a mass of gas,

when the volume changes from V to 3V

constant pressure p, is:-

(1) R/(–1) (2) pV

(3) 2pV/(–1) (4) pV/(–1)

29. Three simple Harmonic motions of equalamplitudes A and equal time periods in thesame direction combine. The phase of thesecond motion is 60° ahead of the first and thephase of the third motion is 60° ahead of thesecond. The amplitude of the resultant motion

is:-

(1) 2A (2) 3A

2(3) A (4)

5A

2

LATS-7/350999DM610216003


30.

(1) 2A

2

(2)

2A

2

(3) 22A

(4)

31. y = 10 sin(ax + bt) 64%

(1) y = –8 sin(ax – bt) (2) y = –6.4 sin(ax – bt)

(3) y = –6.4 sin(bt – ax) (4) y = 8 sin(ax – bt)

32. u v f 1/v 1/u :-

(1) (2)

(3) (4)

33. ABC BCDE AB BC ( sin–1(3/5) = 37°):-

(1) 37° (2) > 37°

(3) 53° (4) < 53°

30. The magnitude of average acceleration in half

time period from equilibrium position in a

simple harmonic motion is

(1) 2A

2

(2)

2A

2

(3) 22A

(4) zero

31. A wave y = 10 sin(ax + bt) is reflected from

a dense medium at an origin. If 64% of energy

is reflected then the equation of reflected wave is

(1) y = –8 sin(ax – bt) (2) y = –6.4 sin(ax – bt)

(3) y = –6.4 sin(bt – ax) (4) y = 8 sin(ax – bt)

32. An object is placed at a distance u from a

concave mirror and its real image is received

on a screen placed at a distance of v from the

mirror. If f is the focal length of the mirror,

then the graph between 1/v versus 1/u is:-

(1) (2)

(3) (4)

33. In the figure ABC is the cross section of a right

angled prism and BCDE is the cross section of

a glass slab. The value of so that light incident

normally on the face AB does not cross the face

BC is (given sin–1(3/5) = 37°):-

(1) 37° (2) > 37°

(3) 53° (4) < 53°

0999DM610216003LATS-8/35


34. In a Young's Double slit experiment, first

maxima is observed at a fixed point P on the

screen. Now the screen is continuously moved

away from the plane of slits. The ratio of

intensity at point P to the intensity at point O

(centre of the screen)

(1) remains constant

(2) keeps on decreasing

(3) first decreases and then increases

(4) First decreases and then becomes constant

35. In the adjacent diagram, CP represents a

wavefront and AO and BP, the corresponding

two rays. Find the condition on for

constructive interference at P between the ray

BP and reflected ray OP.

(1) cos = 3

2d

(2) cos = 4d

(3) sec – cos = d

(4) sec – cos = 4

d

34. P

P

O

(1)

(2)

(3)

(4)

35. CP AO BP

BP

OP P

(1) cos = 3

2d

(2) cos = 4d

(3) sec – cos = d

(4) sec – cos = 4

d

Use stop, look and go method in reading the question

LATS-9/350999DM610216003


36. The isotopic mass of 73Li is 7.016005 u and

those of H-atom and neutron are respectively,

1.007825 u and 1.008665 u. Then, the

binding energy of the Li-nucleus is -

(1) 5.6 MeV (2) 39.2 Mev

(3) 0.042 MeV (4) 8.8 Mev

37. Which of the following statements is false-

(1) The energy spectrum of -decay is line spectrum.

(2) The energy spectrum of -particles is

continuous.

(3) The energy spectrum of -decay is

continuous.

(4) The energy spectra of & -decay are line

spectra.

38. Photon of energy 2.5ev falls on a surface of

metal having photoelectrons of maximum

kinetic energy 2ev then the stopping voltage

required for this electron is :-

(1) 4.5v (2) 2.5v

(3) 2v (4) 0.5v

39. Half life of a radioactive substance A is two

times the half life of another radioactive

substance B initially, the number of nuclei of

A and B are NA and NB respectively. After three

half lives of A, number of nuclei of both are

equal. Then, the ratio A

B

N

N is :-

(1)1

4(2)

1

8(3)

1

3(4)

1

6

40. The output across the diode in the given circuit

in figure.

~vmsin t

R

(1) Would be zero at all times.

(2) Would be like a half wave rectifier with

positive cycles in output.

(3) Would be like a half wave rectifier with

negative cycles in output.

(4) Would be like that of a full wave rectifier.

36. 73Li 7.016005 amu

H- 1.007825 u

1.008665 u. Li

(1) 5.6 MeV (2) 39.2 Mev

(3) 0.042 MeV (4) 8.8 Mev

37.

(1) -

(2) -

(3) -

(4) -

38. 2.5ev

2ev

:-

(1) 4.5v (2) 2.5v

(3) 2v (4) 0.5v

39. A

B A B NA NB A

A

B

N

N

:-

(1)1

4(2)

1

8(3)

1

3(4)

1

6

40. :-

~vmsin t

R

(1)

(2)

(3)

(4)

0999DM610216003LATS-10/35


41. Vanderwaal radius of H is 1.5 Å, then distance

between H nucleus in two H2 molecule is :-

(1) 3.0 Å (2) 0.75 Å

(3) 6.0 Å (4) 1.5 Å

42. Total screening effect of valence electron in

element having maximum EA is periodic table is

applied by :-

(1) Electrons of penultimate shell only

(2) All electrons present in that atom (except any

two electrons)

(3) 1s2 2s2 2p6 3s2 3p4

(4) 1s2 2s2 2p6

43. During reaction of following reactants, in which

case formed gaseous product have no

hybridisation :-

(1) NH4Cl + Ca(OH)2 (2) Al4C3 + H2O

(3) KMnO4 + HCl (4) CaC2 + H2O

44. Which force is strongest :-

(1) ion-ion interaction

(2) ion-dipole interaction

(3) Instantaneous dipole induced dipole

(4) Kessom force & Debye force

45. Dipole moment of the AX4 type of molecule is

zero. The geometry of it can be :-

(1) Tetrahedral or square planar

(2) See saw or square planar

(3) Only tetrahedral planar

(4) Only square planar

46. A sodium salt on treatment with MgCl2 gives white

precipitate only on heating. The anion of the

sodium salt is :-

(1) SO4–2 & CO

3–2 (2) HCO

3–

(3) NO3– (4) CO3

–2

47. Hydrogen can be obtained from water, by the

action of water on :-

(1) Hydrolith & Calcium carbide

(2) Quick lime & CaH2

(3) Calcium & Calcium hydride

(4) Aluminium carbide

41. H 1.5 Å H2 H

:-(1) 3.0 Å (2) 0.75 Å

(3) 6.0 Å (4) 1.5 Å

42.

:-

(1)

(2) (

)(3) 1s2 2s2 2p6 3s2 3p4

(4) 1s2 2s2 2p6

43.

:-

(1) NH4Cl + Ca(OH)

2(2) Al

4C

3 + H

2O

(3) KMnO4 + HCl (4) CaC

2 + H

2O

44. :-

(1)

(2)

(3)

(4)

45. AX4

:-

(1)

(2)

(3)

(4)

46. MgCl2

:-

(1) SO4–2 & CO3

–2 (2) HCO3–

(3) NO3– (4) CO3

–2

47.

:-

(1)

(2) CaH2

(3)

(4)

Take it Easy and Make it Easy

LATS-11/350999DM610216003


48. Paramagnet ion on reduction in acidic medium

forms :-

(1) MnO2 & MnO4

–2

(2) Mn+2

(3) Mnº & MnO2

(4) Traces of Wolframite & Cinnebar

49. The number of possible isomers of a tetrahedral

complex [M(PQRS)] is :-

(1) 4 (2) 3

(3) 2 (cis & trans) (4) None of the above

50. Highest bond dissociation energy for C–O

bond is related to :-

(1) [V(CO)6]

– (2) [Fe(CO)5]º

(3) [Mn(CO)6]+ (4) [Cr(CO)

6]º

51. Colateral (side by side) overlapping is present

in:-

(1) B2H6 & BH3 (2) BF4

– & SiO2

(3) BF3

& H3PO

4(4) BF

3 & B

3N

3H

6Cl

3

52. The species present in solution when "Tri

atomic oxide of carbon" is dissolved in

universal solvent (means hydrogen oxide) are:-

(1) CO2 & H

2CO

3(2) HCO

3– & CO

3–2

(3) H2CO3 & CO3–2 (4) All of the above

53. Metals which are not present in German silver

are :-

(1) Ni & Cu (2) Cu & Zn

(3) Cr & Ag (4) None of these

54. In the following

3 2–2 6 3 2 5 2 3Al(H O) HCO Al(H O) OH H CO

(A) (B) (C) (D)

Species behaving as Bronsted – lowry acids

are :-

(1) (A), (D) (2) (A), (C)

(3) (B), (C) (4) (B), (D)

55. For the reaction,

A(g)

+ 2B(g)

2C(g)

+ 3D(g)

The value of H at 27°C is 19.0 Kcal. The

value of U for the reaction would be

(1) 20.8 Kcal (2) 19.8 Kcal

(3) 18.8 Kcal (4) 17.8 Kcal

48. :-

(1) MnO2 MnO4–2

(2) Mn+2

(3) Mnº MnO2

(4)

49. [M(PQRS)]

:-(1) 4 (2) 3

(3) 2 () (4)

50. C–O

:-(1) [V(CO)6]

– (2) [Fe(CO)5]º

(3) [Mn(CO)6]+ (4) [Cr(CO)

6]º

51. :-

(1) B2H

6 & BH

3(2) BF

4– & SiO

2

(3) BF3 & H3PO4 (4) BF3 & B3N3H6Cl3

52. " "

:-(1) CO

2 & H

2CO

3(2) HCO

3– & CO

3–2

(3) H2CO3 & CO3–2 (4)

53. :-

(1) Ni & Cu (2) Cu & Zn

(3) Cr & Ag (4)

54.

3 2–2 6 3 2 5 2 3Al(H O) HCO Al(H O) OH H CO

(A) (B) (C) (D)

:-

(1) (A), (D) (2) (A), (C)

(3) (B), (C) (4) (B), (D)

55. A

(g) + 2B

(g) 2C

(g) + 3D

(g)

27°C H = 19.0 Kcal U :-(1) 20.8 Kcal (2) 19.8 Kcal

(3) 18.8 Kcal (4) 17.8 Kcal

0999DM610216003LATS-12/35


56. If velocity of electron is 75% of velocity of

light, find dynamic mass of electron is :-

(1)2

3M

rest(2)

4

15M

rest

(3) 4

7M

rest(4)

4

5M

rest

57. A solution is prepared by mixing 100 mL each

of CH3OH(d = 0.8 g/mL) and C2H5OH

(d = 1 g/mL). If M1 is molarity of solution

having CH3OH solute in C2H5OH solvent and

M2 is molarity of solution having C2H5OH

solute in CH3OH solvent. Then :-

(1) M1 < M

2(2) M

1 > M

2

(3) M1 = M

2(4) M

1 + M

2 > 50

58. Determine the boiling point of a mixture

containing 1560 g benzene (molar mass = 78)

and 1125 g chlorobenzene (molar mass =

112.5) using the following graph at

atmospheric pressure of 1000 torr :-

200300400540

1000135018002200

90 100 110 120

t(C°)

Vapourpressure

benzene

chlorobenzene

(1) 90° (2) 100°C

(3) 110°C (4) 120°C

59. In a concentration cell, the same reactants are

present in both the anode and the cathode

compartments, but at different concentrations.

Calculate the emf of cell containing 0.04 M Cr3+

in one compartment and 1.0 M Cr3+ in the other

if Cr electrodes are used in both :-

(1) 0.028 V (2) 0.249 V

(3) 0.083 V (4) 0.125 V

60. Kc for the reaction X3++ Y– X + Y2+

is found to be 1018. The ºCellE is :-

(1) 0.708 V (2) 0.177 V

(3) 0.088 V (4) 0.354 V

56. 75% :-

(1)2

3M

rest(2)

4

15M

rest

(3) 4

7M

rest(4)

4

5M

rest

57. CH3OH(d = 0.8 g/mL) C

2H

5OH

(d = 1 g/mL) 100 mL

C2H

5OH CH

3OH

M1 CH3OH

C2H5OH M2 :-

(1) M1 < M

2(2) M

1 > M

2

(3) M1 = M2 (4) M1 + M2 > 50

58. 1000 torr

1560 (= 78) 1125

(= 112.5)

:-

200300400540

1000135018002200

90 100 110 120

t(C°)

benzene

chlorobenzene

(1) 90° (2) 100°C

(3) 110°C (4) 120°C

59.

0.04 M Cr3+ 1M Cr3+

emf Cr

:-

(1) 0.028 V (2) 0.249 V

(3) 0.083 V (4) 0.125 V

60. X3++ Y– X + Y2+ Kc

1018 ºCellE :-

(1) 0.708 V (2) 0.177 V

(3) 0.088 V (4) 0.354 V

LATS-13/350999DM610216003


61. In a multi layered close-packed structure

(1) there are twice as many tetrahedral holes

as there are close-packed atoms

(2) there are as many tetrahedral holes as there

are closed packed atoms

(3) there are twice as many octahedral holes as

there are close-packed atoms

(4) there are as many tetrahedral holes as there

are octahedral holes

62. Consider the following statements :

(i) increase in concentration of reactant

increases the rate of a zero order reaction

(ii) rate constant k is equal to 'A' if Ea = 0

(iii) rate constant k is equal to 'A' if Ea =

(iv) loge k vs T is a straight line

(v) loge k vs 1/T is a straight line

Correct statement are :

(1) (i) and (iv) (2) (ii) and (v)

(3) (iii) and (iv) (4) (ii) and (iii)

63. Reaction :

2Br– + H2O

2 + 2H+ Br

2 + 2H

2O

takes place in two steps :

(a) Br– + H+ + H2O

2

slow HOBr + H2O

(b) HOBr + Br– + H+ fast H2O + Br

2

The order of the reaction is -(1) 3 (2) 6 (3) 2 (4) 0

64. In the reaction X(g) + Y(g) 2Z(g), 2 mole

of X, 1 mole of Y and 1 mole of Z are initially

placed in a 10 litre vessel and allowed to reach

equilibrium. If equilibrium concentration of Z

is 0.2 M, then Kc for the given reaction is -

(1) 1.60 (2) 80

3

(3) 16

3(4) None of these

65. According to Freundlich adsorption isotherm,

which of the following is correct ?

(1) 0x

pm

(2) 1x

pm

(3) 1/ nx

pm

(4) All the above are correct for different

ranges of pressure

61.

(1)

(2)

(3)

(4)

62. (i)

(ii) k, 'A' Ea = 0

(iii) k, 'A' Ea =

(iv) loge k vs T, (v) loge k vs 1/T, (1) (i) (iv) (2) (ii) (v)

(3) (iii) (iv) (4) (ii) (iii)63. :

2Br– + H2O

2 + 2H+ Br

2 + 2H

2O

:(a) Br– + H+ + H

2O

2

HOBr + H2O

(b) HOBr + Br– + H+ H2O + Br

2

-(1) 3 (2) 6 (3) 2 (4) 0

64. X(g) + Y(g) 2Z(g)2X, 1 Y 1 Z,10 Z 0.2

MKc -

(1) 1.60 (2) 80

3

(3) 16

3(4)

65.

?

(1) 0x

pm

(2) 1x

pm

(3) 1/ nx

pm

(4)

0999DM610216003LATS-14/35


66. When CO2(g) is passed over red hot coke it

partially gets reduced to CO(g). Upon passing

0.5 litre of CO2(g) over red hot coke, the total

volume of the gases increased to 700 mL. The

composition of the gaseous mixture at STP is:-

(1) CO2 = 200 mL ; CO = 500 mL

(2) CO2 = 350 mL ; CO = 350 mL

(3) CO2 = 0.0 mL ; CO = 700 mL

(4) CO2 = 300 mL ; CO = 400 mL

67. Which is correct statement :-

(1) CH –Cl2

+

is more stable CH –F2

+

(2)

OH |

|Cl

is less reactive than

OH |

|CH 3

towards

diazotization

(3) –

CN is better nucleophile then –

NH2

(4) All carbon-carbon bond length in

CH2=CH–CH=CH2 are equal

68. Which is meso compound :-

(1)

COOH

COOH

H Cl

Cl H (2)

COOH

COOH

H Cl

H Br

(3)

COOH

H

H Br

Br COOH (4)

COOH

Cl

H Cl

H COOH

69. CH –CH –C–H + CH –C CH3 2 3 ||O

NaNH2 H O2 ?

(1) (2)

(3) (4) OH

NH

66. CO2(g) CO(g) CO2(g) 0.5

700 mL STP :-

(1) CO2 = 200 mL ; CO = 500 mL(2) CO2 = 350 mL ; CO = 350 mL

(3) CO2 = 0.0 mL ; CO = 700 mL(4) CO2 = 300 mL ; CO = 400 mL

67. :-

(1) CH –Cl2

+

CH –F2

+

(2)

OH |

|Cl

OH |

|CH 3

(3) –

CN –

NH2

(4) CH2=CH–CH=CH2 C–C

68. :-

(1)

COOH

COOH

H Cl

Cl H (2)

COOH

COOH

H Cl

H Br

(3)

COOH

H

H Br

Br COOH (4)

COOH

Cl

H Cl

H COOH

69. CH –CH –C–H + CH –C CH3 2 3 ||O

NaNH2 H O2 ?

(1) (2)

(3) (4) OH

NH

LATS-15/350999DM610216003


70. Rate of hydrohalogenation of following are :-

CH=CH–CH3

(P)

CH=CH2

(Q)

CH=CH2

(R)

CH –O3

(S)

CH –C–CH=CH3 2

Ph |

|CH3

(1) R > P > Q > S

(2) P > R > Q > S

(3) S > P > Q > R

(4) R > S > P > Q

71. Which alkene can produce diastereomers :-

(1) CH3–CH=CH–CH3

(2) Ph–CH=CH2

(3)

(4) CH3–CH=CH2

72.

B on ozonolysis gives C + D. C gives iodoform

test but 'D' does not.

D O

NaOH

E ?

(1) O

CH –OH2

(2) O

CH2

(3) (4) ||O

OH

C–CH3

70. :-

CH=CH–CH3

(P)

CH=CH2

(Q)

CH=CH2

(R)

CH –O3

(S)

CH –C–CH=CH3 2

Ph |

|CH3

(1) R > P > Q > S

(2) P > R > Q > S

(3) S > P > Q > R

(4) R > S > P > Q

71. :-

(1) CH3–CH=CH–CH3

(2) Ph–CH=CH2

(3)

(4) CH3–CH=CH2

72.

B C + D C

'D'

DO

NaOH

E ?

(1) O

CH –OH2

(2) O

CH2

(3) (4) ||O

OH

C–CH3

0999DM610216003LATS-16/35


73. Which gives nitrosoamine on treatement with

HNO2 ?

(1) NH (2) CH –CH–NH3 2 |CH3

(3) N

(4) N–CH3

74. CH–OH |CH3

KCN

H A 2 5Na C H OH B ?

(1) CH–CH |NH

3

2

(2) CH–CH –NH |CH

2 2

3

(3) CH –CH 2 3

(4) CH–NH–CH |CH

3

3

75. Which ester gives racemization on hydrolysis:-

(1) Ph–CH–C–O–CH –CH2 3

|CH3

|| O

(2) Ph–C–O–C NO2

|| O

CH |

3

|CH3

(3) CH –C–O–CH OCH3 3 || O

|CH3

(4) CH –C–O–CH –Ph3 2

|| O

73. HNO2 ?

(1) NH (2) CH –CH–NH3 2 |CH3

(3) N

(4) N–CH3

74. CH–OH |CH3

KCN

H A 2 5Na C H OH B ?

(1) CH–CH |NH

3

2

(2) CH–CH –NH |CH

2 2

3

(3) CH –CH 2 3

(4) CH–NH–CH |CH

3

3

75. :-

(1) Ph–CH–C–O–CH –CH2 3

|CH3

|| O

(2) Ph–C–O–C NO2

|| O

CH |

3

|CH3

(3) CH –C–O–CH OCH3 3

|| O

|CH3

(4) CH –C–O–CH –Ph3 2

|| O

LATS-17/350999DM610216003


76. X + Y 1. EtO

2. H

O||

O||

O

X and Y are :-

(1)

O|| O

||O+ O

(2)

O|| O

||O+ H

(3)

O||

O||

O +HO

(4)

O||

O||

H +

O||

O

77. Which one of the following monomer gives

the polymer neoprene on polymerization –

(1) CH2 CHCl

(2) CCl2 CCl2

(3)C

Cl

CH2 CH CH2

(4) CF2 CF2

78. Denaturation of proteins leads to loss of its

biological activity by :-

(1) Formation of amino acids

(2) Loss of primary structure

(3) Loss of both primary and secondary

structures

(4) Loss of both secondary and tertiary

structures

76. X + Y 1. EtO

2. H

O||

O||

O

X Y :-

(1)

O|| O

||O+ O

(2)

O|| O

||O+ H

(3)

O||

O||

O +HO

(4)

O||

O||

H +

O||

O

77.

(1) CH2 CHCl

(2) CCl2 CCl2

(3)C

Cl

CH2 CH CH2

(4) CF2 CF2

78.

:-

(1)

(2)

(3)

(4)

0999DM610216003LATS-18/35


79. Which of the following disaccharide is a non

reducing sugar :-

(1)

OH H

HO

CH OH2

H

OH

H

H

OH

HO

OCH OH2

H

OH

H

H

OH

H

OH

(2)

OH HOH C2

HO

CH OH2

H

OH

H

H

OH

HO

O

H

OH

OH

H

H

CH OH2

(3)

OH HO

HO

CH OH2

H

OH

H

H

OH

HO

OCH OH2

H

OH

H

H

OH

OH

H

(4)

OH H

HO

CH OH2

H

OH

H

H

OH

HO

OCH OH2

H

OH

H

H

OH

OH

H

80. D-Glucose and L-Glucose are:-

(1) Epimer

(2) Anomer

(3) Diastereomers

(4) Enantiomers

79. :-

(1)

OH H

HO

CH OH2

H

OH

H

H

OH

HO

OCH OH2

H

OH

H

H

OH

H

OH

(2)

OH HOH C2

HO

CH OH2

H

OH

H

H

OH

HO

O

H

OH

OH

H

H

CH OH2

(3)

OH HO

HO

CH OH2

H

OH

H

H

OH

HO

OCH OH2

H

OH

H

H

OH

OH

H

(4)

OH H

HO

CH OH2

H

OH

H

H

OH

HO

OCH OH2

H

OH

H

H

OH

OH

H

80. D- L-:-

(1)

(2)

(3)

(4)

LATS-19/350999DM610216003


81. It's a diagrammatic sketch of different type ofmeristematic tissue. Identity. The parts labelleda, b and c and select the right option about them-

a

c

b

(a) (b) (c)

(1) Apicalmeristem

Secondarymeristem

Secondarymeristem

(2) Primarymeristem

Secondarymeristem

Character ofgrass stem

(3) Axillary bud Node Internode

(4) Primary inorigin

Character ofGrass stem

Secondaryin origin

82. In some legumes plants, the leaf base maybecome swollen which is called -

(1) Phyllode (2) Pulvinus

(3) Leaf pitcher (4) Sheathing leaf base

83. Consider the following four statements (a-d)and select the option which includes all thecorrect ones only -

(a) Fasciculated roots are found in asparagus(b) In banana plant type of stem is sucker

(c) Rachis is present in both pinnately andpalmately compound leaf

(d) A bud is present in the axil of leaflets

(1) statement (a) and (b)

(2) statement (a) and (d)

(3) statements (a) (b) and (d)

(4) statements (b) and (c)

81. ;g ,d esfjLVse Ård dks n'kkZrk fp= gSA blds ckjs esa

ukaekfdr Hkkx a, b, rFkk c dks igpkfu;s rFkk lgh fodYi

dk pquko fdft;s -

a

c

b

(a) (b) (c)

(1) 'kh"kZLFk esfjLVse f}rh;d esfjLVse f}rh;desfjLVse

(2) izkFkfedesfjLVse

f}rh;d esfjLVse ?kkal rus dky{k.k

(3) d{kLFk dfydk ioZ laf/k;k ioZ

(4) mRifÙk esaizkFkfed

?kkal rus dky{k.k

mRifr esaf}rh;d

82. dqN ySX;we ikniks esa] o.kkZ/kkj Qwyk gqvk gks ldrk gS] ;g

dgykrk gS -

(1) i.kkZHkoUr (2) iyfoul/i.kZorarYi

(3) i.kZ ?kV (4) vkfPNn~ i.kkZ/kkj

83. fn;s x;s pkj dFkuks (a-d) ij fopkj fdft;s rFkk lHkh lgh

dFkuks okys ,d fodYi dk pquko fdft;s -

(a) iqyfdr ewy lrkoj eas ik;k tkrk gSA

(b) dsys ds ikni es vUr% HkwLrkjh rus dk izdkj gksrk gSA

(c) fiPNkdkj ,oa gLrkdkj i.kZ es jsfpl ik;k tkrk gSA

(d) i.kZd ds v{k ij ,d dfydk ik;h tkrh gSA

(1) dFku (a) rFkk (b)

(2) dFku (a) rFkk (d)

(3) dFku (a) (b) rFkk (d)

(4) dFku (b) rFkk (c)

0999DM610216003LATS-20/35


84. How many statements are correct regardinggiven diagram ?

(a) Virus have genetic material DNA(b) Virus have genetic material RNA(c) Virus have 2130 capsomere(d) It causes infection in animals(e) They are living only inside host(1) Two (2) Three (3) Four (4) All

85. Sexual reproduction of spirogyra is -(1) Morphological as well as physiological

isogamy(2) Morphological isogamy and physiological

anisogamy(3) Morphological as well as physiological

anisogamy(4) Morphological anisogamy and

physiological isogamy.86. Study the following statements. Which of them

are incorrect ?(a) Gametophyte is not produced in

pteridophyta(b) In gymnosperms male and female

gametophytes do not have an independentfree-living existence.

(c) Coralloid roots are produced in Pinus andmycorrnizal roots are found in Cycas.

(d) Unbranched stem occurs in Cycas while thestem of Pinus and Cedrus is branched.

(1) only a & c (2) only c & d(3) only a, c & d (4) All a, b, c & d

87. Percentage of water in the honey is –(1) 17 – 20% (2) 32 – 37%(3) 40 – 45% (4) 98%

88. Estimation says that in India and China whatpercentage of world livestock population in present.

(1) 25% (2) 70% (3) 50% (4) 45%

84. fn;s x;s fp= ds lUnHkZ esa fdrus dFku lR; gS\

(a) okbjl esa vkuqokaf'kd inkFkZ Mh,u, gSA

(b) okbjl esa vkuqoakf'kd inkFkZ vkj,u, gSA

(c) okbjl esa 2130 dsIlkseh;j gSA

(d) ;g tUrqvksa esa laØe.k djrk gSA

(e) ;g ijiks"kh ds vUnj gh ltho gksrs gSA

(1) nks (2) rhu (3) pkj (4) lHkh

85. Likbjksxkbjk esa ySafxd tuu gS -

(1) vkdkfjdh ,oa dkf;Zdh le;qXedh

(2) vkdkfjdh le;qXedh ,oa dkf;Zdh fo"ke ;qXedh

(3) vkdkfjdh ,oa dkf;Zdh fo"ke;qXedh

(4) vkdkfjdh fo"ke ;qXedh ,oa dkf;Zdh le;qXedh

86. fuEu dFkuksa dk v/;;u dj crkb;s buesa ls xyr dFku

dkSu&dkSu ls gS\

(a) VsfjMksQkbV~l esa ;qXedksn~fHkn ugha curk gSA

(b) ftEuksLieZ esa uj o eknk ;qXedksn~fHkn dk eqDr thoh

vfLrRo ugha gksrk gSA

(c) ikbul esa dWkjsyksbM ewy rFkk lkbdl esa dod ewy gksrh

gSA

(d) lkbdl esa v'kkf[kr ruk rFkk ikbul o lhMªl esa 'kkf[kr

ruk gksrk gSA

(1) dsoy a o c (2) dsoy c o d

(3) dsoy a, c o d (4) lHkh a, b, c o d

87. 'kgn esa ty dk fdruk izfr'kr gksrk gS &(1) 17 – 20% (2) 32 – 37%(3) 40 – 45% (4) 98%

88. ,d vuqeku ds vuqlkj bf.M;k vkSj phu esa dqy i'kq/ku dh

fdruh izfr'kr vkcknh jgrh gS &

(1) 25% (2) 70% (3) 50% (4) 45%

LATS-21/350999DM610216003


89. In nearly all animal tissues, specialisedjunctions provide which of the following typeof links between its individual cells

(1) functional (2) structural

(3) Biochemical (4) both 1 and 2

90. Chromatin name was given by -

(1) Robert Brown (2) Flemming

(3) Schwann (4) Ramchandran

91. Most abundant protein in whole biosphere is :-

(1) RuBisCo (2) Collagen

(3) Tryprin (4) Insulin

92. Which of the following is longest phase ofmeiosis ?

(1) Prophase I (2) Anaphase I

(3) Prophase II (4) Metaphase II

93. Select odd one with respect to factors affectphotosynthesis :

(1) There is a linear relationship betweenincident light and CO2 fixation rates at lowlight intensities

(2) C4 plants show CO2 saturation at about 360 ml L–1

(3) Tropical plants have a higher temperatureoptimum than the plants adapted totemperate climates

(4) Light is a major limiting factor in clear sky.

94. Sugarcane, Maize, Sorghum, Tomato, Bellpepper, Tobacco

How many plants from above box fix their CO2

through Calvin cycle?

(1) Six (2) Four

(3) Three (4) Five

95. The first member of TCA cycle is :

(1) Pyruvate (2) Succinate

(3) OAA (4) Malic acid

96. What for the ascending limb of Loop of Henleis permeable ?(1) Glucose (2) NH3

(3) Na+ (4) Water

89. yxHkx lHkh tUrq Årdksa esa fo'ks"khÏr laf/k fuEu esa ls fdl

izdkj dk lgkjk iznku djrs gS:-

(1) fØ;kRed (2) lajpukRed

(3) tSo jklk;fud (4) 1 vkSj 2 nksuksa

90. ØksesVhu uke fdlus fn;k Fkk -

(1) jkcVZ czkmu (2) ¶ysfeax

(3) 'oku (4) jkekpaæu

91. tho eaMy esa lokZf/kd ik;k tkus okyk izksVhu gS :-

(1) :fcLdks (2) dksystu

(3) fVªiflu (4) balqfyu

92. fuEu esa ls dkSu v/kZlw=h foHkktu dh lcls yEch voLFkk

gS ?

(1) iwokZoLFkk I (2) i'pkoLFkk I

(3) iwokZoLFkk II (4) e/;koLFkk II

93. izdk'k la'ys"k.k dks izHkkfor djus okys dkjdksa ds lanHkZ esa

fo"ke dk p;u dhft, &

(1) de izdk'k rhozrk ij iFoh dh lrg ij vkus okys izdk'k

rFkk CO2 ds fLFkjhdj.k dh nj esa js[kh; lEcU/k gksrk gSA

(2) C4 ikniksa esa 360 ml L–1 eku ij CO2 larIrrk vkrh gSA

(3) m".kdfVca/kh; ikniksa esa mfpr rkieku 'khrks".k tyok;q

esa vuqdwfyr ikniksa ls vf/kd gksrk gSA

(4) lkQ vkdk'k esa izdk'k ,d o`gr lhekdkjh dkjd gksrk

gSA

94. xUuk] eDdk] Tokj] VekVj] f'keyk fepZ] rEckdw

mijksDr ckWDl esa ls fdrus ikni dsfYou pØ ds }kjk CO2

fLFkj djrs gS\

(1) N% (2) pkj

(3) rhu (4) ikap

95. TCA pØ dk izFke lnL; gS &

(1) ik;:osV (2) lfDlusV

(3) OAA (4) eSfyd vEy

96. gsuys ik'k dh vkjksgh Hkqtk fdlds fy, ikjxE; gksrh gS %

(1) Xywdkst (2) NH3

(3) Na+ (4) ty

J ges'kk eqLdjkrs jgs a A

0999DM610216003LATS-22/35


97. Consider the following step and Identify A, B,C and D :

Starch Amylase¾¾¾¾® A.

Peptone Trypsin¾¾¾® B.

Fat Lipase¾¾¾® C.

Lactose Lactase¾¾¾® D.

A B C D

(1) Disacharide Dipeptide Fatty acidGalactose

andGlucose

(2) Fafly Acid Disacharide Glucose Dipeptide

(3) Glucose Fatty acid Disachanide Dipeptide

(4) Dipeptide Galactose Disacharide Fatty acid

98. The Intestine is different from the stomach bythe presence of :(1) Digestive gland (2) Villi(3) Sub- mucosa (4) Serosa

99. Find out the incorrectly matched pair regardingyour skeletal system :-(1) Vertebrochondral ribs = 6(2) Skull bones = 22(3) Occipetal condyles = 2(4) Vertebrosternal ribs = 7

100.

Which structure is responsible for equalisingthe pressure on either sides of the ear drum.(1) D (2) B (3) C (4) A

101. Which of the following pair of structure of eye

are transparent and helps in refraction of light?

(1) Cornea and lens (2) Iris and lens

(3) Cornea and Iris (4) Lens and sclera

97. fuEu inksa ij fopkj djs vkSj A, B, C rFkk D dks igpkusa :

LVkpZ ¾¾¾®,ekbyts A.

isIVksu ¾¾¾®fVªfIlu B.

olk ¾¾¾®ykbist C.

ySDVkst ¾¾¾®yDS Vst D.

A B C D

(1) Mk;lSdsjkbM Mk;isIVkbM olh; vEyXkSysDVkst rFkk

Xywdkst

(2) olh; vEy Mk;lSdsjkbM Xywdkst MkbZisIVkbM

(3) Xywdkst olh; vEy MkblSdsjkbM MkbZisIVkbM

(4) MkbisIVkbM xSysDVkst MkblSdsjkbM olh; vEy

98. fdldh mifLFkfr ds dkj.k vk¡r vkek'k; ls fHkUu gksrh gS :

(1) ikpu xazfFk;k¡ (2) foykbZ

(3) lc-E;wdkslk (4) lhjkslk

99. vkids dadky ra= ds lanHkZ esa xyr esfyr ; qXe dkspqfu;s :-(1) oVhZcjks&dks.Mjy ilfy;k¡ = 6(2) diky vfLFk;ka = 22(3) vkfDlfiVy dks.Mkby = 2(4) oVhZcjks&LVuZy ilfy;k¡ = 7

100.

dkSu lh lajpuk d.kZ iVy ds nksuks rjQ nkc dks cjkcj djusdk dk;Z djrh gS(1) D (2) B (3) C (4) A

101. fuEu esa dkSu lh us= dh lajpuk, ijn'khZ gksrh gS vkSj çdk'kds viorZu es lg;ksx djrh gS ?(1) dksfuZ;k vkSj ysUl (2) vkbfjl vkSj ysUl(3) dksfuZ;k vkSj vkbfjl (4) ysUl vkSj Ldsysjk

viuh {kerk dks iwjk olwyus dk iz;kl djsa A

LATS-23/350999DM610216003


102. Sequence of development during the formationof embryosac is :-

(1) Archesporical cell ® Megaspore ®Megaspore mother cell ® Embryosac

(2) Megasporocyte ® Archesporical cell ®Megaspore ® Embryosac.

(3) Megaspore ® Megaspore mother cell ®Archesporial cell ® Embryosac.

(4) Archesporial cell ® Megaspore mothercell ® Megaspore ® Embryosac

103. Binding of oxygen with haemoglobin isprimarily related to :-

(1) Partial pressure of O2

(2) Partial pressure of CO2

(3) H+ ion concentration

(4) Temperature

104. Plant with ovaries having only one ovule isgenerally pollinated by :-

(1) Wind (2) Butterflies

(3) Birds (4) Bees

105. Which extra-embryonic membrane participatein the formation of placenta ?

(1) Amnione & chorione

(2) Chorione & Allentois

(3) Chorione & Yolk sac

(4) Yolk sac & Allentois

106. Which one is not considered as a naturalmethod ?

(1) Rhythm/periodic abstinence

(2) Withdrawal/coitus interruptus

(3) Lactional amenorrhoea

(4) Vasectomy

107. The codon UUU and UUC codes forphenylalanine, this feature of genetic code is:-

(1) degenerate (2) commaless

(3) non-ambiguous (4) non-overlapping

108. Plants obtained through tissue culture aregenetically identical and they are obtained bysomatic cells they are called :-

(1) Somatic hybrids

(2) Somaclones

(3) Cross hybrids

(4) Monoclones

102. Hkzw.kdks.k ds xBu ds nkSjku fodkl ds vuqØe :-

(1) çilw dksf'kdk ® xq:chtk.kq ® xq:chtk.kq ekr`

dksf'kdk ® Hkzw.kdks"k

(2) esxkliksjkslkbV ® çilw dksf'kdk ® xq:chtk.kq ®

Hkzw.kdks"k

(3) xq:chtk.kq ® xq:chtk.kq ekr` dksf'kdk ® çilw

dksf'kdk ® Hkzw.kdks"k

(4) çilw dksf'kdk ® xq:chtk.k q ekr` dksf'kdk ®

xq:chtk.kq ® Hkzw.kdks"k

103. vkWDlhtu dk fgeksXyksfcu ds lkFk ca/ku izkFkfed :i ls

fdlls laacaf/kr gS&

(1) O2 dk vkaf'kd nkc

(2) CO2 dk vkaf'kd nkc

(3) H+ vk;u lkaær

(4) rkieku

104. ,d chtk.M ;q Dr v.Mk'k; okyk ikS/kk lkekU;r% blds }kjkijkfxr gksrk gS\(1) ok;q (2) frrfy;k¡(3) if{k;ksa (4) efD[k;ksa

105. vijk ds fuekZ.k esa dkSu&dkSulh vfrfjDr Hkwz.kh; f>fYy;kHkkx ysrh gS ?(1) ,sfEu;ksu rFkk dkWjh;ku(2) dkWjh;ku rFkk , sys.Vksbl(3) dkWjh;ku rFkk ;ksd lsd(4) ;ksd lsd rFkk ,sys.Vksbl

106. fuEu esa ls dkSulk ,d xHkZfujks/kd dk izkdfrd mik; ughagS ?(1) vkof/kd la;e(2) cká&L[kyu(3) Lruiku vukorZu(4) oslsDVkseh

107. dksMksu UUU rFkk UUC Qhukby,sysuhu dks dksM djrsgS] vkuqokaf'kd dksMksu ds bl xq.k dks dgrs gS :-(1) viâkflrk (2) dksekysl(3) vlafnX/k (4) ukWu vksojysfiax

108. Ård lao/kZu }kjk izkIr ikni vkuqokaf'kd :i ls leku gksrs

gS rFkk dkf;d dksf'kdk }kjk izkIr gksrs gSA bUgsa dgrs gS :-

(1) Somatic hybrids

(2) Somaclones

(3) Cross hybrids

(4) Monoclones

0999DM610216003LATS-24/35


109. In a polysaccheride, number of monosaccherideare linked by :-

(1) glycosidic bond (2) peptide bond

(3) Hydrogen bond (4) phosphoester bond110. Which one of the following statement is not

correct about a plasmid ?(1) Self-replicating(2) Circular DNA(3) Antibiotic resistant gene(4) Linear DNA

111. The gene disorder phenylketonuria is anexample of :-(1) Multiple allele(2) Polygenic inheritance(3) Multiple factor(4) Pleiotropy

112. A human female is heterozygous forautosomal genes A and B and alsoheterozygous for hemophilic gene h. Whatproportion of his ova will be abh ?

(1) 14

(2) 18

(3) 1

32(4)

116

113. According to Darwin evolution is a :(1) a sudden but discontinuous process(2) a gradual but discontinuous process(3) a gradual but continuous process(4) a quick and continuous process

114. "Balancing selection" promotes :(1) Homozygotes (2) Heterozygotes(3) Polyploids (4) Recessive traits

115. One defective gene of x-linked recessivedisorder found in male and female. Correctoption for this situation is ?(1) Male – carrier, female – carrier(2) Male – normal, female – diseased(3) Male – diseased, female – carrier(4) Male – diseased, female – diseased

116. Correct statement regarding interferones ?(1) Interferones are virus specific proteins(2) Interferones are not species specific(3) Interferones directly attacks on viruses and

destroy them(4) Interferones can be used for prophylaxis of

viral infections

109. IkkWyhlsdsjkbM esa dbZ eksukslsdsjkbM tqM+h gksrh gS :-

(1) XykbZdksflfMd ca/k (2) isIVkbM ca/k

(3) gkbMªkstu ca/k (4) QkWLQks,LVj ca/k

110. mijksDr esa ls dkSulk dFku IykfTeM ds fy, lgh ugh gS ?

(1) Lor% izfrfyfidj.k

(2) xksykdkj Mh,u,

(3) izfrtSfod izfrjks/kh thu

(4) js[kh; Mh,u,

111. thu fodkj QhukbydhVksuwfj;k fdldk mnkgj.k gS :-

(1) cgq;qXefodYih

(2) cgqthuh oa'kkxfr

(3) cgqdkjd

(4) cgqizHkkfodrk

112. ,d eknk ekuo vfyaxlw=h thuks A rFkk B ds fy,fo"ke;qXeth gS vkSj lkFk gh gheksQhyh;k thu h ds fy, Hkhfo"ke;qXeth gSA mlds mu v.Mk.kqvks dk vuqikr D;k gksxkftuesa abh O;oLFkk gksxh ?

(1) 14

(2) 18

(3) 1

32(4)

116

113. MkfoZu ds vuqlkj mn~fodkl gS :(1) ,d vpkud ijUrq vlrr izfØ;k(2) ,d /kheh ijUrq vlrr izfØ;k(3) ,d /kheh rFkk lrr izfØ;k(4) ,d rhoz rFkk lrr izfØ;k

114. "larqfyr oj.k" i{k ysrk gS :(1) le;qXeth dk (2) fo"ke;qXeth dk(3) cgqxqf.kr dk (4) vizHkkohdk

115. x-Øksekslkse vizHkkoh fodkj fd ,d nks"k;qDr thu iq:"kvkSj L=h es a ikbZ xbZA bl voLFkk ds fy, lgh fodYigksxk ?(1) iq:"k – okgd, L=h – okgd(2) iq:"k – lkekU;, L=h – jksxh(3) iq:"k – jksxh, L=h – okgd(4) iq:"k – jksxh, L=h – jksxh

116. bUVjQsjksu ds fy, lgh dFku dkSulk gS ?

(1) bUVjQsjksu ok;jl fof'k"V izksVhu gS

(2) bUVjQsjksu tkrh; fof'k"V ugha gksrs

(3) bUVjQsjksu lh/ks ok;jl ij geyk djds mls u"V djrs gS

(4) bUVjQsjksu ok;jl laØe.kksa esa jksxfujks/kd ds :i esa mi;ksx

fd;k tkrk gS

Time Management is Life Management

LATS-25/350999DM610216003


117. PAN (peroxy acetyl nitrate) is a secondarypollutant and is found in :-(1) Herbicide (2) Pesticide(3) Fertilizer (4) Smog

118. Most hazardous metal pollutant of automobile

exhaust is :-

(1) Hg (2) Cd (3) Pb (4) Cu119. Grassland with scattered trees is called :-

(1) Savana biome (2) Rain forest

(3) Decidous forest (4) Taiga

120. According to national forest policy how much areashould be covered by forest on hills in India ?(1) 33% (2) 67% (3) 48% (4) 50%

DIRECTIONS FOR Q. NO. 121 TO 180

These questions consist of two statements each,printed as Assertion and Reason.Whileanswering these Questions you are required tochoose any one of the following four responses.

A. If both Assertion & Reason are True & theReason is a correct explanation of the Assertion.

B. If both Assertion & Reason are True but Reasonis not a correct explanation of the Assertion.

C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False.

121. Assertion :- In an elastic collision between twobodies, the relative speed of the bodies aftercollision is equal to the relative speed beforethe collision.Reason :- In an elastic collision, the linearmomentum of the system is conserved.(1) A (2) B (3) C (4) D

122. Assertion :- A cloth covers a table. Some dishesare kept on it. The cloth can be pulled outwithout dislodging the dishes from the table.

Reason :- For every action there is an equal andopposite reaction.

(1) A (2) B (3) C (4) D

123. Assertion :- The equation of motion can beapplied only if the acceleration is along thedirection of velocity and is constant.

Reason :- If the acceleration of a body is constantthen its motion is known as uniform motion.

(1) A (2) B (3) C (4) D

117. PAN (ijvkWDlh ,flVkby ukbVªsV) ,d f}rh;d iznw"kd gSfdlesa ik;k tkrk gS :-(1) 'kkduk'kh (2) ihM+duk'kh(3) moZjd (4) Leksx

118. okguksa ds /kq,sa ls eqDr gksus okyk lcls gkfudkjd /kkrq iznw"kdgS :-(1) Hg (2) Cd (3) Pb (4) Cu

119. ?kklLFky esa fc[kjs gq, o`{k ik, tkrs gS] ftls dgrs gSa :-

(1) lokuk ck;kse (2) o"kkZ ou

(3) ir>M+ ou (4) Vsxk

120. jk"Vªh; ou uhfr ds vuqlkj Hkkjr esa igkfM+;ksa ij fdruk {ks=

ou ls f?kjk gksuk pkfg,\(1) 33% (2) 67% (3) 48% (4) 50%

iz'u la[;k 121 ls 180 ds fy, funs Z'k

izR;sd iz'u es a dFku rFkk dkj.k fn, x;s gSaA iz'uks a

dks gy djrs le; uhps fn, x, pkjks a fodYiks a es a

ls lgh fodYi dks pqfu,A

A. ;fn dFku ,oa dkj.k nksuks a lR; ga S rFkk dkj.k dFkudk lgh Li"Vhdj.k gSA

B. ;fn dFku ,oa dkj.k nksuks a lR; gaS] ysfdu dkj.k] dFku

dk lgh Li"Vhdj.k ugha gSAC. ;fn dFku lR; gS] ysfdu dkj.k vlR; gSAD. dFku o dkj.k nk suk s a vlR; gSaA

121. dFku :- nks fi.Mksa dh izR;kLFk VDdj esa] VDdj ds cknfi.Mks dh lkis{k pky] VDdj ls iwoZ lkis{k pky ds cjkcjgksrh gSA

dkj.k :- izR;kLFk VDdj esa] fudk; dk js[kh; laosx lajf{krjgrk gSA

(1) A (2) B (3) C (4) D

122. dFku :- ,d Vscy dks diM+s ls <kad j[kk gSA dqN oLrqvksadks bl ij j[kk gqvk gSA Vscy ds diM+s dks Vscy ls] Vscyij j[kh oLrqvksa dks fcuk izHkkfor fd;s [khapk tk ldrk gSAdkj.k :- izR;sd fØ;k dh cjkcj rFkk fn'kk esa foijhrizfrfØ;k gksrh gSa(1) A (2) B (3) C (4) D

123. dFku :- xfr dh lehdj.k dsoy rHkh ykxw gksrh gS tcRoj.k dh fn'kk osx ds vuqfn'k gk s rFkk bldk eku vpjgksAdkj.k :- ;fn fdlh oLrq dk Roj.k vpj gS rks bldhxfr ,dleku xfr dgykrh gSA(1) A (2) B (3) C (4) D

0999DM610216003LATS-26/35


124. Assertion :- When a man jumps from a boat to shore,the boat slightly moves away from the shore.Reason :- The total momentum should remainconserved.(1) A (2) B (3) C (4) D

125. Assertion :– In series combination of electricbulbs the bulb of lower power emits more lightthan that of higher power bulb.Reason :– The lower power bulb in series getsmore current than the higher power bulb.(1) A (2) B (3) C (4) D

126. Assertion : Electric field is always directedperpendicular to an equipotential surface.Reason : Equipotential surface is a surface onwhich each point potential is same.(1) A (2) B (3) C (4) D

127. Assertion :- Eddy currents is produced in anymetallic conductor when magnetic flux linkedwith it changes.Reason :- Electric potential determines the flowof charge.(1) A (2) B (3) C (4) D

128. Assertion :- We cannot think of magnetic fieldconfiguration with three poles.Reason :- A bar magnet does exert a torque onitself due to its own field.(1) A (2) B (3) C (4) D

129. Assertion :- The dc and ac both can bemeasured by a hot wire instrument.Reason :- The hot wire instrument is based onthe principle of magnetic effect of current.(1) A (2) B (3) C (4) D

130. Assertion :- If an object is submerged in fluidat rest, the fluid exerts a force on its surface.Reason :- The force exerted by the fluid at resthas to be parallel to the surface in contact with it.(1) A (2) B (3) C (4) D

131. Assertion :- The principle of superposition isnot valid for gravitational forces.Reason :- Gravitational forces are non-conservative.(1) A (2) B (3) C (4) D

132. Assertion :- If earth were to shrink, length ofthe day would increase.Reason :- Smaller objects would take moretime to complete one rotation around its axis.(1) A (2) B (3) C (4) D

124. dFku :- tc dksbZ O;fDr uko ds vUnj ls rV ij dwnrk gSrks uko rV ls FkksM+k nwj gV tkrh gSA

dkj.k :- dqy laosx lajf{kr jguk pkfg,A

(1) A (2) B (3) C (4) D

125. dFku :– fo|qr cYcksa ds Js.khØe la;kstu esa de 'kfDr dkcYc vf/kd 'kfDr ds cYc ls vf/kd izdk'k mRlftZr djrkgSAdkj.k :– Js.khØe esa de 'kfDr dk cYc vf/kd 'kfDr dscYc dh vis{kk vf/kd /kkjk izkIr djrk gSA

(1) A (2) B (3) C (4) D126. dFku : fo|qr {ks= ges'kk lefoHko lrg ds yacor gksrk

gSAdkj.k : lefoHko lrg ,slh lrg gS ftlds gj fcanq ij foHkoleku gSA(1) A (2) B (3) C (4) D

127. dFku :- tc fdlh /kkfRod pkyd ls lac¼ pqEcdh;¶yDl ifjofrZr gksrk gS rks mlesa Hkaoj /kkjk;sa mRiUu gksrhgSaAdkj.k :- fo|qr foHko vkos'k izokg dks fu/kkZfjr djrkgSA(1) A (2) B (3) C (4) D

128. dFku :- rhu pqEcdh; /kzqoksa ds fudk; dk pqEcdh; {ks=ugha gksrk gSAdkj.k :- ,d NM+ pqEcd Lo;a ds pqEcdh; {ks= ds dkj.kcy vk?kw.kZ dk vuqHko djrk gSA(1) A (2) B (3) C (4) D

129. dFku :- dc o ac nksuksa rIr rkj midj.k (hot wireinstrument) }kjk ekih tk ldrh gSAdkj.k :- rIr rkj midj.k /kkjk ds pqEcdh; çHkko ijvkèkkfjr gSA(1) A (2) B (3) C (4) D

130. dFku :- ;fn fdlh oLrq dks fojkekoLFkk esa rjy esa Mqck;ktkrk gS] rks rjy bldh lrg ij ,d cy lEikfnr djrk gSAdkj.k :- fojkekoLFkk esa rjy }kjk lEikfnr cy dks bldslEidZ esa lrg ds lekukUrj gksuk iM+rk gSA(1) A (2) B (3) C (4) D

131. dFku :- v/;kjksi.k dk fl¼kUr xq:Rokd"kZ.k cyksa ds fy;soS/k ugha gksrk gSA

dkj.k :- xq:Rokd"kZ.k cy vlaj{kh gksrs gSaA

(1) A (2) B (3) C (4) D

132. dFku :- ;fn i`Foh fldqM+ tk;s rks fnu dh yEckbZ c<+tk;sxhAdkj.k :- NksVh oLrq vius v{k ds ifjr% ,d pDdj iwjkdjus esa vf/kd le; ysrh gSA(1) A (2) B (3) C (4) D

LATS-27/350999DM610216003


133. Assertion :- The melting point of ice decreaseswith increase of pressure.

Reason :- Ice contracts on melting

(1) A (2) B (3) C (4) D

134. Assertion :- The root mean square and mostprobable speeds of the molecules in a gas arethe same.

Reason :- The maxwell distribution for thespeed of molecules in a gas is symmetrical.

(1) A (2) B (3) C (4) D

135. Assertion :- The time period of a simplependulum is independent of its amplitude ofvibration.

Reason :- If the amplitude of a simplependulum is double; its Vmax is also doubled.

(1) A (2) B (3) C (4) D

136. Assertion :- Transverse waves are possible inboth solids and fluids

Reason :- Transverse waves require rigidity inthe medium for the propagation.

(1) A (2) B (3) C (4) D

137. Assertion :- In glass, red light travels faster thanblue light.

Reason :- Red light has a wavelength longerthan blue.

(1) A (2) B (3) C (4) D

138. Assertion :- If a source of light is placed in frontof rough wall its image is not seen.

Reason :- The wall does not reflect light.

(1) A (2) B (3) C (4) D

139. Assertion :- Nuclear fusion reactions aredifficult to be carried out.

Reason :- Nuclear fusion requires high temperatureand it is difficult to attain such a high temperature.

(1) A (2) B (3) C (4) D

140. Assertion :- Nucleus contains no electrons butcan eject them.

Reason :- g - Rays are emitted by then excitedNuclei

(1) A (2) B (3) C (4) D

141. Assertion :- Among the halogens bond energyof F2 is minimum.

Reason :- Maximum lp – lp repulsion occursin F2 molecule.

(1) A (2) B (3) C (4) D

133. dFku :- nkc c<+kus ij cQZ dk xyukad ?kVrk gSA

dkj.k :- fi?kyus ij cQZ fldqM+rh gSA

(1) A (2) B (3) C (4) D

134. dFku :- ,d xSl ds v.kqvksa dh oxZ ek/; ewy pky ,oavf/kdre izkFkfed pky leku gksrh gSA

dkj.k :- xSl esa v.kqvksa dh pky ds fy, eSDlosy dk forj.klefer gskrk gSA

(1) A (2) B (3) C (4) D

135. dFku :- ljy yksyd dk vkorZdky dEiUu ds vk;ke ijfuHkZj ugh djrk gSA

dkj.k :- ;fn ljy yksyd dk vk;ke nqxquk dj fn;k tk;srks yksyd dk vf/kdre osx nqxquk gks tkrk gSA

(1) A (2) B (3) C (4) D

136. dFku :- Bksl rFkk æo esa vuqizLFk rjaxksa dh mRifÙk laHkogSAdkj.k :- vuqizLFk rjaxksa ds lapfjr gksus ds fy, ek/;e esalqn`<+rk vko';d gSA(1) A (2) B (3) C (4) D

137. dFku :- dkap esa uhys izdk'k dh rqyuk esa yky izdk'k rhozxeu djrk gSAdkj.k :- uhys izdk'k dh rqyuk esa yky izdk'k dh rjaxnSè;Zvf/kd gksrh gSA(1) A (2) B (3) C (4) D

138. dFku :- ;fn ,d [kqjnjh nhokj ij izdk'k Jksr ls izdk'kvkifrr fd;k tkrk gSA rks izfrfcEc ugha fn[kkbZ nsrkAdkj.k :- nhokj izdk'k dks ijkofrZr ugha djrhA(1) A (2) B (3) C (4) D

139. dFku :- ukfHkdh; lay;u vfHkfØ;k, cMh dfBukbZ lslEiUu gksrh gSAdkj.k :- ukfHkdh; ly;u ds fy, mPp rki dh vko';drkgksrh gS rFkk mPp rki mRiUu djuk dfBu gSA(1) A (2) B (3) C (4) D

140. dFku :- ukfHkd esa dksbZ bysDVªkWu ugha gksrs gSa ijUrq mUgs mRlftZrdj ldrk gSAdkj.k :- mRrsftr ukfHkd ls g-fdj.kksa dk mRltZu gksrkgSA(1) A (2) B (3) C (4) D

141. dFku :- gsykstuksa esa F2 dh ca/k ÅtkZ lcls de gSA

dkj.k :- lokZf/kd lp – lp izfrd"kZ.k F2 v.kq esa gksrkgSA

(1) A (2) B (3) C (4) D

0999DM610216003LATS-28/35


142. Assertion :- Shape of carbon sub oxide is zig-zag.

Reason :- Each central atom in carbon suboxide is sp-hybridised.

(1) A (2) B (3) C (4) D

143. Assertion :- All alkaline earth metals impartcolour to the flame.

Reason :- Their ionisation energies are low.

(1) A (2) B (3) C (4) D

144. Assertion :- Hexa aqua titanium(III) is purplein colour.

Reason :- It is due to intermolecular vibrations& presence of water molecules.

(1) A (2) B (3) C (4) D

145. Assertion :- PF3 is much better ligand thanphosphine

Reason :- Back bonding from F-atom isdecreasing the electron density on P-atom.

(1) A (2) B (3) C (4) D

146. Assertion :- Fluorine does not show oxidationnumber greater than zero.

Reason :- Rest halogens can show positiveoxidation states like +1, +3, +5 & +7.

(1) A (2) B (3) C (4) D

147. Assertion :- During froth floatation method,NaCN & CuSO4 are used as activator &depressant respectively.

Reason :- Use when 2 types of sulphide oresare present in same container.

(1) A (2) B (3) C (4) D

148. Assertion :- When lead storage battery ischarged H2SO4 is regenerated.

Reason :- As the following reaction occurs :2PbSO4(s) + 2H2O ® PbO2(s) + Pb(s) + 2H2SO4

(1) A (2) B (3) C (4) D

149. Assertion :– If temp does not effect the rate ofreaction Ea = 0.

Reason :– Lesser is the activation energyslower is the rate.

(1) A (2) B (3) C (4) D

150. Assertion :– pH of 10–8M HCl is not equal to 8.

Reason :– HCl does not dissociate properly invery dilute solution.

(1) A (2) B (3) C (4) D

142. dFku :- dkcZu lc vkWDlkbM dh vkd`fr ftx&tsxgSAdkj.k :- dkcZu lc vkWDlkbM dk izR;sd dsUnzh; ijek.kqsp-ladfjr gSA(1) A (2) B (3) C (4) D

143. dFku :- lHkh {kkjh; e`nk /kkrq,¡ Tokyk dks jax iznku djrhgSAdkj.k :- budh vk;uu ÅtkZ,¡ de gksrh gSA(1) A (2) B (3) C (4) D

144. dFku :- gsDlk ,Dok VkbVsfu;e(III) tkequh jax dkgSAdkj.k :- bldk dkj.k vUrjkf.od dEiUu rFkk ty v.kqvksadh mifLFkr gSA(1) A (2) B (3) C (4) D

145. dFku :- QkWLQhu dh rqyuk es a PF3 vPNk fyxs.MgSAdkj.k :- F-ijek.kq }kjk i'p vkca/ku ds dkj.k P-ijek.kqij bysDVªkWu ?kuRo ?kV tkrk gSA(1) A (2) B (3) C (4) D

146. dFku :- ¶yksjhu 'kwU; ls T;knk vkWDlhdj.k vad ugha n'kkZrkgSAdkj.k :- 'ks"k gsykstu /kukRed vkWDlhdj.k voLFkk tSls+1, +3, +5 rFkk +7 n'kkZrs gSaA(1) A (2) B (3) C (4) D

147. dFku :- >kx Iyou fof/k esa NaCN rFkk CuSO4 dks lfØ;dkjd rFkk leand ds :i esa (Øe'k%) mi;ksx djrsgSaAdkj.k :- tc 2 izdkj ds lYQkbM v;Ld ,d gh ik= esamifLFkr gksA(1) A (2) B (3) C (4) D

148. dFku :- tc lhlk lapk;d lsy dks vkosf'kr djrs gS rksH2SO4 iquthZfor gksrk gSAdkj.k :- lsy esa fuEu vfHkfØ;k gksrh gS2PbSO4(s) + 2H2O ® PbO2(s) + Pb(s) + 2H2SO4

(1) A (2) B (3) C (4) D

149. dFku :- ;fn rki vfHkfØ;k dh nj dks izHkkfor ugha djrkrks lfØ;.k ÅtkZ = 0 D;ksafddkj.k :- lfØ;.k ÅtkZ dk de eku vfHkfØ;k dksèkhek dj nsrk gSA(1) A (2) B (3) C (4) D

150. dFku :- 10–8 M HCl dk pH 8 ds cjkcj ughagSAdkj.k :- HCl vfr ruq foy;u esa fo;ksftr ugh gksrkA(1) A (2) B (3) C (4) D

LATS-29/350999DM610216003


151. Assertion :– DGmix < 0 and DSmix > 0 for an idealsolution.

Reason :– A... ...B interaction in an idealsolution are same as between A....A and B......Binteraction.

(1) A (2) B (3) C (4) D

152. Assertion :- A spectral line is seen for x y2p 2p-

transition.(For single e– specie)

Reason :- Energy is released when electronjumps from 2px to 2py orbital.

(1) A (2) B (3) C (4) D

153. Assertion : For fluorite structure, the F— ionsoccupy tetrahedral void and Ca+2 ions are inCCP.

Reason : The radius ratio of fluorite structureis 0.424.

(1) A (2) B (3) C (4) D

154. Assertion : In the following reaction.C(s)+O2(g)®CO2(g); DH = DE – RT

Reason : DH is related to DE by equation.DH = DE + Dng RT

(1) A (2) B (3) C (4) D

155. Assertion :- Acetophenone is more reactivethan Benzophenone towards Grignard reagent.

Reason :- Acetophenone shows tautomerism.

(1) A (2) B (3) C (4) D

156. Assertion :- Hydrolysis of vinyl acetate givesacetaldehyde and acetic acid.

Reason :- Reaction processed via electrophilicaddition.

(1) A (2) B (3) C (4) D

157. Assertion :- 1º and 2º amine can bedifferentiated by Hinsberg reagent.

Reason :- 1º amine gives salt with Hinsbergreagent.

(1) A (2) B (3) C (4) D

158. Assertion :- All +M groups are ortho/paradirecting group

Reason :- +M group increases electron densityat ortho/para.

(1) A (2) B (3) C (4) D

151. dFku :– vknZ'k foy;u ds fy;s DGmix < 0 ,oaDSmix > 0 gksrs gSA

dkj.k :– vkn'kZ foy;u esa A ,oa B v.kqvksa ds e/; yxusokyk vkd"kZ.k cy] A ,oa A rFkk B ,oa B ds e/; yxusokys vkd"kZ.k cy ds leku gksrs gSaA

(1) A (2) B (3) C (4) D

152. dFku :- 2px – 2py laØe.k ij LisDVªe esa 1 ykbu curh

gSA (,dy e– Lih'kh gsrq)

dkj.k :- 2px ls 2py laØe.k ds nkSjku ÅtkZ mRlftZr gksrhgSA

(1) A (2) B (3) C (4) D

153. dFku : ¶yksjkbV lajpuk esa F— vk;u prq"Qydh;fjfDr ?ksjrs gSa rFkk Ca+2 vk;u CCP esa mifLFkr gksrsgSaA

dkj.k : ¶yksjkbV lajpuk dk f=T;k vuqikr 0.424 gSA

(1) A (2) B (3) C (4) D

154. dFku : fuEu vfHkfØ;k es a C(s)+O2(g)®CO2(g);DH = DE – RT

dkj.k : DH, DE ls fuEu lehdj.k }kjk lEcfU/kr gSADH = DE + Dng RT

(1) A (2) B (3) C (4) D

155. dFku :- xzhU;kj vfHkdeZd ds izfr ,lhVksQhuksu dhfØ;k'khyrk cSUtksfQuksu ls vf/kd gksrh gSA

dkj.k :- ,lhVksfQuksu esa pyko;ork gksrh gSA

(1) A (2) B (3) C (4) D

156. dFku :- okbfuy ,lhVsV dk tyvi?kVu djus ij,flVSfYMgkbM ,oa ,flfVd vEy curk gSA

dkj.k :- vfHkfØ;k bysDVªkWu Lusgh ;k sxkRed gksrhgSA

(1) A (2) B (3) C (4) D

157. dFku :- 1º rFkk 2º ,ehu dks fglacxZ vfHkdeZd }kjk foHksndj ldrs gSaA

dkj.k :- 1º ,ehu fglacxZ vfHkdeZd ds lkFk yo.k nsrkgSA

(1) A (2) B (3) C (4) D

158. dFku :- lHkh +M lewg vkFkksZ@iSjk funsZ'kh lewg gksrsga SA

dkj.k :- +M lewg vkFkksZ@iSjk fLFkfr ij bysDVªkWu ?kuRo c<+krsgSaA

(1) A (2) B (3) C (4) D

0999DM610216003LATS-30/35


159. Assertion :- +CH –O–CH2 3 is more stable then

+CH –CH=O2

.

Reason :- Resonance in cation increasesstability.

(1) A (2) B (3) C (4) D

160. Assertion :- Reaction of methyl alcohol with1-chloro-1-phenyl ethane gives partiallyracemic mixture.

Reason :- Reaction is SN1 and product havechiral carbon.

(1) A (2) B (3) C (4) D

161. Assertion :- In sun-flower family petals aremodified in to pappus.

Reason :- Pappus helps in dispersal of flower.

(1) A (2) B (3) C (4) D

162. Assertion :- In fungi sexual apparatus decreasesin complexity from lower to higher forms.

Reason :- In algae, sexual apparatus increasesin complexity from simple to higher forms.

(1) A (2) B (3) C (4) D

163. Assertion :- Platyhelminthes are acoelomates.

Reason :- They have solid mesoderm.

(1) A (2) B (3) C (4) D

164. Assertion :- Plasmodesmata occurs amongstanimal cells.

Reason :- Cell membrane is quasifluid in nature.

(1) A (2) B (3) C (4) D

165. Assertion :- Grape mainly contains fructose.

Reason :- Fructose is called blood sugar.

(1) A (2) B (3) C (4) D

166. Assertion :- In living organisms respiratorysubstrate are often more than one.

Reason :- Pure proteins or fats are always usedas respiratory substrates.

(1) A (2) B (3) C (4) D

167. Assertion :- Tropical plants have a highertemperature optimum than the plants adaptedto temperate climate.

Reason :- The temperature optimum forphotosynthesis of different plants also dependsup on habitat that they are adapted to.

(1) A (2) B (3) C (4) D

159. dFku :- +CH –O–CH2 3 dk LFkk;hRo,

+CH –CH=O2 ls

vf/kd gksrk gSA

dkj.k :- dsVk;u esa vuqukn LFkk;hRo dks c<+krk gSA

(1) A (2) B (3) C (4) D

160. dFku :- 1-Dyksjks-1-Qsfuy ,Fksu dh fØ;k esFksuksy ls djusij vkaf'kd jsflfed feJ.k curk gSA

dkj.k :- vfHkfØ;k SN1 gS ,oa mRIkkn esa fdjSy dkcZugSA

(1) A (2) B (3) C (4) D

161. dFku :- lwjteq[kh dqy eas ny] isil eas :ikUrfjr gks tkrsgSAdkj.k :- isil] iq"i ds izfdZ.kZu eas lgk;rk djrs gSA(1) A (2) B (3) C (4) D

162. dFku :- dodks esa fuEu ls mPp dodksa esa ySafxd lajpukvksadh tfVyrk esa deh vkrh gSAdkj.k :- 'kSokyksa esa] ljy ls mPp :iks esa ySafxd lajpukvksadh tfVyrk esa o`f¼ gksrh gSA(1) A (2) B (3) C (4) D

163. dFku :- IysVhgsYfeUFkht ds lnL; esa nsgxqgk vuqifLFkr gksrk gSAdkj.k :- mueas Bksl e/;LFk peZ ik;k tkrk gSA(1) A (2) B (3) C (4) D

164. dFku :- thoæO; rarq tUrq dksf'kdk esa ik, tkrs gSaA

dkj.k :- dksf'kdk f>Yyh v/kZ rjy vO;w gSaA

(1) A (2) B (3) C (4) D

165. dFku :- vaxwj esa eq[;r% ÝDVkst gksrk gSAdkj.k :- ÝDVkst dks jDr 'kdZjk dgrs gSaA(1) A (2) B (3) C (4) D

166. dFku :- thfor thoksa esa çk;% 'olu fØ;k/kkj ,d ls vfèkdgksrs gSAdkj.k :- 'kq¼ olk vFkok çksVhu lnSo 'olu fØ;k/kkj ds:i esa dke esa yh tkrh gSaA(1) A (2) B (3) C (4) D

167. dFku :- 'khrks".k tyok;q esa vuqdwfyr ikniks dh vis{kk m".kdfVcU/kh; ikniks esa mfpr rkieku mPp gksrk gSA

dkj.k :- fHkUu ikniksa ds çdk'k l'ys"k.k ds fy, mfprrkieku] os ftl vkokl esa vuqdwfyr gS] ij Hkh fuHkZj djrkgSA

(1) A (2) B (3) C (4) D

LATS-31/350999DM610216003


168. Assertion : Small intestine is very long and hasplica circularis & villiReason : All these increase internal surface areaof small intestine for efficient food absorption.(1) A (2) B (3) C (4) D

169. Assertion : During diastole, ventricles receivesblood from auricles.Reason : During ventricular diastole (stage ofrapid inflow) the pressure inside auricles isgreater than ventricles.(1) A (2) B (3) C (4) D

170. Assertion :- The nerve impulse is conductedalong the axon membrane in the form of a waveof depolarisation and repolarisation.Reason :- Chemical involved in thetransmission of impulses at chemical synapseare called neurotransmitter(1) A (2) B (3) C (4) D

171. Assertion :- Pollen grain has a prominent twolayered wall, intine and exine.Reason :- Both has deposition of sporopollenin.(1) A (2) B (3) C (4) D

172. Assertion :- In plants, apomixis is a form of asexualreproduction that mimics sexual reproduction.Reason :- Apomixis involves the production ofseed without the fusion of gametes.(1) A (2) B (3) C (4) D

173. Assertion :- Females not participate in thedetermination of the sex of baby.Reason :- Human male is heterogametic.(1) A (2) B (3) C (4) D

174. Assertion :- Biocontrol refers to the use ofbiological methods for controlling plant pestReason :- In organic forming, these problemshave been tackled by the use of chemicals(1) A (2) B (3) C (4) D

175. Assertion :- The STR belongs to a class ofsatellite DNA referred to as mini-satelliteReason :- The mini-satellite number remainssame from chromosome in an individual(1) A (2) B (3) C (4) D

176. Assertion :- The choice of cry-gene dependsupon the crop & the targeted pestReason :- Gene cry I Ac & Cry II Ab controlthe cotton bollworms while cry I Ab controlscorn borer.(1) A (2) B (3) C (4) D

168. dFku : NksVh vka= vfèkd yEch gksrh gS rFkk bl ij fIydkljdqysfjl o jlkadqj ik;s tkrs gaSAdkj.k : ;s lHkh dkj.k i;kZIr ek=k esa Hkkstu ds vo'kks"k.kds fy;s NksVh vka= dk Hkhrjh lrg dk {ks=Qy c<+krs gSA(1) A (2) B (3) C (4) D

169. dFku : izlkj.k (Diastole) esa fuy; vkfyanks ls jDr izkIrdjrs gSaA

dkj.k : fuy; izlkj.k (Rapid inflow stage) esa vkfyanksads vanj ncko fuy;ksa ls vfèkd gksrk gSA

(1) A (2) B (3) C (4) D

170. dFku :- raf=dk{k f>Yyh dh lrg ij vkosxksa dk lapj.kfo/kzqohdj.k vkSj iqu%/kzqohdj.k ds :i esa gksrk gSA

dkj.k :- jklk;fud fluSIl ij vkosxks ds lapj.k es Hkkxysus okys jlk;u U;wjksVªkalehVj dgykrs gSA

(1) A (2) B (3) C (4) D

171. dFku :- ijkxd.k esa lqLi"V :i ls nks irksZ okyh fHkfÙk gksrhgS] vUr% pksy vkSj ckápksyAdkj.k :- nksuksa esa LiksjksiksfYuu dk fu{ksi.k gksrk gSA(1) A (2) B (3) C (4) D

172. dFku :- ikS/kks esa vlaxtuu] vySafxd çtuu dk ,d :igS tks ySafxd çtuu dk vuqdj.k djrk gSAdkj.k :- vlaxtuu ds fcuk ; q Xedks ds lay;u ds chtksa dkmRiknu gksrk gSA(1) A (2) B (3) C (4) D

173. dFku :- f'k'kq ds fyax fu/kkZj.k esa eknk dh dksbZ Hkwfedk ughagksrh gSaAdkj.k :- uj euq"; fo"ke;qXedh gksrk gSA(1) A (2) B (3) C (4) D

174. dFku :- ikni ihMdks ds fu;a=.k ds fy, tSo oSKkfudfof/k dk iz;ksx gh tSo fu;a=.k gSdkj.k :- vkWxsZfud d`f"k esa ;g leL;k,sa jlk;uksa dh lgk;rkls fu;af=r dh tkrh gS(1) A (2) B (3) C (4) D

175. dFku :- STR vuq"kaxh DNA ds ,d oxZ ls lacaf/kr gSftls mini-satellite dgrs gSAdkj.k :- mini-satellite dh la[;k fdlh O;fDr ds fofHkUuxq.klq=ksa esa leku jgrh gSA(1) A (2) B (3) C (4) D

176. dFku :- ØkbZ thu dk pquko Qly o fu/kkZfjr dhV ij fuHkZjdjrk gSA

dkj.k :- Cry I Ac o Cry II Ab thu dikl ds eqdqydfedks] tcfd cry I Ab eDdk Nsnd dks fu;af=r djrk gSA

(1) A (2) B (3) C (4) D

0999DM610216003LATS-32/35


177. Assertion :- Genetic drift operates in smallpopulation.Reason :- Genetic drift maintains geneticequillibrium in population(1) A (2) B (3) C (4) D

178. Assertion :- Active immunity is more durablebut passive immunity is fast.Reason :- Memory feed in both immunity butamount of antibodies more produced in passiveimmunity.(1) A (2) B (3) C (4) D

179. Assertion :- Depletion of ozone layer maycause cancer.Reason :- Ozone layer absorbs UV radiation.(1) A (2) B (3) C (4) D

180. Assertion :- Productivity generally increasesfrom polar regions toward the tropics.Reason :- It is due to increasing sunlight andtemperature toward the tropics.(1) A (2) B (3) C (4) D

181. Who translated the autobiography of MarieCurie in Hindi?(1) Lal Bahadur Shastri(2) Jawaharlal Nehru(3) Rajendra Prasad(4) S. Radha Krishnan

182. Which island is renamed as Abdul KalamIsland?(1) Elephant Island (2) Kadmat Island(3) Wheeler Island (4) Havelock Island

183. The Phrase "God's own country" is used to referwhich Indian state?(1) Odisha(2) Himachal Pradesh(3) Goa(4) Kerala

184. Which of the following states of India becamethe first carbon free state?(1) Gujarat(2) Arunachal Pradesh(3) Himachal Pradesh(4) Sikkim

185. Who is known as the Missile Woman of India?(1) Geeta Varadan(2) Tessy Thomas(3) M. Chandra Mohan(4) Saroj Kumari

177. dFku :- vkuqoaf'kd fopyu NksVh tula[;k ij ykxw gksrkgSAdkj.k :- vkuqoaf'kd fopyu tula[;k esa "vkuqoaf'kd lkE;"LFkkfir djrk gSA(1) A (2) B (3) C (4) D

178. dFku :- lfØ; izfrj{kk T;knk fVdkmG ij fuf"Ø; izfrj{kkrst gksrh gSAdkj.k :- izfrjf{k; Le`fr nksuks a izfrj{kkvksa esa ns[kh tkrh gSijUrq fuf"Ø; izfrj{kk esa ,UVhckWMh dh ek=k T;knk curhgSA(1) A (2) B (3) C (4) D

179. dFku :- vkstksu ijr ds vi?kVu ls dSalj gk s ldrkgSAdkj.k :- vkstksu ijr UV dks vo'kksf"kr djrh gSA(1) A (2) B (3) C (4) D

180. dFku :- /kz qoh; {ks=ks a ls mG".kdfVcfU/k; {ks=ksa dh vkSjmRikndrk lkekU;r;k c<+rh gSAdkj.k :- ;g mG".kdfVcfU/k; {ks=ksa dh vkSj izdk'k ,oa rkiekuds c<+us ls c<+rh gSA(1) A (2) B (3) C (4) D

181. eSjh D;wjh dh vkRedFkk dk fgUnh esa vuqokn fdlus fd;kFkk\(1) yky cgknqj 'kkL=h(2) tokgj yky usg:(3) jktsUnz izlkn(4) ,l- jk/kkd`".ku

182. fuEu esa fdl }hi dk uke ifjofrZr djds vCnqy dyke }hij[kk x;k gS\(1) ,fyQsUVk }hi (2) dn~er }hi(3) Oghyj }hi (4) gSoykWd }hi

183. okD;ka'k "Hkxoku dk viuk ns'k" fdl Hkkjrh; jkT; lslEcfUèkr gS\(1) vksfM'kk(2) fgekpy izns'k(3) xksok(4) dsjy

184. Hkkjr dk dkSulk jkT; izFke dkcZu eqDr jkT; cu x;kgS\(1) xqtjkr(2) v:.kkpy izns'k(3) fgekpy izns'k(4) flfDde

185. Hkkjr dh felkby owesu fdls dgk tkrk gS\(1) xhrk ojnku(2) Vslh FkkWel(3) ,e- pUnzk eksgu(4) ljkst dqekjh

LATS-33/350999DM610216003


186. Who is appointed as the head of the committeeformed by Supreme Court to run BCCI?(1) Diana Edulji(2) Vinod Rai(3) Ram Chandra Guha(4) Vikrama Limaye

187. Who wins the Australian Open Men's singlestitle in year 2017?(1) Andy Murray(2) Rafael Nadal(3) Novak Djokovic(4) Roger Federer

188. For which film Best Actress award is given inFilmfare awards 2017?(1) Dangal (2) Udta Panjab(3) Sultan (4) Pink

189. Name the programme, which has beenlaunched by Union Cabinet to make 6 crorerural household, Digitally literate, recently?(1) PMSBY (2) PMJDY(3) PMGSY (4) PMGDISHA

190. Name the person, who has received Nobel Prizein 2003 for the discovery of MRI scan, diedrecently?(1) Sir Brookes(2) Sir Peter Mansfield(3) Sir Richard(4) Sir Walter

191. Choose the word from the following that isnecessary for the given word "LAW"(1) Book (2) Court(3) Rule (4) Advocate

192. Find the term which does not fit into the seriesgiven below :G4T, J10R, M20P, P43N, S90L(1) G4T (2) J10R(3) M20P (4) P43N

193. If L stands for +, M stands for –, N stands for ×,P stands for ¸, then 14 N 10 L 42 P 2 M 8 = ?(1) 216 (2) 248(3) 251 (4) 153

194. In a certain code '786' means 'bring apple me','958' means 'cut green apple' and '645' means'bring green fruit' then which one of thefollowing is used for 'me'?(1) 5 (2) 6 (3) 7 (4) 8

186. loksZPp U;k;ky; }kjk Hkkjrh; fØdsV daVªksy cksMZ ds lapkyuds fy, cukbZ xbZ lfefr dk v/;{k fdls fu;qDr fd;k x;k gS\(1) Mk;uk bMqyth(2) fouksn jk;(3) jkepUnz xqgk(4) foØe fye;s

187. o"kZ 2017 esa vkLVªsfy;u vksiu iq:"k ,dy f[krkc fdlusthrk gS\(1) ,aMh ejs(2) jkQsy ukMky(3) uksokd tksdksfop(4) jsktj QsMjj

188. fQYeQs;j iqjLdkj 2017 esa loZJs"B vfHkus=h dk iq jLdkjfdl fQYe ds fy, fn;k x;k gS\(1) naxy (2) mM+rk iatkc(3) lqYrku (4) fiad

189. gky gh esa 6 djksM+ xzkeh.k ifjokjksa dks fMftVy f'k{kk iznkudjus ds fy, dsUnzh; eaf=eaMy }kjk 'kq: fd;s x;s dk;ZØedk uke D;k gS\(1) PMSBY (2) PMJDY(3) PMGSY (4) PMGDISHA

190. ,evkjvkbZ LdSu dk vkfo"dkj djus ds fy, o"kZ 2003 esaukscsy iqjLdkj izkIr djus okys oSKkfud dk gky gh esafu/ku gks x;kA mudk uke crkb;s\(1) lj czqDl(2) lj ihVj eSUlQhYM(3) lj fjpMZ(4) lj okYVj

191. fuEu esa ls og 'kCn pqfu;s tks fd fn;s x, 'kCn ^dkuwu* dsfy, vko';d gSA(1) iqLrd (2) U;k;ky;(3) fu;e (4) odhy

192. fuEu fodYiksa esa ls og in Kkr dhft, tks nh xbZ Js.kh esami;qDr ugha gS %G4T, J10R, M20P, P43N, S90L(1) G4T (2) J10R(3) M20P (4) P43N

193. ;fn L dk vFkZ + gS] M dk vFkZ – gS] N dk vFkZ × gS rFkkP dk vFkZ ¸ gS] rks 14 N 10 L 42 P 2 M 8 = ?(1) 216 (2) 248(3) 251 (4) 153

194. ;fn fdlh dwV Hkk"kk esa '786' dk vFkZ 'bring apple me'gS] '958' dk vFkZ 'cut green apple' rFkk '645' dk vFkZ'bring green fruit' gS rks fuEu esa ls dkSulh la[;k 'me'ds fy, iz;qDr gqbZ gS\(1) 5 (2) 6 (3) 7 (4) 8

0999DM610216003LATS-34/35


195. Find the missing character from among thegiven alternatives.

1 2 3

4 5 6

7 8 9

27 38 ?

(1) 49 (2) 50(3) 51 (4) 52

196. Which of the following is not associated withthe UNO ?(1) ILO (2) WHO(3) Security Council (4) ASEAN

197. Jallikattu is a bull-baiting sport played in :-(1) Andhra Pradesh (2) Tamilnadu(3) Karnataka (4) Kerala

198. Lakshya Sen is associated with which sports ?(1) Badminton (2) Cricket(3) Chess (4) Tennis

199. The book "The Man who became Khali" hasbeen authored by whom ?(1) Dalip Singh Rana (2) Shantanu Rai(3) Vinod Rai (4) Kapil Jain

200. Who was India's first Chief Election Commissioner?(1) Achal kumar Jyoti (2) Nasim Jaidi(3) Sukumar Sen (4) Navin Chawla

195. fn;s x;s fodYiksa esa ls yqIr la[;k Kkr dhft,A

1 2 3

4 5 6

7 8 9

27 38 ?

(1) 49 (2) 50(3) 51 (4) 52

196. fuEu esa ls dkSulk la;qDr jk"Vª la?k (UNO) ls lEcfU/kr ughagS\(1) ILO (2) WHO(3) lqj{kk ifj"kn (4) ASEAN

197. tYyhdV~Vw (,d cSy&mRihM+u [ksy) dgk¡ [ksyk tkrk gS\(1) vka/kz izns'k (2) rfeyukMq(3) dukZVd (4) dsjy

198. y{; lsu fdl [ksy ls lEcfU/kr gS\(1) cSMfeUVu (2) fØdsV(3) 'krjat (4) Vsful

199. "n eSu gw fcdse [kyh" iqLrd ds ys[kd dkSu gS\

(1) nyhi flag jk.kk (2) 'kkUruq jk;

(3) fouksn jk; (4) dfiy tSu

200. Hkkjr ds izFke eq[; pquko vk;qDr dkSu Fks\(1) vpy dqekj T;ksfr (2) ulhe tSnh(3) lqdekj lsu (4) uohu pkoyk

Your moral dutyis to prove that ALLEN is ALLEN

Your Target is to secure Good Rank in Pre-Medical 2017

LATS-35/350999DM610216003


SPACE FOR ROUGH WORK / jQ dk;Z ds fy;s txg

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LEADER TEST SERIES / JOINT PACKAGE COURSE · PDF file-4/35 LATS 0999DM610216003 Target : Pre-Medical 2017/AIIMS-MAJOR/09-04-2017 14. 10 m