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CHEMISTRY Analysis
Sl.No. UNIT NAME Q. Nos. Correct Wrong
1. ATOMIC STRUCTURE 90
2. PERIODIC TABLE 64
3. CHEMICAL BONDING 72
4. STATES OF MATTER 61
5. STOICHIOMETRY 79
6. THERMODYNAMICS 66
7. CHEMICALAND IONIC EQUILIBRIUM 67
8. HYDROGENAND ITS COMPOUNDS 62
9. ALKALI AND ALKALINE EARTH METALS 84
10. P-BLOCK ELEMENTS ( BORON, CARBON FAMILY)
11. PRACTICAL CHEMISTRY 78
12. ENVIRNMENTAL CHEMISTRY 65
13. ORGANIC CHEMISTRY 68
14. HYDRO CARBONS 77, 81
15. SOLID STATE
16. SOLUTIONS 85
17. ELECTROCHEMISTRY 89
18. SURFACE CHEMISTRY 69
19. METALLURGY 74
20. OXYGEN FAMILY
21. NITROGEN FAMILY 80, 86
22. HALOGEN FAMILY
23. D & F-BLOCK ELEMENTS, COORDINATION COMPOUNDS 86, 83, 88
24. POLYMERS 75
25. BIOMLECULES 73
26. CHEMISTRY IN EVERY DAY LIFE 71
27. ORGANIC COMPOUNDS CONTAINING C, H AND O
28. ORGANIC COMPOUNDS CONTAINING NITROGEN 63
29. INERT GASES
30. HALO ALKENES 8231. PURIFICATION AND ANALYSIS ORG COMPOUNDS 70
32. CHEMICAL KINETICS 87
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[CODE - H]
61. Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure ip and temperature
1T are connected through a narrow tube of negligible volume as shown in the figure below. The
temperature of one of the bulbs is then raised to 2.T The final pressure fp is:
1)2
1 2
2 i
Tp
T T
+
2)1 2
1 2
2 i
TTp
T T
+
3)1 2
1 2i
TTp
T T
+
4)1
1 2
2 i
Tp
T T
+
Sol : 1
1 1 2 1 2
f fi if
p V p VpV pV V Vp
T T T T T
+ = + = +
1 2
1 1 2
2 if
pV TV T Vp
T TT
+=
1 2
1 1 2
2.i
f
p TTp
T T T= ×
+
2
1 2
2f i
Tp p
T T
= +
62. Which one of the following statements about water is FALSE?
1) There is extensive intramolecular hydrogen bonding in the condensed phase.
2) Ice formed by heavy water sinks in normal water.
3) Water is oxidized to oxygen during photosynthesis.
4) Water can act both as an acid and as a base.
Sol : 1
Intermolecular H - bond is present
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63. In the Hofmann bromamide degradation reaction, the number of moles of NaOH and 2Br used per
mole of amine produced are:
1) Two moles of NaOH and two moles of 2Br
2) Four moles of NaOH and one mole of 2Br
3) One moles of NaOH and one mole of 2Br
4) Four moles of NaOH and two moles of 2Br
Sol : 2
2 2 2 2 3 24 2 2R CONH NaOH Br RNH Na CO NaBr H O− + + → + + +
64. Which of the following atoms has the highest first ionization energy?
1) K 2) Sc 3) Rb 4) Na
Sol : 2
419 /K kJ mole→
631 /Sc kJ mole→
403 /Rb kJ mole→
496 /Na kJ mole→
65. The concentration of fluoride, lead, nitrate and iron in a water sample from an underground lake wasfound to be 100 ppb, 40 ppb, 100 ppm and 0.2 ppm, respectively. This water is unsuitable for drinkingdue to high concentration of:
1) Nitrate 2) Iron 3) Fluoride 4) Lead
Sol : 1
Nitrate → Upto 50 ppm, it is safe
66. The heats of combustion of carbon and carbon monoxide are 1393.5 and 283.5 kJ mol ,−− −respectively. The heat of formation (in kJ) of carbon monoxide per mole is:
1) -676.5 2) -110.5 3) 110.5 4) 676.5
Sol : 2
( )21/ 2 ! 1C O CO H+ → ∆ = →
( )2 2 393.5 kJ/mole 2C O CO H+ → ∆ = − →
( )2 2
1283.5 kJ/mole 3
2CO O CO H+ → ∆ = − →
( ) ( ) ( )1 2 3Eq Eq Eq= −
( )393.5 283.5 110.5 kJH∆ = − − − = −
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67. The equilibrium constant at 298 K for a reaction is 100.A B C D+ + If the initial concentration
of all the four species were 1 M each, then equilibrium concentration of D ( )1in mol L− will be:
1) 1.818 2) 1.182 3) 0.182 4) 0.818
Sol : 1
A B C D+ +
1 1 1 1x x x x− − + +
( ) ( )( ) ( )1 1
1001 1c
x xK
x x
+ += =
− −
110
1
x
x
+ =−
1 10 10x x+ = −
11 9x =
9 /11 0.818x = =
[ ] 1 1.818D x= + =
68. The absolute configuration of is
1) (2S, 3S) 2) (2R, 3R) 3) (2R, 3S) 4) (2S, 3R)
Sol : 4
2
14
3
OH
CH3
Cl
H
H
COOH
2
2
3
4 4
OH
CH3
Cl
H
H
COOH
2
2S 3R
2S, 3R
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69. For a linear plot of log (x/m) versus log p in a Freundlich adsorption isotherm, which of the followingstatements is correct? (k and n are constats)
1) Only 1/n appears as the slope 2) log (1/n) appears as the intercept
3) Both k and 1/n appear in the slope term 4) 1/n appears as the intercept
Sol : 1
1/nx k pm =
1log log logx P km n= +
Slope 1n=
70. The distillation technique most suited for separating glycerol from spent-lye in the soap industry is :
1) Steam distillation 2) Distillation under reduced pressure
3) Simple distillation 4) Fractional distillation
Sol : 2
71. Which of the following is an anionic detergent?
1) Cetyltrimethyl ammonium bromide 2) Glyceryl oleate
3) Sodium stearate 4) Sodium lauryl sulphate
Sol : 4
72. The species in which the N atom is in a state of sp hybridization is :
1) 3NO− 2) 2NO 3) 2NO+ 4) 2NO−
Sol : 3
hybrid orbitals ( )15 1 2
2sp= − = ⇒
73. Thiol group is present in :
1) Cystein 2) Methionine 3) Cytosine 4) Cystine
Sol : 1
2
2
|
|
SHCH
H
H N C COOH
−
− −
74. Which on of the following ores is best concentrated by froth floatation method?
1) Galena 2) Malachite 3) Magnetite 4) Siderite
Sol : 1
Galena (PbS)
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75. Which of the following statements about low density polythene is FALSE?
1) Its synthesis requires dioxygen or a peroxide initiator as a catalyst.
2) It is used in the manufacture of buckets, dust-bins etc.
3) Its synthesis requires high pressure.
4) It is a poor conducotor of electricity.
Sol : 2
HDFE in used to prepare buckets, dustbins
76. Which of the following compounds is metallic and ferromagnetic?
1) 2VO 2) 2MnO 3) 2TiO 4) 2CrO
Sol : 4
77. The product of the reaction given below is:
1) 2)
3) 4)
Sol : 4
NBS/hv H O/K CO2 2 3
Bv OH
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78. The hottest region of Bunsen flame shown in the figure below is:
1) region 3 2) region 4 3) region 1 4) region 2
Sol : 4
Region - 2 in the figure is the hottest region
79. At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 220%O by
volume for complete combustion. After combustion the gases occupy 330 mL. Assuming that thewater formed is in liquid form and the volumes were measured at the same temperature and pressure,the formula of the hydrocarbon is :
1) 4 8C H 2) 4 10C H 3) 3 6C H 4) 3 8C H
Sol : 4
80. The pair in which phosphorous atoms have a formal oxidation state of + 3 is :
1) Orthophosphorous and hypophosphoric acids
2) Pyrophosphorous and pyrophosphoric acids
3) Orthophosphorous and pyrophosphous acids
4) Pyrophosphorous and hypophosphoric acids
Sol : 3
Orthophosphorous acid 3 3H PO=
||
|OH
O
HO P H− − oxidation state of “P” = +3
Pyrophosphorous acid 4 2 5H P O=
|| ||
| |
O O
H H
HO P O P OH− − − − oxidation state of " " 3P = +
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Pyrophosphoric acid 4 2 7H O O
5|| ||
| |
O O
OH OH
H O P O P O H P− − − − − − = +
Hypophosphoric
4|| ||
| |
O O
OH OH
H O P P O H P− − − − − = +
81. The reaction of propene with HOCl ( )2 2Cl H O+ proceeds through the intermediate :
1) ( )3 2CH CH OH CH +− − 2) 3 2CH CHCl CH +− −
3) 3 2CH CH CH OH+− − − 4) 3 2CH CH CH Cl+− − −
Sol : 4
3 2CH CH CH HOCl− = +
3 2CH CH CH Cl
OH
⊕
−
− − −
↓
3 2|OH
CH C H CH Cl− − −
Hence3 2CH CH CH Cl
⊕− − −
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82. 2-chloro-2-methylpentane on reaction with sodium methoxide in methanol yields :
a) 2 5 2 3
3
3
|
|
CH
CH
C H CH C OCH− b)2 5 2 2
3
|CH
C H CH C CH=
c)2 2 3
3
|CH
C H CH C CH= −
1) (c) only 2) (a) and (b) 3) All of these 4) (a) and (c)Sol : 1
3 2 2 3
3
|
|
Cl
CH
CH CH CH C CH− − − − 3
3
CH ONa
CH O−
3 2 3
3
|CH
CH CH CH C CH− = −
3CH O− is a strong base and alkyl halide is tertiary hence keeping energy parameter product
formed is
3 2 3
3
|CH
CH CH CH C CH− = −
83. Which one of the following complexes shows optical isomerism?
1) ( ) 22trans Co en Cl Cl 2) ( )3 24
Co NH Cl Cl
3) ( )3 33Co NH Cl 4) ( ) 22
cis Co en Cl Cl (en = ethylenediamine)
Sol : 4
( ) 22M a a b−
c is
trans
( ) 22opticaly active c is .Co en Cl Cl →
( )2opticaly inactive trans c is .Co en Cl Cl →
trans4 2Ma b
( )3 24is optically inactive Co NH Cl
( )3 24Optically inactive Co NH Cl
( )3 3 3 33 is always inactiveMa b Co NH Cl
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84. The main oxides formed on combustion of Li, Na and K in excess of air are, respectively :
1) 2 2 2 2 2, andLi O Na O KO 2) 2 2 2 2, andLi O Na O KO
3) 2 2 2, andLi O Na O KO 4) 2 2 2 2, andLiO Na O K O
Sol : 2
2Li O+ excess 2Li O
2 2 22Na O Na O+ −
2 2K O KO+ −
85. 18 g glucose ( )6 12 6C H O is added to 178.2 water. The vapour pressure of water (in torr) for this
aqueous solution is :
1) 752.4 2) 759.0 3) 7.6 4) 76.0
Sol : 1
180.1
180= 178.2
9.918
=
2
18 180760
18 178.2180 18
H OP
= × +
0.1 1760 760 7.6
0.1 9.9 100= × = × =
+
760 7.6 752.4P = − =86. The reaction of zinc with dilute and concentrated nitric acid, respectively, produces :
1) 2 andNO N O 2) 2 2 andNO N O 3) 2 2 andN O NO 4) 2 andNO NO
Sol : 3
With conc 3HNO
[ ]3 2 22 2 0HNO H O NO→ + +
[ ]0Zn ZnO+ →
( )3 3 222ZnO HNO Zn NO H O+ → +
( )3 3 2 224 2 2HNO Zn Zn NO NO H O+ → + +
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With dil 3HNO
[ ]3 2 22 4 0HNO N O H O→ + +
[ ]0Zn ZnO+ → 4
( )3 3 234 2ZnO HNO Zn NO H O + → +
( )3 2 2 3 24 10 5 4Zn HNO N O H O Zn NO+ → + +
87. Decomposition of 2 2H O follows a first order reaction. In fifty minutes the concentration of 2 2H O
decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of 2 2H O
reaches 0.05 M, the rate of formation of 2O will be :
1) 12.66 L min at STP− 2) 2 11.34 10 mol min− −×
3) 2 16.93 10 mol min− −× 4) 4 16.93 10 mol min− −×
Sol : 4
0.5 0.25 0.125− −
1/22 0.50 mint= =
1/2 25 mint =
1/2
0.693K
t=
Rate0.693
0.0525
= ×
0.6935
25= × 210−×
Rate20.693
105
−= ×
2 2 2 2
1
2H O H O O→ +
OR
2 2 2 22 2H O H O O→ +
( ) [ ]22 21
2
d Od H O
dt dt− =
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[ ]2 21 0.69310
2 5
d O
dt−= + × ×
20.69310
10−= ×
30.693 10−= ×46.93 10−= ×
88. The pair having the same magnetic moment is :
[ ]At. No. : 24, 25, 26, 27Cr Mn Fe Co= = = =
1) ( ) ( )2 2
2 26 6 andMn H O Cr H O
+ + 2) [ ] ( ) 22
4 2 6 andCoCl Fe H O
+−
3) ( ) [ ]2 2
2 46 andCr H O CoCl
+ − 4) ( ) ( )2 2
2 2 66 andCr H O Fe H O
+ + Sol : 4
[ ] 5 23 4Mn Ar d s=
[ ]2 53Mn Ar d+ 2H O Weak field ligend
35⇒ =
[ ] 5 13 4Cr Ar d s=
[ ]2 43Cr Ar d+ = 2H O Weak field ligend
24 =
[ ] 7 23 4Co Ar d s= 2H O Weak field ligend
[ ]2 73 15Co Ar d + = =
[ ] 6 23 4Fe Ar d s= 2H O Weak field ligend
[ ]2 63Fe Ar d+ = 24 =
( ) ( )2 2
2 26 6 andCr H O Fe H O
+ + ⇒
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89. Galvanization is applying a coating of :
1) Cu 2) Zn 3) Pb 4) Cr
Sol : 2
Zn
90. A stream of electrons from a heated filament was passed between two charged plates kept at apotential difference V esu. If e and m are charge and mass of an electron, respectively, then the value
of /h (where is wavelength associated with electron wave) is given by :
1) meV 2) 2meV 3) meV 4) 2meV
Sol : 2
2
h hKE eV
mV mKE = = =
2
h
meV⇒ =
2
h
meV =
2h
meV
⇒ =