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Laterally Loaded Piles Broms
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At z = 0 m bgl : p = 1.0×10 - 2×50 = -90.00 kN/m2
At z = 3.5 m bgl : p = 1.0×(10 + 3.5×19.8) - 2×50 = -22.68 kN/m2 < 0 MEFP governs
MEFP= 5z = 5×3.5 = 17.50 kN/m2
Ph = ½×17.5×3.5 = 30.63 kN/m × 1.5m = 45.95 kN/№
yh = ⅓ × 3.5 = 1.17 m
1.17ms = 19.8 kN/m
3
cu = 50 kN/m2
q = 10 kN/m2
(No access)
(From: CIRIA Special Publication 95, p. 36)
p = 17.5kN/m2
Ph = 46 kN
Actual Structure Calculation Model
(For soldier pile stability and integrity)
s = 19.8 kN/m3
cu = 50 kN/m2
D
The stability and integrity of the soldier piles will be assessed according to a laterally loaded pile
by the method of Broms (refer charts next page).
Apply factor by embedment, provide embedment length D = 1.2 × 3.4 = 4.08m
Required total length of soldier pile = 3.50 + 4.08 = 7.58 say 8.0m
□ DESIGN LOAD
FH = 46 kN/№ { Horizontal load }
e = 1.17 m { Load application from GL }ɣLf FH = 64.4 kN/№ (( ɣLf = 1.4 ))
□ PILE DATA
Pile Top Condition: FREE
Pile Size: H-200x200x8x12 (( Sx = 525 cm³ ))
My = py Sx = 144.375 kNm/№ (( py = 275 N/mm² ))
b OR d = 0.2 m { Breadth of pile }
D OR L = 3.4 m { Embedment of pile }
□ SOIL DATA
ɣs = 19 kN/m³ { Average unit weight of soil }
cu = 50 kN/m² { Ave undr shear strength }
□ CAPACITY AS SHORT PILE
▪ Ultimate Lateral Resistance in Cohesive Soils
(( L/d = 17 e/d = 5.85 ))
Hu,c / (cu d²) = 33.28 {Read from chart}
Hu,c = 66.57 kN/№
□ CAPACITY AS LONG PILE
▪ Ultimate Lateral Resistance in Cohesive Soils
(( My / (cu d³) = 360.9 e/d = 5.85 ))
Hu,c / (cu d²) = 45.18 {Read from chart}
Hu,c = 90.37 kN/№