At z = 0 m bgl : p = 1.0×10 - 2×50 = -90.00 kN/m2

At z = 3.5 m bgl : p = 1.0×(10 + 3.5×19.8) - 2×50 = -22.68 kN/m2 < 0 MEFP governs

MEFP= 5z = 5×3.5 = 17.50 kN/m2

Ph = ½×17.5×3.5 = 30.63 kN/m × 1.5m = 45.95 kN/№

yh = ⅓ × 3.5 = 1.17 m

1.17ms = 19.8 kN/m

3

cu = 50 kN/m2

q = 10 kN/m2

(No access)

(From: CIRIA Special Publication 95, p. 36)

p = 17.5kN/m2

Ph = 46 kN

Actual Structure Calculation Model

(For soldier pile stability and integrity)

s = 19.8 kN/m3

cu = 50 kN/m2

D

The stability and integrity of the soldier piles will be assessed according to a laterally loaded pile

by the method of Broms (refer charts next page).

Apply factor by embedment, provide embedment length D = 1.2 × 3.4 = 4.08m

Required total length of soldier pile = 3.50 + 4.08 = 7.58 say 8.0m

□ DESIGN LOAD

FH = 46 kN/№ { Horizontal load }

e = 1.17 m { Load application from GL }ɣLf FH = 64.4 kN/№ (( ɣLf = 1.4 ))

□ PILE DATA

Pile Top Condition: FREE

Pile Size: H-200x200x8x12 (( Sx = 525 cm³ ))

My = py Sx = 144.375 kNm/№ (( py = 275 N/mm² ))

b OR d = 0.2 m { Breadth of pile }

D OR L = 3.4 m { Embedment of pile }

□ SOIL DATA

ɣs = 19 kN/m³ { Average unit weight of soil }

cu = 50 kN/m² { Ave undr shear strength }

□ CAPACITY AS SHORT PILE

▪ Ultimate Lateral Resistance in Cohesive Soils

(( L/d = 17 e/d = 5.85 ))

Hu,c / (cu d²) = 33.28 {Read from chart}

Hu,c = 66.57 kN/№

□ CAPACITY AS LONG PILE

▪ Ultimate Lateral Resistance in Cohesive Soils

(( My / (cu d³) = 360.9 e/d = 5.85 ))

Hu,c / (cu d²) = 45.18 {Read from chart}

Hu,c = 90.37 kN/№