Upload
l-fattih-diwa-modeon
View
229
Download
0
Embed Size (px)
Citation preview
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
1/35
"Energi &Hukum I Termodinamika"
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
2/35
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
3/35
Step 1: Problem Statement
Tulus B.S. - Teknik Mesin USU3
In your own words,briefly state theproblem, the keyinformation given, and
the quantities to befound.
This is to make sure thatyou understand theproblem and theobjectives before youattempt to solve theproblem.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
4/35
Step 2: Schematic
Tulus B.S. - Teknik Mesin USU4
Draw a realistic sketch of the physical system involved, andlist the relevant information on the figure.
The sketch does not have to be something elaborate, but itshould resemble the actual system and show the key features.
Indicate any energy and mass interactions with thesurroundings.
Listing the given information on the sketch helps one to seethe entire problem at once.
Also, check for properties that remain constant during aprocess (such as temperature during an isothermal process),and indicate them on the sketch.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
5/35
Step 3: Assumptions and ApproximationsStep 4 : Physical Laws
State any appropriate assumptions andapproximations made to simplify theproblem to make it possible to obtain asolution.
Justify the questionable assumptions.
Assume reasonable values for missing
quantities that are necessary. For example, in the absence of specific
data for atmospheric pressure, it canbe taken to be 1 atm.
However, it should be noted in theanalysis that the atmospheric pressure
decreases with increasing elevation.
Apply all the relevant basic physicallaws and principles (such as theconservation of mass), and reducethem to their simplest form byutilizing the assumptions made.
However, the region to which a
physical law is applied must be clearlyidentified first. For example, theincrease in speed of water flowingthrough a nozzle is analyzed byapplying conservation of massbetween the inlet and outlet of thenozzle.
Tulus B.S. - Teknik Mesin USU5
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
6/35
Tulus B.S. - Teknik Mesin USU6
Step 5: Properties Determine the unknown properties
at known states necessary to solvethe problem from propertyrelations or tables.
List the properties separately, and
indicate their source, if applicable.
Step 6: Calculations Substitute the known quantities
into the simplified relations andperform the calculations todetermine the unknowns.
Pay particular attention to the units
and unit cancellations, andremember that a dimensionalquantity without a unit ismeaningless.
Also, dont give a false implicationof high precision by copying all the
digits from the screen of thecalculatorround the results to anappropriate number of significantdigits
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
7/35
Step 7 : Reasoning, Verification & Discussion
Tulus B.S. - Teknik Mesin USU7
Check to make sure thatthe results obtained arereasonable and intuitive,and verify the validity of
the questionableassumptions.
Repeat the calculations thatresulted in unreasonable
values. A step-by-step approach can greatlysimplify problem solving.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
8/35
Energi berasal dari bahasa Yunani :
energeia yang berarti aktivitas
energos yang berarti aktif
Energi merupakan suatu besaran fisik
skalar yang menggambarkan jumlah kerjayang dapat dilakukan oleh suatu gaya
Energi
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
9/35
Energi
The term energy wascoined in 1807 by ThomasYoung, and its use inthermodynamics was
proposed in 1852 by LordKelvin.
The term internal energy
and its symbol U firstappeared in the works ofRudolph Clausius andWilliam Rankine in thesecond half of thenineteenth century, andit eventually replacedthe alternative termsinner work, internal work,and intrinsic energycommonly used at thetime.
Tulus B.S. - Teknik Mesin USU9
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
10/35
Energi
Satuan SI untukenergi dan kerjaadalah joule (J)
Dinamakan untukmenghormati JamesPrescott Joule danpercobaannya dalam
persamaan mekanikpanas.
1 Joule = 1 newton
meter= 1kg m2 s2
Tulus B.S. - Teknik Mesin USU10
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
11/35
Bentuk Energi
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
12/35
Energi Dalam
Internal energy is representedby the symbol U, and thechange in internal energy in aprocess is U2 - U1.
The specific internal energy issymbolized by u orrespectively, depending onwhether it is expressed on a
unit mass or per mole basis.
The change in the totalenergy of a system is
Tulus B.S. - Teknik Mesin USU12
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
13/35
Energi Dalam When work is done to
compress a spring, energy
is stored within the spring. When a battery is charged,
the energy stored within itis increased.
When a gas (or liquid)initially at an equilibriumstate in a closed, insulatedvessel is stirred vigorously
and allowed to come to afinal equilibrium state, theenergy of the gas isincreased in the process.
Tulus B.S. - Teknik Mesin USU13
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
14/35
Energi Mekanis
Tulus B.S. - Teknik Mesin USU14
The mechanical energycan be defined as the
form of energy that can beconverted to mechanical
work completely anddirectly by an idealmechanical device such asan ideal turbine.
Kinetic and potentialenergies are the familiarforms of mechanicalenergy.
Thermal energy is notmechanical energy,however, since itcannot be converted
to work directly andcompletely (thesecond law ofthermodynamics).
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
15/35
Energi Kinetik & Potensial
The change in kineticenergy of the body is
The quantity mgz is thegravitational potentialenergy, PE.
The change in gravitationalpotential energy, is
Tulus B.S. - Teknik Mesin USU15
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
16/35
Energi Potensial
Gravitasi bumi, salah satu gaya yangmenimbulkan energi potensial. Energi potensial dari kereta roller
coaster akan maksimum saat beradapada lintasan tertinggi.
Tulus B.S. - Teknik Mesin USU16
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
17/35
Energy Transfer by Heat
Energi dapatberupa panas &kerja
Energy can cross the boundaries of a closedsystem in the form of heat and work.
Tulus B.S. - Teknik Mesin USU17
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
18/35
Temperaturedifference is thedriving force for heattransfer.
The larger thetemperaturedifference, the higheris the rate of heat
transfer.
Tulus B.S. - Teknik Mesin USU18
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
19/35
Proses Adiabatik
Tulus B.S. - Teknik Mesin USU19
A process during whichthere is no heat transferis called an adiabaticprocess.
The word adiabatic
comes from the Greekword adiabatos, whichmeans not to be passed.
There are two ways aprocess can beadiabatic: Either thesystem is well insulatedso that only a negligible
amount of heat can passthrough the boundary,or both the system andthe surroundings are atthe same temperatureand therefore there is
no driving force(temperaturedifference) for heattransfer.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
20/35
Tulus B.S. - Teknik Mesin USU20
During an adiabaticprocess, a systemexchanges no heatwith its surroundings.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
21/35
Proses Adiabatik
NO HEAT EXCHANGE : Q = 0
Q = U + W ; W = -U or U = -W
Work done at EXPENSE of internal energy
INPUT Work INCREASES internal energy
Work Out Work In
U +U
Q = 0
W = -U U = -W
Tulus B.S. - Teknik Mesin USU21
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
22/35
Energy Transfer by Work
Tulus B.S. - Teknik Mesin USU22
If the energy crossingthe boundary of aclosed system is notheat, it must be work.
The work done perunit time is calledpower and is denotedW
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
23/35
Tulus B.S. - Teknik Mesin USU23
Heat and work aredirectional quantities,and thus the completedescription of a heat or
work interactionrequires thespecification of boththe magnitude and
direction.Specifying the directions of heat and work
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
24/35
Example : Heating of a Potato in an Oven
Tulus B.S. - Teknik Mesin USU24
A potato initially atroom temperature(25C) is being bakedin an oven that is
maintained at 200C. Is there any heat
transfer during thisbaking process?
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
25/35
Solution
Tulus B.S. - Teknik Mesin USU25
Analysis : This is not a well-definedproblem since the system is notspecified.
Let us assume that we are observingthe potato, which will be our
system. Then the skin of the potato can be
viewed as the system boundary. Part of the energy in the oven will
pass through the skin to the potato. Since the driving force for this
energy transfer is a temperaturedifference, this is a heat transferprocess.
A potato is being baked inan oven.
It is to be determined
whether there is any heattransfer during thisprocess.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
26/35
Example : Burning of a Candle in an Insulated Room
Tulus B.S. - Teknik Mesin USU26
A candle is burning in a
well-insulated room.
Taking the room (the airplus the candle) as thesystem, determine
(a) if there is any heat transfer
during this burning process
and
(b) if there is any change in
the internal energy of the
system.
Solution : A candleburning in a well-insulatedroom is considered.
It is to be determined
whether there is any heattransfer and any change ininternal energy.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
27/35
Analisa
Tulus B.S. - Teknik Mesin USU27
Analysis (a) The interior surfaces of the
room form the systemboundary, as indicated by thedashed lines in Figure.
As pointed out earlier, heat isrecognized as it crosses the
boundaries.
Since the room is well insulated,we have an adiabatic system and
no heat will pass through theboundaries.
Therefore, Q= 0 for this process.
(b) The internal energy involvesenergies that exist in variousforms (sensible, latent,chemical, nuclear).
During the process just
described, part of the chemicalenergy is converted to sensibleenergy.
Since there is no increase ordecrease in the total internal
energy of the system, U = 0for this process.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
28/35
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
29/35
Shaft Work
Tulus B.S. - Teknik Mesin USU29
Shaft work is proportionalto the torque applied andthe number of revolutionsof the shaft.
Energy transmissionthrough rotating shafts iscommonly encountered inpractice
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
30/35
EXAMPLE Power Transmission by the Shaft of a Car
Tulus B.S. - Teknik Mesin USU30
Determine the power
transmitted through theshaft of a car when thetorque applied is 200 Nmand the shaft rotates at a
rate of 4000 revolutionsper minute (rpm).
Solution The torque andthe rpm for a car engineare given.
The power transmitted isto be determined.
Analysis A sketch of the car is given
in Figure. The shaft power is determined
directly from
Discussion Note that powertransmitted by a shaft isproportional to torque and therotational speed.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
31/35
Work Done to Raise or to Accelerate a Body
Tulus B.S. - Teknik Mesin USU31
When a body is raisedin a gravitationalfield, its potentialenergy increases.
Likewise, when abody is accelerated,its kinetic energyincreases.
The energy transferred to a body whilebeing raised is equal to the change inits potential energy.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
32/35
EXAMPLE Power Needs of a Car to Climb a Hill
Tulus B.S. - Teknik Mesin USU32
Consider a 1200-kg carcruising steadily on a levelroad at 90 km/h.
Now the car starts climbing a
hill that is sloped 30 fromthe horizontal .
If the velocity of the car is toremain constant during
climbing, determine theadditional power that must bedelivered by the engine.
Solution The power required toaccelerate a car to a specifiedvelocity is to be determined.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
33/35
Analisa & Diskusi
Tulus B.S. - Teknik Mesin USU33
Analysis
The work needed toaccelerate a body is simplythe change in the kinetic
energy of the body,
Discussion
This is in addition to thepower required toovercome friction, rollingresistance, and other
imperfections.
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
34/35
Electrical Energy
Tulus B.S. - Teknik Mesin USU34
8/10/2019 Kuliah - Energi & Hukum Pertama Termodinamika Bagian I - MHS_2
35/35
Bagaimana perbedaan energi dengan exergi ?
Tulus B S Teknik Mesin USU35