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HP-35 How-To Online Course
PROGRAMS COVERED
• Area by Coordinates• Azimuth Bearing• Triangles• Intersections
• H & V Curves• Inversing
– Standard– Radial
• Stubbing• Traversing
AREA BY COORDINATES
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2
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AREA BY COORDINATES
)*()*)(*()*)(*()*)(*()*)(*(*2
4145342312
14433221
YXYXYXYXYXYXYXYXYXA
AREA BY COORDINATES• XEQ A• -25 R/S• 25 R/S• 35 R/S• 15 R/S• 20 R/S• 5 R/S
• -20 R/S• 5 R/S
• -25 R/S• 25 R/S
ANGLE CONVERSIONS
• Bearing->Azimuth
• Azimuth->Bearing
• DMS to DD
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AZIMUTHBEARING
BEARING->AZIMUTH
• Tiny Tim is retracing a survey from the early 1950’s. Unfortunately, he just realized that his total station traverse is in azimuths while the original survey is in bearings. What are the azimuths for the given bearings?– N32E S82W S82-92-19W
BEARING->AZIMUTH
• What are the azimuths for the given bearings?– N32E– S82W– S82-42-19W
• XEQ B
• 32 R/S• 1 R/S
• PRESTO!• A = 32
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BEARING->AZIMUTH• XEQ B
• 32 R/S• 1 R/S
• PRESTO!• A = 32
• XEQ B
• 82 R/S• 3 R/S
• PRESTO!• A = 262
• XEQ B
• 82.4219 R/S
• 3 R/S
• PRESTO!• A =
BEARING->AZIMUTH• XEQ B• 39-39-12 R/S• 1 R/S• [read azimuth] R/S
• XEQ B• 44-22-55 R/S• 3 R/S• [read azimuth] R/S
• N39-39-12E to AZ
• S44-22-55W to AZ
AZIMUTH->BEARING
• Jimmy John is a student in a 4-year surveying program. As part of a national competition, the students have been asked to use a compass & chain to perform a historic survey. Luckily, he surveyed the same points as a student last year with a total station. He wants to compare his compass survey with the total station traverse. Help him convert the following azimuths to bearings: 293-21-19, 118-11-59, 092-22-21
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AZIMUTH->BEARING
• Help him convert the following azimuths to bearings: – 293-21-19– 118-11-59– 092-22-21
• XEQ Q
• 293.2119 R/S
• PRESTO!• B = 66-38-41 R/S• Q = 4
AZIMUTH->BEARING• XEQ Q
• 293.2119 R/S
• PRESTO!• B = 66-38-41
R/S• Q = 4
• XEQ Q
• 118-11-59 R/S
• PRESTO!• B = 61-48-01
R/S• Q = 2
• XEQ Q
• 092-22-21 R/S
• PRESTO!• B = 87-37-39
R/S• Q = 2
TRIANGLES, TRIANGLES, TRIANGLES, TRIANGLES!
• SSS• SAS• SAA• ASA• SSA
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ONLINE TRIANGLE SOLVER
https://www.calculator.net/triangle-calculator.html
TRIANGLESSIDE-SIDE-SIDE
SIDE-SIDE-SIDE TRIANGLES
"SSS" is when we know three sides of the triangle, and want to
find the missing angles
cos(C) = a2 + b2 − c2 / 2abcos(A) = b2 + c2 − a2 / 2bccos(B) = c2 + a2 − b2 / 2ca
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SIDE-SIDE-SIDE TRIANGLESA traverse is observed with a differential level, only able to measure rough distances. To verify the accuracy of the total station reading last week, your boss asks you to compute the interior angles of the 3-sided
traverse. The triangle measures 1029.39, 993.28 and 897.27 What do you
report back?
• XEQ C ENTER
• 1029.39 R/S
• 993.28 R/S
• 897.27 R/S
SIDE-SIDE-SIDE TRIANGLESINPUT
• XEQ C
• 1029.39 R/S• 993.28 R/S • 897.27 R/S
• PRESTO!• 65.4506/1029.39 R/S• 61.3701/993.28 R/S• 52.3754/897.27
OUTPUT
• ANGLE OPP & SIDE 1 DIST
• ANGLE OPP & SIDE 2 DIST
• ANGLE OPP & SIDE 3 DIST
• TRIANGLE AREA
TRIANGLESSIDE-ANGLE-SIDE
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SIDE-ANGLE-SIDE TRIANGLES
"SAS" is when we know two sides and the
angle between them.
a2 = b2 + c2 − 2bc cosA
SIDE-ANGLE-SIDE TRIANGLES
The City of Nowhere has mandated that all flagpoles must not exceed a
height of 49.50’ because the city revenue needs a shot in the arm. You, Super Surveyor, have been
asked to survey all 595,393 flagpoles in the city. Since you don’t enjoy
climbing, you have decided to use your total station. On flagpole
393,232, the measurements include: bottom of 49.49’, top of 66.32’ and angle of 45 degrees. What’s the
height of the flagpole?
• XEQ D ENTER
• 49.49 R/S
• 45 R/S
• 66.32 R/S
SIDE-ANGLE-SIDE TRIANGLESINPUT
• XEQ D ENTER
• 66.32 R/S
• 45 R/S
• 49.49 R/S
OUTPUT
• 48.1000 / 49.49
• 86.4959 / 66.32
• 45.0000 / 46.97
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TRIANGLESSIDE-ANGLE-ANGLE
SIDE-ANGLE-ANGLE TRIANGLES
“AAS” is when we know two angles and
one side (which is not between the
angles)𝐴 𝐵 𝐶 180
+ +
SIDE-ANGLE-ANGLE TRIANGLES
• Solve the following triangle • XEQ E ENTER
• 7 R/S
• 35 R/S
• 62 R/S
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SIDE-ANGLE-ANGLE TRIANGLESINPUT
• XEQ E ENTER
• 7 R/S
• 35 R/S
• 62 R/S
OUTPUT
• 62.0000 / 7
• 83.0000 / 7.8689
• 35.0000 / 4.5473
TRIANGLESANGLE-SIDE-ANGLE
ANGLE-SIDE-ANGLE TRIANGLES
"ASA" is when we know two angles
and a side between the
angles𝐴 𝐵 𝐶 180
+ +
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ANGLE-SIDE-ANGLE TRIANGLESA total station traverse was performed
on Cranky Customer’s residential lot last week. But apparently, the data collector
was acting-up. It collected the angle between the SE corner and the N corner
as 64-15-35 degrees and the angle between the SW corner and the N corner as 53-44-50 degrees. Luckily, you also got the distance between the SE and
SW corners at 954.49’. What’s the distance from the SE to N and SW to N
corners?
• XEQ F ENTER
• 64-15-35 R/S
• 954.49 R/S
• 53-44-50 R/S
TRIANGLESSIDE-SIDE-ANGLE
ANGLE-SIDE-ANGLE TRIANGLESINPUT
• XEQ F ENTER
• 64-15-35 R/S
• 954.49 R/S
• 53-44-50 R/S
OUTPUT
• 61.5935 / 954.49
• 64.1535 / 973.821
• 53.4450 / 871.7134
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SIDE-SIDE-ANGLE TRIANGLES
"SSA" is when we know two sides
and an angle that is not the angle
between the sides𝐴 𝐵 𝐶 180
+ +
SIDE-SIDE-ANGLE TRIANGLES• Solve This Triangle: • XEQ G ENTER
• 8 R/S
• 13 R/S
• 31-00-00 R/S
SIDE-SIDE-ANGLE TRIANGLESINPUT
• XEQ G ENTER
• 8 R/S
• 13 R/S
• 31-00-00 R/S
SOLUTION 1
• 31-00-00 / 8.0
• 56-49-05 / 13.0
• 92-10-55 / 15.522
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INTERSECTIONS
INTERSECTIONS
• Angle-Angle
• Angle-Distance
• Distance-Distance
ANGLE-ANGLE
• Angle-Angle intersections provide the location of an intersection between two azimuths – bearings -interior angles and the distance from the intersection to either of the original points.
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ANGLE-ANGLE
ANGLE-ANGLEInput
• N1 = 78• E1 = 21• N2 = 128• E1 = 512• Azimuth 1 = 72• Azimuth 2 = 301
Output
• N of Intersection• E of Intersection
• Dist from PT 1 to Int
• Dist from PT 2 to Int
ANGLE-ANGLEInput
• XEQ L• 21 R/S• 78 R/S• 72 R/S• 512 R/S• 128 R/S• 301 R/S
Output
• E = 393.68• N = 199.09
• Dist 1 = 391.86• Dist 2 = 138.03
• DONE!
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ANGLE-DISTANCE
• Angle-Distance intersections provide the location of an intersection between one azimuth and one distance and provide the X/Y coordinates of the intersection as well as the distance from the intersection to either of the original points.
ANGLE-DISTANCE
ANGLE-DISTANCEInput
• X1 = 78• Y1 = 21
• X2 = 128• Y1 = 512
• Azimuth 1 = 72• Distance 2 = 510.25
Output• X-CRD of Int 1• Y-CRD of Int 1• Azimuth to Int 1• Dist to Int 1
• X-CRD of Int 2• Y-CRD of Int 2• Azimuth to Int 2• Dist to Int 2
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ANGLE-DISTANCEInput
• XEQ L• 78 R/S• 21 R/S• 72 R/S• 128 R/S• 512 R/S• 510.25 R/S
Output
• X = 493.56• Y = 156.02• Z = 134.14• S = 436.94
X = 41.48Y = 9.14
Z = 189.45S = 38.39
DONE!
DISTANCE-DISTANCE
• Distance-Distance intersections provide the location of two intersections between two distances (X&Y) and the azimuths from the two intersection to either of the original points.
DISTANCE-DISTANCE
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DISTANCE-DISTANCEInput
• X1 = 0• Y1 = 0• R = 500
• X2 = 500• Y1 = 0• R = 500
Output• X = 250• Y = -433.01• Z = 150-00-00• Z = 210-00-00
• X = 250• Y = 433.01• Z = 30-00-00• Z = 330-00-00
DISTANCE-DISTANCEInput
• XEQ N• 0 R/S• 0 R/S• 500 R/S
• 500 R/S• 0 R/S• 500 R/S
Output• X = 250• Y = -433.01• Z = 150-00-00• Z = 210-00-00
• X = 250• Y = 433.01• Z = 30-00-00• Z = 330-00-00
VERTICLE & HORIZONTAL AND CURVES
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CURVES
• Horizontal
• Vertical
HORIZONTAL CURVES
HORIZONTAL CURVESREQUIRED (1+)
• Delta Angle
• Degree of Curvature
• Radius
OPTIONAL (2+)
• Tangent• Curve Length• Chord Length• Middle-Ordinate• External Distance
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HORIZONTAL CURVE PROBLEM
• Compute R, L and E for a horizontal curve with a tangent of 75’ a central angle of 28° and a PI of 08+00
HORIZONTAL CURVE PROBLEM
• Compute R, L and E
• Tangent 75 • Central angle of 28°• PI of 08+00
• XEQ H
• R/S• 28 R/S• 75 R/S• R/S• R/S• R/S• R/S• R/S• R/S• R/S• R/S• 800 R/S• R/S
• PRESTO!
• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S• READ # R/S
VERTICAL CURVES
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VERTICAL CURVESINPUTS
• PVI Station + Elev
• G1 and G2
• L
• Sta Inc
OUTPUTS
• High/Low Point (Elev + Sta)
• Elev @ Sta
VERTICAL CURVE PROBLEM
• Given an equal-tangent vertical curve with a g1 of +2.20%, g2 of -3.10%, length of 350’ and PVI of 12+50 @ 1000’, what is the station and elevation of the PC?
VERTICAL CURVE PROBLEM
• g1 of +2.20%, • g2 of -3.10%, • length of 350’ • PVI of 12+50 @
1000
• XEQ V
• 1250 R/S• 1000 R/S• 2.2 R/S• -3.1 R/S• 350 R/S
• PRESTO!• (ANY) R/S• S = 1075 R/S• E = 996.15
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RADIALINVERSE
Radial Inverse
Radial Inverse
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Radial Inverse
Using azimuth/distance, any point can be found radiating from the initial point.
Traverse Inverse
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Traverse Inverse
Traverse Inverse
Traverse Inverse
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Traverse Inverse
INVERSING AND STUBBING
• An inverse finds the azimuth/distance between two known points (X & Y)
• A stub finds Point #2’s X & Y coordinates from Point #1 and an azimuth/distance
INVERSING BETWEEN POINTS
• XEQ I
• 5000 R/S• 200 R/S• 1500 R/S• 5350 R/S
• PRESTO!• D = 6226.7568 R/S• A = 124.1202 (DMS)
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LOCATING A POINT BY STUBBING• XEQ S
• 500 R/S• 200 R/S• 88.3902 R/S• 505.22 R/S
• PRESTO!• X = 705.0799• R/S• Y = 511.898
DMS TO DD– Sally has a problem. She is working with
trig functions using a set of survey angles. Unfortunately, you cannot use D-M-S formatted numbers for the SIN, COS and TAN functions. You must convert those numbers to DD and then run the trig functions. Can you help her? Find the following numbers in DD format:
– 293-21-19 118-11-59 092-22-21
DMS TO DD
– Can you help her convert these numbers to DD?
– 293-21-19 – 118-11-59 – 092-22-21
• 293.2119
• Gold + 8 (->HMS)
• Enter
• PRESTO• 293 1248 (293-12-
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DMS TO DD• 293.2119
• Gold + 8 (->HMS)
• Enter
• PRESTO• 293.1248 (293-
12-48)
• 118.1159
• Gold + 8 (->HMS)
• Enter
• PRESTO• 118.0657 (118-06-
57)
• 092.2221
• Gold + 8 (->HMS)
• Enter
• PRESTO• 92.1320 (92-13-20)
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