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Kinetics-2
13.4-13.6; 13.11; 13.141-December
Assigned HW13.22, 13.24, 13.26, 13.34, 13.36, 13.58, 13.62
Due: Monday 6-Dec
Lecture 33
1
Concentration vs. Time – 0th Order
2
0Akt
Arate
The rate of 0th order reactions are independent of concentration
Decreasing Concentration
aA Products
k
t
Arate
Time
[A]
Since the reaction rate does NOT change as [A] changes, [A] decreases linearly.
Slope = k
Concentration vs. Time – 1st Order
3
1Akt
Arate
The rate of 1st order
reactions are dependent on concentration
aA Products
As [A] decreases,
the rate decreases
Rea
ctio
n R
ate
Rate 1
Rate 2
Rate 3
Rate 1 > Rate 2 > Rate 3
Integrated Rate Law - st Order
4
1Akt
Arate
aA Products
kt
A
A
t
eAA
AktA
ktA
A
tkA
A
tkA
A
Akt
Arate
0
0
0
0
lnln
ln
0
Sample Problem
5
How long does it take for the concentration of A to decrease to 1.0% of its initial value in a the reaction (k = 1.0 Ms-1)
A Products
1. Determine the order of the reaction.
2. Use to solve for time. 001.0 AA
k
t
Arate
kt
AA
t
A
0
0
Sample Problem
6
How long does it take for the concentration of A to decrease to 1.0% of its initial value in a the reaction (k = 1.0 s-1)
A Products
1. Determine the order of the reaction.
2. Use to solve for time. 001.0 AA
Half Life for a 1st Order Reaction
7
How long does it take for the concentration of A to decrease to 50.0% of its initial value in a first order reaction.
A Products
05.0 AA
ktA
A
0
ln
kt
ktA
A
5.0ln
5.0ln
0
0
kt
2ln2/1
For a first order reaction, the time it takes for half of the
reactants to decompose to
products
The half life is INDEPENDENT of CONCENTRATION
for a 1st order reaction
Half Life for a 1st Order Reaction
8
A Products
kt
2ln2/1
Each t1/2 is the same for 1st order reactions.
Half Life for a 1st Order Reaction
9
A Products
kt
2ln2/1
The half life is ONLY dependent on k for a 1st order reaction
Half Life for a 1st Order Reaction
10
kt
2ln2/1
For the reaction: C2H6 2 CH3 k = 5.5 x 10-4 s-1
How long will it take for [C2H6] to fall to 1/16th it’s original concentration?
Half Life for a 1st Order Reaction
11
kt
2ln2/1
For the reaction: C2H6 2 CH3 k = 5.5 x 10-4 s-1
Calculate how long it will take for 1.5 M CH3 to be produced if the reaction begins with 1 M C2H6.
Concentration vs. Time – 2nd Order
12
2Akt
Arate
The rate of 2nd order reactions are dependent on
concentration
aA Products
Bigger k faster rate
Integrated Rate Law – 2nd Order
13
2Akt
Arate
aA Products
011
Akt
A
A couple math steps
Integrated Rate Law Summary
14
011
Akt
A
2Akrate Akratekrate
kteAA 0 0AktA
RateLaw
IntegratedRate Law
0th Order 1st Order 2nd Order
Rates and Temperature – the link to Thermodynamics
15
RT
EAk alnln
Arrhenius Equation
RT
Ea
Aek
Arrhenius parameters:
Temperature independent
A pre-exponential factorEa activation energy
Y-int = lnASlope = -Ea/R
Rates and Temperature – the link to Thermodynamics
16
RT
EAk alnln
Arrhenius Equation
RT
Ea
Aek
The rate constant for the decomposition of N2O5 at 45 °C is k = 5.1 x 10-4 s-1. Determine the value of the rate constant at 50 °C if the activation energy is 103 kJ mol-1.
Rates and Temperature – the link to Thermodynamics
17
RT
EAk alnln
Arrhenius Equation
RT
Ea
Aek
Arrhenius parameters:
Temperature independent
A pre-exponential factorEa activation energy
The reverse reaction has a much larger Energy Barrier (Ea)
Activation Energy and Catalysis
18