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How Tall Is It? : The Director’s Stand. Jessica Mena, Austin Coker, Sarah Alyce Hartley, Scott Williams 5 th Period March 9. 15° Angle-Scott. Tan15=x/74 .28=x/74 x=19.38 19.38ft+5.17ft=24.55ft. 5.17 ft. 15°. 74 feet. 60° Angle-Jessica. Tan60=x/12 - PowerPoint PPT Presentation
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How Tall Is It? : The Director’s Stand
Jessica Mena, Austin Coker, Sarah Alyce Hartley, Scott Williams
5th PeriodMarch 9
15° Angle-Scott
Tan15=x/74 .28=x/74 x=19.38
19.38ft+5.17ft=24.55ft
74 feet
5.17 ft
15°
60° Angle-Jessica
Tan60=x/12 1.73=x/12 x=20.78 20.78+5.33=26.11f
t L.leg=12√3 = 20.78 20.78 + 5.33 =
26.11ft 12 feet
5.33 feet
60°
30˚ Angle – Austin
Tan 30˚ = x/34ft 0.58 = x/34 X=19.63 19.63 + 5.75 =
25.38 S.Leg = 34ft/√3 Height = 34√3 / 3 Short leg = 19.63 19.63 + 5.75 =
25.38
34 feet
5.75 feet
45° Angle - Sarah Alyce
Tan 45 = x/18 1 = x/18 X = 18 5.17 + 18 = 23.17
ft Leg=Leg 18 + 5.17 = 23.17
ft18 Feet
5.17 feet
Conclusion
Average height = 24.8 feet
We learned that trigonometry is a very valuable tool and not just something you learn in math. It is very useful when dealing with a very tall object.