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In-Class Project: Normal Distribution Name ____________________________________ Date __________ Period _________ The Masters Golf Tournament has been held since 1934 for every year (except 1943-1945 due to WWII) and is played in Augusta, GA. For the years 1934-2004, 3472 golfers have “made the cut” and completed all 4 rounds of the tournament. The frequency distribution and histogram of first round scores (from the golfers making the cut) is given below, with a superimposed normal curve (µ=73.54, σ=3.08).
1. If par for this course is 72, how would you describe the scores in the histogram in relation to par?
What does this tell you about the skill level of the players?
2. Assuming a Normal distribution, what percent of scores would we expect to be below 70?
Score Frequency Proportion
63 1 0.00029
64 2 0.00058
65 6 0.00173
66 16 0.00461
67 46 0.01325
68 67 0.01930
69 151 0.04349
70 238 0.06855
71 337 0.09706
72 428 0.12327
73 467 0.13450
74 498 0.14343
75 397 0.11434
76 293 0.08439
77 203 0.05847
78 125 0.03600
79 78 0.02247
80 50 0.01440
81 28 0.00806
82 17 0.00490
83 7 0.00202
84 7 0.00202
85 4 0.00115
86 3 0.00086
87 1 0.00029
88 2 0.00058
More 0 0.00000
0
100
200
300
400
500
600
Count
60 65 70 75 80 85 90Round 1
Histogram
3. Based on the Normal Distribution with µ=73.54 and σ=3.08, between what two scores would we
expect the middle 95% of scores to fall? (Hint: use the normal curve below to help you.)
4. Assuming a Normal distribution with µ=73.54 and σ=3.08, what score would the lowest 5% of all
scores be below?
PROJECT: NORMAL PROBABILITY DISTRIBUTION
Objective: Use the Normal Probability Distribution to make decisions about a
population.
Scenario: An apparel company makes blue jeans and leather pants.
I. The female division.
Female Height in inches
66.4 68.1 66.7 67.9 63.1 67.8 66.1 68.9 66.1 69.2 64.9 67.6 57.6 65.1 66.7 67.8 66.8 63.6 67.5 60.2 69.4 68.4 62.2 67.2 64.7 66.3 64.2 62.2 64.3 67.2 63.2 58.1
A. Use the "Statistics" function of your calculator to find the sample mean and sample
standard deviation for the data. (Round to tenths.)
1. Mean ____________ 2. Standard deviation __________
Use these statistics when calculating the standard (z) scores.
B. Use the Normal Probability Distribution table to find:
1. What percent of female adults are taller than 6 feet (72 inches)? __________
2. What percent of female adults are taller than 5 feet (60 inches)? __________
3. What percent of female adult heights are between 60 inches
and 72 inches? __________
C. Because of the high cost of leather, the company has decided they cannot profitably make
leather pants in all sizes.
Use the Normal Probability Distribution table to find the heights corresponding to the
following percentages. These are the heights of the shortest and tallest females who
cannot purchase leather pants from this company. (Round to tenths.)
1. The bottom 8%
2. The upper 6%
II. The male division
Male Height in inches
68 65.5 68.1 72.5 65.4 71.2 67.7 73.5 67.7 65.1 65.3 65.5 72 73.2 62.5 77.2 70.5 66.7 67.5 70.2 67.4 71.8 65.1 67.2 66.3 69.3 67.7 67 73.8 66.5 66.1 68.6
A. Use the "Statistics" function of your calculator to find the sample mean and sample
standard deviation for the data. (Round to tenths.)
1. Mean __________ 2. Standard deviation __________
Use these statistics when calculating the standard (z) scores.
B. Use the Normal Probability Distribution table to find:
1. What percent of male adults are shorter than 6 feet (72 inches)? __________
2. What percent of male adults are shorter than 5 feet (60 inches)? __________
3. What percent of male adult heights are between 60 inches and 72 inches? __________
D. Because of the high cost of leather, the company has decided they cannot profitably make
leather pants in all sizes.
Use the Normal Probability Distribution table to find the heights corresponding to
the following percentages. These are the heights of the shortest and tallest males who
cannot purchase leather pants from this company. (Round to tenths.)
1. The bottom 9% __________
2. The upper 7% __________