Heat Exchangers of Polypropylene

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  • 7/30/2019 Heat Exchangers of Polypropylene

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    Exchangers of polypropylene

    //www.segerfrojd.com/ppvsmetal.htm[21/11/2012 2:50:49 p.m.]

    How can Polypropylener ansfer h eat as good as

    metals?

    Many people have the opinion that heat

    exchangers of plastics should have a very poor

    performance because of the poor thermal

    onductivity of plastics. This is not the case!

    Figu re 1 . Heat transfer through a single wall.

    The heat transfer through a single wall is

    dependent on three factors; the overall heat

    ransfer coefficient, U, the heat transferring area,

    A, and the temperature difference between the

    heat emitting and the heat absorbing media.

    n a heat exchanger the overall heat transfer

    oefficient, U, is dependent on; the convective

    heat transfer coefficient for both the hot and the

    old fluid and the thermal conductivity of the wall

    material.

    t can be shown that the overall heat transfer

    oefficient, U, is governed by the individual

    onvection heat transfer coefficient, h, on the gas

    air) side of the walls in the heat exchanger.

    This means that the heat transfer in this case is

    elatively insensitive to the type of material used

    n the walls. If the heat exchanger was made of

    luminum or steel instead of polypropylene, the

    overall heat transfer would not change

    ignificantly.

    The surface characteristics of the heat exchanger

    s also important, affecting pressure drop and

    ouling tendencies. Organic and mineral deposits

    re less adherent to the plastic surface, compared

    D ef i n i t i on o f t heovera l l hea t t rans fe rcoef f ic ient , U

    The overall heat transfercoefficient for a plate heatexchanger is calculated by;

    where

    U [W/m2K] is the overall heattransfer coefficient

    A [m2] is the contact area foreach fluid side

    k [W/mK] is the thermalconductivity of the material

    h [W/m2K] is the individualconvection heat transfercoefficient for each fluid

    xw [m] is the wall thickness

    Therm a l res istance

    The overall heat transfercoefficient can also be calculatedby the view of thermalresistances. This means that thewall is split in areas of thermalresistance, i.e. the heat transferbetween the fluid and the wall isone resistance, the wall it self isalso one and lastly the transferbetween the wall and the secondfluid is the last thermalresistance.Surface coatings, like fouling andepoxy that is commonly usedwith aluminium in heat

    exchangers, adds extra thermalresistances decreasing theoverall heat transfer.

    The rm a lconduc t i v i t y , k

    The thermal conductivity, k, forsome typical materials used inplate heat exchangers is shownbelow.

    Polypropylene: 0.12 W/mKStainless steel: 21 W/mKAluminium: 221 W/mK

    Conv ect ion h eatt r ans fe r coe f f i c ien t ,h

    The convection heat transfercoefficient, h, is dependent onthe type of media, gas or liquid,the flow properties such asvelocity and other flow andtemperature dependent

    Sim p le exam p les

    Consider a single wall withmedia 1 on the left side thatransfers heat to media 2 onthe right side of the wall. Thwall thickness is assumed to0.1mm and the material is Paluminium or stainless steelThe overall heat transfer

    coefficient, U, for a single w(with equal areas) is;

    Exam p le 1Assume that media 1 and 2 air with the convection heattransfer coefficient hAir=50

    W/m2KThe overall heat transfercoefficient becomes:

    PP: U=24.5 W/m2K

    STEEL: U=25.0 W/m2K

    ALU: U=25.0 W/m2KIf we ignore the influence ofthe wall U becomes:

    Thus with air-to-air the walmaterial is irrelevant, since governed by hAir.

    Exam p le 2Assume that media 2 is a liq(water) with the convectionheat transfer coefficient

    h2=1000 W/m2KThe overall heat transfercoefficient becomes:

    PP: U=45.8 W/m2K

    STEEL: U=47.6 W/m2K

    ALU: U=47.6 W/m2KOnce again we see that U isgoverned by hAir, and the

    variation between differentmaterials is small.

    Exam p le 3Assume that media 1 and 2 water with the convection htransfer coefficient

    hWater=1000 W/m2K

    The overall heat transfercoefficient now becomes:

    PP: U=353 W/m2K

    STEEL: U=499 W/m2K

    ALU: U=500 W/m2KIf the thermal conductivity ivery large or the thickness othe wall is very thin, then th

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    Exchangers of polypropylene

    //www.segerfrojd.com/ppvsmetal.htm[21/11/2012 2:50:49 p.m.]

    o metals, which gives less fouling and that the

    exchangers are easier to clean. Fouling adds an

    extra thermal resistance that lowers the overall

    heat transfer.

    properties.

    Air: 10- 100 W/m2K

    Water: 500-10 000 W/m2K

    theoretical max. heat transfcoefficient becomes: