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1 1.351 HOMEWORK SET 6 Due: Friday April 3 1. The shear strength of a soil is most frequently characterized by a frictional failure criterion. Two commonly used failure criteria are: Mohr-Coulomb: f = σ 1 - σ 3 2 - σ 1 + σ 3 2 sin φ = 0 (1a) Extended von Mises: f = J 2 - h 2 σ 2 = 0 (1b) where: σ 1 , σ 3 are the major and minor principal stresses, φ is the friction angle. J 2 = 1 2 s ij s ij is the second invariant of deviatoric stresses, σ = 1 3 σ kk is the mean (octahedral) stress and h is a constant. In conventional practice, the friction angle (φ = φ TC ) is reported from measurements of the shear strength in triaxial compression type tests (in which σ xx =σ zz < σ yy ; Fig. 1): a) Derive an expression for the frictional parameter, h (eqn. 1b) in terms of this friction angle. b) Assuming that failure of the soil is best described by the extended von Mises criterion, what is the frictional angle mobilized in a triaxial extension test (i.e., φ TE for the case when σ xx =σ zz > σ yy ). c) Plot values of φ TE as a function of the measured friction angle, φ TC for the extended von Mises failure criterion. y x z Figure 1.

HW6 Question

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    1.351 HOMEWORK SET 6 Due: Friday April 3

    1. The shear strength of a soil is most frequently characterized by a frictional failure criterion. Two commonly used failure criteria are:

    Mohr-Coulomb: f = 1 - 32

    - 1 + 32

    sin = 0 (1a)

    Extended von Mises: f = J2 - h22 = 0 (1b) where: 1, 3 are the major and minor principal stresses, is the friction angle. J2= 12 si jsi j is the

    second invariant of deviatoric stresses, = 13 kk is the mean (octahedral) stress and h is a

    constant. In conventional practice, the friction angle ( = TC) is reported from measurements of the shear strength in triaxial compression type tests (in which xx=zz < yy; Fig. 1): a) Derive an expression for the frictional parameter, h (eqn. 1b) in terms of this friction angle. b) Assuming that failure of the soil is best described by the extended von Mises criterion, what is

    the frictional angle mobilized in a triaxial extension test (i.e., TE for the case when xx=zz > yy).

    c) Plot values of TE as a function of the measured friction angle, TC for the extended von Mises failure criterion.

    y

    x

    z

    Figure 1.

  • 2

    2. Figure 2 shows a slope with inclination, i, in a dry soil with c = 0 kPa, and ' = 30o, calculate the ultimate surcharge load, qult, which can be applied vertically to the top of the slope. Do not consider the self weight of the soil, and assume a normal resisting load, p, to act normal to the slope (Fig. 2). There are closed-form solutions for this problem. However, I would like you to solve this problem using the graphical construction method proposed by Scott (1963) - and presented in Appendix C available on stelllar web site.

    Report your results in the form of a dimensionless plot of qult/p versus slope inclination angle, i. State clearly any additional assumptions you make.

    Dry soil' = 300, c = 0

    surcharge, qult (force/unit area)

    H

    i

    resisti

    ng loa

    d, p

    Figure 2

  • 3

    3. A bulldozer blade of height, H=5m, applies a horizontal (H) and vertical (shear) force (V) as it pushes vertically against a layer of clay with unit weight, =20kN/m3 and (undrained) shear strength, c=20kPa, as shown in Figure 3. Assuming that the bulldozer blade remains vertical and that the maximum shear resistance at the blade-soil interface is given by ci=0.7c:

    a) Using the mechanism in figure 3a, compute an upper bound estimate of the forces acting on the bulldozer blade.

    b) By considering the stress states at elements A and B located at a depth z in figure 3b, find a lower bound solution for the same problem.

    Rock

    Clay: = 20 KN/m3c = 20 KN/m3

    Bulldozer blade

    Hu

    V

    Rock

    HL

    V

    z A B

    III

    Figure 3a: Upper Bound Mechanism Figure 3b: Lower Bound Calculation