9
MBA Test Prep MBA Test Prep GBO (SRCC)-2010 1 GBO (SRCC)-2010 Answers and Explanations Set C 1 3 21 4 41 1 61 3 81 2 101 3 121 4 141 2 2 2 22 2 42 2 62 3 82 3 102 2 122 1 142 2 3 3 23 3 43 2 63 3 83 2 103 4 123 4 143 1 4 2 24 2 44 4 64 2 84 4 104 1 124 1 144 4 5 4 25 3 45 2 65 3 85 1 105 3 125 2 145 4 6 1 26 2 46 3 66 2 86 2 106 1 126 4 146 3 7 2 27 4 47 2 67 2 87 4 107 3 127 1 147 3 8 2 28 2 48 3 68 1 88 1 108 2 128 3 148 4 9 4 29 3 49 1 69 3 89 2 109 3 129 3 149 2 10 1 30 1 50 4 70 4 90 3 110 3 130 2 150 1 11 2 31 1 51 4 71 2 91 3 111 3 131 4 151 3 12 3 32 3 52 3 72 4 92 1 112 2 132 1 152 3 13 3 33 4 53 2 73 3 93 4 113 1 133 3 153 1* 14 1 34 1 54 4 74 3 94 2 114 2 134 2 154 4 15 3 35 3 55 1 75 2 95 4 115 3 135 4 155 2 16 2 36 3 56 4 76 3 96 2 116 1 136 3 156 2 17 1 37 2 57 3 77 1 97 4 117 2 137 2 157 4* 18 4 38 4 58 2 78 3 98 3 118 3 138 4 158 1 19 3 39 3 59 3 79 4 99 1 119 1 139 2 159 3 20 1 40 4 60 3 80 3 100 1 120 4 140 3* 160 1

GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

Embed Size (px)

Citation preview

Page 1: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

����������������������GBO (SRCC)-2010 1

����������� �

��������������������������������

1 3 21 4 41 1 61 3 81 2 101 3 121 4 141 22 2 22 2 42 2 62 3 82 3 102 2 122 1 142 23 3 23 3 43 2 63 3 83 2 103 4 123 4 143 14 2 24 2 44 4 64 2 84 4 104 1 124 1 144 45 4 25 3 45 2 65 3 85 1 105 3 125 2 145 46 1 26 2 46 3 66 2 86 2 106 1 126 4 146 37 2 27 4 47 2 67 2 87 4 107 3 127 1 147 38 2 28 2 48 3 68 1 88 1 108 2 128 3 148 49 4 29 3 49 1 69 3 89 2 109 3 129 3 149 210 1 30 1 50 4 70 4 90 3 110 3 130 2 150 111 2 31 1 51 4 71 2 91 3 111 3 131 4 151 312 3 32 3 52 3 72 4 92 1 112 2 132 1 152 313 3 33 4 53 2 73 3 93 4 113 1 133 3 153 1*14 1 34 1 54 4 74 3 94 2 114 2 134 2 154 415 3 35 3 55 1 75 2 95 4 115 3 135 4 155 216 2 36 3 56 4 76 3 96 2 116 1 136 3 156 217 1 37 2 57 3 77 1 97 4 117 2 137 2 157 4*18 4 38 4 58 2 78 3 98 3 118 3 138 4 158 119 3 39 3 59 3 79 4 99 1 119 1 139 2 159 320 1 40 4 60 3 80 3 100 1 120 4 140 3* 160 1

Page 2: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

���������������������� GBO (SRCC)-20102

1. 3 The word ‘industrious’ means ‘hard working’.

2. 2 The word ‘colossus’ means ‘huge’.

3. 3 The word ‘defer’ means ‘postpone’.

4. 2 The word ‘exasperation’ means ‘irritation’.

5. 4 The word ‘endorsement’ means ‘approval’.

6. 1 ‘look after’ means to take care of something orsomeone. So, in the given context option (1) is theanswer.

7. 2 ‘bring out’ means to reveal or to expose something. Inthe question statement ‘brings out’ should be used tomaintain subject verb agreement.

8. 2 ‘put aside’ means to store or to save. In the givencontext option (2) is the best fit.

9. 4 ‘took down’ means to note down something. Thecontext indicates that the reporters noted down thespeech of Mr. Obama.

10. 1 ‘get at’ means to reach to something. The questionstatement indicates that the person is not able to reachthe books. Hence, option (1) is the correct answer.

11. 2 The word opposite in meaning to ‘luscious’ is ‘insipid’.

12. 3 The word opposite in meaning to ‘merciless’ is ‘kind’.

13. 3 The word opposite in meaning to ‘superficial’ is ‘deep’.

14. 1 The word opposite in meaning to ‘opaque’ is‘transparent’.

15. 3 The word opposite in meaning to ‘summit’ is ‘base’.

16. 2 The context of the sentence indicates that thehandicraftsman drew ‘satisfaction’ from the work hewas doing.

17. 1 ‘betterment’ is the correct word to fill the blank.‘Advantage’ is used for something that is physical innature.

18. 4 ‘whole’ work is the correct usage.

19. 3 ‘making’ is the correct word in the given context.

20. 1 ‘often’ which means repeatedly or frequently is thecorrect answer in the given context.

21. 4 ‘difficulties’ is the correct word in the given context.

22. 2 ‘work’ is the correct word to complete the sentence.

23. 3 The sentence has a misprint. Instead of ‘his’ thesentence should have ‘has’. ‘changed’ fits the blankappropriately.

24. 2 ‘manner’ is the right word in the given context.

25. 3 ‘salary’ is the correct word to fill the blank. Astandardized job results in a standardized salary.

26. 2 The first two lines of the second paragraph clearlymention that the most important aspect of the tropicalforests is that these forests are ‘dynamic centers ofevolution’. Hence, option (2) is the correct answer.

27. 4 ‘Primeval’ used in the second paragraph implies thatthese forests have remained ‘untouched’ from theacquisitive hand of man.

28. 2 The author is trying to save the tropical forests. Thisimplies that his ideas would be most supported by‘conservationists and botanists’.

29. 3 The first two lines of the first paragraph state that‘stately primeval forests has given way to erodedland’. This implies that the damage to the soil is theresult of chopping down of tropical rain forests.

30. 1 ‘will take only a few decades’ is the correct answer.

31. 1 ‘has’ should be used in place of ‘have’ to maintainsubject-verb agreement.

32. 3 ‘have’ should be used in place of ‘has’ to maintainsubject-verb agreement.

33. 4 ‘himself’ should be used in place of ‘oneself’ as thepersonal pronoun used is ‘him’.

34. 1 ‘In spite of’ would be the correct usage in the sentence(of is not used with despite).

35. 3 ‘when’ should be used in place of ‘while’.

36. 3 ‘be overcome’ would be idiomatically correct usage inthe given sentence.

37. 2 ‘won’t be’ would be idiomatically correct usage in thegiven sentence.

38. 4 ‘him’ would be the correct usage in the given sentence.

39. 3 ‘But for’ would be the correct usage. The sentenceintends to say that if timely medical assistance wasnot tendered to the patient, he/she might have died.

40. 4 ‘reads’ would be the correct usage in the givensentence.

Page 3: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

����������������������GBO (SRCC)-2010 3

41. 1( )( )

( )

22 2 2

2 2 2 2 2

a b a b c 2bca b c 2bc

a b 2ab c a c c

− + − −− − − =+ − − − −

( )( ) ( ) ( )( )( ) ( )

2

2 2

0.3 0.2 0.5 2 0.05 0.5

0.3 0.5

− − −=

14 716 8

−= =−

42. 2 4a3 + 984 is divisible by 11.984 leaves remainder 5 when divided by 11.So, 4a3 must leave remainder 11 – 5 = 6 when dividedby 11.We know that 440 is divisible by 11 and hence 446 willleave a remainder of 6 when divided by 11.Hence, ‘446 – 33 = 413’ ends with 3 and also leavesremainder 6 when divided by 11.Hence 4a3 = 413 and a = 1Also, 413 + 984 = 1397 and b = 9The value |2a – b| = |2 – 9| = 7

43. 2 Let the natural numbers in increasing order be a, b, cand d.We can definitely conclude that ‘b + c + d’ (which ismaximum possible sum of any three) will be 222 .…(1)Also,(a + b + c) + (b + c + d) + (c + d + a) + (d + a + b)= 180 + 197 + 208 + 222

3(a b c d) 807⇒ + + + =

a b c d 269⇒ + + + = …(2)From (2) – (1) :d = 269 – 222 = 47

44. 4 Using the formula for summation in a G. P. we canreduce the expression to:

( )( )( )( )( ) ( )

( )( )( )( )

17 7 3

1 2

1 1

1.331 1 1.331 11.331 1.331

1.331 1 1.331 1

− −− −

− −

− − ÷ − −

[ ]131.331 1.1= =

45. 2 % of Coins + % of beads = 100% of Coins = 100 – 20 = 80%

% of Silver coins40

80 32%100

= × =

% of Gold coins = 80 – 32 = 48%

46. 3 Let the (initial) income of the woman be IHence, Initial expenditure = 0.80 IIncreased expenditure = (0.8) (1.375) = 1.10 IIncreased Income = 1.25 I

Percent Saving 1.25 1.10 0.15100 100% 12%

1.25 1.25−= × = × =

47. 2 Let the initial volume of mixture be V and initial volumeof acid in water = AHence

A 120%

V 1 5= =

+ .....(1)

And,

A 1 A 1 1 133 %

V 1 1 V 2 3 3+ += = =

+ + + .......(2)

Solving (1) and (2)A = 1 and V = 4So, percentage of acid in the original mixture

= 1

100 25%4× =

Percentage of water = 100 – 25 = 75%

48. 3 Let the cost (to merchant) of 1 pen = C700 pens sold for 749C and hence, 749 pens sold for

749 749C700×

Percent gain

749 749C 749C

700 100% 7%749C

× −= × =

49. 1 Let the cost of dress = C

Price at which she actually sold a dress3

C2

=

As there was ‘14

off on these dresses’, we can say

that the Price 3' C'2

was 3

th4

of marked price.

So, the marked price4 3

C 2C3 2

= × =

Ratio = C : 2C = 1 : 2

50. 4 After 3 hrs. both candles have same length remaining.Let this length be ‘L’.The shorter one takes 11 – 3 = 8 hrs. to burn length LThe longer one takes 7 – 3 = 4 hrs. to burn length LSo rate of burning (Length/time) has the ratio (shorterto longer)

L L: 1: 2

8 4=

So in 1hr the longer one burns twice the length ascompared to the shorter one.If in 11 hrs. the shorter are burns 11k length, then in 7hrs. the longer one burns 7 × 2 = 14k lengthRatio = 11 : 14

Page 4: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

���������������������� GBO (SRCC)-20104

51. 4 Let xy = C (C is a constant) .......(1)

If x is increased by p% then we get 100 p

x100

+

Let this leads to a new value of y, y′′So,

100 py x C

100+ ′′ =

........(2)

Dividing (1) by (2)–

y 100 py 100

+=′′ or

100yy

100 p′′ =

+

% decrease

1001

y y 100 p100% 100%y 1

−′′ − += × = ×

100p%

100 p=

+

52. 3 Let the man started with amount Rs. ASo,((1.1A – 125000) × 1.1 – 65000) × 1.1 = 110000

(1.21A 202500)1.1 110000⇒ − =

1.21A 302500⇒ =

A Rs. 2,50,000⇒ =

53. 2 Let the radius of smallest circle (S) = r unitsHence, the radius of middle sized circle (M) = 2r unitsAlso, the radius of largest circle = 5r units

Area of largest circle = 225 rπ

Area of S 2r= π

Area of M 24 r= π

Area of shaded region 2 2 2 225 r 2 r 4 r 19 r= π − × π − π = πFraction of shaded region in the large circle

2

219 r 19

2525 r

π= =π

54. 4 Let the amount of work done by B in 1 hour = ‘b’ unitsSo, the amount of work done by A in 1 hour = ‘3b’ unitsWhen A and B work together–Amount of work done in 1 hour = b + 3b = 4b unitsAmount of work done in 4 hours = 4 × 4b = 16b unitsNow, ‘16b’ is half of the whole work and hence, theother half work ‘16b’ was completed by A and Ctogether in 1 hour.Hence, the amount of work done by C in 1 hour= 16b – 3b = 13b unitsTotal work = 32b

Time taken by C to complete the job 32b 32

hours13b 13

= =

55. 1 Total volume of conical vessel 21

V r h3

= = π

( )21 2220 21

3 7= × × × = 8800 cm3

Cross-sectional area of cylinderical pipe

( )22 322 11R 0.5 cm

7 14= π = × =

Volume of water flowing per minute across the Cross

section of the pipe 2 311 11000v 10 10 cm

14 14= = × × =

Total time taken V 8 14

11.2 minutesv 10

×= = =

56. 4 Let the amount of work done by a person in 1 hour =‘P’ unitsTwo persons working 2 hours a day assemble2 machines in 2 days. In other words : two personsworking 2 hours a day assemble 1 machine in 1 day.Total amount of work done by 2 persons in a dayWhen working for 2 hours each = 2 × 2P = ‘4P’ unitsHence ‘4P’ amount of work leads to assembling1 machine. ...(1)Total Amount of work done by 6 persons working6 hours a day in 6 days = 6 × 6 × 6P = 216PComparing with statement (1) we can say that–‘216P’ amount of work will lead to assembling

21654 machines

4=

57. 3 Let the total distance between P and Q be 15x unitsLet speed of 1st person = 5vSo, speed of 2nd person = 3v (as speed is inverse oftime taken)The 2nd person starts at 4 a.m. and by this time the 1st

person would be only 1

153× = 5x units from Q.

In 1 hour the 1st person travels 5x units so we cansay ‘x = v’ numerically.So, they will meet (after 4 a.m.) in

5x 5x 5hours

5v 3v 8v 8= = =

+Time at which they cross at =

5 14 : 60 4 : 37 a.m.

8 2 × =

58. 2 Total distance covered = mw + hkTotal time taken = m + k

total dis tance mw hkAverage rate

total time m k+= =+

Page 5: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

����������������������GBO (SRCC)-2010 5

59. 3 Let the time spent by A travelling by air, water and landbe T, 16T and 2T respectively.Let the average speed for A when travelling by air,water and land be 20V, V and 3V respectively.Hence, distance covered when travelling by–Air = T × 20V = 20TVWater = 16T × V = 16TVLand = 2T × 3V = 6TVTotal Distance = 20 + 16 + 6 = 42TV = 3990 km

Distance covered by Air = 3990

20 1900km42

× =

60. 3 Let compound interest at rate 5% and 4% per annumbe C1 and C2 respectively.

Now, ( ){ }21C P 1.05 1= − …(1) and

( ){ }22C P 1.04 1= − …(2)

(Where P is the principle amount).Dividing (i) by (ii) we get–

( )( )

21

222

1.05 1C 816C 102.50 Rs.81.6

C 10251.04 1

−= ⇒ = × =

61. 3 Let the side of the equilateral triangle be ‘a’ units

Radius of the inscribed circle1 3 a

a units3 2 2 3

= × =

Side of the square inscribed in circle = a

2 units2 3

×

aunits

6=

Area of equilateral triangle 2 23a unit

4=

Area of square2

2aunit

6=

Ratio 3 1: 3 3 : 2

4 6= =

62. 3 A

B

1.6 m

HE

F

C2.6 m

G

D 4.4 m

10 m

The above figure is for the swimming pool mentionedin the question.

Total volume = ( )Area ABCD DE⋅ ×

AB CDBC DE

2+ = × ×

1.6 4.426 10

2+ = × ×

36 26 10780m

2× ×= =

63. 3

H

A

B C

D

E8

8

121

12–x

G

Fx

Construction: Join AFLet FG = x cm and hence EF = ‘12 – x’ cm

In ADF∆ –AF2 = AD2 + DF2 = 122 + 12 = 145 …(1)

In AEF∆ –AF2 = AE2 + EF2 = 82 + (12 – x)2 = 64 + (12 – x)2…(2)From (1) and (2)AF2 = 145 = 64 + (12 – x)2

( )212 x 81⇒ − =

x 3 cm⇒ =Area of shaded region

= Area ABCD Area AEF Area ADF⋅ − ∆ − ⋅ ∆

( )8 12 3 12 112 8

2 2

× − ×= × − −

= 96 – 36 – 6 = 54 cm2

64. 2 Let the sides of rectangular box be of a, b and c cm

2 2 22r a b c= + +

( ) ( )2a b c 2 ab bc ca= + + − + +

24(a b c)2(ab bc ca)

4+ + = − + +

( )2Sum of length of 12 edges

Surface area4

= −

22112

384 28 384 20cm4

= − = − =

Hence, 20

r 10cm2

= =

Page 6: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

���������������������� GBO (SRCC)-20106

65. 3 Surplus of steel for the year–2003 = 4.1 million tons2004 = 9.3 million tons2005 = 9.4 million tons (highest)2007 = – 25.8 million tons

66. 2 Average Supply total supply

6=

274.845.8 million tons

6= =

67. 2 If you analyze the table correctly you’ll observe thatfrom 2006 to 2007 (i.e. 30.2 to 56.6 million tons) thepercentage increase is maximum.

68. 1 Percentage increase60 49.2 10.8

100 10049.2 49.2−= × = ×

21.95%=

69. 3 Increase in surplus (in million tons) as compared topreceding year for–2004 = 9.5 – 4.1 = 5.2 (maximum)2005 = 9.4 – 0.012006 = 1.7 – 9.4 = – 7.7

70. 4 Raw material cost (in crore Rs.) for–P = 25 – 10 = 15Q = 25 – 10 = 15R = 25 – 10 = 15S = 70 – 30 = 40 <highest>

71. 2 Sales = total cost + profitProfit per rupee of sales for the company–

S = 1080

R = 2045

(highest)

Q = 1035

P = 5

30

72. 4 Raw material cost per rupee of the total cost for–

P = 1525

Q = 1525

R = 1525

S = 4070

(lowest)

73. 3 Sales of company S = Rs. 80 croreSales of company Q = Rs. 35 croreSales of company R = Rs. 45 crore

74. 3 Profit as percentage of total cost for–

5P 100% 20%

25= × =

10Q 100% 40%

25= × =

20R 100% 80%

25= × = (highest)

10S 100% 14.28%

70= × =

75. 2 ( )21 11, 1, 2 1 1 2−− = − − −

= 1 – 1 – 2 = – 2

76. 3( ) ( )2 2 6 1 32 2 2 3

33 2 3 2 3 2 3

+ + −= × ×+ + −

( ) ( ) ( )( )2

1 3 2 32 2 2 24 2 3 2 3

3 34 3

+ −= × = + −

2 2 2 2 48 4 3 4 3 6 2

3 3 3= − + − = × =

77. 1( )

( )

17 17 171 17 1 1 1

2 3 1919 19 19

1 19 1 1 12 3 17

+ + + + + + + +

19 20 3618

2 3 1921 22 36

202 3 17

× × × = × × ×

18 19 20 36 2 3 4 172 3 4 19 20 21 22 36× × × ×= ×× × × ×

� �

� �

36!1

36!= =

78. 3 (101010101)2 = 10203040504030201

79. 4 If it leaves the same remainder then (13903 – 13511)and (14589 – 13903) both must be divisible by thisnumber.Hence we need to find the HCF of 392 and 686 whichis 98.

80. 3 Let the days be numbered 1 to 1000 (starting from the1st day to the 1000th day)Days on which A takes rest–4, 8, 12, 16 ... (all multiples of 4)Days on which B takes rest–8, 9, 10, 18, 19, 20 ... (Sets of 3 consecutive naturalnumbers of type 10k – 2, 10k – 1 + 10k)

Page 7: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

����������������������GBO (SRCC)-2010 7

We know that in every 3 consecutive naturalnumbers only 1 can be divisible by 4 at maximum.However here in every set of 3 natural numbersthere will be 1 such number definitely(8 in 8, 9 and 10, 20 in 18, 19 and 20 etc.)Total set of 3 consecutive natural numbers

1000100

10= = . So, answer = 100

81. 2. Course of Action I is beyond the scope of informationgiven in the question statement. Only course of actionII follows. The Government is requesting concretesuggestions and course of action II is also referringthe same.

82. 3. There is no reason to believe that the requirement ofcoal for thermal power stations should be assessedrealistically. Moreover, introduction of welfaremeasures is not addressing the issue at hand. Hence,both course of action I and II do not follow,

83. 2. The issue at hand is the irregular supply of raw materialand reasonable prices are not offered to the rawmaterial producers. Regulation of the supply of rawmaterial to other industries is beyond the scope ofinformation offered in the question statement. Hence,only II follows.

84. 4. Both I and II follow. The statement highlights twoproblems: First is the loosing credibility of the electronicmedia and second is the need for training. Course ofaction I and II address these two issues hence, bothfollow.

85. 1. Doordarshan is suffering from a dearth of talent. It isnot able to attract talent for its programs. Hence, courseof action I is the right action to solve the problem.Course of action II is not addressing the issue at hand.

For 86 to 90:Based on the statements given, the following can be inferred:

Male/female Person Subject Spouse

male A Maths E

male B N.A. X

female C Social Science D

male D Chemistry C

female E Zoology A

male F Commerce X

female G Physics X

86. 2

87. 4

88. 1

89. 2

90. 3

91. 3

S

OB

S = SoapsO = O ilsB = Bo ttles

92. 1 GK

J

G KJ

G

K

J G Glasses

K Kettles

J Jugs

===

93. 4

T

D C

D

TC

DC

T

CD

T

D Dogs

C Cats

T Tigers

===

94. 2 B

M

NB

M

N

BN

M

B Books

M Magazines

N Newspapers

===

Page 8: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

���������������������� GBO (SRCC)-20108

95. 4

P G

S

S P G

P = P is to lsG = G unsS = Sw ords

96. 2 Statements:N < W, L > N, K = L, W = D

Conclusion I.:L = WWe have, L > N < W. So, this may not be true.

Conclusion II:D > NWe have, N < W = D. So, this is true.

97. 4 Statements:

L A≥ , S < E, A = S, G > L

Conclusion I:A < EWe have, A = S < E. So, this is true.

Conclusion II:G > A

We have, G L A.> ≥ So, this is true.

98. 3 We have assumed a mis-print here (I as 1 instatements)Statements:

M = I, A > M, T I,≤ T = K

Conclusion I:M = KWe have, M I T K.= ≥ = So, M K≥ and this may notbe true.Conclusion II:K < MWe have, M I T K.= ≥ = So, M K≥ and this may notbe true.Either conclusion I or conclusion II is true.

99. 1 Statements:

I R, D I, E C, R E≤ < = >Conclusion I:R > C.We have, R > E = C. So, this is true

Conclusion II:I = RWe have I R.≤ So, this may not be true.

100. 1 We have assumed a mis-print here (Q as O in thestatements)Statements:

U N, S Q, N D, Q U> ≥ < =Conclusion I:N < S.

We have, S Q U N.≥ = > So, this is true.Conclusion II:U = DWe have U > N < D. So, this may not be true

For 101 to 105:

101. 3 All three are visceral body parts.

102. 2 All three are ways to measure quantities

103. 4 All three are natural calamities

104. 1 Liberate is synonymous to free, release andemancipate.

105. 3 All are natural fibres/polymers

For 106 to 110:

106. 1

5 , 6 , 7 , 8 , 10, 11, 14 , (....)Series:

+2 +3 +4

+2 +3 +4

Answer = 11 + 4 = 15

107. 3

4 6 13 13 28 121 5940

2×6+1 2×13+2 2×28+3

4×3+1 13×3+1 40×3+1

Answer = 13 × 3 + 1 = 40

108. 2 Series =

5 6 9 15 (....) 40 1 3 6 10 15

2 3 4 5Answer= 15 + 10 = 25

109. 3 Series:

2 , 26 , (64 ), 124 , 214 , 342 24 38 60

14 22 30 3890 128

8 8 8

Page 9: GBO (SRCC)-2010 Exp - Amazon Web Servicesmedia.careerlauncher.com.s3.amazonaws.com/iift2009/GBO (SRCC)-20… · gbo (srcc)-2010 1 ˘ˇ ˆ˙˝ ˛ ˆ 1 3 21 4 41 1 61 3 81 2 101 3 121

����������������������GBO (SRCC)-2010 9

110. 3 1 , 5, 9 , 17, (....), 37 , 49

+4 +4 +8 +8 +12 +12Answer = 17 + 8 = 25

111. 3

112. 2

113. 1

114. 2

115. 3

116. 1. Only I is implicit. We cannot say that Mr. Mehta is veryreligious as we are not sure that the author is talkingabout Geeta, the holy book, or someone named Geetais talked about. Hence, II is not implicit. III is not implicitas it is beyond the scope of information given in thestatement.

117. 2. Both I and II are implicit. The question statement statesthat, " We would go ….. law and order situation of thestate." This implies that the Chief Election Commissionis not satisfied with the current law and order situation.Moreover, the Chief Election Commission states thathe/she will go ahead with the process only when heis satisfied with law and order situation. It means thathe can decide the dates for polls. III is not implicit as itbeyond the scope of information offered.

118. 3. Since the focus of the literacy campaigns is oneducating women, it can be assumed that women areless literate when in comparison to men. Hence, onlyIII is implicit.

119. 1. Since mobile dispensaries are promoted in the areaswhere there are no hospitals, it implies that it is notpossible to have hospitals in those areas. Hence, II isimplicit. Following the same logic, one can say thatthere is a lack of hospitals in Uttarakhand and mobiledispensaries is an effort to bridge the gap. Hence, I isalso implicit.

120. 4 None is implicit. All three assumptions are beyond thescope of information offered in the question statement.

121. 4

122. 1

123. 4

124. 1

125. 2

126. 4

127. 1

128. 3

129. 3

130. 2

131. 4

132. 1

133. 3

134. 2

135. 4

136. 3

137. 2

138. 4

139. 2

140. 3* Here * means most likely answer.

141. 2

142. 2

143. 1

144. 4

145. 4

146. 3

147. 3

148. 4

149. 2

150. 1

151. 3

152. 3

153. 1* Here * means most likely answer.

154. 4

155. 2

156. 2

157. 4* Here * means most likely answer.

158. 1

159. 3

160. 1