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METODE NUMERIK “Interpolasi Gauss Mundur” Kelas 2012 C Anggota Kelompok 3: 1. Suprat Dwi Cahyono 12030174060 2. Muryati 12030174062 3. Nurfi Rif’atul Himmah H. A. 12030174242 4. Hetri Nur Fajarwati 12030174244 5. Dita Nilamsari 12030174245 Universitas Negeri Surabaya Fakultas Matematika dan Ilmu Pengetahuan Alam Jurusan Matematika Program Studi S1 Pendidikan Matematika

Gauss's Backward Interpolation

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Metode Numerik Interpolasi Gaus Mundur

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METODE NUMERIKInterpolasi Gauss Mundur

Kelas 2012 C

Anggota Kelompok 3:

1. Suprat Dwi Cahyono

12030174060

2. Muryati

12030174062

3. Nurfi Rifatul Himmah H. A.12030174242

4. Hetri Nur Fajarwati

12030174244

5. Dita Nilamsari

12030174245

Universitas Negeri Surabaya

Fakultas Matematika dan Ilmu Pengetahuan Alam

Jurusan MatematikaProgram Studi S1 Pendidikan Matematika

2015

Interpolasi Gauss MundurMetode ini hanya dapat digunakan jika data yang diberikan berupa data yang memiliki beda sama ( konstan) dengan mendefinisikan .Bentuk umum formula interpolasi gauss mundur adalah sebagai berikut. Rumus ini cocok di hingga

Dengan

Contoh Soal

1. Hitunglah nilai dan tentukan nilai apabila diberikan tabel diferensi berikut ini (pendekatan hingga )

0.1 0.09983

0.379600.5 0.47943 - 0.07570 0.30390 - 0.047970.9 0.78333 - 0.12367 0.01951 0.18023 - 0.02846

1.3 0.96356 - 0.15231 0.02404

0.02810 - 0.004421.7 0.99166 - 0.15655

0.128452.1 0.86321

Penyelesaian:

= - 0.25

2. Apply Gausss backward formulas to obtain sin 45, given in the following table.x203040506070

y = sin x0,34200,50200,64280,76600,86600,9397

Penyelesaian:

20 0,3420 0,16 30 0,5020 - 0,0192 0,1408 0,0016 40 0,6428 - 0,0176 - 0,0072 0,1232 - 0,0056 0,0097 50 0,7660 - 0,0232 0,0025

0,1 - 0,0031 60 0,8660 - 0,0263

0,0737 70 0,9397

= 0,7660 0,06155 + 0,0029 0,00035 + 0,0000585938 0,0001136719

= 0,70694492193. Find the values of y when x = 2.9 from the following data using Gausss backward formula respectively :x2,02,53,03,54,0

y246,2409,3537,2636,3715,9

Penyelesaian:

2,0 246,2 163,12,5 409,3 - 35,2 127,9 6,43,0 537,2 - 28,8 2,9 99,1 9,3

3,5 636,3 - 19,5

79,6 4,0 715,9

= 537,2 25,58 + 2,304 + 0,2048 + 0,04176

= 514,170564. Given that = 2,2361; and find by using Gausss backward formula.

Penyelesaian:

4 2 0,2361 5 2,2361 - 0,0227 0,2134 0,00566 2,4495 - 0,0171 - 0,0022 0,1963 0,0034 0,0015 7 2,6458 - 0,0137 - 0,0007

0,1826 0,0027 8 2,8284 - 0,011

0,1716 9 3

= 2,6458 0,03926 + 0,001096 + 0,0001088 0,00001008 0,000009504

= 2,607725216Daftar Pustaka

Fuad, Yusuf. 2014. Metode Numerik 1. Surabaya: Jurusan Matematika FMIPA Unesa.

https://books.google.co.id/books?id=cL1boM2uyQwC&pg=SA6-PA4&lpg=SA6 PA4&dq=gauss+backward+interpolation&source=bl&ots=Q_kjG-G3sz&sig= Xzy2kV1ZklRHVBZWM21oZ9EO4&hl=id&sa=X&ei=D1dRVd2OAZLjoATQg4GIBg&ved=0CF4Q6AEwCA#v=onepage&q=gauss%20backward%20interpolation&f=false.(Diakses pada Selasa 12 Mei 2015 pukul 09.00)http://sakshieducation.com/Engg/EnggAcademia/CommonSubjects/MathMethods Interpolation.pdf. (Diakses pada Senin 11 Mei 2015 pukul 10.00) EMBED Equation.3

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