Integrating Vector Particle Physics with the Dodecahedron Quark Ball and the Octahedral Hexagonal Fractal ©WRHohenberger 1992-2013 By William R Hohenberger

Integrating Vector Particle Physics with the Dodecahedron Quark Ball and the Octahedral

Hexagonal Fractal

©WRHohenberger 1992-2013

By William R HohenbergerNatural Philosophy Alliance

April 6, 2013Internet Video Presentation

Table of ContentsPart 1 – The Electromagnetic Wave

Part 2 – The Octahedral Hexagonal Fractal

Part 3 – Electron Cube Vs Octahedral Hexagonal Fractal

Part 4 – Other Considerations

Part 5 – Summary


1. There is an aether that pervades all of the spaces within the universe including both the material and the nonmaterial worlds. Therefore, aether is a real substance!!!

2. Aether is a hyper-dynamic, non-homogeneous, elastic substance that contians a myriad of plethora's of various field structures, as holistic arrays of constantly changing motions and structures. I describe them as Field Vector Arrays.

3. Aether has a fine structure within which the smallest electromagnetic wave or highest frequency that can be manifested is directly related to or is a derivative of Planck's Length. I use the name ‘energy cell’ or ‘Aetheron’.

4. The electromagnetic wave is a rotating oscillating system within the aether with up to three generations of concentric waves. Of prime importance is the two generational dual concentric wave.

5. Assuming that aether is an elastic continuum, then whatever occurs in the inner (light) wave, the opposite must occur in the outer (dark) wave. This is a mechanical Universe.

6. Particles are fractal structures condensed from individual energy cells (aetherons) that are built from scalar multiples of the smallest electromagnetic wave at Planck's Frequency. Therefore, particles are condensed aether(ons).

Some Basic Rules & Assumptions



Part 1The

Electromagnetic Wave

Static Energy (potential energy – zero velocity) Dynamic Energy (kinetic energy)

Pendulum Left Side Height of Pendulum Forward Velocity – No Static EnergyRight Side Height of Pendulum Reverse Velocity – No Static Energy

Water Wave Positive Height of water Forward Circular Motion of WaterNegative Height of water Backwards Circular Motion of Water

Clock Timing Spring Tension of spring – No velocity Forward Velocity of Rotational Mass(rotary oscillating system) Compression of spring – No velocity Reverse Velocity of Rotational Mass

(Electrostatic Energy – Charge) (Electromagnetic Energy - Motion)Electromagnetic Wave Tension of Aether – No aethereal velocity Forward Rotation of Aethereal Mass(rotary oscillating system) Compression of Aether – No aethereal velocity Reverse Rotation of Aethereal Mass

Various Oscillating Systems


Eq. 7.2 S = 0.5 (E x H)

Eq. 7.3 S = 0.5 [(sin⋅ φ⋅E) (sin⋅ φ⋅H) + (cosφ⋅H) (cos⋅ φ⋅E)]

Lockyer’s SummaryA vector structure for the photon has been deduced that explains all of the questions raised by the paradox of electric E and magnetic H field strengths showing a paradoxical in-phase (sine/sine) that would not result in a lossless transport of the photon’s stored energy. The traveling wave of electromagnetic energy was shown to be the symbiosis of two conjugate resonances, and the paradoxes were explained logically by using a trigo-nometric identity (sin2φ + cos2φ =1) .

Chapter 7 - ENERGY (PHOTON) STRUCTURE

Equation 7.2 gives the classic sinusoidal Poynting vector S effective power density value at a single peak value, but does not show the correct nature of the photon, over all cycle time. The correct sinusoidal mathematics that describes the above graphics is given in the trigonometric identity, Equation 7.3; Equation 7.3 gives the same effective value, as Equation 7.2, for the S Poynting vector, but uses the correct photon conjugate vector structure. From Tom Lockyer’s VPP, Pages 65 & 68

In Figure 7.1, the traveling wave appears, to our relativistic distorted view, to be in phase (100 percent power factor) on account of the time coincidence, between the E and H peak values. This (100 percent power factor) is not reality, because the vacuum is reactive, making the Poynting vectors E and H time coincidence inconsistent with the required (sine/cosine) reactive relationship. Also, in violation of nature, the energy seems to disappear, as E and H go to zero twice each cycle in the traveling wave. This energy disappearance is not natural, the photon energy is known to be continuous, not discontinuous as it appears, when viewed from our stationary frame of reference. Refer to Figure 7.1, the traveling wave paradox, of lost energy twice each cycle, as E and H identically pass through zero, is explained by using two conjugate resonances. The photon is a symbiosis of (two) E to H and H to E resonances combined into the axial (S) vector. This symbiosis not only gives the lateral (sine/sine) power factor but also gives the axial (cosine/cosine) loss-less resonances from each conjugate, separately, effectively storing the energy resonantly. Lateral events are not distorted by relativistic effects, so we do see the lateral E, H as they appear in both the stationary view and the relativistic view of the Poynting vector, as (sine/sine). The Lorentz-Fitzgerald contraction makes (S) appear to be zero briefly, from our stationary frame of view. Thus relativity modifies the classical equation for photon power density given in (Equation 7.2) into that shown in (Equation 7.3.)

From Tom Lockyer’s VPP, Pages 65 & 66

Lockyer’s Explanation of Sine/Sine Paradox

360° Graph of an Electromagnetic

Wave

©WRHohenberger 1992-2013©WRHohenberger 1992-2013


Wave



1st Generation EM Wave – (The Inner Light Wave)

LIGHT WAVE


DARK WAVE

2nd Generation EM Wave – (The Outer Dark Wave)


Combined Concentric Light & Dark 2nd Generation EM Wave


Wave


Quark Ball with a Baryon Octet

Spin Vectors

Method for Developing the DBQ Dodecahedron

Quark Ball

Dodecahedron Quark Ball

Baryon Octet


Baryon Octet & Decuplet FamiliesMeson Family

Baryon Decuplet

Baryon Octet

DBQ Dodecahedron Quark Ball Particle Correlations


Poynting Vector Relationship to Dual Concentric Waves

From Tom Lockyer’s VPP, Page 71


Vector Development

©WRHohenberger 1992-2013From Tom Lockyer’s VPP

Vector Analysis


Constructing an Octahedron

VPP Electron CubeCompared to DBQ



Transposition Graphs






Electromagnetic Photon Stores Energy ResonantlyThe photon resonant structure conserves and transports energy over vast distances, in the vacuum of space, with no apparent losses. (Rather than tired light, the red shift is thought to be a Doppler effect from an expanding universe.) The energy is alternately stored in the inductance (L = μo λ ) and the capacitance is (C = εo λ ) of the vacuum. For any frequency (f) the wavelength is (λ = c / f ) and the corresponding space inductance is (L = μo λ ) and capacitance (C = εo λ) and their combinations are analogous to the familiar (LC) electrical resonant circuit.


Lockyer’s Explanation of Photon Resonant Light Energy

Part 2The Octahedral

Hexagonal Fractal


N S = π / N S = sin π / N r1 / r2 r1 / r r2 / r

12 .26179939 .258819045 1.86370331 .349198186.650801814

11 .28559933 .281732557 1.55946553 .392239074.607760926

10 .31415927 .309016994 1.23606799 .447213595.552786405

9 .34906585 .342020143 .923804400 .519803365.480196635

8 .39269908 .382683432 .613125930 .619914404.380085596

7 .44879895 .433883739 .304764871 .766421615.233578385

6 .52359878 .500000000 0 1 0


Chart of Various Twist-Loop Fractals

o

r2

r1

r

R1

R2R

O

2r

2ΘR

First, Second, & Third Generations of an11 Twist-Loop Fractal


First & Second Generation

7 Twist-Loop Fractal


First and Second Generation

9.5 Twist-Loop Fractal


First, Second, & Third GenerationHexagonal Fractal


The Hexagonal Fractal



The Octahedral Hexagonal Fractal and the



Sierpinksi’s Pyramid& The Octahedral Hexagonal Fractal

Part 3(VPP) Electron Cube

Vs(OHF) Octagonal

Hexagonal Fractal


R

.707R

= R c

.707R = Rc

.5R = Rm

Volume Cube = R3 Volume Cylinder (Rotating Cube) = (.707R)2 x R

= R3/2 = (/2)R3

©WRHohenberger 1992-2013Cube Vs Octahedron

If you are talking about logarithmic variables then 1.618 and .618 are important numbers, since the natural logarithm of each number is the same except for the sign; However, if you are talking about mass structures then 1.414 and .707 are important, since 1.4142/.7071 = 2 the same multiplier for the hexagonal fractal.


The Phi Pyramid

Lockyer’s Calculated Results for Electron Charge

From Tom Lockyer’s VPP, Pages 72 & 76

Rc=.70

7R

R

Rm=.5R

Rc=.70

7RR c

=

R

RR

m =.707R

Volume (Octahedron) =1/3 x (.707R)2 x R

= 1/3 x R2/2 x R = R3/6

Vol (Rotating Octahedron) = /3 x (.5R)2 x R = /3 x R2/4 x R

= R3/12 = (/2)R3/6

Volume (Octahedron) = 1/3 x (R)2 x √2R = 1/3 x R2 x √2(R)

= (2√2)R3/6 = (√2/3)R3

Vol (Rotating Octahedron) = /3 x (.707R)2 x 1.414R

= /3 x R2/2 x √2R = (2√2)(/2)R3/6 =√2R3/6

= (/2)(√2/3)R3

Volume (Octahedron) = 1/3 x (1.414R)2 x 2R

= 1/3 x 2R2 x 2R= (2√2)(2√2)R3/6 = 8R3/6 (2√2)(√2/3)R3 = (4/3)R3

Vol (Rotating Octahedron).= /3 x (R)2 x 2R

= 2R3/3 = 2√2(/2)(√2/3)R3

= (/2)4/3R3


Comparing Octahedron Volumes Volume Cube = R3 Volume Rotating Cube = (/2)R3

Surface Area (Octahedron) = 8 x (√2/2)R/2 x √3(√2/2)R/2

= √3R2

SA (Rotating Octahedron) = 2[ x (1/2)R x (√2/2)R]

= (√2/2)R2

Surface Area (Octahedron) = 8 x R/2 x √3R/2

= 2√3R2

SA (Rotating Octahedron) = 2[ x (√2/2)R x R

= √2R2

Surface Area (Octahedron) = 8 x √2R/2 x √3√2R/2

= 4√3R2

SA (Rotating Octahedron).

= 2[ x R x √2R] = 2√2R2


Comparing Octahedron Surface AreaSurface Area = 6R2 Volume Cube = R3

Surface Area 2 Ends Rotating Cube = R2 Volume Rotating Cube = (/2)R3

Surface Area Sides Rotating Cube = 2√2R2

Rc=.70

7R

R

Rm=.5R

Rc=.70

7R R c=

R

RR

m =.707R

Vol. (Rotating Octahedron) = (/2)R3/6

1/6# .1661/# 6.0√1/# 2.4449

SA (Rotating Octahedron) (√2/2)R2

# .7071

Vol. (Rotating Octahedron) = (√2/3)(/2)R3

√2/3.4714

2.1213 1.4565

SA (Rotating Octahedron) = √2R2

1.4142

Vol. (Rotating Octahedron) = (4/3)(/2)R3

4/31.3333 .7500.8660

SA (Rotating Octahedron).= 2√2R2

2.8284©WRHohenberger 1992-2013

Comparing Octahedrons

Rc=.70

7RR

Rm=.5R

Rc=.70

7RR c

=

R

RR

m =.707R

Surface Area = 6R2 Volume Cube = R3

Surface Area 2 Ends Rotating Cube = R2 Volume Rotating Cube = (/2)R3


Rc=.707

R

R

Rm=.5R

Rc=.707

R

Vol. (Rotating Octahedron) = (√2/3)(/2)R3

# .4714 .00617283951/# 2.1213 162√1/# 1.456512.72792206

Surface Area (Rotating Octahedron)

= √2R2

# 1.4142 0.785674201 ©WRHohenberger 1992-2013

Deriving the Octahedron Correction Scaling Factor

1/√[1/(√2/3)R3] = √2R2

1 = √[3/√2R3 √2R2

1 = 3/√2R3 2R4

1 = (6/√2)R

R = √2/6 = (1/3)(1/√2)

R = (√2/6] = 0.23570226034

= .3333333333/√2

0.23570226034(√2) = .33333333333

Volume Cube = R3

Volume Rotating Cube = (/2)R3

Surface Area = 6R2

Surface Area 2 Ends Rotating Cube = R2


Vol. (Rotating Octahedron) = (1/6)(/2)R3

# .1666 .00617283950621/# 6.0000 162√1/# 2.449412.72792206135

Surface Area (Rotating Octahedron) = (√2/2)R2

# .7071.0758674201318


Deriving the Octahedron Correction Scaling Factor

1/√[1/(1/6)R3] = (√2/2)R2

1/√[6/R3] = (√2/2)R2

1 = √[6/R3] (√2/2)R2

1 = [6/R3] (1/2)R4

1 = (6/2)R

R = 1/3

R = .33333333333333

Volume Cube = R3


Surface Area = 6R2




Calculating Octahedron Electron Charge

Js = 5.97441869080294 x 10-16

Vol2 = [.006172839506173]Vol.Vol2 = .055834706642392 x 10-38

Pe = 641.5671442167432 x 10-30

E = 49.16276958706 x 1016

D = 43.529639552774 x 105

SA = L2 [.0785674201318]SA = .368065646670 x 10-25

e = 1.60217648697431 x 10-19

Volume Sphere = 4/3(Radius)3

= (4/3)(R/2)3 = (4/3)(1/8)R3 = (1/3)(/2)R3

# 0.3333.01234567901231/# 3.0000 81√1/# 1.7321 9

Surface Area Sphere = 4(Radius)2

= 4(R/2)2 = R2

# 1.0000.11111111111111


Deriving the inside Sphere Correction Scaling Factor

1/√[1/(1/3)R3] = R2

1/√[3/R3] = R2

1 = √[3/R3] R2

1 = [3/R3] R4

1 = 3R

R = 1/3

R = 0.33333333333

.5R

R Volume Cube = R3


Surface Area = 6R2



Volume Sphere = 4/3R3

= (4/3)(√5R/2)3 = (5√5/3)(/2)R3

# 3.7268 .01234567901231/# 0.2683 81√1/# 0.5180 9

Surface Area Sphere = 4R2

= 4(√5R/2)2 = 5R2

# 5.0000 .11111111111111 ©WRHohenberger 1992-2013

Deriving the Sphere Correction Scaling Factor

1/√[1/(5√5/3)R3] = 5R2

1/√[(3/5√5)/R3] = 5R2

1 = √[(3/5√5)/R3] 5R2

1 = [(3/5√5)/R3] 25R4

1 = [(3/√5)] 5R = [(15/√5)R

R = √5/15

R = √5/15 = (√5/5)(1/3)= √5R = 1/3

R = .1490711984999

R

.√5R/2

Volume Cube = R3


Surface Area = 6R2



Volume Rotating VPP Cube (Cylinder)[(√2/2)R]2 R = (/2)R3

# 1.0000 1.000000001/# 1.0000 1.00000000√1/# 1.0000 1.00000000

Surface Area 2 Ends of Cylinder = (2)R2 = 2[(√2/2)R]2 = R2

# 1.0000 1.000000000 ©WRHohenberger 1992-2013

Deriving the VPP Cube Correction Scaling Factor

1/√[1/R3] = R2

1 = √[1/R3] R2

1 = [1/R3] R4

1 = R

R = 1.00000

Rc=.707R

R

Rm=.5R Volume Cube = R3


Surface Area = 6R2



Volume VPP Cylinder= (/2)R3

# 1.0000 .000317597951/# 1.0000 3148.6349186√1/# 1.0000 56.112698372

Surface Area VPP Cylinder= (2√2+1)R2

# 3.8284 .01782127805 ©WRHohenberger 1992-2013

Deriving the VPP Entire Cylinder Correction Scaling Factor

1/√[1/R3] = ((2√2+1)R2

1 = √[1/R3] ((2√2+1)R2

1 = [1/R3] (8+4√2+1)R4

1 = (9+4√2)R

R = 1/(9+4√2)

R = 1/14.65685424

R = 0.0682274642

Rc=.707R

R

Rm=.5R Volume Cube = R3


Surface Area = 6R2



Type R Scaling Factor Compton Frequency

Rot. VPP Cube 1.000000000000 1.0

Blue Rot. Octahedron 0.333333333333 3.0

Inside Sphere 0.333333333333 3.0

Comparative Data for Various Polyhedrons ©WRHohenberger 1992-2013

.5R

R

Rc=.7

70R

R

Rm=.5R

.5R

R

Sphere

Volume= (4/3) (Radius)3

= (4/3) (R/2)3

= (4/3) (1/8)R3

= (1/3)(/2)R3

Surface Area = 4 (Radius)2

= 4 (1/4)R2

= R2

Rotating Octahedron (2 Cones)

Volume = /3 (Radius)2(Height)= /3 (R/2)2R= /3 (1/4)R2R= (1/6)(/2)R3

Surface Area= 2[ (Radius) (Side)] = 2 x (1/2)R x (√2/2)R = (√2/2)R2


VPP Rotating Cube

Volume= (Radius)2(Height)= (√2/2)2R2R= (1/2)R2R= (/2)R3

Surface Area (2 Ends)= 2[ (Radius)2]

= 2[ x (√2/2)2R2]= R2

Comparative Data for Various Polyhedrons

Volume Sphere = 4/3(Radius)3

= (4/3)(R/2)3 = (4/3)(1/8)R3 = [(3)](1/3)(/2)R3

# 1.0000 1.00001/# 1.0000 1.0000√1/# 1.0000 1.0000

Surface Area Sphere = 4(Radius)2

= 4(R/2)2 = R2

# 1.0000 1.0000©WRHohenberger 1992-2013

Deriving the Triple Sphere Correction Scaling Factor

1/√[1/R3] = R2

1/√[1/R3] = R2

1 = √[1/R3] R2

1 = [1/R3] R4

1 = R

R = 1

Volume Cube = R3


Surface Area = 6R2



Volume (Rotating Octahedron) = [(3)](1/6)(/2)R3

# 0.5000 0.500001/# 2.0000 2.00000√1/# 1.4142 1.414213562373

Surface Area (Rotating Octahedron) = (√2/2)R2

# .7071.7071067811865


Deriving the Triple Octahedron Correction Scaling Factor

1/√[1/(1/2)R3] = (√2/2)R2

1/√[2/R3] = (√2/2)R2

1 = √[2/R3] (√2/2)R2

1 = [2/R3] (1/2)R4

1 = R

R = 1

Volume Cube = R3


Surface Area = 6R2



1st GenerationElectron DBQ Octahedron Mass Structure

with Briddell’s Field Structure Lines of Force


Part 4Other Considerations


The Structure of Aether©WRHohenberger 1992-2013

Neutrinos, Electrons,Positrons & Virtual

PositronsOctahedron Contains aninner Octahedron Fractal

at its center


Electron/Neutrino Virtual Positron

2R/√6 = .8164R

LRad

Calculating Electron Charge from new Rotational Axis



Virtual Electron-Positron Lattice

The Structure of Aether©WRHohenberger 1992-2013

1 – There is a significant congruency between Lockyer’s Vector Particle Physics (VPP) and my own Dodecahedron Quark Ball (DQB), since both are derived from a vector field analysis, although mine is of physical vector field forces within the aether.

2 – VPP generates a plethora of mathematical derivations for the electron, and DQB defines entire families of particles.

3 – Quarks are not particles but instead are field structure arrays within a dual concentric electromagnetic wave.

4 – There may be up to three generations of concentric electromagnetic waves, which form particles when three such waves from three dual concentric waves are superimposed on top of each other on x, y, z Cartesian coordinates.

5 – The quantum limit of the fine structure of the aether forces saturated energy to drop out of suspension, from which twist-loop fractals form particles of matter.

6 – Particles form from the inner electromagnetic (light) wave, and their corresponding field structures form from the outer electromagnetic (dark) wave, which are reflections or mirror images of opposites of each other.

7 – Particle mass structures are captured energy cells, while field structures are lines of force carried by free energy cells.

8 – There is still a lot of work to be done to IRREFUTABLY prove that the electron is an octahedron. ©WRHohenberger 1992-2013

Part 5 Summary

Part 6Protons


Data for Electron Proton Scaling Ratios©WRHohenberger 1992-2013

Expanded Data for Electon Proton Scaling Ratios©WRHohenberger 1992-2013

A Periodic Table for Fractals©WRHohenberger 1992-2013

Planck’s Length Vs Octagonal Hexagonal Fractal

- Fractal Scaling Ratio


Proton Mass Calculations



Proton Mass Calculations

The next problem is to determine how the 1,061,540,183 energy cells in Eq. 23 are structured within each of the seven generations. The solution is to take the seventh root of 2 times the proton charge radius divided by the Planck’s Length, with a result of 857.4809. This number was then rounded off to the nearest odd number of energy loops or 857, which was then divided into the number of energy cells in a single generation of the twist-loop structure to determine the number of interlaced loops.

7√(Proton Charge Circumference/Planck’s Length) = # of Twist-Loops7√(2Proton Charge Radius) = # of Twist-Loops

7√(2)(.8768(69)E-15/1.616252E-35) = 857.4809

Proton Twist-Loop Calculations


Proton Charge Radius = 8.768E-16Charge Radius Circumference =

= 2R = 5.5091E-15Planck’s Length =

1.616252E-35Ratio of Cir./PL =

3.4086E+207th root Cir. = 857.4809

857 LoopsS = Sin /857 = .00366579

1 / S = 272.79for 1/32 in. Dia. = 8.52

inches 1,061,540,183 (11 Layers)

Proton Twist-Loop Calculations


Proton Structure


Proton Loop Calculations


Documents

Integrating Vector Particle Physics with the Dodecahedron Quark Ball and the Octahedral Hexagonal Fractal ©WRHohenberger 1992-2013 By William R Hohenberger