Hookes Law w Sheet Answers

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    Name___________________________ IGCSE-Hookes Law Worksheet Answers

    1.1.

    1 | P a g e

    F = k . x

    Therefore k = F/x..

    k1 = k2 therefore

    F1/x1=F2/x2

    100/10 = m /20

    10 m = 2000. M = 200

    Or

    If 100g causes an extenti

    of 10cm than 200g should

    cause an extension of 20c

    = 20cm !10cm = 10cm

    "#ring 1 = $0cm !10cm = 200cm

    "#ring 2

    ans

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    1.2.

    1.3.

    1..

    2 | P a g e

    ans

    1%.2 cm & 2.1 = 1'.$

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    1.!.

    3 | P a g e

    Mass is the

    same

    Weight is the

    same

    Volume is

    ans

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    1.".

    | P a g e

    From gra#h( )00* o

    #lanet + has a mass

    )0 kg.

    Mass does not chang

    From the gra#h )0kg

    has a mas of 200*

    #lanet ,

    ans

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    2.1.

    ! | P a g e

    = 1-.) cm 1% cm

    = 1.)cm

    From gra#h an exten

    of 1.) =$.% *

    ans

    F = * '* o##. irection! sutract3

    = 2* left

    2N let

    F = m x a

    a = F/m = 2/ 0.%kg = )m.s!2

    X =1

    X =

    1

    X =

    1

    X =

    1

    X =

    1

    X =

    0.8

    X =

    0.8

    X =

    0.8

    X = 1

    X=

    1.2

    X =

    0.8

    X =

    0.8

    X =

    0.8

    X = 1

    X=

    1.2

    X =

    1.1

    X =

    1.1

    X =

    1.1

    X =

    1.1

    X=

    1.1

    "tudent 4

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    2.2.

    " | P a g e

    The extension for an increase of 0.% * is costant for student

    5(6 and ut is not al7a8s constant for student 4

    1cm

    .! cm " 1cm = #.!

    e$tensti

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    # | P a g e

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    $ | P a g e

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    2.3.

    % | P a g e

    directl% &ro&ortional

    Newton

    From the gra#h a load of 2.% * causes an

    extension of 2%mm. The total length of the s#ring

    is %0mm original length3 & 2%mm = '%mm

    '%mm

    The force of gra9it8 #ulls it do7n

    It has magnitude and direction

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    1& | P a g e

    "#ring 1. From the gra#h a force of 10* causes an extension of

    12.%mm in s#ring 1 and an extension of 1%mm in s#ring 2.

    5fter #oint + the gra#h is no longer straight

    P

    From the gra#h the extensions are 1mm and 2-mm. The differencein extension is 'mm

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    11 | P a g e

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    12 | P a g e

    1 2' ( 2 1

    )rror on

    :imit of #ro#ortionalit8 has een reached

    Find the original length of the s#ring. Measure the ne7

    length of the s#ring 7hen it has a load. "utract the

    measured length from the original length.

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    4.1. What is the extension of the spring? (1)

    = 20mm $2mm = 12 mm

    4.2. If the spring obeys Hookes Law, what oes it te!! yo" abo"t the

    extension an the !oa? (2)

    The extension is directl8 #ro#ortional to the load.

    4.#. What wo"! the extension be if there was a $% !oa? (2)

    F = k . x

    Therefore ; = F/x..

    k1 = k2 therefore

    F1/x1=F2/x2