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Lab #2 Report due TODAY Individual Data Processing and Individual Write Up Lab #2 Report is due TODAY by midnight Answer Multiple Choice Questions ONLINE TODAY by midnight Answer Student Survey ONLINE TODAY by midnight Submit the Lab Report #2 in the drawer labeled “MECE204-Strength Lab” under M. E. Mail Folders

Lab #2 Report due TODAY

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Lab #2 Report due TODAY. Individual Data Processing and Individual Write Up Lab #2 Report is due TODAY by midnight Answer Multiple Choice Questions ONLINE TODAY by midnight Answer Student Survey ONLINE TODAY by midnight - PowerPoint PPT Presentation

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Page 1: Lab #2 Report due TODAY

Lab #2 Report due TODAY Individual Data Processing and

Individual Write Up Lab #2 Report is due TODAY by

midnight Answer Multiple Choice Questions

ONLINE TODAY by midnight Answer Student Survey ONLINE TODAY

by midnight Submit the Lab Report #2 in the drawer

labeled “MECE204-Strength Lab” under M. E. Mail Folders

Page 2: Lab #2 Report due TODAY

Torsion Testing Circular Cross-section Only Determine Material Properties in Torsion Draw Shear Stress-Strain Curve Ductile or Brittle Failure ? ASTM E-143 Test Method Compare results from Tensile, Poisson’s &

Torsion Test

Become familiar with Tinius Olsen Torsion Tester (10,000 in-lb capacity)

Page 3: Lab #2 Report due TODAY

Sign Convention

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Assumptions

Perfectly linear-elastic behavior Circular x-section (solid or hollow) Small rotations Constant length Constant diameter

Page 5: Lab #2 Report due TODAY

No deformation A highly

deformable member

A circular x-section

A grid of parallel circles and longitudinal lines on the outer surface

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After Deformation

Two torques are applied

Circles remain circles

Longitudinal lines become twisted

All angles are equal

End x-section remains flat

Page 7: Lab #2 Report due TODAY

Angle of Twist A prismatic circular

member Fixed at x = 0 Other end is FREE Loaded by a torque

at the free end Angle (x) - angle

of twist It depends on x:

/x=constant

Page 8: Lab #2 Report due TODAY

Shear Strain

Before After

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9

Shear Strain Distribution

max = c• max - occurs on the

outer surface• = (/c) max

• Result valid also for circular tubes within the material

• Valid for plastic deformation also

Page 10: Lab #2 Report due TODAY

Shear Strain Distribution

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Shear Strain & Angle of Twist

= * / L

max = * D / 2 / L

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12

Shear Stress Distribution - Elastic Deformation only

X-section: linear distribution Complimentary stresses in action Shear stress occur on axial planes (normal to the x-section

Page 13: Lab #2 Report due TODAY

Shear Stress & Torque- Linear Elastic Deformation Only

= T * / J

max = T * D / 2 / J

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Shear Stress-Strain Curve

max, rad

max, psi

Modulusof Rupture

Slope = = Shear Modulus, G

Figure 3.2 Typical shear stress-strain diagram from a Torsion Test

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Linear Elastic Region – Shear Modulus

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Failure Surface – Tensile Testing

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Failure Surface – Torsion Test

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Brittle Failure – Torsion Test

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Stresses on an Inclined Plane in an Axially Loaded Member Seek for equilibrium after

cutting along the oblique plane

n

P

NV

t

2sin)2/(sincos

)2cos1)(2/(cos

: )/ that note (and plane inclined on the

ly,respectivestresses,shear and normal the

obtain to with V and N Normalize

)cos(

:is plane inclined theof Area

)sin(:0

)cos(:0

xxnt

x2

xn

x

AP

A

AA

PVF

PNF

n

n

t

n

x

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Maximum Stress – Uniaxial Tension

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Comparing Tensile vs. Torsion Results

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Measuring Angle of TwistT=(R-R0)-(L-L0)

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Torsion Data Sheet

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Computing the Slip Angle

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Manually Recorded Data

R0

L0

T=(R-R0)-(L-L0)

slip= H-(LH/LT)T

cor = H - slip

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Shear Strain and Stress

=Radians(cor)*D/2/LH

=16T//D3

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Integrating Computer Data

slip= constant

cor=H - slip

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Selecting Computer Data

Head Angle = 30.00 deg

When Protractors taken OFF

Max Torque = 1931 in-lb

Page 29: Lab #2 Report due TODAY

Entire Stress Strain Curve

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Elastic Curve

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Proportional Limit

=G*

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Proportional Limit

Plot columns H, I, & J

Page 33: Lab #2 Report due TODAY

Key Ideas - Torsion Shear strain formula is valid in both

elastic & plastic region Torque formula is valid in linear

elastic region ONLY Thus, shear stress formula is valid

until proportional limit After proportional limit, shear stress

formula overestimates stress.

Page 34: Lab #2 Report due TODAY

Torsion Results

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Comparing Tensile vs. Torsion Results

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Comparing Lab 1, 2, & 3Experimental Results

Page 37: Lab #2 Report due TODAY

Lab #2 Report due TODAY Individual Data Processing and

Individual Write Up Lab #2 Report is due TODAY by

midnight Answer Multiple Choice Questions

ONLINE TODAY by midnight Answer Student Survey ONLINE TODAY

by midnight Submit the Lab Report #2 in the drawer

labeled “MECE204-Strength Lab” under M. E. Mail Folders