Jens Kleimann and Gunnar Hornig- Non-ideal MHD Properties of Magnetic Flux Tubes in the Solar Photosphere

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  • 8/3/2019 Jens Kleimann and Gunnar Hornig- Non-ideal MHD Properties of Magnetic Flux Tubes in the Solar Photosphere

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    Non-ideal MHD Properties of Magnetic

    Flux Tubes in the Solar Photosphere

    Jens Kleimann and Gunnar Hornig

    VW Group Presentation, February 22, 2002

    Topological Fluid Dynamics

    Theoretische Physik IV

    Ruhr-Universitat Bochum, Germany

    Talk basis:

    diploma thesis (April 1999 April 2000)

    publication: Solar Physics, 200: 47-62, 2001

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

    Page 2 of12

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    1. Introduction

    One major test case for MHD theory:

    The Sun

    Fundamental building blocks for surface structures:arching flux tubes with Binside Boutside.

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    Solar flux tubes are usually modelled usingideal MHD ( 0). This results in:

    Frozenness of field lines (plasma flowcannot cross tube surface)

    Iso-rotation: = 0 = t (v/r) B = 0

    (i.e., all field lines rotate rigidly.)

    B field may get wound up infinitelyby convective footpoint motion:

    =

    Settings of this type are particularly relevant in the framework oftopological dissipation (Parker 1972).

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    but:

    Photospheric temperature is too low for sufficient ionisation! A pronounced non-ideal layer is present!

    For = 0, we have: For = 0, we expect:

    Tube interior is isolated Infinite twist/no static solution

    Iso-rotation

    Mass exchange through surface Finite twist at steady state

    ???

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    2. Question and Strategy

    Question:

    Which changes of the tube properties are induced by thenon-ideal layer as compared to the ideal case?

    Method:

    Use given temperature variation with

    height to derive resistivity profile

    Compute a flux tube model using re-sistive MHD, focusing on one footpointonly

    Impose stationary footpoint vortexwhile summit is held fixed

    B field gets wound up, but slippagewill keep the resulting twist finite.

    ...and of course: Try to keep it SIMPLE!

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    3. Set of MHD Equations

    t v + (v ) v = P +j B + gt +

    ( v) = 0

    j = E + v B E = t B B = j B = 0

    Simplifications made:

    stationary solutions t = 0 E =:

    v vA := B/ neglect inertia term against induction. restriction to one single footpoint implies axial symmetry = 0 in

    cylindrical coordinates [r,,z].

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    4. Resistive Inflow

    Let

    Bp := poloidal Part ofB andv := flow across tube surface.

    Then Ohms law

    + v B =

    B

    yields:

    v =(x)

    BP ( BP)BP2

    Flow properties:

    proportional to (cf. ideal case) independent of Bs direction and strength (B B leaves v unchanged) v e < 0 ( inflow!) in the generic case where (Bp/Bp) is small. take R as tubes radius v 1/R Total mass inflow indep. of R !

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    5. Quantifying

    From now on: assume cylindrical tube geometry (i.e., no change of cross sectionwith height.) Justified by

    (h)nonideal layer tube height and observation of coronal loops.

    Since = (z) and = (z), B can be shown to be force-free: j B = 0 .

    Simple solution (with x := r/R)

    Bff = B0

    0,

    x

    1 + x2,

    1

    1 + x2

    Resistivity (z) fitted according toVAL reference atmosphere; Density (z) decays exp(z/H).

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    Question and Strategy

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    Resistive Inflow

    Quantifying

    Summary

    Appendix

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    Total inflow M :=

    ( v) da 2 108 kg/s

    Timescale :=Mtot

    M

    70 hR

    100 km2

    Toroidal slippage (contours of v): Scaling: v vs. vA, R {1, 2,...20km}

    = 0 z(v/r) = 0 (cf. iso-rotation)

    Footpoint vortex (cut along z = 0): v(x, 0)130 m/s

    R

    100 km

    2x

    (1 + x2).

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    Introduction

    Question and Strategy

    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

    Title Page

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    6. Summary

    Ohms law enforces an inflow of fluid towards loci of higher field strength,which is independent of

    the presence of additional forces (e.g. gravity) the tubes cross section and

    the strength and direction of its B field.

    Since v , this inflow occurs wherever the tube penetrates the coolphotospheric layer, in particular near the tubes footpoints.

    A static flux tube of cylindrical shape has to be force-free if the ambientplasma temperature is horizontally stratified.The introduction of a resistive layer allows for stationary MHD solutions withfinite field twist and yields a marked deviation from the iso-rotational ruleknown from ideal MHD.

    Although the flow magnitudes scaling law makes these effects possibly eithertoo small or too slow to be detected by (present) solar observations, they

    may play an important role for small-scale structures such as the magneticcarpet.

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    Set of MHD Equations

    Resistive Inflow

    Quantifying

    Summary

    Appendix

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    7. Appendix

    References: Vernazza, Avrett & Loeser: 1981, ApJ Supp. 45, 635

    Kubat & Karlicky: 1986, Ast. Inst. Czech. Bull. 37, 155

    Counterexample for OutflowSetting

    Bsp. :=cosh z

    1 + (r cosh z)2

    r sinh z, 0, cosh z

    tube profile R(z) = 1/ cosh(z)

    field drops as Bsp.z=0 1/(1+r2)

    but: (j

    B)sp.

    =

    P

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    Quantifying

    Summary

    Appendix

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    The Magnetic Carpet

    Potential-field predictions for the structure of the magnetic field using data forthe magnetic data from SOHO/MDI, compared to the heating. Black/white

    indicating polarity, underlying image: brightness observed at the same timeby SOHO/EIT at 195 Angstroms, with bright green corresponding to hotand dense regions and dark green corresponding to cooler ones.

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