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How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23 . a) 7.115 x 10 22 b) 1.327 x 10 23 c) 4.262 x 10 23 d) 8.571 x 10 23 e) 3.174 x 10 24

How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

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Page 1: How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 1023.

a) 7.115 x 1022 b) 1.327 x 1023 c) 4.262 x 1023

d) 8.571 x 1023 e) 3.174 x 1024

Page 2: How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

How many moles of silicon are present if you have 4.623 x 1024 silicon atoms?Note that Avogadro’s number is 6.022 x 1023.

a) 1.598 mol b) 4.024 mol c) 7.677 mol

d) 9.322 mol e) 11.15 mol

Page 3: How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

What is the mass of 5.273 mol of iron? The atomic weight of iron is 55.85 g/mol.

a) 12.41 g b) 48.15 g c) 141.9 g

d) 294.5 g e) 416.3 g

Page 4: How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

How many moles of magnesium are present in 62.48 g of magnesium?The atomic weight of magnesium is 24.31 g/mol.

a) 1.373 mol b) 2.570 mol c) 3.995 mol

d) 8.821 mol e) 11.23 mol

Page 5: How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

How many zinc atoms are present in 27.19 g of zinc? The atomic weight of zinc is65.38 g/mol, and Avogadro’s number is 6.022 x 1023.

a) 2.504 x 1023 b) 3.955 x 1023 c) 5.822 x 1023

d) 9.127 x 1023 e) 3.647 x 1024

Page 6: How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

What is the mass of 9.583 x 1021 lead atoms? The atomic weight of lead is 207.2 g/moland Avogadro’s number is 6.022 x 1023.

a) 1.227 g b) 2.305 g c) 3.297 g

d) 4.182 g e) 6.016 g

Page 7: How many atoms of aluminum are present in 1.423 moles of aluminum? Note that Avogadro’s number is 6.022 x 10 23. a)7.115 x 10 22 b) 1.327 x 10 23 c) 4.262

How many moles of H2O are present in 72.15 g of H2O?Atomic weights: H 1.008 O 16.00

a) 1.183 mol b) 1.854 mol c) 2.672 mol

d) 4.005 mol e) 7.124 mol