IIT JEE maths solutions

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  • 7/30/2019 IIT JEE maths solutions

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    5. (2)

    Now,2 2x y

    116 9

    A = 4, b = 3

    23 7C 1

    44

    So, foci = ae,0 7,0

    Radius of new wide = 2 2

    0 7 3 0

    = 4.Centre = (0, 3)

    Equation of wide = 2 2 2x 0 y 3 4

    = 2 2x y 6y 9 16

    =2 2

    x y 6y 7 0

    6. (3)2

    Adj A A

    2

    1 3

    1 3 3 4 1

    2 4 4

    7. (3)

    p q ~ p ~ q p q ~ q ~ p p^ ~ q ^ ~ p ^ q p q ~ q ~ p

    T T F F T T F T

    T F F T F F F T

    F T T F T T F T

    F F T T T T F T

    8. (3)

    Mid-points are 0,1 , 1,1 and 1,0

    Vertices are 0,0 , 2,0 , 0,2

    radius of incentre : 2 2 x co-ordinate 2 2

    9. (1)

    3f x 2x 3x K

    2f x 6x 3 0 for all x Hence, only one root is positive at max

    10. (4) f x dx x

    5 3 3x x dx Let t x

    1

    2

    3

    -1

    -2

    -3

    1 2 3-4 -1-2-3 4

    (0, 0)

    (0, 2)

    (2, 0)

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    2dt 3x dx

    So,

    3 3

    5 3 2x f x

    x x dx 3x dx3

    1

    t f t dt3

    After Inequation by parts,

    1 t t dt ft t dt dt3

    1

    t t dt as f x dx a3

    Putting t as 3x

    3 3 3 21 x x x 3x dx3

    3 3 2 31 x a x x dx c3

    11. (3)

    k 1 x 8y 4k

    kx k 3 y 3k 1

    For no solutionk 1 8

    0k k 3

    And atleast one of4k 8 k 1 4k

    and 03k 1 k 3 k k 3

    The only value of k which satisfies is k = 3.

    No. of values = 1.

    12. (3)

    Tn is the number of triangle formed by joinly vertices of n sided polygon

    So, nn 3T C n 1

    n 1 3T C

    n 1 n n

    n 1 n 3 3 2T T C C C 10

    x 5

    13. (3)

    Circle 2 21S x y 5 2

    Equation of tangent 25

    y mx tan2

    .(1)

    Parabola 22S y 4 5x

    5y mx

    m .(2)

    (1)&(2) one some equation

    25 5

    1 m2 m

    4 2m m 2

    2 2m 1 m 2 0

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    So, m 1 So, y x 5 y is a tangent

    M 1 , satisfies the equation 4 2m 3m 2 0 Hence, S-I is True

    S-II is True

    14. (2)

    Point of intersection (9, 3)

    Area =3

    Right left

    0

    X X .dy

    3

    2

    0

    2y 3 y .dy

    = 9

    15. (3)tan A cot A

    1 cot A 1 tan A

    2 2sin A cos A

    cosA sin A cos A sin A cos A sin A

    3 3sin A cos A

    sin A cos A sin A cos A

    2 2sin A cos A sin A cos A

    sinAcosA

    secA.cosecA 1

    16. (1)3

    6

    cosxI dx

    cos x sin x

    3

    6

    2I dx3 6 6

    I12

    17. (2)

    1 1 2x 1

    1sec tan x tan tan x

    1 x

    1 12

    1 1 2

    x

    2y x 3 0

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    18. (4)

    z

    z

    otg 2

    19. (1)Self Explanatory

    20. (3)

    o30

    x 3y 3

    3, 0

    1

    y 0 x 33

    x-axis

    Hence, option (3) is correct

    21. (4)S 0.7 0.77 0.777 ........(20terms)

    7S 0.9 0.99 0.999 ....(20terms)9

    7 2 37S 20 10 10 10 ... 20 terms9

    20

    1 1

    1

    10 1 107

    S 209 1 10

    20

    7 1 1S 20 1

    9 9 10

    207 179 1081

    Hence option (a) is correct

    22. (4)4 5

    5 54 5

    1 2 1C C

    3 3 3

    5 5

    10 1 11

    3 3

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    23. (4)

    1 10

    3 x 1x 1x

    101 1

    3 2x x

    10 r r 1 1

    10 3 2rC x x

    10 r r 10 3 2

    rC x

    r 4 10

    410.9.8.7

    C 2104!

    24. (4)

    n A 2 n B 4

    n A B 8 8 8 8 8

    3 4 5 8C C C ..... C 219

    25. (4)

    AB BC CA 0

    BC AB CA

    AB CABM

    2

    Now, AM BM AB

    AB CAAM 33

    2

    26. (2)

    dyx

    dx

    2

    2

    xx 0

    xy

    xx 0

    2

    Slope

    x x 0

    x x 0

    x 0 x 0 x 2 x 2 y 2 y 2

    1P 2, 2 2P 2, 2

    T : y 2 2 x 2 T : y 2 2 x 2 x intercept 1 x intercept 1

    C

    M

    BA

    5i 2 j 4k

    3i 4k

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    30. (2)

    A B

    CD

    p

    2 2p q

    N

    p

    q

    p

    tanq

    p

    tanAn

    p

    tanAN

    tan tan R

    1 tan tan AN

    ptan

    q tan p pq

    p q p tan AN1 tanq

    p p tan qq AN q

    q tan p

    2 2p tan pq q tan pq

    q tan p

    2 2p q sinp sin qsin