IEEE CTs and PTs 6-10.pdf

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    GE MultilinInstrument Transformers, Inc.

    Are you using the right CT's and PT's

    for your application?John Levine, P.E.

    Levine Lectronics and LectricE-mail: [email protected]

    GE Multilin / Instrument Transformers, Inc.

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    GE MultilinInstrument Transformers, Inc.

    Current & Voltage TransformerBasics (IEEE Standards)

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    GE MultilinInstrument Transformers, Inc.

    Agenda

    Current TransformersVoltage TransformersRequired Information for Specifying CTs & VTsTake Home Rules for CTs & VTsApplications where used

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    GE MultilinInstrument Transformers, Inc.

    Why use Instrument Transformers?

    Circuit Isolation

    Reduce voltage and currents

    to reasonable working levels.

    Phasor combinations for

    summing and measuringpower

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    GE MultilinInstrument Transformers, Inc.

    CURRENT TRANSFORMERS

    TYPES OF C.T. CONSTRUCTION

    The most common type of C.T. construction is the DOUGHNUTtype. It is constructed of an iron toroid, which forms the core of thetransformer, and is wound with secondary turns.

    Secondary Winding Primary Conductor

    Iron Core

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    Transformer ratio (TR)

    Primary Current(100 amps) Secondary Current(5 amps)

    Primary Current

    Secondary CurrentTransformer Ratio = _____________________

    1005

    ___ = 100:5 or 20:1

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    Polarity

    Direction of Primary Current

    Direction ofSecondary Current

    H1

    X1

    Primary current into polarity =

    Secondary current out of polarity

    P1

    IEEE

    IEC

    PrimaryPolarityMarks

    IEEEIECS1

    SecondaryPolarityMarks

    Remember:

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    Polarity

    Direction of Primary Current

    Direction ofSecondary Current

    H1

    X1

    P1

    IEEE

    IEC

    PrimaryPolarityMarks

    IEEEIECS1

    Secondary

    PolarityMarks

    Primary current into non polarity =Secondary current out of non polarity

    Remember:

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    Generator t !ical "irin#

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    GE MultilinInstrument Transformers, Inc.

    What is your application?

    If your application is metering , how high do I

    need to go in current? 2 times ?

    If your application is protective relaying, howhigh do I need to go in current? 20 times ? 40times ?

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    GE MultilinInstrument Transformers, Inc.

    C! Ratin" #actor $R#% IEEERated current & $R#% =

    Ma&imum continuous current carryin"capability:

    'it(out e&ceedin" temperature limits'it(out loss of publis(ed accuracy class

    !ypical ratin" factors for Meterin" C!s are:)*+, )*--, )*., /*+, -*+, 0*+

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    +*-+

    +*-+

    +*1+

    +*1+

    Ratin" #actor

    2 c c u r a c y C

    l a s s 3

    C! Ratin" #actor $R#% IEEE

    )+3 )++3 /++3 -++3 0++3

    )*+ /*+ -*+ 0*+

    IEEE C.4*)- 2ccuracy+*-3 5 67*7 R# 0*+

    +*-3 2ccuracyRe"ion

    +*132ccuracy

    Re"ion

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    S(ort !ime !(ermal Current Ratin"

    8ne $)% 9 second t(ermal ratin"E&pressed as alue of RMS primary current

    Main influencin" factor:C! primary ; secondary e< 2mbient?>e< 2mbient

    E&ample: C!

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    C! Meterin" 2ccuracy

    Actual secondarycurrent

    Rated secondarycurrent=

    Difference in 3 is kno

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    IEEE C! Meterin" 2ccuracy2ccuracyClass $ B %

    2pplication

    +*).i"( 2ccuracy Meterin"

    +*).S Special i"( 2ccuracyMeterin"

    +*-Re enue Meterin"

    +*1

    B 2ll accuracy classes defined by IEEE C.4*)- or C.4*)-*1

    B 2ccuracy classes include bot( ratio ; p(ase an"le error

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    IEEE C! Meterin" 2ccuracy

    6urdenoad connected to C! secondary

    Includes de ices ; connectin" leads

    E&pressed in o(ms

    Standard alues = 6+*), 6+*/, 6+*., 6+*A, 6)*@E+*+0, E+*/

    2ll burdens defined by IEEE C.4*)- or C.4*)-*1 for 1+ only

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    Application BurdenDesignation

    Impedance(Ohms)

    VA @5 amps

    PowerFactor

    Metering B0.1 0.1 2.5 0.9B0.2 0.2 5 0.9B0.5 0.5 12.5 0.9B0.9 0.9 22.5 0.9

    B1.8 1.8 45 0.9

    Standard IEEE C! 6urdens $. 2mp%$Per IEEE Std* C.4*)- )AA- ; C.4*)-*1%

    IEEE C! Meterin" 2ccuracy

    E0.2E0.04

    0.20.04

    51

    1.01.0

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    A current transformer for metering purposes maytypically have an accuracy of 0.3%. The C.T. mustmaintain this accuracy for normal load currents,

    provided the rated burden on the C.T. is not exceeded.It is quite acceptable, and in fact desirable, for the C.T.to saturate when fault current flows. The accuracy for atypical metering C.T. is specified as:

    0.3 M 0.9

    O.3% METERING O.9 OHMS BURDEN

    This metering C.T. has an accuracy of 0.3% when the

    connected burden does not exceed 0.9 OHMS.

    CT CLASSIFICATION for Metering

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    IEEE C! Meterin" 2ccuracy

    2ccuracy Class$+*-, +*1, )*/% $B%

    6urden $8(ms%$6+*), 6+*/, 6+*.,6+*A, 6)*@%

    2ccuracy e&pressed as:

    +*-6+*/+*16+*A

    )*/6)*@+*).E+*/

    =

    !ypicalE&amples

    B 2ccuracy class is stated at )++3 rated currentB 2t )+3 rated current, t

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    +*-+

    +*-+

    +*1+

    +*1+

    Ratin" #actor

    2 c c u r a c y C

    l a s s 3

    )+3 /++3 -++3

    )*+ /*+ -*+ 0*+

    IEEE C.4*)- 2ccuracy+*- 5 67*7G R# 0*+

    +*-3 2ccuracyRe"ion

    +*132ccuracy

    Re"ion

    IEEE C! Meterin" 2ccuracy

    )++3 0++3

    >o accuracy "uaranteed atcurrent le els less t(an )+3

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    IEEE C! Meterin" 2ccuracyC! Parallelo"ram 9 IEEE C.4*)-

    8ut of +*-3 Class

    +*- classparallelo"ram

    +*1 class

    parallelo"ram

    )++3)+3

    >ote:6urden mustbe specified

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    GE MultilinInstrument Transformers, Inc.

    IEEE C! Meterin" 2ccuracy

    Corrected to +*-3 Class

    C! Parallelo"ram 9 IEEE C.4*)-+*- classparallelo"ram

    +*1 class

    parallelo"ram

    )++3

    )+3

    >ote:6urden mustbe specified

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    +*-+

    +*-+

    +*1+

    +*1+

    Ratin" #actor

    2 c c u r a c y C

    l a s s 3

    .3 )++3 /++3 -++3 0++3

    )*+ /*+ -*+ 0*+

    IEEE C.4*)-*1 2ccuracy+*). 5 E0.04, E0.20$+*). 5 67*7G R#0*+

    +*).3 2ccuracyRe"ion+*-3

    2ccuracyRe"ion

    IEEE C! Meterin" 2ccuracy

    +*).

    +*).

    >o accuracy "uaranteed

    at current le els less t(an .3

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    +*-+

    +*-+

    +*1+

    +*1+

    Ratin" #actor

    2 c c u r a c y C

    l a s s 3

    .3 /++3 -++3

    )*+ /*+ -*+ 0*+

    IEEE C.4*)-*1 2ccuracy+*).S 5 E0.04, E0.20$+*).S 5 67*7, R#0*+

    +*).3 2ccuracyRe"ion

    IEEE C! Meterin" 2ccuracy

    +*).

    +*).

    >o accuracy "uaranteed

    at current le els less t(an .3

    0++3)++3

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    IEEE C! Relay 2ccuracyProtection C!

    Standard Relay 2ccuracy Classes

    C or !)++

    C or !/++C or !0++

    C or !@++

    '(at do t(ese meanH

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    Instrument Transformers, Inc.

    IEEE C! Relay 2ccuracy

    Relay class $C or ! % desi"nates minimum

    secondary terminal oltsJ2t /+ times rated current

    'it(out e&ceedin" )+3 ratio error

    Into a ma&imum specified burden

    Now that everyone is totally confusedlets look at some simple examples

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    Instrument Transformers, Inc.

    T = Determined by test

    CT CLASSIFICATION for RELAYING

    10 C 400

    Protection Class CTs - Must supply 20 times rated current

    C = CalculatedK = CalculatedL = Low internal secondary impedanceH = High internal secondary impedance

    Format

    LetterAccuracy Voltage at 20 times CT

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    Instrument Transformers, Inc.

    Primary current/0,+++ amps$/+ & )/++ %

    IEEE C! Relay 2ccuracy

    C!)/++:.

    C or !)++

    7)7/

    6urden of De ices $ %

    6urden of eads $ %

    Secondary current)++ amps $/+ & .%

    !otal E&t6urden)*+

    C or !)++ e&ample

    !erminal Kolts = $/+ times rated% $!otal e&ternal burden%)++ Kolts = $)++ amps% $)*+ %

    ! e r m

    i n a l K o l t s =

    ) + +

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    Instrument Transformers, Inc.

    Primary current/0,+++ amps$/+ & )/++ %

    IEEE C! Relay 2ccuracy

    C!)/++:.

    C or !/++

    7)7/

    6urden of De ices $ %

    6urden of eads $ %

    Secondary current)++ amps $/+ & .%

    !otal E&t6urden/*+

    C or !/++ e&ample

    !erminal olts = $/+ times rated% $!otal e&ternal burden%/++ Kolts = $)++ amps% $/*+ %

    ! e r m

    i n a l K o l t s =

    / + +

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    Instrument Transformers, Inc.

    Standard IEEE C! 6urdens $. 2mp%$Per IEEE Std* C.4*)- )AA-%

    IEEE C! Relay 2ccuracy

    Application BurdenDesignation

    Impedance(Ohms)

    VA @5 amps

    PowerFactor

    Relaying B1 1 25 0.5 B2 2 50 0.5 B4 4 100 0.5 B8 8 200 0.5

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    Instrument Transformers, Inc.

    IEEE C! Relay 2ccuracyE&citation cur e includes

    olta"e reLuired to o ercomeinternal resistance $DCR% of C!*2ppro&imately -/ olts*

    )+3 ratio error = $/+ & .% $)+3%= $)++% $+*)+%= )+ amps

    o< many terminal olts

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    Instrument Transformers, Inc.

    )+++:. C!

    )+++ 2mps .amps

    IE +*.amps

    I6 N0*.amps

    'it( )+3 error, I 6 is any

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    Instrument Transformers, Inc.

    C! 6urden Calculation

    PrimaryCurrent

    C!

    7)7/

    6urden of De ices $ %

    6urden of eads $ %

    Secondary current

    !otal6urden

    !

    o< do

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    Instrument Transformers, Inc.

    C! 6urden Calculation

    2ssumption: - p(ase C!s are Q connected

    ! = RC! R 6

    ! = !otal burden in o(ms $ ector summation ofresistance and inductance components%

    RC! = C! secondary resistance in o(ms 54. de" C $DCR%

    R = Resistance of leads in o(ms $!otal loop distance%

    6 = De ice impedance in o(ms

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    Instrument Transformers, Inc.

    GE Multilin Electronic %ela &ur'en

    VA = VI. V= IR, So 0.2 = I*I*R.

    .2/25 = .008 ohms

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    Instrument Transformers, Inc.

    100:5 C.T. Secondary Winding Resistance (DCR) = .062 ohm

    Resistance of Cable from C.T. to Relay and back = .1 ohms

    Resistance of Relay Coil = .02 ohms

    Total Resistance = .182 ohms

    If we have a fault of 2,000 amps and the C.T. ratio is 100:5 then the C.T.secondary current is 100 amps. Therefore we will produce a voltage of 100

    amps x .182 ohms = 18.2 Volts. To prevent CT saturation, select a CT with aknee point above 18.2 Volts.

    .062

    .1

    .02

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    Instrument Transformers, Inc.

    780-102 is a 1000 to 5 CT, Class C100

    1000:5 C.T. Secondary Winding Resistance (DCR) = .32 ohm

    Resistance of Cable from C.T. to Relay and back = .1 ohms

    Resistance of Relay Coil = .008 ohms

    Total Resistance = .428 ohms

    If we have a fault of 20,000 amps and the C.T. ratio is 1000:5 then the C.T.secondary current is 100 amps. Therefore we will produce a voltage of 100amps x .428 ohms = 42.8 Volts. To prevent CT saturation, select a CT with a

    knee point above 42.8 Volts.What happens if the fault current is 40,000 amps?

    .32

    .1

    .008

    # I fl i " C! 2

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    Instrument Transformers, Inc.

    #actors Influencin" C! 2ccuracy#reLuency

    Current Ratio

    6urden

    o< freLuency and i"( accuracy are not friends

    o< ratio and (i"( accuracy are not friends

    i"( burden and i"( 2ccuracy are not friends

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    (T )aturation

    *+at is (T )aturation

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    Instrument Transformers, Inc.

    -o"er ) stems %ela (ommittee -)%(/

    )aturation (alculator

    ff f )

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    Instrument Transformers, Inc.

    actors ffectin# e#ree of )aturation

    an' Time to )aturation( ffsetault Ma#nitu'e s mmetrical current/

    100 to 5 (T 20 times 2000 am!s, at 20,000 am!s "e +a e 200 times (T

    (T Turns %atio

    )econ'ar &ur'en(T ccurac%emanence lu

    (an occur if current interru!te' "+en core is saturate'If ( flo"s in "in'in#s 'urin# testin#

    ee' a olta#e a:o e 60; of

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    Instrument Transformers, Inc.

    !ips for 2 oidin" C! Saturationse (i"(er ratio C!s

    se separate set of (i"( ratio C!s for (i"( faultcurrent trippin"

    Reduce secondary burden

    Select lo< burden relays ; metersDistribute sin"le p(ase burdens amon" p(asesIncrease si e of secondary leads

    Reduce len"t( of secondary leadsse step do

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    Instrument Transformers, Inc.

    -otential Transformers

    f

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    Instrument Transformers, Inc.

    DefinitionsVoltage Transformer (VT)

    An instrument transformer used to reflect a primaryvoltage into a secondary voltage through a magnetic medium.Always connected in parallel with primary conductor across acircuit load.

    Secondary (measuring) voltage is usually 115 or 120volts nominally. The secondary voltage level is selected for easeof measurement and safety.Control Power Transformer (CPT)

    Designed to provide power for contractors, relays and

    devices with high inrush currents, Regulation is not as critical.

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    Instrument Transformers, Inc.

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    Instrument Transformers, Inc.

    POTENTIAL TRANSFORMERS

    VP

    Vs

    Relay

    14,400/120 = 120/1

    4200/120 = 35/1

    2400/120 = 20/1

    IEEE K! 2ccuracy Class

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    Instrument Transformers, Inc.

    IEEE K! 2ccuracy ClassMeterin" 2ccuracy

    Classes $3 error%

    +*-

    +*1

    )*/

    +*).

    Defined by IEEE C.4*)-

    2pplicable from A+3 to ))+3rated olta"e

    Defined by IEEE C.4*)-*1

    IEEE K! 2ccuracy Class

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    Instrument Transformers, Inc.

    IEEE K! 2ccuracy Class

    !(ese standard burden desi"nations (a e no si"nificanceat freLuencies ot(er t(an 1+ *

    Burden VA PF

    W 12.5 0.10X 25 0.70M 35 0.20Y 75 0.85Z 200 0.85

    ZZ 400 0.85

    Meterin" 2ccuracyClass 6urdens

    IEEE K! 2ccuracy Class

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    Instrument Transformers, Inc.

    IEEE K! 2ccuracy Class

    E&pressed as:

    2ccuracy Class 6urden Code

    +*- ',7,Q+*1

    )*/

    !(ese standard desi"nations (a e no si"nificanceat freLuencies ot(er t(an 1+ *

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    Instrument Transformers, Inc.

    K! Installation Tuidelines

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    Instrument Transformers, Inc.

    K! Installation TuidelinesCaution:

    Rated olta"e: Do not operate abo e ))+3

    ine to "round rated:Do not connect line to lineDo not use on un"rounded systems

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    Instrument Transformers, Inc.

    pK!

    Troup>o* of

    6us(in"Connection

    Met(od

    >eutralTroundin"

    >otes

    ) / open

    Q Q possible

    2ny 'it(stand /.3 o er rated olta"e onan emer"ency basis

    / / open

    Q Q possible

    2ny 'it(stand )+3 o er rated olta"econtinuously* Primary rated for line toline olta"e*

    - ) Q Q Q 2ny 8utdoor, t

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    Instrument Transformers, Inc.

    K! !ypical Connections

    8pen Delta Connection$/% Double 6us(in" K!s

    Q 9 Q Connection$-% Sin"le 6us(in" K!s

    #erroresonance

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    Instrument Transformers, Inc.

    #erroresonancePossible

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    Instrument Transformers, Inc.

    #erroresonance

    Recommended readin":

    Ferroresonance of rounded !otential

    Transformers on "ngrounded !ower #ystems$

    2IEE Po

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    Instrument Transformers, Inc.

    p

    Q 9 6roken Corner K! connection

    Ferroresonance

    damping resistor % F%

    Kolta"e relay todetect "roundfault

    >on effecti ely"rounded system

    + olts 5 normal condition

    - times normal > p(aseolta"e 5 "round fault

    Preferred met(od

    #erroresonance Dampin"

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    Instrument Transformers, Inc.

    e o eso a ce Da p

    Q Q?6roken Corner Connection

    Double secondary K!$)% Relayin" ? Meterin"

    $)% Tround fault detectionand ferroresonance damping

    Preferred met(od

    #erroresonance

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    Dampin"#erroresonancedampin" resistor

    R#R alue

    6ased on / ariables:2ir core inductance of primary

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    Instrument Transformers, Inc.

    ReLuired Informationfor Specifyin" C!s ; K!s

    Current !ransformer $C!% R#V SpecificationEn ironment: Indoor 8utdoor

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    Instrument Transformers, Inc.

    En ironment: Indoor 8utdoor

    System Kolta"e $kK%+*1+*4/-*1.*+4*/

    @*4)/)./0/.

    -0*.-0*.

    Po

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    62GE Multilin

    Instrument Transformers, Inc.

    Indication 8nly: 3, K2 $Skip meterin" ; protection selections%

    Meterin" Class:IEEE: +*- +*1 )*/ /*0 8t(erIEC: +*/ +*. )*+ 8t(er

    Meterin" 6urden:

    IEEE $8(ms%: 6+*) 6+*/ 6+*. 6+*A 6)*@ 8t(erIEC $K2%: /*. .*+ )+ ). -+ 8t(er

    Protection Class: C $IEEE% K2, P $IEC%

    8peratin" #reLuency: 1+ .+

    Ratin" #actor: )*+ )*-- )*. /*+ 8t(er

    Secondary Connections: !erminals /0 inc( leads

    8uter Insulation: Standard Cotton tape ; arnis( Polyester tape

    Insulation Class: )+. +C $Standard% 8t(er

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    System Kolta"e $kK%+*1+*4/-*1.*+4*/

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    !(ermal Ratin": K2 $8ptional%

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    C!s are intended to be proportionalcurrent de ices* Kery (i"( olta"es canresult from open circuitin" t(e secondary

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    >e er s(ort circuit t(esecondary of an ener"i ed K!

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    Meterin" applicationsdo not reLuire a C class C!

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    C! secondary leads must beadded to t(e C! burden

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    !ake ome Rule W 1

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    E&ercise caution

  • 8/11/2019 IEEE CTs and PTs 6-10.pdf

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    It is common practice to apply1++ Kolt C! to systems

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    Mo'el 780, 778

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    ut'oor & 7 F%e!laces &(T@s in s+iel'e'aluminum +ousin#

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    ut'oor T !e & 7for %etrofit

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    uestions